6. CR 3 Wind Side 1/2
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CR-3 ComputerWind Side
1/2
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1.Given TAS, TC and W/VTAS = 110 ktTC = 090ºW/V = 310º / 30 kt
Find:HW or TWCW (left or right)WCAHDGGS
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TW = 23 kt GS = TAS + TW = 110 + 23 = 133 ktCW = -20 kt (left)
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WCA = -10.5º (left)HDG = TC + WCA = 090º - 10.5º =079.5º
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2.Given WCA, TAS, GS & TC
TAS = 120 ktWCA = -8º (left)GS = 100TC = 200º
Find:HDGHW or TWCW (left or right)W/V
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GS – TAS = 100 – 120 = -20 (HW)HDG = TC + WCA = 200º - 8º = 192º
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CW = -17 kt (left)
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W/V = 157º / 27 kt
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3.FORECAST WINDSGiven:
TAS 180 mphM Course 140ºVariation 10º WW/V 100º / 40 mph
Find: WCA MH GS
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140º - 6º = 134º M H
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TAS – HW = GS
180 – 35 = 145 mph
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Answer:
WCA = 6º left M H = 134º GS = 145 mph
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4.Forecast winds 2nd legGiven:
TAS 180mph MC 186º Variation 11º W W/V 100º/40 mph
Find: WCA MH GS
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M C – WCA (L)= M H
186º - 12º = 174º
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TAS – H W = GSBut WCA exceeds 10º (12º)Use ETAS
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TAS – HW = GS
176 – 10 = 166 mph
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Answer:
WCA = 12º
MH = 174º
GS = 166 mph