4 Ponchon Savarit Method

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Transcript of 4 Ponchon Savarit Method

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For a non-ideal system, where the molar latent heat is no longer constant and where there is a substantial heat of mixing, the calculations become much more tedious.

For binary mixtures of this kind a graphical model has been developed by RUHEMANN, PONCHON, and SAVARIT, based on the use of an enthalpy-composition chart.

It is necessary to construct an enthalpy-composition diagram for particular binary system over a temperature range covering the two-phase vapor-liquid region at the pressure of the distillation.

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The following data are needed:

1. Heat capacity as a function of temperature, composition and pressure.

2. Heat of mixing and dilution as a function of temperature and composition.

3. Latent heats of vaporization as a function of composition and pressure or temperature.

4. Bubble-point temperature as a function of composition and pressure.

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Enthalpy-composition diagram

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0

2,000

4,000

6,000

8,000

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12,000

14,000

16,000

18,000

20,000

0 0.2 0.4 0.6 0.8 1

x

HVapor

2 Phase

Liquid Saturated liquid

Saturated vapor

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L0, Dh0, hD

V1

H1

(hD – QD), xD

hD – QD – H1

H1 – hD

y1, x0, xD

H o

r h

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h0, x0

V1

HD, yD

(HD – QD), yD

HD – QD – H1

H1 – h0

y1, x0, yD

H o

r h

D

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x or y

H o

r h

V1V2

V3V4

DL1L2L3

(x, h)

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PLATE-TO-PLATE GRAPHICAL PROCEDURE FOR DETERMINING THE NUMBER OF EQUILIBRIUM STAGES:

1. Draw a straight line passing through F and .

2. Draw a vertical straight line at xB all the way down until it intersects the extension of line F in

3. Assuming the reboiler to be an equilibrium stage, the vapor VM+1 is in equilibrium with the bottom stream.

4. Use equilibrium data alone to establish the value of ym+1 on the saturated-vapor line.

5. Draw the operating line between Lm(xm, hm) and VM+1. This line intersects the saturated-liquid line at

6. Repeat steps 4 and 5 until the feed plate is reached.

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x or y

H o

r h

hB

1MV MV 1MV

Bx,

LM LM-1

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H o

r h

F

123456789

xF xDxB

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H o

r h

V1

y1

x1

L1

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0

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x

y

F

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H

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= 21,700 cal/mole

0

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x

y

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H

F

D1

1DD0

hHHQh

DL

D1

1

hHHh

117,5723,12723,12700,21

DL

min

0

= 1.18

(b)

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0

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x

y

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H

F

1234567

N = 7

(c)