5-Minute Check on Activity 5-12
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5-Minute Check on Activity 5-125-Minute Check on Activity 5-125-Minute Check on Activity 5-125-Minute Check on Activity 5-12
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Using logarithmic regression from the following data, determine the function and the specified value to two decimal places:
Function:
F(18) =
y = a + b ln x y = 2089.97 + 630.49 ln x
X 1 2 3 4 5 6
Y 2201 2422 2688 2902 3144 3331
y (18)= 2089.97 + 630.49 ln (18) = 3912.32
Activity 5 - 13
The Elastic Ball
Objectives• Apply the log of a product property
• Apply the log of a quotient property
• Apply the log of a power property
• Discover change of base formula
Vocabulary• None new
Activity
You are continuing your work on the development of the elastic ball. You are still investigating the question, “If the ball is launched straight up, how far has it traveled vertically when it hits the ground for the 10th time?” However, your supervisor tells you that you cannot count the initial launch distance. You must calculate only the rebound distance.
Using some physical properties, timers and your calculator, you collect the following data.
Times Ball hits Ground 1 2 3 4 5 6
Total Rebound Distance 0 9.0 13.5 16.3 18.7 21.0
Activity Cont
Plot the data using STATPLOT
What does the graph say about a model: linear, exponential or logarithmic?
The data can be modeled (thru logarithmic regression) as T = 26.75 log N
Plot both and see if the model is reasonable
Times Ball hits Ground 1 2 3 4 5 6
Total Rebound Distance 0 9.0 13.5 16.3 18.7 21.0
logarithmic
Activity Cont
Plots
Times Ball hits Ground 1 2 3 4 5 6
Total Rebound Distance 0 9.0 13.5 16.3 18.7 21.0
Properties of Logarithms
Product Property:
Division Property:
Exponent Property:
Change of Base Property:
No Sum or Subtraction Property:
logb (A×B) = logb A + logb B
logb (A÷B) = logb A – logb B
logb (Ap) = p logb A
loga xlogb (x) = ----------- loga b
logb (A ± B) ≠ logb A ± logb B
PLEASE NOTE!
Product Examples
Log2 32 =
Log (5st) =
Log4 3 + log4 9 =
Log2 7 + log2 11 =
log2 (2×2×2×2×2) = log2 2 + log2 2 + log2 2 + log2 2 + log2 2= 5 log2 2 = 5
log4 (3×9) = log4 27
log2 (7×11) = log2 77
log 5 + log s + log t
Quotient Examples
Log2 (2x/y) =
Log (¾st) =
Log4 3 - log4 9 =
Log2 7 - log2 11 =
log2 (2) + log2 (x) – log2 (y) = 1 + log2 (x) – log2 (y)
log4 (3÷9) = log4 (1/3)
log2 (7÷11) = log2 (7/11)
log 3 – log 4 + log s + log t
Power Examples
Log2 32 =
Ln (st)7 =
Log4 √51 =
4Log2 3 =
log2 (25) = 5 log2 2 = 5
½ log4 (3×17) = ½ (log4 3 + log4 3)
log2 (34) = log2 81
7(ln s + ln t)
Change of Base Examples
Most calculators have only log (base 10) and ln (base e) functions defined. In order to use logs to other bases, we need to convert to one of these two.
Log3 (5) =
Log4 x =
Log2 7x =
ln x-------- ≈ 0.72135 ln x ln 4
ln 7x-------- ≈ 1.4427 (ln 7 + ln x) ln 2
≈ 2.8074 + 1.4427 ln x
ln 5----------- ≈ 1.465 ln 3
Summary and Homework
• SummaryProperties of Logarithmic Functions:
– logb (A ∙ B) = logb A + logb B
– logb (A / B) = logb A – logb B
– logb (A)p = p∙logb A
– Change bases:
– Remember: logb (x + y) ≠ logb x + logb y
• Homework– pg 662-665; problems 1, 2, 6-9
log x ln xlogb x = ------- or logb x = ------ log b ln b