—7. Y 3—0) PET, Y + Z O)ftþ 94 95 96 E-2000 600 610 97 Y-H-*Y 98 584 (0/0… · 2017. 11....

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Transcript of —7. Y 3—0) PET, Y + Z O)ftþ 94 95 96 E-2000 600 610 97 Y-H-*Y 98 584 (0/0… · 2017. 11....

Page 1: —7. Y 3—0) PET, Y + Z O)ftþ 94 95 96 E-2000 600 610 97 Y-H-*Y 98 584 (0/0… · 2017. 11. 13. · Y 3—0) PET, Y + Z O)ftþ 94 95 96 E-2000 600 610 97 Y-H-*Y 98 584 (0/0) 50

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X= {x 0, x 1,….,x J-1 } Y= {y 0, y 1, ….,y K-1 } Channel Finite set of input (X= {x 0, x 1,….,x J-1 }), and output (Y= {y 0, y 1,….,y K-1 }) alphabet.

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実施設計db.pref.tottori.jp/HacchuKoukai.nsf...Y = 1 0 0 Y = 1 0 0 0 Y = 1 1 0 Y = 1 1 0 0 Y = 1 2 0 0 Y = 1 2 0 0 Y = 1 3 0 0 Y = 1 4 0 0 X = - 4 6 00 0 X =-X-4 5 90 0 X =-X =-4

実施設計db.pref.tottori.jp/HacchuKoukai.nsf...Y = 1 0 0 Y = 1 0 0 0 Y = 1 1 0 Y = 1 1 0 0 Y = 1 2 0 0 Y = 1 2 0 0 Y = 1 3 0 0 Y = 1 4 0 0 X = - 4 6 00 0 X =-X-4 5 90 0 X =-X =-4

Hashing algorithms & password cracking · Brute force attack Password length 6 y d h m 26 0 0 0 0 36 0 0 0 0 62 0 0 0 0 95 0 0 0 3 7 y d h m 0 0 0 0 0 0 0 0 0 0 0 14 0 0 4 50 8 y

Hashing algorithms & password cracking · Brute force attack Password length 6 y d h m 26 0 0 0 0 36 0 0 0 0 62 0 0 0 0 95 0 0 0 3 7 y d h m 0 0 0 0 0 0 0 0 0 0 0 14 0 0 4 50 8 y

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BOT Oct 6th Agenda - Providence Hallprovidencehall.com/dynamic/content/1048/543/bot_oct_6th...0 1 1 y 2 126 125 335 1 0 2 y 3 125 365 0 0 0 y 4 150 125 325 25 0 0-d: ys y 5 175 125

cv - მთავარიprocurement.gov.ge/files/_data/geo/whitelist/20131119_n... · 2014-12-26 · J['183060011m0301l 0(Y)lID0(Y)OOa06do~%D 006b(Y)(Y)GOD~D0'J~0 0J311a(Y)030~0

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Color Scheme Primary Color: C-80 M-90 Y-0 K-10 Gray Colors(C=0 M=0 Y=0): Color 1: K = 46 C=0 M=0 Y=0 K=46 Color 2: K = 29 C=0 M=0 Y=0 K=29 Color 4: K.

Color Scheme Primary Color: C-80 M-90 Y-0 K-10 Gray Colors(C=0 M=0 Y=0): Color 1: K = 46 C=0 M=0 Y=0 K=46 Color 2: K = 29 C=0 M=0 Y=0 K=29 Color 4: K.

DETAIL TEACHING SCHEME · CP200 Service Oriented Architecture 3 0 2 4 Y Y CP115 Cryptography and Network Security 3 0 2 4 Y Y Elective I 3 0 2 4 Y Y Elective II 3 0 2 4 Y Y Total

DETAIL TEACHING SCHEME · CP200 Service Oriented Architecture 3 0 2 4 Y Y CP115 Cryptography and Network Security 3 0 2 4 Y Y Elective I 3 0 2 4 Y Y Elective II 3 0 2 4 Y Y Total

Unit 5 x -5 0 510 0 y 20 x -5 0 510 0 y 20 x -5 0 510 0 y 20 x -5 0 510 0 y 20 Check this 10.00 = 10(1.1) 0 = 10(1+.1) 0 11.00 = 10(1.1) 1 = 10(1+.1) 1.

Unit 5 x -5 0 510 0 y 20 x -5 0 510 0 y 20 x -5 0 510 0 y 20 x -5 0 510 0 y 20 Check this 10.00 = 10(1.1) 0 = 10(1+.1) 0 11.00 = 10(1.1) 1 = 10(1+.1) 1.

Optimal Design of Micro-Seismic Monitoring Array and ...0 = (x 0 x i)2 +(y 0 y i)2 +(z 0 z i)2 v(x 0,y 0,z 0) (1) Where x 0, y 0 and z 0 are the hypocenter coordinates, t 0 is the

Optimal Design of Micro-Seismic Monitoring Array and ...0 = (x 0 x i)2 +(y 0 y i)2 +(z 0 z i)2 v(x 0,y 0,z 0) (1) Where x 0, y 0 and z 0 are the hypocenter coordinates, t 0 is the

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kamran/EE3301/class notes/ch7.pdf · y(t) = y transient + y steady state for t 0 y transient =[y(0) y( )]e t/ y steady state = y( ) for t 0 y transient = y(0)e t/ y( )e t/ for t 0

kamran/EE3301/class notes/ch7.pdf · y(t) = y transient + y steady state for t 0 y transient =[y(0) y( )]e t/ y steady state = y( ) for t 0 y transient = y(0)e t/ y( )e t/ for t 0

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Product selection guide - Petrolvalves · cool gray 2 0 C 0 M 0 Y 0 K 0 C 0 M 0 Y 25 K 0 C 0 M 0 Y 0 K. 1956. 1968. 1970. 1980 /90. 1964. PetrolValves . is founded as a metalworking

Product selection guide - Petrolvalves · cool gray 2 0 C 0 M 0 Y 0 K 0 C 0 M 0 Y 25 K 0 C 0 M 0 Y 0 K. 1956. 1968. 1970. 1980 /90. 1964. PetrolValves . is founded as a metalworking

SENIOR MEN RESULTS / PLACINGS me t y e y y n inn u ... · u/60 AIBERTI Luca AUS VIC Y 0 0 u/60 TANDEAN Bjorn AUS NSW Y 0 0 0 u/60 SADELI Indra AUS NSW Y 0 u/60 CAULEY Harry AUS QLD

SENIOR MEN RESULTS / PLACINGS me t y e y y n inn u ... · u/60 AIBERTI Luca AUS VIC Y 0 0 u/60 TANDEAN Bjorn AUS NSW Y 0 0 0 u/60 SADELI Indra AUS NSW Y 0 u/60 CAULEY Harry AUS QLD

6.641 Electromagnetic Fields, Forces, and Motion · Ky1 x +∞ =− 0 tan −1 2π y y x=−∞ ⎧ K ⎪− 0 y > 0 ⎪ 2 =⎨ ⎪+ K 0 y < 0 ⎪⎩ 2 Check boundary condition

6.641 Electromagnetic Fields, Forces, and Motion · Ky1 x +∞ =− 0 tan −1 2π y y x=−∞ ⎧ K ⎪− 0 y > 0 ⎪ 2 =⎨ ⎪+ K 0 y < 0 ⎪⎩ 2 Check boundary condition

Basic Logical Operations fascinatingpages.cpsc.ucalgary.ca/~tamj/2002/231P/notes/numbers/logic.pdf · Y X Y Logic gate Truth table 1 1 1 1 0 0 0 1 0 0 0 0 X Y X AND Y. James Tam Logical

Basic Logical Operations fascinatingpages.cpsc.ucalgary.ca/~tamj/2002/231P/notes/numbers/logic.pdf · Y X Y Logic gate Truth table 1 1 1 1 0 0 0 1 0 0 0 0 X Y X AND Y. James Tam Logical