482 Lecture - faculty.math.illinois.edu

9
Math 482 Lecture 7 Announcements Awk 2 due Friday Evening office hours this week thµ8pm_ on class zoom link not OH link Rearrest supplementary problems if taking the 4 unit version Readings Lect 7 GM 5.5 5,6 5 so PS 2.5 2.6 2 I 2.2 handout BT chap 3 I Lect 8 Degeneracies Gm 5,7 5,8 PS 2,3 2.8 chap 3 BJ 24 4 today An unbounded example matrix notation

Transcript of 482 Lecture - faculty.math.illinois.edu

Page 1: 482 Lecture - faculty.math.illinois.edu

Math 482Lecture 7

Announcements

Awk 2 due Friday

Evening officehours this week thµ8pm_

on class zoom link not OH link

Rearrest supplementary problems if taking

the 4 unit version

ReadingsLect 7 GM 5.5 5,6 5 so

PS 2.5 2.62 I 2.2

handoutBT chap 3 I

Lect 8 DegeneraciesGm 5,7 5,8PS 2,3 2.8chap 3

BJ 24 4

today An unbounded examplematrix notation

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Anunbound edexampleMax 2 X 2 Xz

i

as

In standard form

Max 2 X 2 2

Subj X Xz 1 3 I

I Is Elise

Xi 42,43 4 30

Tableau Xi Xz Xs XL solve

I I is

I I 0 O lE not auite solved

Does this work

Ra

EE'd to keep entries in this firstpushescolumn non negative for feasibility notwork

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Instead try putting in basis

EERIEI II 0 O I

pivot here

i H 7Bi 17isfENext

try to pivot againMax LP pivot column must be XyBut no restriction on how big X4 grows

Claim this means LP is unbounded

Let Xz o whereDictionary

4 M M isZ X 2 1 4 1 as large

qX XIII the Miz asHE

X M 11

ButI 2 Mtl

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MatrixNotationKEIRNconsider the LP

q I o aTyberm

Let Aj be the jth column of A

Given basis 93 let BCD Bc2 Bang

to denote basic indices

Basic variables XBas XBc XBCm

XB X Bcn XBes n XBcm

CB CBcis CBas CBCm

AB mxm sub matrix of A

BCD Bcm

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Claim If X is a bfs

AB is invertible by def of bfs

CTX CTzXB since xjjop.frp XB AI't

2 x E'AI b follows fromprevious

2Cx CTXI'BXB

P fpEBAfb

Doing Row operations on A

to turn The columns ABCD ABCm

to the identity matrix Im

is conivalent to multiplying on left

by Ats

EEE KITENE ENAE AB

Row operations

must on left by Ats

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Since Apj'AXB Inxs XB

qB

AI Axa'Eb

a

MainpiotingstepSuppose your tableau has form

a fit

pivoting can be thought of as left multiplication

by seauence of elementarymatrices

T Xk XzX T

What is form for X

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T dTI dX

Uo U8 Cmas xConti

x if.ECEi aEaI

Suppose XT s solved for basis B

Then UA Im

so U AIWe also know that Iida D

So CBT dTAB

d cigars

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xt

ffn.IN bifaaaJTableau solved for basis B

Xss Ats'bFirst column tells us values ofbasic variables

relatist'sIT CT CBTAB'A u reducedcosts

Top

DI Ej.is osEfXj

Cg is cost per unit increase in

variable Xj

CBTABTAj is cost of compensating changein basic variables necessitated

by constraint Ax b

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Them If X is a bfs for a

minimization LP then

if c 20 then x is optimal

maximization LP ESO n