5.3 5.4 notes
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Transcript of 5.3 5.4 notes
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5.35.4 Angle Bisectors, Medians & Altitudes
HW Wkst Evens 1
November 05, 2012
Nov 82:25 PM
BellworkDo problems on HW worksheet.
5.1 #2, 14
5.2 #2, 6, 85.1
2. x=8
14. DE = 17
5.22. AB = 26
6. yes
8. DE = 44
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5.35.4 Angle Bisectors, Medians & Altitudes
HW Wkst Evens 2
November 05, 2012
Nov 82:35 PM
5.3 Angle Bisectors
Angle Bisector Theorem: If a point is on the < bisector, then it is equidistant from the 2 sides of the angle.
Converse of Angle Bisector Theorem: If a point is in the interior of an < and is equidistant from the sides of the <, then it lies on the < bisector.
CA
BD
A
B
C
D
DB = DC
AD bisects <BAC
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5.35.4 Angle Bisectors, Medians & Altitudes
HW Wkst Evens 3
November 05, 2012
Nov 108:05 AM
5.4 Medians & Altitudes
Median: segment from a vertex to the midpoint of opposite side
Centroid: point of concurrency (intersection of medians)
Concurrency of Medians of a Triangle Theorem: The medians intersect at a point that is 2/3 of the distance from each
vertex to the midpoint of the opposite side.
A C
B
P E
F
D AP = 2/3 AEBP = 2/3 BFCP = 2/3 CD
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5.35.4 Angle Bisectors, Medians & Altitudes
HW Wkst Evens 4
November 05, 2012
Nov 123:38 PM
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5.35.4 Angle Bisectors, Medians & Altitudes
HW Wkst Evens 5
November 05, 2012
Nov 108:18 AM
Altitude: perpendicular segment form a vertex to the opposite side
Concurrency of Altitudes Theorem: The lines containing the altitudes are concurrent.
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5.35.4 Angle Bisectors, Medians & Altitudes
HW Wkst Evens 6
November 05, 2012
Nov 108:33 AM
HW5.35.4 Worksheet Evens
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5.35.4 Angle Bisectors, Medians & Altitudes
HW Wkst Evens 7
November 05, 2012
Nov 167:14 AM
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5.35.4 Angle Bisectors, Medians & Altitudes
HW Wkst Evens 8
November 05, 2012
Nov 167:15 AM