A quick and easy guide to naming and writing them

Multivalent ions

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Multivalent: multi (more than one) + valent

(number of valence electrons) AKA. Multiple Charges

What are multivalent ions?

Atomic Number (# p+)

Symbol

Name

Atomic Mass

Ion ChargeMultivalent = 4+ or 3+

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Transition Metals

More common ones

Iron (Fe) 3+ or 2+ Lead (Pb) 2+ or 4+ Nickel (Ni) 2+ or 3+ Copper (Cu) 2+ or1+ Gold (Au) 3+ or 1+

MultiValent Ions

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Numerals are used when indicating an ion’s charge.

Distinguishing charges

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Examples:

Fe 3+ iron (III)

Cu 1+ copper (I)

Examples of multivalent charges

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Example: Au3N

1.Identify the metal and list the possible charges1. Au = 3+ or 1+

2.Identify the non-metal and it’s charge1. N = 3-

3.Notice how many ions of each you have1. 3 Au ions AND 1 N ion

4.Figure out what charge needs to be used so that the positive and negative charges balance out

1. 3 Au ions = +1 +1 +1 = +3 1 N ion = -3

5.Determine which roman numeral to use for the metal charge1. Au (I)

6.Write the compound name (non-metal suffix is “ide”)1. Gold (I) Nitride

Naming multivalent ions

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Example: PdS2 1.Identify the metal and list the possible charges

1. Pd = 2+ or 4+

2.Identify the non-metal and it’s charge1. S = 2-

3.Notice how many ions of each you have1. 1 Pd ion AND 2 S ions

4.Figure out what charge needs to be used so that the positive and negative charges balance out

1. 1 Pd ion = +4 = +4 2 S ions = -2 -2 = -4

5.Determine which roman numeral to use for the metal charge1. Pd (IV)

6.Write the compound name (non-metal suffix is “ide”)1. Palladium (IV) sulphide

Practice Naming

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Example: manganese (IV) sulfide1.Figure out what these two ions are and write down their charges

a. Manganese (IV) = Mn+4

b. S = S-2

2.Determine how many of each ion you need to balance out the charges

a. Mn+4 = +4b. S-2 = - 2 You will need another ion of S to balance

3.Note the ratio of positive ions to negative ionsa. 1 Mnb. 2 S

4.Write the formula, indicating the number of each ion in a subscript right after if

1. MnS2

Writing formulas

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Example: colbalt (III) oxide

1.Figure out what these two ions are and write down their chargesa. Colbalt (III) = Co+3

b. O = O-2

2.Determine how many of each ion you need to balance out the chargesa. Co+3 = +3 +3 = +6b. O-2 = - 2 -2 -2 = -6

3.Note the ratio of positive ions to negative ionsa. 2 Cob. 3 O

4.Write the formula, indicating the number of each ion in a subscript right after if

a. Co2O3

Practice writing the formula

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The assignment is to be done individually. If you need help, please ask me or Ms. Smith

This is due on Friday, and is for marks!!

Every day late is -1 markTotal is out of…

Assignment #1

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