Additional Mathematics Project 2013

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    First and foremost, I would like to thank god that finally, I had succeeded

    in finishing project work.

    I would like to thank my beloved Additional Mathematics teacher, Mr. Ng

    Seng Chew for all the assistance he has provided me during my job search. I appreciate the

    information and advices he has given, as well as the connections he have shared with me. His

    expertise and help have been invaluable during this process.

    Also, thanks to my parents, Ahmad Hanit Mohd Jah and Rahemah Tan ,

    for giving me full support in completing this project work. I sincerely appreciate their

    generosity. I would like to give my special thanks to my fellow friends who had given me

    extra information on the project work and study group that we had done. Thank you for

    spending time with me to discuss about the course work.

    Last but not least, I would like to express my highest gratitude to all those

    who gave me the possibility to complete this course work. I really appreciate all your helps.

    Again, thank you so much.

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    The aims of carrying out this project work are :

    To apply and adapt a variety of problem-solving strategies to solve

    problems.To improve thinking skills.

    To develop mathematical knowledge through problem solving in way that

    increase students interest and confidence.

    To use the language of mathematical to express mathematical ideas

    precisely.

    To provide learning environment that stimulates and enhances effective

    learning.

    To develop positive attitude towards mathematics.

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    Acknowledgement

    Objective

    Introduction

    Part 1

    Part 2

    Part 3

    Further Exploration

    Conclusion

    Reflection

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    QUADRILATERAL

    In Euclidean plane geometry, a quadrilateral is a polygon with four sides (or edges) and fourvertices or corners. Sometimes, the term quadrangle is used, by analogy with triangle, and

    sometimes tetragon for consistency with pentagon (5-sided), hexagon (6-sided) and so on.

    The origin of the word "quadrilateral" is the two Latin words quadri, a variant of four, and

    latus, meaning "side."

    Quadrilaterals are simple (not self-intersecting) or complex (self-intersecting), also called

    crossed. Simple quadrilaterals are either convex or concave.

    The interior angles of a simple (and planar) quadrilateral ABCD add up to 360 degrees of arc,

    that is

    This is a special case of the n-gon interior angle sum formula (n 2) 180. In a crossed

    quadrilateral, the four interior angles on either side of the crossing add up to 720.[1]

    All convex quadrilaterals tile the plane by repeated rotation around the midpoints of their

    edges.

    HISTORY OF QUADRILATERAL

    Quadrilaterals were invented by the Ancient Greeks. It is said that Pythagoras was the first to

    draw one. In those days quadrilaterals had three sides and their properties were only dimly

    understood. It was the genius of the Romans to add a fourth side and they were the first to

    make a list of the different kinds of quadrilaterals but it wasn't until 1813 that an English

    mathematician, J.P. Smith, discovered the trapezium. Quadrilaterals remain a rich source of

    investigations for researchers, the best known unsolved problem being to find a general

    formula for the number of interior angles.

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    The Rectangle

    means "right angle"

    and show equal sides

    Arectangleis a four-sided shape where every angle is aright angle(90).

    Also opposite sidesareparalleland of equal length.

    The Rhombus

    Arhombusis a four-sided shape where all sides have equal length.

    Also opposite sides are parallel andopposite angles are equal.

    Another interesting thing is that the diagonals (dashed lines in second figure) meet in

    the middle at a right angle. In other words they "bisect" (cut in half) each other at right

    angles.

    The Square

    means "right angle"

    show equal sides

    Asquarehas equal sides and every angle is a right angle (90)

    Also opposite sides are parallel.

    A square also fits the definition of a rectangle(all angles are 90), and a rhombus(all

    sides are equal length).

    http://www.mathsisfun.com/geometry/rectangle.htmlhttp://www.mathsisfun.com/geometry/rectangle.htmlhttp://www.mathsisfun.com/geometry/rectangle.htmlhttp://www.mathsisfun.com/rightangle.htmlhttp://www.mathsisfun.com/rightangle.htmlhttp://www.mathsisfun.com/rightangle.htmlhttp://www.mathsisfun.com/geometry/parallel-lines.htmlhttp://www.mathsisfun.com/geometry/parallel-lines.htmlhttp://www.mathsisfun.com/geometry/parallel-lines.htmlhttp://www.mathsisfun.com/geometry/rhombus.htmlhttp://www.mathsisfun.com/geometry/rhombus.htmlhttp://www.mathsisfun.com/geometry/rhombus.htmlhttp://www.mathsisfun.com/geometry/square.htmlhttp://www.mathsisfun.com/geometry/square.htmlhttp://www.mathsisfun.com/geometry/square.htmlhttp://www.mathsisfun.com/geometry/square.htmlhttp://www.mathsisfun.com/geometry/rhombus.htmlhttp://www.mathsisfun.com/geometry/parallel-lines.htmlhttp://www.mathsisfun.com/rightangle.htmlhttp://www.mathsisfun.com/geometry/rectangle.html
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    Example of the geometry in our daily lives

    Rectangular swimming pool

    Square design wallpaper.

    Parallelogram design building.

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    Rhombus design in an architecture college.

    Trapezium bookshelves.

    Kites.

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    QUESTION A

    Variables :

    1. Length of the nylon string

    2. Area of the brick

    3. X = length of the trace area

    4. Width of the trace area

    5. Width of the brick

    6. Shape of the trace

    7. Length of each brick

    8. Type of brick

    Area of the trace area =

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    2x + 2y = 7

    2= 7 - 2

    =

    Area =( x )

    =

    QUESTION B

    i. Differentiation

    A= -

    = =- 2

    =

    2

    4

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    A =

    (

    ) (

    )

    =

    = ( x , A )

    = ( 1.75 , 3.0625 )

    A = 3.0625 when x = 1.75 Thus, the maximum area of the trace area is 3.0625 .

    ii. Graphical Method

    Plot graph A against x. Based on the table of values of x and A.

    X

    m)

    1.70 1.71 1.72 1.73 1.74 1.75 1.76 1.77 1.78 1.79 1.80

    A

    3.06 3.0609 3.0616 3.0621 3.0624 3.0625 3.0624 3.0621 3.0616 3.0609 3.06

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    QUESTION C

    The perimeter of nylon string = 7.0 m

    The length of a brick = 0.2 m

    The minimum number of pieces =

    =

    = 35 bricks.

    The minimum cost for making the trace area :

    The minimum number of pieces x the cost = 355 x RM7

    = RM245

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    Therefore, the minimum cost to build the park site is RM245.

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    = 0.7038 = 2.254

    The radius of the ponds is 0.7038m and 2.254m

    Since large fish pond has bigger radius, therefore the radius for the large fish pond is

    2.254m

    The diameter of the large fish pond = 2.254m + 2.254m

    = 4.508m

    Therefore the diameter of the large fish pond is 4.508m

    QUESTION C

    To minimise the cost of the construction of building a flower site, we must find its

    maximum area of the flower site. There are many methods to find the maximum

    area. In here, I will show two methods that is differentiation methodand

    tabulation of data.

    Differentiation method

    Firstly, we use the quadratic equation we formed from the 3(a),

    y= - 2x2+ (9-6x) + 138

    We insert =22/7 into the formulae

    y= -6.286x2-18.86x+138 + 28.29

    y= -6.286x2

    -18.86x + 166.89

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    Now we differentiate the quadratic equation above

    Since at the maximum point, it has a stationary value,

    -12.572x18.86 = 0

    -12.572x= 18.86

    X =-1.500m2

    Tabulation of data

    x y = -6.286+ 18.857 x + 109.7141.0 122.285

    1.1 122.850

    1.2 123.290

    1.3 123.604

    1.4 123.793

    1.5 123.856

    1.6 123.793

    1.7 123.604

    1.8 123.290

    1.9 123.850

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    2.0 122.284

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    1 ) CIRCLE

    Area of circle ,

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    Perimeter of circle ,

    1 ) SQUARE

    Area of square ,

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    Perimeter of square ,

    3) SEMI - CIRCLE

    Area of semi-circle ,

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    ( )

    Perimeter of regular pentagon ,

    Therefore, circle is the best shape to build the garden as it gives the minimum perimeter than

    other shapes.

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    Area of circle ,

    Perimeter of circle ,

    As the conclusion to this project work , there are so many quadrilateral around us. Its

    plays an important role in our design of building or an object . So, student should be more

    aware about this.

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    Plus, it is widely used in building of modern structures and designing of a gadget. The

    triangle, for instance is often used in construction because its shape makes it comparatively

    strong. The use of polygon shape reduces costs and maximizes profits in a business

    environment . The rectangle is used in a number of applications, due to the fact our field of

    vision broadly consist of a rectangle shape.

    Without it, mans creativity will be limited. Therefore, we should be thankful of the

    people who contribute in the idea of using quadrilateral.

    While I am doing this Additional Mathematics project work, I have learned some

    moral values. This project work had taught me to be responsible on the works that are given.

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    I had learned on how to complete this project work by identifying and interpreting the

    problems.

    Moreover, this project work has also make me feel more confident to do all of the

    work and to not give up easily when I found that it is hard to find the solution because, when

    theres a will, there will always be a way.

    Not just that, I am also enjoying doing this project. I spend more time with my

    friends, thus it will tightened our friendship.

    Last but not least, this project work has also increase my interest in learning

    additional mathematics subject.

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