6-Moments Couples and Force Couple Systems_Partb.ppt

download 6-Moments Couples and Force Couple Systems_Partb.ppt

of 37

Transcript of 6-Moments Couples and Force Couple Systems_Partb.ppt

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    1/37

    4.6 Moment due to Force

    Couples

    A Couple is defined as two Forces having the

    same magnitude, parallel lines of action, and

    opposite sense separated by a perpendicular

    distance.

    In this situation, the sum of the forces in each

    direction is zero, so a couple does not affect

    the sum of forces equations A force couple will however tend to rotate the

    body it is acting on

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    2/37

    Moment Due to a Force Couple

    By multiplying the magnitude of one Force by the

    distance between the Forces in the Couple, the

    moment due to the couple can be calculated.

    M = Fdc The couple will create a moment around an axis

    perpendicular to the plane that the couple falls in.

    Pay attention to the sense of the Moment (Right

    Hand Rule)

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    3/37

    Moment of a Couple

    Two couples will have equal moments if

    2211

    dFdF

    the two couples lie in parallel planes, and

    the two couples have the same sense or

    the tendency to cause rotation in the same

    direction.

    Do

    example

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    4/37

    Why do we use Force Couples?

    The reason we use Force Couples to analyze

    Moments is that the location of the axis the

    Moment is calculated about does not matter

    The Moment of a Couple is constant over the

    entire body it is acting on

    Equivalent couplestwo couples that

    produce the same magnitude and direction(example).

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    5/37

    Couples are Free Vectors

    The point of action of a Couple does notmatter

    The plane that the Couple is acting in does

    not matter All that matters is the orientation of the plane

    the Couple is acting in

    Therefore, a Force Couple is said to be aFree Vector and can be applied at any pointon the body it is acting

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    6/37

    Example: Force Couple

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    7/37

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    8/37

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    9/37

    4.7 Simplification of a Force and

    Couple System (Resolution of

    Vectors)

    The Moment due to the Force Couple is

    normally placed at the Cartesian Coordinate

    Origin and resolved into its x, y, and z

    components (Mx, My, and Mz).

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    10/37

    Vector Addition of Couples

    By applying Varignons Theorem to the Forces in the

    Couple, it can be proven that couples can be added

    and resolved as Vectors.

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    11/37

    Force Couple System

    Two opposing force can be added to a rigid bodywithout affecting the equilibrium of it.

    If there is a force acting at a distance from an axis,

    two forces of equal magnitude and oppositedirection can be added at the axis with out affectingthe equilibrium of the rigid body.

    The original force and its opposing force at the axismake a couple that equates to a moment on therigid body.

    The other force at the axis results in the same forceacting on the body

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    12/37

    Force Couple Systems

    As a result of this it can be stated that any

    force (F) acting on a rigid body may be

    moved to any given point on the rigid body as

    long as a moment equal to moment of (F)

    about the axis is added to the rigid body.

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    13/37

    Resolution of a System of

    Forces in 3D

    Each Force can be Resolved into a Force

    and Moment at the point of interest using the

    method just discussed.

    The Resultant Force can then be found by

    Vector Addition.

    The Resultant Moment must also be found

    using Vector Addition.

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    14/37

    SIMPLIFICATION OF FORCE AND COUPLE SYSTEMS

    Objectives:

    :

    a) Determine the effect of moving a

    force.

    b) Find an equivalent force-couplesystem for a system of forces and

    couples.

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    15/37

    READING QUIZ

    1. A general systemof forces and couple moments acting on a

    rigid body can be reduced to a ___ .

    A) single force

    B) single moment

    C) single force and two moments

    D) single force and a single moment

    2. The original force and couple system and an equivalent

    force-couple system have the same _____ effect on a body.

    A) internal B) external

    C) internal and external D) microscopic

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    16/37

    APPLICATIONS

    What are the resultant effects on the persons handwhen the force is applied in these four different ways?

    Why is understanding these difference important when

    designing various load-bearing structures?

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    17/37

    APPLICATIONS (continued)

    Several forces and a couple momentare acting on this vertical section of

    an I-beam.

    For the process of designing the I-

    beam, it would be very helpful if

    you could replace the various forces

    and moment just one force and onecouple moment at point O with the

    same external effect? How will

    you do that?

    | | ??

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    18/37

    SIMPLIFICATION OF FORCE AND COUPLE SYSTEM

    (Section 4.7)

    When a number of forces and couplemoments are acting on a body, it is

    easier to understand their overall effect

    on the body if they are combined into a

    single force and couple moment having

    the same external effect.

    The two force and couple systems are

    called equivalent systemssince they

    have the same externaleffect on thebody.

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    19/37

    MOVING A FORCE ON ITS LINE OF ACTION

    Moving a force from A to B, when both points are on the

    vectors line of action, does not change the external effect.

    Hence, a force vector is called a sliding vector. (But the

    internal effect of the force on the body does depend on where

    the force is applied).

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    20/37

    MOVING A FORCE OFF OF ITS LINE OF ACTION

    When a force is moved, but not along its line of action, there is

    a change in its external effect!Essentially, moving a force from point A to B (as shown above)

    requires creating an additional couple moment. So moving a

    force means you have to add a new couple.

    Since this new couple moment is a free vector, it can beapplied at any point on the body.

    B

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    21/37

    SIMPLIFICATION OF A FORCE AND COUPLE SYSTEM

    When several forces and couple moments

    act on a body, you can move each forceand its associated couple moment to a

    common point O.

    Now you can add all the forces and

    couple moments together and find oneresultant force-couple moment pair.

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    22/37

    If the force system lies in the x-y plane (a 2-D case), then the

    reduced equivalent system can be obtained using the following

    three scalar equations.

    SIMPLIFICATION OF A FORCE AND COUPLE SYSTEM

    (continued)

    WR = W1 + W2(MR)o= W1 d1+ W2 d2

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    23/37

    EXAMPLE #1

    1) Sum all the x and y components of the forces to find FRA.

    2) Find and sum all the moments resulting from moving each

    force component to A.

    3) Shift FRAto a distance d such that d = MRA/FRy

    Given: A 2-D force system

    with geometry as shown.

    Find: The equivalent resultant

    force and couple

    moment acting at A and

    then the equivalentsingle force location

    measured from A.

    Plan:

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    24/37

    EXAMPLE #1

    (continued)

    + FRx

    = 150 (3/5) + 50100 (4/5)

    = 60 lb

    + FRy = 150 (4/5) + 100 (3/5)

    = 180 lb

    + MRA = 100 (4/5) 1100 (3/5) 6

    150(4/5) 3 =640 lbft

    FR= ( 602+ 1802)1/2 = 190 lb

    = tan-1( 180/60) = 71.6

    The equivalent single force FRcan be located at a distance d

    measured from A.

    d = MRA/FRy = 640 / 180 = 3.56 ft.

    FR

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    25/37

    CONCEPT QUIZ

    2. Consider two couplesacting on a body. The simplest possible

    equivalent system at any arbitrary point on the body will have

    A) One force and one couple moment.

    B) One force.

    C) One couple moment.

    D) Two couple moments.

    1. The forces on the pole can be reduced to

    a single force and a single moment at

    point ____ .

    A) P B) Q C) R

    D) S E) Any of these points.

    R

    Z

    S

    Q

    P

    X

    Y

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    26/37

    GROUP PROBLEM SOLVING

    1) Sum all the x and y components of the two forces to find FRA.

    2) Find and sum all the moments resulting from moving each

    force to A and add them to the 45 kN m free moment to find

    the resultant MRA.

    Given:A 2-D force and couple

    system as shown.

    Find: The equivalent resultant

    force and couple

    moment acting at A.

    Plan:

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    27/37

    GROUP PROBLEM SOLVING (continued)

    + Fx = (5/13) 2630 sin 30

    =5 kN

    + Fy =(12/13) 2630 cos 30

    =49.98 kN

    + MRA = {30 sin 30(0.3m)30 cos 30(2m)(5/13) 26 (0.3m)

    (12/13) 26 (6m)45 } = 239 kN m

    Now find the magnitude and direction of the resultant.

    FRA= ( 52+ 49.98 2)1/2= 50.2 kN and = tan-1(49.98/5)

    = 84.3

    Summing the force components:

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    28/37

    ATTENTION QUIZ

    1. For this force system, the equivalent system at P is

    ___________ .

    A) FRP= 40 lb (along +x-dir.) and MRP= +60 ft lb

    B) FRP= 0 lb and MRP= +30 ft lb

    C) FRP= 30 lb (along +y-dir.) and MRP= -30 ft lb

    D) FRP= 40 lb (along +x-dir.) and MRP= +30 ft lb

    P

    1' 1'

    30 lb40 lb

    30 lb

    x

    y

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    29/37

    ATTENTION QUIZ

    2. Consider three couples acting on a body. Equivalent

    systems will be _______ at different points on the body.

    A) Different when located

    B) The same even when located

    C) Zero when located

    D) None of the above.

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    30/37

    Examples: Simplification of a Force and

    Couple System:

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    31/37

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    32/37

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    33/37

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    34/37

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    35/37

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    36/37

  • 8/10/2019 6-Moments Couples and Force Couple Systems_Partb.ppt

    37/37