57401301 Ch 6 Differential Analysis of Fluid Flow

download 57401301 Ch 6 Differential Analysis of Fluid Flow

of 116

Transcript of 57401301 Ch 6 Differential Analysis of Fluid Flow

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    1/116

    1

    ME 311: Fluid Mechanics

    Differential Analysis

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    2/116

    2

    Course Outline Navier-Stokes equations for Laminar Flow

    Characterization of Laminar and Turbulent Flow Reynold Stresses

    Boundary layer theory

    Flow over flat plate and in pipes

    Lift and Drag Forces

    Applying energy, momentum and continuityequations of Thermofluids to turbo-machinery,

    Performance of Turbo-Machines.

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    3/116

    3

    Recommended Text Books

    1 Fundamentals of Fluid

    Mechanics

    Munson, Young

    & Okiishi

    2 Mechanics of Fluids B. S. Massey

    3. Fluid Mechanics Victor L. Streeter

    and E. Benjamin

    Wylie

    4. Mechanics of Fluids Merle C. Potter;

    David C. Wiggert

    5 Introduction to Fluid

    Mechanics

    Robert W. Fox ;

    Alan T.

    McDonald

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    4/116

    4

    General Classroom Rules

    Mutual respect (golden rule)

    Punctuality

    Minimal disturbance to fellow students and teacher

    Turn off your cell phone

    No chewing /tobacco

    Questions are encouraged

    No question is stupid

    Your question is valuable to others in learning

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    5/116

    5

    My Preference

    Learning happens both inside and

    outside the classroom

    Inside classroom: interactive,participation

    Outside classroom: Any time

    Welcome feedback anytime during the

    quarter (class format/materials/pace)

    you are welcome to come to see me /

    call me any time any where.

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    6/116

    6

    Outline

    Introduction

    Kinematics Review Conservation of Mass

    Stream Function

    Linear Momentum Inviscid Flow

    Viscous Flows

    Navier-Stokes Equations

    Exact Solutions

    Intro. to Computational Fluid Dynamics

    Examples

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    7/116

    7

    Differential Analysis: Introduction

    Some problems require more detailed analysis.

    We apply the analysis to an infinitesimal control

    volume or at a point. The governing equations are differential equations

    and provide detailed analysis.

    Around only 80 exact solutions to the governingdifferential equations.

    We look to simplifying assumptions to solve theequations.

    Numerical methods provide another avenue forsolution (Computational Fluid Dynamics)

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    8/116

    8

    Kinematic Velocity FieldContinuum Hypothesis: the flow is made of tightly packed fluid particles that

    interact with each other. Each particle consists of numerous molecules, and we

    can describe velocity, acceleration, pressure, and density of these particles at a

    given time.

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    9/116

    9

    Kinematic Acceleration FieldLagrangian Frame:

    Eulerian Frame: we describe the acceleration in terms of position and time

    without following an individual particle. This is analogous to describing the

    velocity field in terms of space and time.

    A fluid particle can accelerate due to a change in velocity in time (unsteady)

    or in space (moving to a place with a greater velocity).

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    10/116

    10

    Kinematic Acceleration Field: Material (Substantial) Derivative

    time dependence spatial dependence

    We note:

    Then, substituting:

    The above is good for any fluid particle, so we drop A:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    11/116

    11

    Kinematic Acceleration Field: Material (Substantial) Derivative

    Writing out these terms in vector components:

    x-direction:

    y-direction:

    z-direction:

    Writing these results in short-hand:

    where,

    kz

    jy

    ix

    ()

    ,

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    12/116

    12

    Kinematics: Deformation of a Fluid Element

    General deformation of fluid element is rather complex, however, we can

    break the different types of deformation or movement into a

    superposition of each type.

    Linear Motion Rotational Motion

    Linear deformation Angular Deformation

    General

    Motion

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    13/116

    13

    Kinematics: Linear Motion and DeformationLinear Motion/Translation due to u and vvelocity:

    Simplest form of motion the element

    moves as a solid body. Unlikely to be the

    only affect as we see velocity gradients inthe fluid.

    Deformation: Velocity gradients can cause deformation, stretching

    resulting in a change in volume of the fluid element.

    Rate of Change for one direction:

    For all 3 directions: The shape does not change, linear deformation

    The linear deformation is zero for incompressible fluids.

    = 0

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    14/116

    14

    Kinematics:Angular Motion and DeformationAngular Motion/Rotation:

    Angular Motion results from

    cross derivatives.

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    15/116

    15

    Kinematics:Angular Motion and Deformation

    The rotation of the element about the z-axis is the average of the angular

    velocities :

    Likewise, about the y-axis, and the x-axis:

    Counterclockwise rotation is considered positive.

    and

    The three components gives the rotation vector:

    Using vector identities, we note, the rotation vector is one-half the curl of the

    velocity vector:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    16/116

    16

    Kinematics:Angular Motion and Deformation

    The definition, then of the vector operation is the following:

    The vorticity is twice the angular rotation:

    Vorticity is used to describe the rotational characteristics of a fluid.The fluid only rotates as and undeformed block when ,

    otherwise, the rotation also deforms the body.

    If , then there is no rotation, and the flow is said to be irrotational.

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    17/116

    17

    Kinematics:Angular Motion and Deformation

    Angular deformation:

    The associated rotation gives rise to angular deformation, which results in the

    change in shape of the element

    Shearing Strain:

    Rate of Shearing Strain:

    If , the rate of shearing strain is zero.

    The rate of angular deformation is related to the shear stress.

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    18/116

    18

    Conservation of Mass: Cartesian Coordinates

    System: Control Volume:

    Now apply to an infinitesimal control volume:

    For an infinitesimal control volume:

    Now, we look at the mass flux in the x-direction:

    Out: In:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    19/116

    19

    Conservation of Mass: Cartesian Coordinates

    Net rate of mass in the outflow y-direction:

    Net rate of mass in the outflow z-direction:

    Net rate of mass in the outflow x-direction:

    Net rate of mass flow for all directions:

    +

    Now, combining the two parts for the infinitesimal control volume:

    = 0

    Divide out

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    20/116

    20

    Conservation of Mass: Cartesian CoordinatesFinally, the differential form of the equation for Conservation of Mass:

    a.k.a. The Continuity Equation

    In vector notation, the equation is the following:

    If the flow is steady and compressible:

    If the flow is steady and incompressible:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    21/116

    21

    Conservation of Mass: Cylindrical-Polar Coordinates

    If the flow is steady and compressible:

    If the flow is steady and incompressible:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    22/116

    22

    Conservation of Mass: Stream Functions

    Stream Functions are defined for steady, incompressible, two-dimensional flow.

    Continuity:

    Then, we define the stream functions as follows:

    Now, substitute the stream function into continuity:

    It satisfies the continuity condition.

    The slope at any point along a streamline:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    23/116

    23

    Conservation of Mass: Stream Functions

    Streamlines are constant, thus d = 0:

    Now, calculate the volumetric flow rate between streamlines:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    24/116

    24

    Conservation of Mass: Stream Functions

    In cylindrical coordinates:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    25/116

    25

    Conservation of Linear Momentum

    P is linear momentum,System:

    ControlVolume:

    We could apply either approach to find the differential form. It turns out the System

    approach is better as we dont bound the mass, and allow a differential mass.

    By system approach,m is constant.

    If we apply the control volume approach to an infinitesimal control volume, wewould end up with the same result.

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    26/116

    26

    Conservation of Linear Momentum: Forces Descriptions

    Body forces or surface forces act on the differential element: surface forces act

    on the surface of the element while body forces are distributed throughout the

    element (weight is the only body force we are concerned with).

    Body Forces:

    Surface Forces: Normal Stress:

    Shear Stress:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    27/116

    27

    Conservation of Linear Momentum: Forces Descriptions

    Looking at the various sides of the differential element, we must usesubscripts to indicate the shear and normal stresses (shown for an x-face).

    The first subscript indicates the plane on which the stress acts

    and the second subscript the direction

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    28/116

    28

    Conservation of Linear Momentum: Forces

    Descriptions

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    29/116

    29

    Now, the surface forces acting on a small cubicle element in each

    direction.

    Then the total forces:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    30/116

    30

    Conservation of Linear Momentum: Equations of Motion

    Now, we both sides of the equation in the system approach:

    In components:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    31/116

    31

    Conservation of Linear Momentum: Equations of Motion

    Writing out the terms for the Generalize Equation of Motion:

    The motion is rather complex.

    Material derivative foraForce Terms

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    32/116

    32

    Inviscid Flow

    An inviscid flow is a flow in which viscosity effects or shearing effects become

    negligible.

    If this is the case,

    And, we define

    A compressive force give a positive pressure.

    The equations of motion for this type of flow then becomes the following:

    Eulers

    Equations

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    33/116

    33

    Inviscid Flow: Euler s Equations

    Leonhard Euler

    (1707 1783)

    Famous Swiss mathematician who pioneered work on the

    relationship between pressure and flow.

    In vector notation Eulers Equation:

    The above equation, though simpler than the generalized equations, are still

    highly non-linear partial differential equations:

    There is no general method of solving these equations for an analytical solution.

    The Eulers equation, for special situations can lead to some useful information

    about inviscid flow fields.

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    34/116

    34

    Surface Stress Terms for a General Newtonian Fluid

    General Stress Elements:

    Normal Stresses:

    Shear Stresses:

    Note, and is known as the second viscosity coefficient

    is the viscosity of the fluid and for the general form is allowed to be non-constant.

    xxxx p

    yyyy p

    zzzz p

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    35/116

    35

    Viscous Flows: Surface Stress Terms

    Now, we allow viscosity effects for an incompressible Newtonian Fluid:

    Normal Stresses:

    Shear Stresses:

    Cartesian

    Coordinates:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    36/116

    36

    Viscous Flows: Surface Stress Terms

    Normal Stresses:

    Shear Stresses:

    Cylindrical

    Coordinates:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    37/116

    37

    Viscous Flows: Navier-Stokes Equations

    Now plugging the stresses into the differential

    equations of motion for incompressible flow giveNavier-Stokes Equations:

    French Mathematician, L. M. H. Navier (1758-1836) andEnglish Mathematician Sir G. G. Stokes (1819-1903)

    formulated the Navier-Stokes Equations by including

    viscous effects in the equations of motion.

    L. M. H. Navier(1758-1836)

    Sir G. G. Stokes(1819-1903)

    (x direction)

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    38/116

    38

    Viscous Flows: Navier Stokes Equations

    Local Acceleration Advective Acceleration

    (non-linear terms)

    Pressure term Weight term

    Viscous terms

    Terms in the x-direction:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    39/116

    39

    Viscous Flows: Navier-Stokes Equations

    The governing equations can be written in cylindrical coordinates as well:

    (r-direction)

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    40/116

    40

    Viscous Flows: Navier-Stokes Equations

    There are very few exact solutions to Navier-Stokes Equations, maybe a

    total of 80 that fall into 8 categories. The Navier-Stokes equations are

    highly non-linear and are difficult to solve.

    Some simple exact solutions presented in the text are the following:

    1. Steady, Laminar Flow Between Fixed Parallel Plates

    2. Couette Flow3. Steady, Laminar Flow in Circular Tubes

    4. Steady, Axial Laminar Flow in an Annulus

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    41/116

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    42/116

    42

    4

    Assumptions:

    1. Plates are infinite and parallel/horizontal

    2. The flow is steady and laminar3. Fluid flows 2D, in the x-direction only u=u(y)

    only, v and w = 0

    4. Fully develop

    5. 5. Incompressible

    32

    2

    21

    3

    3

    333

    33 3

    33 4

    3

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    43/116

    43

    Viscous Flows: Exact Solutions/Parallel Plate Flow

    Navier-Stokes Equations Simplify Considerably:

    Applying Boundary conditions (no-slip conditions at y = h) and solve:

    The pressure gradient must be specified and is

    typically constant in this flow! The sign is

    negative.

    (Integrate Twice)

    3 3

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    44/116

    44

    Viscous Flows: Exact Solutions/Parallel Plate Flow

    Solution is Parabolic:

    Can determine Volumetric Flow Rate:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    45/116

    45

    Viscous Flows: Exact Solutions/Parallel Plate Flow

    Navier-Stokes Equations Simplify Considerably:

    Applying Boundary conditions (no-slip conditions at y = h) and solve:

    The pressure gradient must be specified and is

    typically constant in this flow! The sign is

    negative.

    (Integrate Twice)

    3 3

    Solution of flow between two flat plates (Couette flow)

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    46/116

    46

    Solution of flow between two flat plates (Couette flow)

    The differential equation may be solved by integration

    2

    2

    1d u dpdy dydy dx

    Hence 1du dp y Ady dx

    And a further integration wrt y yields21

    2

    dp yu Ay B

    dx

    Boundary conditions

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    47/116

    47

    Boundary conditions

    Due to molecular bonding between the fluid and the wall

    it may be assumed that the fluid velocity on the wall is zero

    u=0 at y=0u=0 at y=c

    This is known as the no-slip condition.

    To satisfy the first boundary condition, B=0Then the second b.c. gives

    210

    2

    dpcAc

    dx

    1

    2

    dp cA

    dx

    Quadratic velocity profile for flow in a channel

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    48/116

    48

    Quadratic velocity profile for f low in a channel

    Substituting the values for A and B into the previous

    equation gives the quadratic equation:

    212

    dpu y ycdx

    For a long, straight channel, of length l, p decreases

    with length at a constant rate, so

    dp p

    dx l

    21

    2

    pu y yc

    l

    Graph of velocity profile

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    49/116

    49

    G ap o e oc y p o e

    0

    0.2

    0.4

    0.6

    0.8

    1

    0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1

    y

    u

    Volume flow rate

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    50/116

    50

    Volume flow rate

    To calculate the volume flow rate, integrate from y=0 to y=c

    y=0

    y=c

    dy

    dq udy 202

    cp

    q yc y dy

    l

    3

    12

    c pq

    l

    per unit width (z direction)

    Maximum and mean velocity

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    51/116

    51

    y

    Max velocity occurs at y=c/2, the centre of the channel

    2

    max8

    c pu l

    Mean velocity is gained by dividing the flow rate by the

    channel width

    /u q c

    2

    max

    2

    12 3

    c pu u

    l

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    52/116

    52

    Viscous Flows: Exact Solutions/Couette FlowAgain we simplify Navier-Stokes Equations:

    Same assumptions as before except the no-slip

    condition at the upper boundary is u(b) = U.

    Solving,

    If there is no Pressure Gradient:

    The termDetermines effects of

    pressure gradient

    Dimensionless,

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    53/116

    53

    Viscous Flows: Exact Solutions/Pipe Flow

    Assumptions:

    Steady Flow and Laminar FlowFlow is only in the z-direction

    vz = f(r)

    Navier-Stokes

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    54/116

    54

    Note that exactly the same result for the velocity

    distribution could be derived by solving the Navier-

    Stokes equations in radial coordinates.

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    55/116

    Cylindrical Coordinates

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    56/116

    56

    Cylindrical Coordinates

    The Navier-Stokes equation in the r-direction is:

    rzrr

    r

    z

    rr

    r

    r

    g

    z

    vv

    r

    v

    rr

    rv

    rrr

    p

    z

    vv

    r

    vv

    r

    v

    r

    vv

    t

    v

    2

    2

    22

    2

    2

    2

    21)(1

    Cylindrical Coordinates

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    57/116

    57

    Cylindrical Coordinates

    The Navier-Stokes equation in the -direction is:

    gz

    vv

    r

    v

    rr

    rv

    rr

    p

    r

    z

    v

    vr

    vvv

    r

    v

    r

    v

    vt

    v

    r

    z

    r

    r

    2

    2

    22

    2

    2

    21)(11

    Cylindrical Coordinates

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    58/116

    58

    y

    The Navier-Stokes equation in the z-direction is:

    zzzz

    z

    z

    zz

    r

    z

    gz

    vv

    rr

    vr

    rrz

    p

    z

    v

    v

    v

    r

    v

    r

    v

    vt

    v

    2

    2

    2

    2

    2

    11

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    59/116

    59

    We will return to the pipe flow problem from the start ofthe lecture and solve it using the Navier-Stokes

    equations.

    Continuity:

    0

    0

    v

    vr

    01)(1

    z

    vv

    rr

    rv

    rzr

    0 0

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    60/116

    60

    r-direction Navier-Stokes:

    0

    21)(1

    2

    2

    2

    2

    22

    2

    2

    2

    z

    v

    r

    p

    gzvv

    rv

    rrrv

    rrrp

    zvv

    rvv

    rv

    rvv

    tv

    z

    rzrr

    rz

    rrr

    r

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    61/116

    61

    -direction Navier-Stokes:

    0

    21)(112

    2

    22

    2

    2

    p

    gzvv

    rv

    rrrv

    rrp

    r

    z

    vv

    r

    vvv

    r

    v

    r

    vv

    t

    v

    r

    zr

    r

    z direction Navier Stokes

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    62/116

    62

    z-direction Navier-Stokes

    zz

    zzzz

    zz

    zzr

    z

    gr

    vr

    rrz

    p

    gzvv

    rrvr

    rrzp

    zvvv

    rv

    rvv

    tv

    2

    2

    2

    2

    211

    Integrate:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    63/116

    63

    Integrate:

    2

    2

    1

    1

    1

    2

    4

    00

    2

    2

    cr

    gL

    ppv

    ratfinite

    r

    vkeeptoc

    r

    v

    r

    crgL

    pp

    rvrcrg

    Lpp

    gr

    vr

    rrz

    p

    zoL

    z

    z

    zzoL

    zz

    oL

    zz

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    64/116

    64

    Viscous Flows: Exact Solutions/Pipe Flow

    Solving the equations with the no slip

    conditions applied at r = R (the walls of the

    pipe).

    Parabolic Velocity Profile

    Viscous Flows: Exact Solutions/Pipe Flow

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    65/116

    65

    Viscous Flows: Exact Solutions/Pipe Flow

    The volumetric flow rate:

    The mean velocity:

    Pressure drop per length of pipe:

    The maximum velocity:

    Non-Dimensional velocity profile:

    For Laminar Flow:

    Substituing Q,

    Conservation of Energy

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    66/116

    66

    gy

    The energy equation is developed similar to the momentum equation for aninfinitesimal control volume.

    Conservation of Energy

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    67/116

    67

    The energy equation is developed similar to the momentum equation for an

    infinitesimal control volume.

    (Heat and Work)

    Internal Kinetic Potential

    (Time rate of change

    following the particle)

    Differentiate:To get the L.H.S:

    Now for the R.H.S., define the fluid properties of Heat and Work:

    Heat Conduction into the element, Fouriers Law

    Heat per Unit Area

    Heat:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    68/116

    68

    Conservation of Energy

    Now, we do a control volume analysis on our control element:

    Heat Flow into the left x-face of the element

    Heat Flow out of the right x-face of the element

    The above can be written for all six faces of the cube with the net result

    between the in and out:

    The net heat flow is transferred to the element, neglecting production terms

    Heat: Heat Conduction into the element, Fouriers Law

    Heat per Unit Area

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    69/116

    69

    Conservation of EnergyWork: Work is done on the element per unit area.

    on the left x-face

    on the right x-face

    We can do the same for the other faces, and the net rate of work done is:

    In condensed form:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    70/116

    70

    Conservation of EnergyWe can rewrite the equation using and identity:

    We note, then, that from the momentum equation:

    Now, the rate of change of work is the following:

    Kinetic Potential

    =

    Now, when we substitute work and heat back into the governing equation:

    We note potential and kinetic energy portions cancelled on each side!

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    71/116

    71

    Conservation of EnergyNow, we can split the stress tensor into pressure and viscous terms:

    Using continuity, we can rewrite the pressure term:

    Now, rewriting the Conservation of Energy:

    Noting, the definition of fluid enthalpy:

    And, defining the dissipation function:

    This term always takes energy from the flow!

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    72/116

    72

    Conservation of EnergyWriting out the terms of Viscous Dissipation for a Newtonian Fluid:

    Now, with the substitutions, the energy equation take the following form:

    We note,

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    73/116

    73

    Conservation of Energy

    Now, lets assume the flow is incompressible:

    Enthalpy:

    Then,

    If the flow velocity is low relative to Heat Transfer then terms of order

    U disappear.

    is the thermal expansion coefficient, for aper fect gas the second term goes to zero!

    If, we assume constant thermal conductivity:

    Heat Convection Equation

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    74/116

    74

    Summary of Governing Equations

    Mass:

    Momentum:

    Energy:

    Most General forms of the Equations:

    Only Assumptions:

    (1) The fluid is a continuum

    (2) the particles are essentially in thermodynamics equilibrium

    (3) Only body forces are gravity

    (4) The Heat conduction follows Fouriers Law

    (5) There are no internal heat sources.

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    75/116

    75

    Summary of Governing Equations

    Some general comments on the general form of the governing equations:

    1. They are a coupled system of non-linear partial differential equations

    you must solve energy, continuity, and linear momentumsimultaneously. No closed form solution exists!

    2. For Newtonian flow, the shear and normal stresses can be written in

    terms of the velocity gradients introducing no new unknowns.

    3. There appear to be five equations and nine unknowns in the system of

    equations: , k, p, u, v, w, h, and T.4. However, we note the following:

    5. Now, we have five unknowns and five equations

    ),(),,(

    ),(),,(

    TpkkTphh

    TpTp

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    76/116

    76

    Summary of Governing EquationsIn, general in Fluid Mechanics/CFD we often work with a simplified form of the

    equations known as the Navier-Stokes Equations:

    Additional Assumptions:

    (1) The fluid is Newtonian(2) Incompressible

    (3) Constant properties (k, )

    where,

    uncoupled equations: The fluid flowcan be solved independent of the Heat

    Transfer

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    77/116

    77

    Summary of Governing EquationsSome general comments on the Navier-Stokes governing equations:

    1. They are non-linear partial differential equations which are uncoupled

    in energy, and linear momentum. We can solve linear momentum andcontinuity equations separately for the flow field without knowledge of

    the Temperature field (4 Equations, 4 unknowns, u, v, w, p).

    2. For Newtonian flow, the shear and normal stresses can be written in

    terms of the velocity gradients introducing no new unknowns.

    3. There appear to be five equations and 5 unknowns in the system of

    equations: p, u, v, w, and T.

    4. If the convective term disappears we have a linear solution.

    5. If the convective term remains we have a non-linear solution.

    6. The Energy equations relies on the solution of the flow field for itssolution.

    Viscous Flow Equations

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    78/116

    78

    Summary of Governing EquationsSummary of the Euler form of the governing equations: Inviscid Flow Equations

    Linear Momentum:

    Continuity and Energy are the same as for Navier-Stokes Equations

    Some general remarks:

    (1) The system of equations have five unknowns and five equations (same as

    Navier-Stokes)

    (2) Flow is Inviscid (frictionless), Pressure is the only normal stress, and

    there are no shear stresses.

    (3) A specialized case of inviscid flow is irrotational flow.(4) The energy and momentum equations are also uncoupled in this set of

    equations.

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    79/116

    79

    Physical Boundary ConditionsTypes of Boundary Conditions: Fluid/Gas-Solid Interface

    Fluid-Fluid Interface

    Gas-Fluid Interface

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    80/116

    80

    Physical Boundary Conditions

    No Slip Condition:

    At the fluid-boundary interface the velocities must be equal. If the boundary

    is stationary, then u, v, w = 0.

    The temperature of the fluid has to equal the temperature

    of boundary at the interface.

    Heat Flux in the fluid must equal the heat flux of the solid at the interface

    At a solid boundary:

    No Temperature Jump:

    Equality of Heat Flux:

    Examples:

    Stationary Solid BoundaryMoving Boundary:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    81/116

    81

    Computational Fluid Dynamics: Differential AnalysisGoverning Equations:

    Navier-Stokes:

    Continuity:The above equations can not be solved for most practical problems with analytical

    methods so Computational Fluid Dynamics or experimental methods are

    employed.

    The numerical methods employed are the following:1. Finite difference method

    2. Finite element (finite volume) method

    3. Boundary element method.

    These methods provide a way of writing the governing equations in discreteform that can be analyzed with a digital computer.

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    82/116

    82

    Computational Fluid Dynamics: Finite ElementThese methods discretize the domain of the flow of interest (Finite Element

    Method Shown):

    The discrete governing equations are solved in every element. This

    method often leads to 1000 to 10,000 elements with 50,000 equationsor more that are solved.

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    83/116

    83

    Computational Fluid Dynamics: Finite DifferenceThese methods discretize the domain of the flow of interest as well (FiniteDifference Method Shown):

    Finite Difference Mesh:

    Comparison between

    Experiment and CFD

    Analysis:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    84/116

    84

    Computational Fluid Dynamics: Pitfalls

    Numerical Solutions can diverge or exhibit unstable wiggles.

    Finer grids may cause instability in the solution rather than better

    results.

    Large flow domains can be computationally intensive.

    Turbulent flows have yet to be well described with CFD.

    Inviscid Flow: Bernoull i Equation

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    85/116

    85

    Daniel Bernoulli

    (1700-1782)

    Earlier, we derived the Bernoulli Equation from a direct

    application of Newtons Second Law applied to a fluid particle

    along a streamline.

    Now, we derive the equation from the Euler Equation

    First assume steady state:

    Select, the vertical direction as up, opposite gravity:

    Use the vector identity:

    Now, rewriting the Euler Equation:

    Rearrange:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    86/116

    86

    Inviscid Flow: Bernoulli EquationNow, take the dot product with the differential length ds along a streamline:

    ds and Vare parrallel, , is perpendicular to V, and thus to ds.

    We note,

    Now, combining the terms:

    Integrate:

    Then,1) Inviscid flow

    2) Steady f low

    3) Incompressible flow

    4) Along a streamline

    I i id Fl I t ti l Fl

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    87/116

    87

    Inviscid Flow: Irrotational FlowIrrotational Flow: the vorticity of an irrotational flow is zero.

    = 0

    For a flow to be irrotational, each of the vorticity vector components must be

    equal to zero.

    The z-component:

    The x-component lead to a similar result:

    The y-component lead to a similar result:

    Uniform flow will satisfy these conditions:

    There are no shear forces in irrotational flow.

    Inviscid Flow: Irrotational Flow

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    88/116

    88

    Example flows, where inviscid flow theory can be used:

    Viscous RegionInviscid Region

    Inviscid Flow: Bernoull i Irrotational Flow

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    89/116

    89

    Recall, in the Bernoulli derivation,

    However, for irrotational flow, .

    Thus, for irrotational flow, we do not have to follow a streamline.

    Then,

    1) Inviscid flow

    2) Steady flow

    3) Incompressible flow4) Irrotational Flow

    Potential Flow: Velocity Potential

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    90/116

    90

    For irrotational flow there exists a velocity potential:

    Take one component of vorticity to show that the velocity potential is irrotational:

    Substitute u and v components:

    02

    1 22

    xyyx

    we could do this to show all vorticity components are zero.

    Then, rewriting the u,v, and w components as a vector:

    For an incompressible flow:

    Then for incompressible irrotational flow:

    And, the above equation is known as Laplaces Equation.

    Potential Flow: Velocity Potential

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    91/116

    91

    Laplacian Operator in Cartesian Coordinates:

    Laplacian Operator in Cylindrical Coordinates:

    Where the gradient in cylindrical coordinates, the gradient operator,

    Then,

    May choose cylindrical

    coordinates based on the

    geometry of the flow problem,

    i.e. pipe flow.

    If a Potential Flow exists, with

    appropriate boundary

    conditions, the entire velocity

    and pressure field can bespecified.

    Potential Flow: Plane Potential Flows

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    92/116

    92

    Laplaces Equation is a Linear Partial Differential Equation, thus there are

    know theories for solving these equations.

    Furthermore, linear superposition of solutions is allowed:

    where andare solutions to Laplaces equation

    For simplicity, we consider 2D (planar) flows:

    Cartesian:

    Cylindrical:

    We note that the stream functions also exist for 2D planar flows

    Cartesian:

    Cylindrical:

    Potential Flow: Plane Potential Flows

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    93/116

    93

    For irrotational, planar flow:

    Now substitute the stream function:

    Then, Laplaces Equation

    For plane, irrotational flow, we use either the potential or the stream function,

    which both must satisfy Laplaces equations in two dimensions.

    Lines of constant are streamlines:

    Now, the change of from one point (x, y) to a nearby point (x + dx, y + dy):

    Along lines of constant we have d = 0,

    0

    Potential Flow: Plane Potential Flows

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    94/116

    94

    Lines of constant are called equipotential lines.

    The equipotential lines are orthogonal to lines of constant , streamlineswhere they intersect.

    The flow net consists of a family of streamlines and equipotential lines.

    The combination of streamlines and equipotential lines are used to visualize a

    graphical flow situation.

    The velocity is inversely proportional

    to the spacing between streamlines.

    Velocity increases

    along this streamline.

    Velocity decreases

    along this streamline.

    Potential Flow: Uniform Flow

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    95/116

    95

    The simplest plane potential flow is a uniform flow in which the streamlines

    are all parallel to each other.

    Consider a uniform flow in the x-direction:Integrate the two equations:

    = Ux + f(y) + C

    = f(x) + C

    Matching the solution

    C is an arbitrary constant, can be set to zero:

    Now for the stream function solution:

    Integrating the two equations similarto above.

    Potential Flow: Uniform Flow

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    96/116

    96

    For Uniform Flow in an Arbitrary direction,

    Potential Flow: Source and Sink Flow

    S Fl

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    97/116

    97

    Source/Sink Flow is a purely radial flow.

    Fluid is flowing radially from a line through

    the origin perpendicular to the x-y plane.

    Let m be the volume rate emanating from the line (perunit length.

    Then, to satisfy mass conservation:

    Since the flow is purely radial:

    Now, the velocity potential can be obtained:

    Integrate

    0If m is positive, the flow is radially outward, source flow.

    If m is negative, the flow is radially inward, sink flow.

    m is the strength of the source or sink!

    This potential flow does not exist at r = 0, the origin, because it is not a real flow, but can

    approximate flows.

    Source Flow:

    Potential Flow: Source and Sink Flow

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    98/116

    98

    0

    Now, obtain the stream function for the flow:

    Then, integrate to obtain the solution:

    The streamlines are radial lines and the equipotentiallines are concentric circles centered about the origin:

    lines

    lines

    Potential Flow: Vortex Flow

    In vortex flow the streamlines are concentric circles and the equipotential

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    99/116

    99

    In vortex flow the streamlines are concentric circles, and the equipotential

    lines are radial lines.

    where K is a constant.

    Solution:

    The sign of K determines whether the flow rotates

    clockwise or counterclockwise.

    In this case, ,

    The tangential velocity varies inversely with the distance from the origin. At the

    origin it encounters a singularity becoming infinite.

    lines

    lines

    Potential Flow: Vortex FlowHow can a vortex flow be irrotational?

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    100/116

    100

    How can a vortex flow be irrotational?

    Rotation refers to the orientation of a fluid element and not the path

    followed by the element.

    Irrotational Flow: Free VortexRotational Flow: Forced Vortex

    Traveling from A to B, consider two sticks

    Initially, sticks aligned, one in the flow direction, and the

    other perpendicular to the flow.

    As they move from A to B the perpendicular-aligned

    stick rotates clockwise, while the flow-aligned stick

    rotates counter clockwise.

    The average angular velocities cancel each other, thus, the

    flow is irrotational.

    Irrotational Flow:

    Velocity

    increases

    inward.

    Velocity

    increases

    outward.

    Rotational Flow: Rigid Body RotationInitially, sticks aligned, one in the flow

    direction, and the other perpendicular to theflow.

    As they move from A to B they sticks move

    in a rigid body motion, and thus the flow is

    rotational.

    i.e., water

    draining from

    a bathtub

    i.e., a rotatingtank filled with

    fluid

    Potential Flow: Vortex Flow

    A bi d t fl i i hi h th i f d t t th d

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    101/116

    101

    A combined vortex flow is one in which there is a forced vortex at the core, and

    a free vortex outside the core.

    A Hurricane is

    approximately a

    combined vortex

    Circulation is a quantity associated with vortex flow. It is defined as the lineintegral of the tangential component of the velocity taken around a closed

    curve in the flow field.

    For irrotational flow the

    circulation is generally

    zero.

    Potential Flow: Vortex Flow

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    102/116

    102

    However, if there are singularities in the flow, the circulation is not zero if the

    closed curve includes the singularity.

    For the free vortex:

    The circulation is non-zero and constant for the free vortex:

    The velocity potential and the stream function can be rewritten in terms of the

    circulation:

    An example in which the closed surface circulation will be zero:

    Beaker Vortex:

    Potential Flow: Doublet FlowCombination of a Equal Source and Sink Pair:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    103/116

    103

    Rearrange and take tangent,

    Note, the following:

    Substituting the above expressions,

    and

    Then,

    If a is small, then tangent of angle is approximated by the angle:

    Potential Flow: Doublet Flow

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    104/116

    104

    Now, we obtain the doublet flow by letting the source and sink approach one

    another, and letting the strength increase.

    K is the strength of the doublet, and is

    equal to ma/is then constant.

    The corresponding velocity potential then is the following:

    Streamlines of a Doublet:

    Potential Flow: Summary of Basic Flows

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    105/116

    105

    Potential Flow: Superposition of Basic Flows

    Beca se Potential Flo s are go erned b linear partial differential eq ations

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    106/116

    106

    Because Potential Flows are governed by linear partial differential equations,

    the solutions can be combined in superposition.

    Any streamline in an inviscid flow acts as solid boundary, such that there is no

    flow through the boundary or streamline.

    Thus, some of the basic velocity potentials or stream functions can be

    combined to yield a streamline that represents a particular body shape.

    The superposition representing a body can lead to describing the flow aroundthe body in detail.

    Superposition of Potential Flows: Rankine Half-Body

    The Rankine Half-Body is a combination of a source and a uniform flow.

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    107/116

    107

    The Rankine Half Body is a combination of a source and a uniform flow.

    Stream Function (cylindrical coordinates):

    Potential Function (cylindrical coordinates):

    There will be a stagnation point, somewhere along the negative x-axis wherethe source and uniform flow cancel (

    For the source: For the uniform flow:

    Evaluate the radial velocity:

    cosUvr

    For Uvr

    Then for a stagnation point, at some r = -b, = :

    2

    mvr and

    Superposition of Potential Flows: Rankine Half-Body

    Now, the stagnation streamline can be defined by evaluating at r = b, and

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    108/116

    108

    Now, the stagnation streamline can be defined by evaluating at r b, and = .

    Now, we note that m/2 = bU, so following this constant streamline givesthe outline of the body:

    Then, describes the half-body outline.

    So, the source and uniform can be used to describe an aerodynamic body.

    The other streamlines can be obtained by setting constant and plotting:

    Half-Body:

    Superposition of Potential Flows: Rankine Half-Body

    The width of the half-body:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    109/116

    109

    The width of the half-body:

    Total width then,

    The magnitude of the velocity at any point in the flow:

    Noting,

    and

    Knowing, the velocity we can now determine the pressure field using the BernoulliEquation:

    Po and U are at a point far away from the body and are known.

    Superposition of Potential Flows: Rankine Half-Body

    Notes on this type of flow:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    110/116

    110

    Notes on this type of flow:

    Provides useful information about the flow in the front part of streamlined body.

    A practical example is a bridge pier or a strut placed in a uniform stream

    In a potential flow the tangent velocity is not zero at a boundary, it slips The flow slips due to a lack of viscosity (an approximation result).

    At the boundary, the flow is not properly represented for a real flow.

    Outside the boundary layer, the flow is a reasonable representation.

    The pressure at the boundary is reasonably approximated with potential flow.

    The boundary layer is to thin to cause much pressure variation.

    Superposition of Potential Flows: Rankine Oval

    Rankine Ovals are the combination a source, a sink and a uniform flow,

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    111/116

    111

    producing a closed body.

    Some equations describing the flow: The body half-length

    The body half-width

    Iterative

    Potential and Stream Function

    Superposition of Potential Flows: Rankine Oval

    Notes on this type of flow:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    112/116

    112

    yp

    Provides useful information about the flow about a streamlined body.

    At the boundary, the flow is not properly represented for a real flow.

    Outside the boundary layer, the flow is a reasonable representation. The pressure at the boundary is reasonably approximated with potential flow.

    Only the pressure on the front of the body is accurate though.

    Pressure outside the boundary is reasonably approximated.

    Superposit ion of Potential Flows: Flow Around a Circular Cylinder

    Combines a uniform flow and a doublet flow:

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    113/116

    113

    and

    Then require that the stream function is constant for r = a, where a is the

    radius of the circular cylinder:

    K = Ua2

    Then, and

    Then the velocity components:

    Superposit ion of Potential Flows: Flow Around a Circular Cylinder

    At the surface of the cylinder (r = a):

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    114/116

    114

    y ( )

    The maximum velocity occurs at the top and bottom of the cylinder,

    magnitude of 2U.

    Superposit ion of Potential Flows: Flow Around a Circular Cylinder

    Pressure distribution on a circular cylinder found with the Bernoulli equation

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    115/116

    115

    Then substituting for the surface velocity:

    Theoretical and experimental agree

    well on the front of the cylinder.

    Flow separation on the back-half in the

    real flow due to viscous effects causes

    differences between the theory and

    experiment.

    Superposit ion of Potential Flows: Flow Around a Circular Cylinder

    The resultant force per unit force acting on the cylinder can be determined

  • 7/29/2019 57401301 Ch 6 Differential Analysis of Fluid Flow

    116/116

    116

    by integrating the pressure over the surface (equate to lift and drag).

    (Drag)

    (Lift)

    Substituting,

    Evaluating the integrals:

    Both drag and lift are predicted to be zero on fixed cylinder in a uniform flow?

    Mathematically, this makes sense since the pressure distribution is

    symmetric about cylinder, ahowever, in practice/experiment we see

    substantial drag on a circular cylinder (dAlemberts Paradox, 1717-

    1783).Viscosity in real flows is the Culprit Again!

    Jean le Rond

    dAlembert

    (1717-1783)