4.2 Triangle Congruence by SSS and SAS You will construct and justify statements about triangles...
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Transcript of 4.2 Triangle Congruence by SSS and SAS You will construct and justify statements about triangles...
4.2 Triangle
Congruence by SSS and SAS
You will construct and
justify statements
about triangles using Side Side Side and Side
Angle SidePardekooper
First, we need to look at First, we need to look at some things.some things.
What makes two items congruent?
All the corresponding sides are congruent.
All the corresponding angles are congruent.
Pardekooper
Lets label the congruent Lets label the congruent partsparts
L
N M
P
Q R
N R
L P
M Q
NL RP
LM PQ
NM RQ
NLM RPQPardekooper
There is a theorem.There is a theorem.
If two angles of one triangle are congruent to two
angles of another triangle, then the third angle is
congruent
Pardekooper
If three sides of a triangle are If three sides of a triangle are congruent to three sides of congruent to three sides of another triangle, then the another triangle, then the triangles are congruent.triangles are congruent.
Lets look at some postulates
Side Side Side (SSS) Postulate
A
B
C
D
E
F
ABCABCDEFDEF
Pardekooper
If two sides and the included angle of a If two sides and the included angle of a triangle are congruent to two sides triangle are congruent to two sides and the included angle of another and the included angle of another
triangle, then the triangles are triangle, then the triangles are congruent.congruent.
Just one more postulate
Side Angle Side (SAS) Postulate
A
B
C
D
E
F
ABCABCDEFDEF
Pardekooper
Are the following congruent ?
Yes
SSSSAS
No
It’s the wrong angle
No
One angle is
off
Pardekooper
Now, its time for a proof.
Given: HFGiven: HFHJ, FGHJ, FGJI, H is midpoint of GI.JI, H is midpoint of GI.
Prove: Prove: FGHFGHJIHJIH
StatementStatement ReasonReason
1. Given1. HFHJ, FGJI
H is midpont of GI
2. Def. of midpoint2. GHHI
3. FGHJIH 3. SSS
HG
F J
I
Pardekooper
Given: EBGiven: EBCB, ABCB, ABDBDB
Prove: Prove: AEBAEBDCBDCB
Last proof.
StatementStatement ReasonReason
1. Given1. EBCB, ABDB
2. Vertical ’s2. EBACBD
3. AEBDCB 3. SAS
BE
A
D
C
Pardekooper