8th Grade Week 6 - Davison Community Schools · 2020. 4. 27. · The Fiction Partner Challenge -...
Transcript of 8th Grade Week 6 - Davison Community Schools · 2020. 4. 27. · The Fiction Partner Challenge -...
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8th Grade Week 6
ELA, Math and Science
Answer Keys
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The Fiction Partner Challenge - Comprehension Questions Answer Key
1. What does Mrs. Applegate want her students to learn something about by writing a
story together?
A. writing fiction
B. patience
C. teamwork
D. manners
2. Who are the two main characters in this text?
A. Bertram and Glenda
B. Brian and Stacey
C. Brian and Mrs. Applegate
D. Stacey and Mrs. Applegate
3. In the passage, both Brian and Stacy object to the assignment from Mrs. Applegate.
Based on this evidence, what conclusion can be made?
A. They work on projects together every day.
B. Neither wants to work with the other.
C. They're looking forward to working together.
D. They won't have to work together at all.
4. In the passage, Stacey tells Brian "don't screw it up" when it's his turn to write a
sentence. Based on this evidence, what conclusion can be made?
A. Brian does not trust Stacey's writing.
B. Brian and Stacey are working well together.
C. Stacey does not trust Brian's writing.
D. Brian and Stacey have the same story ideas.
5. What is this story mainly about?
A. two students writing a story together
B. how Mrs. Applegate runs her classroom
C. ninjas and robots being part of a wedding
D. the best way to name a story's characters
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The Fiction Partner Challenge - Comprehension Questions Answer Key
6. Read the following sentences: "You say that they're happy and content and joyous.
Those all mean basically the same thing. It's redundant." As used in this sentence, what
does "redundant" mean?
A. simple
B. useful
C. repetitive
D. necessary
7. ________ Brian and Stacy don't want to work together, they still have to complete the
assignment.
Choose the answer that best completes the sentence below.
A. In contrast
B. Especially
C. Because
D. Even though
8. What does Mrs. Applegate think about the story Stacey and Brian wrote together?
Mrs. Applegate thinks the story is "a laugh riot" and worthy of an A+.
9. How does Brian feel about working with Stacey on the story? Use evidence from the
text to support your answer.
Answers may vary slightly. Students should recognize that Brian does not
want to work with Stacey, and does not enjoy working with her. He
complains about working with her at the beginning of the text, and also
voices a negative opinion of her writing. His portions of the story also
indicate that Brian does not agree with Stacey's story ideas.
ReadWorks.org · © 2020 ReadWorks®, Inc. All rights reserved.
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The Fiction Partner Challenge - Comprehension Questions Answer Key
10. Did Brian and Stacey make a good story-writing team? Use evidence from the text to
support your argument.
Answers may vary as long as they are supported with evidence from the
text. Students may argue that Brian and Stacey did make a good story-
writing team, because they rose above their reluctance to work together
and their disagreements about plot and language to create a story. They
followed directions and took turns, and created a story that was "a laugh
riot" and earned an A+.
On the other hand, students may argue that Brian and Stacey did not
make a good story-writing team, because they complained the entire
time they worked together. Although they completed the assignment,
their individual sections of the story showed disdain for the other's
ideas, which is not characteristic of good teamwork. There is no
evidence in the story that their negative feelings about each other's
input changed at all.
ReadWorks.org · © 2020 ReadWorks®, Inc. All rights reserved.
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4/16/2020 Worksheet: Slope and Linear Equations
https://www.helpingwithmath.com/printables/worksheets/equations_expressions/8ee6-slope01.htm 1/4
1. (a) Plot the values from the table on to the coordinate grid below.
X -5 -4 -3 -2 -1 0 1 2 3 4 5
Y -10 -8 -6 -4 -2 0 2 4 6 8 10
1. (b) Write the linear equation that defines the relationship between the X and Yvalues in the form y = mx. y = 2x
2. (a) Plot the values from the table on to the coordinate grid below.
X -3 -2 -1 0 1 2 3
Y -9 -6 -3 0 3 6 9
2. (b) Write the linear equation that defines the relationship between the X and Yvalues in the form y = mx. y = 3x
Plotting and Determine the Equation of a Line (page 1 of 4)
Name:______________________
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4/16/2020 Worksheet: Slope and Linear Equations
https://www.helpingwithmath.com/printables/worksheets/equations_expressions/8ee6-slope01.htm 2/4
3. (a) Plot the values from the table on to the coordinate grid below.
X -6 -4 -2 0 2 4 6
Y -9 -6 -3 0 3 6 9
3. (b) Write the linear equation that defines the relationship between the X and Yvalues in the form y = mx. y = 1.5x
4. (a) Plot the values from the table on to the coordinate grid below.
X -6 -4 -2 0 2 4 6
Y 6 4 2 0 -2 -4 -6
4. (b) Write the linear equation that defines the relationship between the X and Yvalues in the form y = mx. y = -x
Plotting and Determining the Equation of a Line (page 2 of 4)
Name:______________________
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4/16/2020 Worksheet: Slope and Linear Equations
https://www.helpingwithmath.com/printables/worksheets/equations_expressions/8ee6-slope01.htm 3/4
5. (a) Plot the values from the table on to the coordinate grid below.
X -5 -4 -3 -2 -1 0 1 2 3 4 5
Y 10 8 6 4 2 0 -2 -4 -6 -8 -10
5. (b) Write the linear equation that defines the relationship between the X and Yvalues in the form y = mx. y = -2x
6. Use the equation y = 2.5x to complete the table below and plot the values on tothe coordinate grid below.
X -4 -3 -2 -1 0 1 2 3
Y -10 -7.5 -5 -2.5 0 2.5 5 7.5
Plotting and Determining the Equation of a Line (page 3 of 4)
Name:______________________
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4/16/2020 Worksheet: Slope and Linear Equations
https://www.helpingwithmath.com/printables/worksheets/equations_expressions/8ee6-slope01.htm 4/4
7. Drawn a line from each of the linear equations to the graph and slope that theymatch.
y = x/2 y = x y = 2xy = 2x y = x/2 y = x
Plotting and Determining the Equation of a Line (page 4 of 4)
Name:______________________
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Note on the Density Practice Problem Worksheet
Throughout this worksheet, the term “weights” or “weight” is used. It is common for weight
and mass to be confused. While in everyday life, they may mean the same thing, in science they
are very different (yet still often not used correctly).
Mass is the amount of “stuff” that makes up an object. It is measured in grams or kilograms or
even pounds and ounces. The mass of an object remains the same regardless of where it is.
Weight depends on gravity. So, your weight on the moon is less than your weight on Earth
because gravity is less strong on the moon. However, and this is important, your mass on the
moon and your mass on Earth is the same. The unit for weight is Newtons.
As you do this worksheet, just regard every time “weight” or “weigh” is used to mean mass.
The formula for Density = Mass / Volume
Density Practice Problem Worksheet
1) A block of aluminum occupies a volume of 15.0 mL and weighs 40.5 g. What is its density?
Density = Mass / Volume
= 40.5g / 15.0 mL
= 2.7 g/mL
2) Mercury metal is poured into a graduated cylinder that holds exactly 22.5 mL. The mercury used to fill the cylinder weighs 306.0 g. From this information, calculate the
density of mercury.
Density = Mass / Volume
= 306.0 g/ 22.5 mL
= 13.6 g/mL
3) What is the weight of the ethyl alcohol that exactly fills a 200.0 mL container? The density of ethyl alcohol is 0.789 g/mL.
Remember that even though the problem asks for weight, it is really mass that they want
Density = Mass / Volume
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So, Mass = Density x Volume
= 0.789 g/mL x 200.0 mL
= 157.8 g
4) A rectangular block of copper metal weighs 1896 g. The dimensions of the block are 8.4 cm by 5.5 cm by 4.6 cm. From this data, what is the density of copper?
Volume needs to be calculated. You can get the volume by multiplying the sides
of the block
Volume = 8.4 cm x 5.5 cm x 4.6 cm
= 212.52 cm3 (note the unit is now cm3, since the cm unit was
multiplied three times)
Density = Mass / Volume
= 1896 g/ 212.52 cm3
= 8.92 g/cm3
The unit cm3 is read as centimeters cubed or cubic centimeters. If you put down the units for
your answer as g/mL, you are still correct because a 1 cm3 = 1 mL
5) A flask that weighs 345.8 g is filled with 225 mL of carbon tetrachloride. The weight of the flask and carbon tetrachloride is found to be 703.55 g. From this information,
calculate the density of carbon tetrachloride.
If the mass of the flask and the carbon tetrachloride is 703.55 g and the mass of the empty
flask is 345.8 g, then the carbon tetrachloride must be 703.55g – 345.8g = 357.75 g
Density = Mass / Volume
= 357.75 g/ 225 mL
= 1.59 g/mL
6) Calculate the density of sulfuric acid if 35.4 mL of the acid weighs 65.14 g.
Density = Mass / Volume
= 65.14 g/ 35.4 mL
= 1.84 g/mL
7) Find the mass of 250.0 mL of benzene. The density of benzene is 0.8765 g/mL.
You can look at problem #10 if you need
help with rearranging the formula
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Mass = Density x Volume
= 0.8765 g/mL x 250.0 mL
= 219.13 g
8) A block of lead has dimensions of 4.50 cm by 5.20 cm by 6.00 cm. The block weighs 1587 g. From this information, calculate the density of lead.
Just like in problem #4, you will have to calculate the volume first. This is also a block,
so the volume will the product of the sides
Volume = 4.50 cm x 5.20 cm x 6.00 cm
= 140.4 cm3
Density = Mass / Volume
= 1587 g / 140.4 cm3
= 11.3 g/cm3
9) 28.5 g of iron shot is added to a graduated cylinder containing 45.50 mL of water. The water level rises to the 49.10 mL mark, from this information, calculate the
density of iron.
This is a graduated cylinder.
Density = Mass / Volume
= 28.5 g/ 3.6 mL
= 7.92 g/mL
Figuring out the volume of the iron shot
Finding volume using this method of water
displacement with a graduated cylinder is used
often in experiments.
If you have put in 45.50 mL of water and then
drop in the iron shot, the water will naturally
move up in the graduated cylinder. If it goes up
to 49.10 mL, then the volume of the iron shot
must be 49.10 mL – 45.50 mL = 3.6 mL
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10) What volume of silver metal will weigh exactly 2500.0 g. The density of silver is 10.5
g/cm3.
Students sometimes have difficulty rearranging an equation for a variable in the
denominator like volume is in the Density formula. Included below are the steps
to rearrange the density formula to solve for volume.
In problem #10, mass is 2500.0 g and density is 10.5 g/cm3
Volume = Mass/ Density
= 2500.0 g / 10.5 g/cm3
= 238.1 cm3
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Solutions Cloze
A ___solution____ is a special kind of mixture in which one substance is uniformly mixed
into another. Mixtures in which one substance is uniformly mixed into another are called
__homogeneous__ mixtures. Solutions can take many forms such as sugar water, which is a
____solid___ dissolved in a liquid, and carbonated water, which is a ____gas____ dissolved in a
liquid. Solutions can also include mixtures of two liquids like ____alcohol_____ and water, and
mixtures of gases such as air. Solutions even include mixtures of metals and other solids called
__alloys___.
A simple solution is a combination of two substances. One substance called a __solvent___
dissolves the other. The substance that is dissolved is called the __solute___. So for example, in
salt water, __water____ is the solvent and ___salt_____ is the solute.
The amount of solute that can be dissolved be a solvent is called the __solubility___. The
solubility of a solid in a liquid usually increases as the ___temperature___ increases. The
solubility of a gas in a liquid usually increases as the pressure increases.
Going further on solutions
This is a good time to think about the classic definition of a solution. A solution is a
mixture of two (or more) fluids. When we think about the term “fluid”, naturally we think of
liquids but gasses are fluids too. Hence, a solution can be a mixture of two gasses or a liquid and
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a gas as mentioned in the worksheet. It is important to also think about alloys. For two metals to
mix, they have to be melted. So they are in liquid (or fluid) state for them to be able to mix.
The worksheet also mentions that solubility is the amount of solute that can dissolve into
solution and that temperature has a role in this. Consider the following, you are dissolving sugar
in water-making a solution. At a certain point, no matter how much more sugar you add to the
water-the sugar will not dissolve. It will just sit in the bottom on the container. We call this type
of solution a saturated solution. In other words, a saturated solution is holding the maximum
amount of solute that can dissolve in it.
However, if we heat the solution the sugar that was sitting in the container will start to
dissolve. We call this a super-saturated solution. Keep in mind that when the solution cools, that
sugar will end up back on the bottom of the container.
This is how sugar crystals are made. A super-saturated solution of sugar water is allowed
to cool. A string or something like that is placed in the container as it cools and the sugar
crystals form around the sting. If you have ever seen a “grow your own crystal” kit. They work
the same way, allow a super-saturated solution to cool with something in it for crystals to form
on.
8th Grade Week 6 Answer Key Cover Sheet.docx8th Grade Answers Week 6 The Fiction Partner Challengegrade 8- week6- math answers8th grade key science week 6 april 27th 2020