38115743 Basics of Hydraulic Circuits

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  • BASICS .OFHYDRAULIC CIRCUITS

    Authors :

    P.K. MUKHERJEE S. ILANGOB.E. (Mech) B.E., PGDIT., MBA.,

    f

    FLOWLINES ENGINEERING PVT. LTD.W-124, 3rd Avenue

    Anna NagarMadras - 600 040

    INDIA

  • Second Edition : 1996 Copyright : Authors

    Price : Rs. 102

    THANKS

    We thank M/s Flowlines Engineering Pvt. Ltd., Madras,for having sponsored this book

    - Authors

    Lasertypesetting at:Sri Maruthy Laser Printers, 174, Peters Road, Royapettah, Madras-600 014.

    PREFACE

    Oil Hydraulics is a fascinating field in engineering. Many ofus take this specialised subject for granted. Indian Universitiesgenerally do not offer specialisation in oil hydraulics in graduatelevel or in post graduate level, even.

    Generally, it is the international companies involved in oilhydraulics like Rexroth and Vickers who have brought outpublications to spread knowledge relating to the basics of oilhydraulics as well as constructional details of hydraulic elements.

    These books cover the principles behind the constructionaldetails of the hydraulic elements and other components extremelywell. We however find that the basics of hydraulic circuits have notbeen given adequate coverage.

    The information / knowledge given in this book is preparedand pretested by the experience, we have gained in making oilhydraulic systems at our factory for varied applications.

    Further, the experience gained in training our own engineersis also used in the book i.e. in making our engineers capable ofdesigning the hydraulic circuits to meet different applications ofcustomers.

    The book starts with a set of questions that an applicationengineer in oil hydraulics should be aware of, before the design ofhydraulic circuit is even considered.

    Step by step procedure is laid out from thereon about circuitdesign, chapters are then devoted to designing the circuits for newapplications.

    At the end, we have tried to appraise the different problemsthat can come up in hydraulic power units so designed. And a chartis given for trouble shooting.

    We sincerely hope that the book serves everyone interestedin learning the basics of hydraulic circuits.

    - Authors

    V

  • Chapter 1

    BASICS OF HYDRAULIC CIRCUITS

    Knowing the Questions

    2. Basic Block-Reservoir and Accesories

    3. A simple Hydraulic Circuit -1

    4. A simple Hydraulic Circuit -2

    5. Machine Tool Hydraulics

    Hydraulics in Simple Plastic Injection Moulding Machines

    7. A Simple Press Circuit

    . Few more Applications

    9. This way to Hydraulic Circuits

    10. Common Problems.

    11. Standard Graphical Symbols

    KNOWING THE QUESTIONS

    Understanding hvdra^lic circuits and hydraulic powerunAsstarts with the end. In hydraulic circuits design, we must firstunderstand the actuators, that are normally the end points of ahydraulic circuit.

    Actuators are nothing but hydraulic cylinders (linearactuators) or hydraulic motors (rotary actuators).

    We must know what the actuator does and we must knowwhat are the specifications of actuators from the customers, beforestarting to design a hydraulic circuit. Designers can study little moreand find out where the actuators are used (i.e.) in what kind ofmachine.

    A standard list of questions to be asked by a hydraulic circuitdesigner to end user is presented here. Once we have the answers,the hydraulic circuit can be designed.

    For simplicity sake, let us assume only hydraulic cylindersare used and not hydraulic motors;

    Most of the users of hydraulic power unit will be in a positionto answer the questions listed here.

    List of questions to be asked

    1. Is the cylinder single acting or double acting?2. How many cylinders are used?3. What is the sequence of cylinder movement-one after other

    or almost together?4. What is the function of each cylinder?

  • 5. What machine all these cylinders go to make?6. What is the bore size of cylinder?

    7. What is the ram size (rod of a hydraulic cylinder) ? Customersmay not know this end hence answer is not an essential one.

    8. What is the stroke length of the cylinder?

    9. Does the customer require manual/solenoid operated(electrically operated or automated) movement?

    10. What is the force acting on the cylinder?

    11. What is the speed of movement required?

    12. Do they require single speed/double speed or multiple speedfor the same cylinder, if so what are these speeds:

    Suppose the customer is better informed and can answeryour questions as below:

    Question Answer

    1. Single acting / Double acting Double acting

    2. How many cylinders 2 cylinders

    3. Sequence one after other

    4. Function of each cylinder 1. Clamping2. Drilling

    5. What machine all these Drilling Machinecylinders go to make?

    6. Bore size of cylinders 1. Clamping 100 mm dia2. Drilling 63 mm dia

    7. Ram size of cylinders I don't know. Standardsize given by anyreputed manufacturer

    8. Stroke length of cylinders 1. Clamp 20 mm2. Drilling - 120 mm

    9. Manual / Solenoid operated Manual

    10. What is the force acting on the 1. Clamping - 500 kgcylinder? 2. Drilling - 300 kg

    11. What is the speed of 1. Clamp - 2 meters/mtmovement required 2. Drilling -100mm/min

    Armed with above information, you have to start working;

    One step at a time

    1. We must know how much or what quantity of fluid isrequired to do the work. Hence the first step is to find,-ihepump capacity. The capacity is expressed in litres per minuteand can be calculated from the following formula.

    Q Capacity in lit/min = Area of cylinderin sq.cms XVelocity of movementof cylinder in cms/minute

    From the above example

    i) Q Capacity in lit/min = 78.5 sq.cm (Clampingcylinder area) X 200cms/min clampingspeed15700 cubic cms/min.15.7 lit/min

    ii) Q Capacity in lit/min = 31.15 sq.cm X l0cros/minincase of drilling along area of cylinder X

    drilling speed= 31.15 cubic cms/min

    0.31pm

    1. Since the cylinders have to actuate one after the other, wecan consider a pump having a capacity of 15.71pm or nearabout. This will take care of both clamping as well as drilling.

    2 3

  • 2.

    2.1

    2.2

    We know the pump size , what about the working pressure?We go back to the age old formula (i.e)Pressure =

    Clamping pressure

    Clamping pressure

    Drilling Pressure Drilling Forcedrill cyl. diameter

    300 Kg31.14 cm2

    Forcearea

    Clamping ForceClamp Cylinder area

    500K g = 6.36 Kg/cm2

    78.5cm2

    9.6 Kg/cm2

    Generally hydraulic pumps are driven by motors of 1440rpm. Thereis a thumb rule forcalculating the HP of the motorrequired, given the flow capacity and pressure.

    ower in KWWhere P = o mg pressure in bar

    Kg/cm2Q = Flow capacity of pump

    in lpmAs per the example,

    P600

    HP

    Note 1 :

    9.6 Kg/ 2 x 15.7 lpm

    0.25KW600

    0.250-346 0.335.0.5 HP

    ,,Z ,Aar = 1.03 kg/cm2. For sake of simplicity in calculationswe take I bar to be equal to 1 kg/cm.

    The maximum working pressure is the higher of the abovetwo. (i.e) 9.6 Kg/sq.cm

    So far we have found the

    1. Capacity of the pump (i.e) 15.71pm ; 16 ^P'n'2. Max working pressure (i.e) 9.6 Kg/sq.cm3. We can decide about the reservoir size of power unit. The

    Thumb rule is that it should be about 4 times the capacity ofthe pump (i.e) the pump capacity say 161pm

    . The reservoirsize should be 16X4=64lit.

    As standard reservoir come in 50 lits, 75 .1its, and 100 fits.We can choose 75 lit capacity reservoir.

    4. What about the Motor HP rating?

    Note 2:

    Generally the above formula of-EQ600 for KW is only a thumbrule and will not be accurate, especially closer to extremes of thecharacteristic curves of the pump. It is better to refer to selectioncurves to decide the exact HP/KW required.

    The above type of calculation, tells us following

    1. Capacity of pump to be chosen

    2. H.P. of the motor to be coupled to the pump.

    3. Working pressure

    4. Size of reservoir

    This is only the beginning, in the design of hydraulic circuit.

    4 5

  • Chapter 2

    BASIC BLOCK - RESERVOIR &ACCESSORIES

    In the last chapter, we have defined the four parametersrequired for designing the Hydraulic Circuit. (i.e) PumpCapacity/Horse Power required to drive the pump/workingpressure and size of the reservoir. The reservoir serves as a storefor hydraulic oil. The reservoir has certain accessories and theseare explained in this chapter.

    The Reservoir in a hydraulic circuit is illustrated in Fig 2 (1)

    A breather filler is indicated as 1. and an oil level gauge as2. The function of the breather fill er is to allow the resen oir tobreathe - (i.e) when the oil from the reservoir is drawn out, itrushes in to fill in the Qap, vacated by oil and as the oil returnsthrough return line filter, air is let t.

    Breather filler also help us to fill/refill or empty the Reservoirwith oil.

    Choose a breather filler of 5 cfm airflow capacity when theresevoir is less than501its . For over 50lits, 25 cfm airflow capacitybreather filler can be chosen

    The oil level indicator (2) indicates the oil level in thereservoir . Normally the level indicator comes in sizes indicating thelength - (i.e). 3 inches , or 5 inches or 10 inches. It is fixed close tothe top edge of the reservoir or (say) 100 mm below the top plateof the reservoir.

    BRE AT HER /FILLER

    FIGURE- 2 (1 )

    FIGURE _2(2)

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    6

  • The hydraulic circuit starts with the reservoir and withaccessories . Please note further addition in building up the circuit-Figure 2(2)

    Please note the addition of pump and the suction strainer. Ifthe pump is say 61pm the , suction strainer size should be atleast 4to 5 times the size of the pump . This will reduce cavitationpossibilities of the pump . Further the suction strainer filtration levelis generally 149 microns.

    We have added two more to the circuit building up. Theseare the relief valve and the return 'line filter.

    The relief valve is selected based on the required workingpressure & flow. We must be in a position to set the workingpressure with the relief valve and the range has to be chosenaccordingly.

    The return line filter is selected on the basis of

    jThe volume of flow back to the reservoir. This can be 4 timesthe capacity of the pump

    Type of mounting on the reservoir (i.e) Tank top or Inlineor tank immersed types

    The filtration level is generally 25 microns or 10 microns.

    Please refer figure 2(4).We have added a gauge isolator and pressure gauge in this

    figure.

    Gauge isolator is to isolate the pressure gauge and only whenthe pressure is to be read , we press it (in the case of push to readgauge isolator) to read the pressure . This helps to prolong the lifeof pressure gauge.

    The pressure gauge is chosen^for twice the working nressnr_erange. Suppose the working pressure is 30 k sq .cm - It is better tochoose 0 -60 kg/cm .

    PR RELIEF VALVE

    SUCTION STRAINER

    FIGURE. 2 (3)

    P T

    BASIC BLOCK OF CIRCUIT

    FIGURE-2(4)

    9

    8

  • For industrial hydraulic power units, it is preferable tochoose 4" dial panel mounted pressure gauge.

    In most of the hydraulic circuits the basic block almostremains same.

    So, till we come to circuits including double pumps, thisbasic only will be common. Hence to simplify illustrations in thechapters to follow, we shall just put a rectangular block to indicatethe basic block with its features.

    To Summarise

    Reservoir size - 4 to 5 times pump capacity

    suction Strainer - 4 to 5 times pump Flow capacity

    iii. The Basic block of hydraulic power unit comprises of

    a. Reservoir

    b. Suction Strainer

    c. Pump coupled to electric motor

    d. Pr. relief valve

    e. Return line filter

    f. Pr. gauge with gauge isolator

    g.

    h. Level gauge

    Breather filler

    Chapter 3

    A SIMPLE HYDRAULIC CIRCUIT - 1

    Before drawing a simple circuit, we must know that thecircuits can be drawn in conventional manner or using modularvalves. conventional manner means - involving more piping work(i.e) connecting the individual valve with properly sized tubing. Thebetter way of doing is using modular valves with manifolds.

    Our first attempt here is to make you understand theconventional way.

    We shall illustrate subsequently the same circuit - withmodular valves.

    Let us consider a system - where the hydraulic cylinder (sayone number) first pushes a load into the furnance.

    The basic block, we have understood in the previous chapter.From the basic block, we have a P line (pump line) coming out. Wehave another end of the circuit (i.e) the T line that gets back to thereservoir.

    Refer Figure 3(1)

    The P line is connected to a direction Control (DC) Valve -a three position DC valve where in its centre position all ports areblocked . From the service ports of the DC valve, connection is takento A 1 and B 1 ports of a horizontal double acting cylinder.

    When the pump is working and solenoid X is energised, oilgets to the Al port of the cylinder. This would push the piston inthe direction indicated.

    10 I 11

  • A B

    (V) CCV_ DIRECTION CC NTROL VALVEP

    P T

    When solenoid Y is energised, the oil from P line gets throto B and to B1 of the hydraulic cylinder and the piston moves inthe opposite direction.

    At any point in time, if neither X solenoid nor Y solenoid isenergised (i.e.) at the neutral position of the DC valve, the pistondoes not move.

    This means, wherever or whichever position you want, youcan position the piston by not energising either of the solenoids.(i.e.) at the neutral position of the DC valve.

    At this neutral position all ports are blocked and hence theoil does not get into the cylinder.

    FIGURE - 3 (1)

    TROL /ALVE WITHREVERSE CHECK

    P T - A,B_SERVICE PORTS OF DC VALVE

    FIGURE- 3 (2)At Bt_SERVICE PORTS OF THE CYLINDER

    12

    Hope you have understood completely fig 3 (1)1. If P and T ports are blocked in neutral position, and the pump,

    keep running, what is happening to the pressure in the `P'line ?

    2. A and B ports of the valve is also blocked in the neutralposition would this mean that where ever the piston isstopped, it cannot be moved by manual force?

    The pressure in the P line keeps building up as long as themotor is running which is coupled to the pump. As thepressure keeps building up, a stage can come as the oil hasno place to go, the pipe line can burst or the motor can stall-unless relieved of the pressure.

    So we must have the relief valve in the system.In the begenning before starting the motor/pump, the DCvalve is not energised. This means, in the begenning, itself,as the motor/pump is started, (Before energising the valve)the `P' line is pressurised. So, when the pump /motor is on, itstarts on load. Is this desirable? It is not:

    13

    2

  • In the neutral position, once the oil is in the pipe lines, thecylinder cannot be just pushed manually ; is this required forthe application in mind?

    Any designer would like the motor (prime mover) to start onno load.

    A B

    P T

    So in such a case, you must choose a DC valve that has aroute (spool configuration) which will allow the oil flow back intothe reservoir in the neutral position.

    FIGURE - 3( 3)

    FLOW CONTROL WITH

    REVERSE CHECK VALVE

    FIGURE _3(5)

    FIGURE-3 (4)

    Al

    B

    T

    BASIC BLOCK

    FIGURE_3(5)

    14

    Look at the DC valve , spool configuations 3 (3) and 3 (4).

    In these types of DC valves, the oil can get back to ` T' linein neutral position. Hence no load starting of motor is possible justby choosing a right DC valve configuration . So far we havediscussed oil route that can go to the cylinder and that comes outthrough the DC valve.

    Please refer Figure 3 (2)

    We introduced another valve here. This valve as it is shownwill allow the oil to go through a restriction which is adjustable.

    Now consider the implications of this flow restrictor (Flowcontrol valve with reverse check ) you can reduce the quantity of oilthat will flow through this valve. Result?

    The speed of the actuator .during the direction of movementindicated comes down - depending on how much is the restriction.But in the opposite direction it is as free as possible. Why? Becauseit can lift the check valve and flow freely and move the piston inthe opposite direction.

    But, the flow control valve allows only limited volume of oilto flow through . What happens to the oil volume that gets pumpedinto the system which is much more.

    15

  • Well. This excess oil is relieved/blown through the pressurerelief valve.

    Remember - all this is applicable only when you consider adouble acting cylinder movement is to be controlled.

    Suppose the application requires only two positions of thecylinder without any intennediate stop.

    In this case, we can choose a DC valve of two position, asillustrated in Figure 3(6).

    We shall consider a slightly different application in the nextchapter.

    Chapter 4

    A SIMPLE HYDRAULIC CIRCUIT - 2

    Consider an application where a load is to be lifted up (say)a stacker.

    What are the pit falls-

    1. The load should not drop down but stay in desired positions.

    2. If the load is lifted and has to be brought down slowly, itshould not come down with a 'thud.' (i.e.) without anycontrol-if this happens it means that the load is driving thesystem.

    Now look at the hydraulic circuit in figure 4(1).

    Take figure 4(1). A three position, solenoid operated DCvalve with all ports connected (in neutral) is in use.

    So, when X is energised, the load is brought down - andbrought down with a thud. (i.e.) The oil takes the path A to Al andpushed the piston down. Already the load is also acting on the pistonand it comes down fast as the outgoing oil through port B I has afree passage.

    While going up - energise Y and load is lifted up and in theneutral position, again , the load will drop down - as all ports areconnected.

    If a dc valve, where in neutral the P and T lines are connectedin Figure 4(1.1) (A and B blocked), for short duration, the load canbe held in any position (i.e.) when the solenoid valve is notenergised.

    16 17

  • aFIGURE _4(77)

    BASIC BLOCK

    FIGURE -4(;)

    DCV _ D^RECTON CONTROL _A-E

    FIGURE-4(2)1 8

    However, we must remember that all conventional slidingspool valves allow a leakage (quantity of leakage depends on thesize and pressure differential) and so the load can creep down.

    Please refer figure 4(2). The additional valve shown is pilotoperated check valve designated as POC in the figure. This valveis a poppet design and hence gives zero leak characteristics.

    The POC valve is located on the B line. The advantage is thatthe load can be held in any mid position without the `creeping'mentioned earlier.

    One problem remains:

    When solenoid X is energised the cylinder can still comedown more driven by the load and can cause uncontrolled dissent.

    Please refer figure 4(3). We have added one more element -a pressure control (i.e) Counter Balance valve designated as CBVin the figure.

    The idea is to control the dissent. This is done by setting theCBV at a particular pressure. This pressure is set at a valueequivalent to the load divided by the bottom area of the cylinder.

    Now the load is counterbalanced and cannot come down dueits own weight unless solenoid X is energised and the set value ofCBV is exceeded on the ram side of the cylinder.

    The CBV has a built in reverse check valve. The advantageis that when the cylinder is to be lifted up just energise solenoid Y.The oil flows into the port B, of the cylinderlifting the reverse checkof the CBV. In furnace gate lifting application, this circuit discussedcan also be employed.

    In effect, it means that for such high runaway loads, it isbetter to have a CBV in addition to POC - so that control is possiblein the runaway direction. One more illustration is in the case of avertical drill where at the opening out of the material , the drill triesto break out of control as the load is not there - suddenly. Even in

    19

    a

  • IL

    ROC

    LOAD

    81

    I CBV

    FIGURE _4(3)

    FIGURE _ 4 (4)

    LOAD

    Al

    Roc

    20

    ,BOTTOM AREA

    such applications we must have a CBV in the circuit - to reducesuch undesirable and uncontrollable movements of the drill or thecylinder.

    Please refer figure 4(4). Suppose further speed control isrequired during descent of the cylinder, then we can have a flowcontrol valve, designated as FCV in the figure 4(4). This applicationjust discussed is also possible with a pump driven by an engine andwith manually operated dc valve. For example, in any lift platformused by airlines for cargo loading.

    To summarise, in this chapter, we have seen practical usageof a pilot operated check valve (POC), counter balance valve (CBV)and Flow control Valve (FCV).

    All these valves are also available in modular form but theidea is that we understand by illustrating the tine diagram.

    For beginners, (For whom this book is meant), they mustimagine the consequence of not using anyone of the valves in thecircuits discussed.

    21

  • Chapter 5

    MACHINE TOOL HYDRAULICS

    Machine tools are generally differentiated into two classes.(i.e.) special purpose machines (SPM) and general purposemachines. (GPM)

    General purpose machines are those which are standardisedand common like lathes, drilling, milling etc., which are availableoff the shelf with standard specifications. The SPM's are tailormade to suit particular component in large volumes. For example,an engine manufacturer, may decide to have a special drillingmachine which can gang drill all the holes on the engine head at atime.

    Let us discuss a few circuits generally used in machine toolhydraulics.

    Clamping Circuit

    In machine tools, the job or the tool or the fixture is to beclamped or held during the machining process.

    Please refer fig 5(1)Here we have two clamping cylinders with one direction

    control valve (Two position , solenoid operated , spring offset dcv)and one pilot operated check valve . The DCV has only onesolenoid . In the de energised position (X side of the valve), thecylinders are in clamped position . The solenoid Y is to be energisedfor declamping operation . What will happen?

    Incase the solenoid is energised , the clamp opens (orreleases), and (say ) the job is either removed or being put back.Imagine in this position , the job is being placed for clamping.

    BASIC BLOCK

    FIGURE-5(1

    BASIC BLOCK

    FIGURE-5(2)23

    22

  • Suppose there is a sudden power failure - then immediately, thespring offset position of the dcv, takes place and the job getsclamped . Perhaps even before the job is in its place . In all possibilitythe hand holding the job also gets clamped , instead of the job - ifthe power fails . It is because the pump continues to deliver for fewmore moments even after power failure due to inertia.

    Please refer figure 5 (2). We have a different type DCV inplace instead of a spring offset solenoid operated dcv. This valveis known as two position solenoid operated detent type DirectionControl Valve.

    The advantage is that this kind of DCV has a mechanicalmemory and even in case of power failure, the position of the spoolof dcv does not change-because of a mechanical detent which keepsthe position of a dcv unchanged incase of power failure.

    In figure 5(2), you will find wehave two additional elements-a pressure switch (PS) and a pilot operated check valve (POC)

    The function of the POC valve is not to allow leakage of oilin the clamped position of the cylinder. this means slackening ofthe clamp cylinder does not take place.

    The function of the pressure switch is that - once theclamping is done, it is quite likely the function of some otheroperation has to take place. We can get an electrical signal from thepressure switch once it is incorporated as shown. The pressureswitch converts a pressure reading into an electrical signal - Thiselectrical signal can be used to trigger some other operation likeenergising some other solenoid.

    The pressure switch is normally set for a particular limit -(say)the clamping pressure; Once the pressure switch line reachesthe set clamping pressure limit, a microswitch in the pressureswitch, makes a contact and sends an electrical signal to start thenext operation.

    FS

    BASIC BLOCK

    FIGURE-5(3)

    25

    24

  • Please refer figure 5(3). We have changed the POC valve toa double pilot operated check valve- what is the significance?

    Well. The significance is that by installing a double pilotoperated check valve, we are ensuring the locking of fluid (i.e.)hermitical sealing on both lines of the actuator. Hence even if thereis an internal leakage (in the cylinder across the piston), the cylinderremains rock steady.

    Please refer figure 5(4).We have one more member to thefamily of valves of this circuit. A pressure reducing valve (PRV) isin place. This PRV reduces the pressure to the clamping circuit asvery often, the job or the tool has to be held positively, firmly andalso delicately. For this purpose, it is not necessary to go upto thesystem pressure limits. If we do not have a PRV in place, then thepressure in the clamping circuit will reach the level of the systempressure which can distort or deform the job.Feed circuits in machine tool applications

    We must first understand what is usually defined as feedcircuit in hydraulics relating to machine tool applications

    Very often, once the job is clamped and the tool is held (saya drill), the tool is moved rapidly towards the job till tool reachesthe job then (say) the drilling starts (feed), After drilling, the tool isretracted rapidly.

    The above is common for any machining job,, like turning,milling etc.,

    The process as explained involves two speeds; rapidapproach, and a feed speed (lower speed compared to rapid speedand rapid return)Dual speed ( feed) with meter in flow control valve

    Please refer fig. 5(5).

    BASIC BLOCK

    FIGURE-5 (4)

    27

    26

  • nWith this kind of circuit, it is possible to get two (dual) speedsin one direction and one rapid speed in the opposite direction.

    Situation 1 : Solenoid X is energised; Flow is through FlowControl valve FCV to port A2 of the cylinder. As the oil has to gothrough the FCV (free flow is not allowed by the check valve ofFCV) the rate of oil flow through part A2 is controlled and hencedesired reduced feed speed can be obtained in the directionindicated. Oil from port B2 flows freely to the tank. This situation(1) happens when DCV 2 is not energised.

    Situation 2 : Solenoid X is energised and DCV2 is alsoenergised. In DCV2, you will observe that port P1 and B I areplugged. The purpose of plugging is to make this single solenoidDCV to function like and on/off valve (or two way valve). Insituation (2) oil flows thro' Ti to Al to A2, thus by passing theFCV. This means there is no restriction to the rate of flow (as in thecase of situation 1) and hence rapid (fast) speed can be obtained inthe same direction, indicated. On the other part B2, oil flows freelyto the tank.

    / Thus in one direction indicated we are in position to get twos'eds. One for rapid approach and the other slow speed for feed(machining) purpose.

    Situation 3: Now solenoid Y is energised and DCV2 is notenergised. The FCV is by passed and rapid return is possible in the-opposite direction. This is because oil flow through part A2 comesthrough the check valve lifting the check valve and to the tank.

    Situation 4 : Solenoid Y is energised and DCV2 is alsoenergised. This situation is superfluous as the oil returning frompart A2 can return freely thro' the check valve of FCV and we arecreating an additional free path for the oil from A2 by energisingDCV2. However, if FCV is not having a built in check valve, thento obtain rapid return, it is necessary to energise DCV2.

    28

    3

    Al

    A 1 1 eDCV.1 P T

    FIGURE - 5 (6)

    Al I 81 CCV2

    BASIC BLOCK

    FIGURE-5(5)

    29

    T

  • Dual speed (feed ) with meter out now control valve

    Please refer figure 5(6). compared to fig. 5(5), the differencehere is the location of FCV. It is now fixed on the outlet of port B2.The check valve position is such that the flow coming out of portB2 has to go through the control orifice of FCV.

    Situation 1: Solenoid X of DCV 1 is energised and DCV2 isnot energised. Oil flows freely to port A2. The flow of oil from portB2 has to come through the control orifice of FCV before going tothe tank line. Hence feed speed is obtained in situation (1) indirection indicated.

    Situation 2: Solenoid X is energised DCV2 is alsoenergised. Oil flows from P line to Port A2 and oil from B2 flowfreely from B2 to Al to T1. Hence rapid speed in the directionindicated is possible.

    Situation 3 : Solenoid Y is energised and DCV 2 is notenergised. Oil flows for movement of ram in the opposite direction.Oil flow is from P to B. Since port PI and B I are blocked, the oilflow takes the path through the FCV. It flows lifting the check valveand onto B2. As the oil flow is not restricted rapid speed is obtainedin the opposite direction to the arrow indicated. The return oil flowfrom A2 is free flow to the tank.

    Situation 4 : Solenoid Y is energised and DCV2 is alsoenergised we are creating and additional free path for the oil flowas in situation 4 of meter in circuit.

    The above meter out circuit is especially useful whenrunaway loads are to be controlled. For example while themachining takes place and ends suddenly, the tool may jumpforward. The meter out circuit is useful in minimising such jumps.

    It must be noted meter out circuits are well accepted andmeter in is not popular. Only for the purpose of theory we haveexplained the' meter in' concept.

    FfGURE.5 (7)

    FIGURE _5(8)

    31

    30

  • Tank line feed control

    Please refer figure 5(7). In both meter in and meter outcontrols, speed/feed is obtainable only in one direction. But withtank line feed control, this dual speed is possible in both directions.

    To have uniformity of speed, in both directions, in figure5(7), we have drawn a cylinder with ram on both sides of the piston.

    The idea is that the equal area becomes available on bothsides and hence same speed is possible in both directions.

    Situation I : Solenoid X of DCVI is energised oil flowsthrough to A 1. DCV2 is not energised. Oil flows from B 1 to tankline but has to go through the FCV. Hence feed speed is obtained.

    Situation 2 : Solenoid X is energised oil flows through toAl. DCV2 is energised. Oil flow from B 1 to tank line and goesthroughTI to T4. Unrestricted flow and hence full speed is obtainedin this direction.

    Section 3 : Solenoid Y is energised and DCV2 is notenergised. Oil flows from P to B I and Al to T. Since DCV2 portT3 is blocked, oil flows through the FCV and feed speed is obtained.

    Situation 4 : Solenoid Y is energised and DCV2 is alsoenergised. As explained above, free flow through to tank line ispossible and hence rapid speed indirection of line arrow is obtained.

    Standard feed block

    We have discussed three standard ways of obtaining feedspeeds. But there is a very popular standard way.

    Please refer figure 5(8).This is a standard block manifolded to take on two DCV's,

    one FCV and one back pressure valve (pressure control valve) Thefunction of the back pressure valve is essentially to take care ofvarying load conditions, jumping of tools or runaway loadconditions. It can be adjusted to reduce the `jump.

    FULL AREA

    AVAILABLE

    FIGURE _5(9)

    33

    AREA AVAILABLEREDUCED AREA

    32

  • 0One advantage of this standard block is that the FCV isconnected to P line directly unlike in other feed circuit . This meansthe response time (of hydrostat in the FCV) of the FCV is muchbetter . This standard feed block is a meter in circuit and you canget feed speed in both the directions.

    But one point to note:-

    The area difference on either side of the piston in caseordinary double acting cylinder is used in the place of double endedrod. This area difference results in speed difference in eitherdirection.

    Please look at the figure 5(9) for better understanding.Another feature of the standard feed block is the back

    pressure valve. This back pressure valve allows us to fix the backpressure at different values. For instance, in a light turningoperation a back pressure of 5 bar is sufficient. But in heavyintermittant milling operation, an increase in back pressure limitwill help rigidity and to have more control over the movement.

    Chucking

    The emphasis is on rotary chucks which are used in highproduction machines like CNC lathes.

    Following points to be kept in mind while developing thehydraulic circuit.

    1. The construction of rotary chuck is such that there will be acontinuous leakage of oil thro rotary joints. Hence there willbe a clamping pressure drop when there is electrical powerfailure.

    This has to be taken care of by adding an accumulator backupin the circuit.

    34

    BASIC BLOCK

    FIGURE -5 (10),

    35

  • Further because of continuous leakage pilot operated checkvalves are not of any use in rotary chuck applications.

    2. The chuck sometimes will have to hold slender jobs. Thism eans reduced pressure adjustment is required.

    3. Internal and External chucking is to be taken care of by twoposition double solenoid detented valves (mechanicalmemory type)

    4. Once chucking is achieved a pressure switch sends a signalfor starting the next operation.

    Please refer figure 5 (10)

    On the basic block, we have an accumulator back up, apressure reducing valve. A Direction control valve for selection ofinternal/external clamp (DCVI) (Detent, two position), anotherdirection control valve for champing/declamping and the pressureswitches.

    In solenoid operated DC valve, (DCV2) the clampingposition is in non energised condition of solenoid. the reason forchoosing such position is explained in the earlier pages. Pleaseremember what would happen if there is a power failure whileclamping. Hence DCV 2 can also be of detented type.

    Even if proper DCV position is chosen (i.e.) the clamping isdone in non energised condition ofthe DCV, there will be a problem.with the operation of rotary chuck because of leakage.

    While the chuck is on (clamp is on and running) and if thereis power failure, there is a pressure loss in the clamping line - dueto drain line of rotary chuck. this can lead to a situation where thejob held gets released from the chuck. If it is an eccentric job thatis held or it is a high speed spindle the sudden release of job canhave the effect of a flying saucer hurled at the unsuspecting personnearby. As per the circuit in 5(10) the DCV2 position hold the job

    P7 ; CURE 5',! I1

    FIGURE - 5(12)

    37

    C ',ING_'EA-

    36

  • and the accumulator backs up the pressure loss till the rotationceases - depending on accumulator sizing.

    The pressure switches serve the function of sending outelectrical signals for commencing next operations. These electricalsignals are sent once the pressure switch set limits for internal/external clampings pressure are reached.

    Counter Balancing

    Let us understand Counter Balancing. In a conventionalmachine, (say) vertical boring machine, the boring head weight iscounter balanced with mechanical counter weight running onpulley or chain as illustrated in figure 5 (11)

    This increases the size and weight of the machine.

    In figure 5(12) a compact hydraulic cylinder (single acting)replaces the counter weight. Immediate advantage is the reductionin size/weight of the machine. The circuit for the same is in 5(13)

    For the sake of simplicity and to save paper space, we haveshown the circuit starting from P line. This goes thro a pressurereducing valve (PRV), a check valve, a relief valve and then to theinput port of the counter balance cylinder.

    The pressure selection for reducing valve is computed by theweight (of the moving head) divided by counter balance cylinderbore area.

    The pressure relief valve setting should be above that ofpressure reducing valve setting to avoid draining of system oil.

    The relief valve comes into play only during descent of themoving head.

    The valve/pump sizing should take care of the rapid ascentof the moving head (and the ram upward movements)

    FIGURE- 5(14

    MOVING HEAD

    FIGURE_5(13)

    39

    38

  • The combination of reducing, check and relief valves areavailable as one valve form reputed hydraulic componentmanufacturers. (Refer sketch enclosed)

    Please refer figure 5 (14)When the moving head stroke is less as in the case of slant

    bed lathe cross slide or the wheel head of a surface grinder, anaccumulator in closed loop is used as a counter balancing device.

    By close loop, here we mean that there is no external supplyof oil to the counter balance cylinder. This cylinder is directlyconnected to an accumulator as shown. The sizing of accumulatorand the cylinder are done in such a way, that at the mid point of thestroke, the precharge pressure of the accumulator and the counterbalance oil pressure are equal.

    Indexing

    Indexing can be linear or rotary. In a linear indexing, therecan be two or more defenite positions. The circuit can be as shownbelow for a two position indexig table.

    The two linear positions are at two ends of the ram travel.For machining requirement, the end positions must be rigidly heldwhich is achieved by this circuit - By continuous pressurisation ofindexing cylinder (with the aid of two position DC valve).

    Please refer figure 5(15)This circuit is similar to tank line control of speed discussed

    earlier.

    We can get dual speeds in both directions by allowing thenow to the tank to go through the FCV. When fast speed is requiredDCV2 is also energised.

    A two speed control is provided to soften or cushion the endapproach. Alternatively a cushioned cylinder can also be used inplace of duel speed control.

    -

    P

    T

    FIGURE - 5(15)

    FIGURE 5 (16)41

    40

  • VHoweverthe advantage of the secondary speed control is that

    we can fix the cushioning as per our requirement , whereas in acushioned cylinder the cushioning action is obtained only at theends of stroke.

    Rotary indexing table in special purpose machines.

    !1LJ

    When machining has to be done in more than 3 or4 locations,a rotary indexing table machanism is used.

    A plan sketch is shown for understanding.

    Please refer figure 5(16)The rotary indexing table is shown for eight station

    I-for loading/unloading

    2 to 8 - for various operations such as drilling, tapping, spotfacing, milling, reaming etc.,

    In principle the rotation is by a hydraulic motor with a pinionand an internal bull gear as shown in the sketch.

    Please refer figure 5(17) and fig 5(18)The precise indexing is achieved by face gear mechanism

    which also helps in locating and clamping of the rotary table.

    Initially the whole indexing table is lifted (declamped),indexed (rotary movement of hydraulic motor) and lowered(clamped). Once lowered the face gear mechanism assures preciselocation and clamping.

    Generally the indexing table rotates little more than the nextlocation (see fig 5 (18) ) repidly and reverses the direction andcomes back slowly to the intended state.

    FIGURE - 508)

    42

    This is achieved by ahydraulic circuit as shown in fig 5 (18).A suggested hydraulic circuit combining the table clamp andidexing is illustrated in fig . attached 5 (19)A.

    43

  • CLAMPING

    Al B1

    PILOT OPTD

    CHECK VALVE

    oCV

    PR GAUGECON NECrON/

    P

    BASIC BLOCK

    LINE DIAGRAM OF CLAMPING CIRCUIT

    FIGURE-5(19)

    44

    T

    I

    CETOP_ 3

    FIGCFE 5(20)

    CETOP_5

    FIGUFE - 5 (21)

    45

    MOUNTING HOLES

  • Hydraulic circuits - in modular form

    CONVENTIONAL LINE MOUNTED VALVE

    DPOC

    DCV

    MODULAR STACKABLE VALVE. We have so far illustrated hydraulic circuits drawn inconventional manner and perhaps also executed the same way.

    By 'Conventional Manner' we mean the piping between hevalves or the manifolds. But with modular, stackable. sandwichtype double interface valves, we can reduce the piping or plumbinginvolved to a great extent.

    The advantage is that it looks neat and reduces leakage,labour and assembly time.

    The limitation is that all valves are not available in modularform.

    P

    BASIC BLOCK

    CLAMPING CIRCUIT IN MODULAR CONVENTIONAL FORM

    FIGURE _ 5(21) A

    46

    The best way to understand the reading of modular hydrauliccircuit is to see how we can convert a conventionally drawn circuitto a modular circuit.

    Please refer figure 5(20) and 5(21).The modular valves, to fecilitate stacking should have two

    interface surfaces. One with '0' rings and the other to receive '0'rings.

    Every modular valve willhave four passages(i.e.)P,T,AandB.' Normally the top valve in the stack will be a direction controlvalve otherwise a cross over plate or a blanking plate takes the topposition.

    A typical hydralic circuit is shown using modular way ofrepresentation.

    Please refer figure 5(21A) which is an equivalent modularcircuit of 5 (19) - clamping circuit.

    47

  • CHAPTER 6

    HYDRAULICS IN SIMPLE PLASTICINJECTION MOULDING MACHINES

    The subject of hydraulics in plastic machine application is avast one and perhaps a separate book can be written for that pu rpose.The idea here is to introduce the subject and cover the basicmachines with conventional valves. Further the emphasis will beon hydraulic circuits and not on the machines.

    We shall see simple plastic injection moulding circuits.The function of hydraulics in these machines are (1) injection

    (2) clamping.Please refercircuit 6(1). We have two cylinders one each for

    clamping and for injection. These are operated manually and oneafter another. Hence the connection shown is in tandem.

    (i.e.) Tank line of one DC valves connected to the pressureline of the second DC valve. The DC valves used are tandem valves(i.e.) P&T are connected in neutral position.

    The pilot operated check valve (POC) takes care of retainingclamping pressure while the valve is in neutral position. Since bothDCV's are connected in tandem, in neutral position of both DCV'sthe pump output is freely vented to tank.

    The circuit has an additional relief valve on the A line ofinjection cylinder. This helps to set the injection pressure ofinjection cylinder.

    While this circuit is a basic one, further sophistication can beadded by having solenoid operated DC valves and a hydraulicmotor drive for injection screw drive etc.

    CLAMPING INJECTION

    FIGURE -6(1)

    49

    48

  • CLAMPING INJECTION

    POCWOR CLOSED.

    CLOSING WILLPRESS VALVE TOTHLS PC6ITION

    M

    IL

    P

    PLASTIC INJECTION MOULDING M/C.

    FIGURE - 6( 2)

    50

    SCREW DRIVE

    w

    FOI

    U

    ' For illustration phase see circuit fig 6(2).:The features of the Circuit are

    1. Safety provision for clamping cylinder - unless knob A ofthe DC Valve is pushed by a sliding door that will close themachine, oil, cannot flow thro' this DC valve to the clampingcylinder. This is for the safety of the operators.

    2. Independent pump lines foreach DCVS to injection cylinder,clamp cylinder and screw drive motor.

    3. To reduce heating, an unloding relief valve is provided. Thiswill help the pump to unload during starting, curing etc.,

    51

  • CHAPTER 7

    A SIMPLE PRESS CIRCUITAPPLICATION OF DOUBLE PUMPS

    We are considering here a hydraulic press. The applicationsof hydraulic press can be many - like deep drawing, forming,shearing, bending, notching, baling, rubber curing etc.,

    For the sake of simplicity let us take an example of a curingpress having

    a. Single cylinder application - single acting - upstroking (i.e.)gravity return

    b. For curing application (i.e) pressure holding for a particularduration of time.

    1. Tonnage or force : 100 tons

    2. Day light : 1 meter (The height available betweenmoving and fixed plates (i.e.) at the fully retractedposition of the cylinder.

    3. Speeds : Rapid appraoch and return 2 meters/mt.Pressing is 0.2 meters/minute -

    4. Curing time : 20 minutes (Steam curing)5. Operation : Manual

    Generally above specifications are sufficient to work out thehydraulic circuit and select the components/elements of the circuit.Perhaps the designer on his own can take more interest to know theother details of the press such as the platen weight (for gravityreturn), duty cycle etc.,

    M

    POC

    --LINE OF PILO'.CEC'!R VALVE

    FIGURE_7(1)

    53

    Q

    52

  • aThe steps involved:

    1. Find out the working pressure:

    At present many of the valves are limited to a workingpressure of 250 bar. Hence we can keep the max workingpressure to 210 bar. (3000psi) and select other parameters.

    2. Work out the area of the cylinder:

    Generally the press manufacturer will give this information.However the method of working is to be understood.

    Working pressure

    210 kg/cm2 =

    LoadFull bore area of Hydraulic cylinder

    100TFull bore area of hyd. cylinder

    Area = 476 cm2

    This is the full bore area of a cylinder that we can choose.

    The cylinder manufacturers follow ISO standards in respectof bore sizes of hydraulic cylinders (e.g.). The preferred bore sizecan be 40,50,63,100,125, 150, 160, 200, 250 and 300 mm.

    The full bore area closest to our requirement of 476 cm2 isby using 250 mm bore dia cylinder whose full bore area works outto 490 Sq.cm.

    So we choose 250 mm bore dia cylinder. The rod size can beleft to the choice of the manufacturer of hydraulic cylinders.

    3. Work back actual working pressure.

    Working pressure Loadarea

    l00T x 1000 kgs490 cm 2

    = 204 Kg/cm2

    54

    P

    FIGURE _ 7 (2)

    FIGURE _7(3)

    HP INDICATED BY THEAREA HATCHED

    ztoKI/cm

    55

    POWER REQLU ED WH'LERAPIDLY MOVING THE

    PLq'EN AT 10 KG'Cm

    BUT USING FULL VOLO'-'EOF 110 LPM_---

    POWER REQUIRE WILEPRESSING AT 210BARBUT USING ONLY LPM

  • 4. Calculate the flow of the pump required:

    Q Flow rate =cylinder bore area x velocity490 cm 2 x 200 ems/m

    1000

    = 981pm

    The pump which can deliver 100 1pm will be the mostappropriate. (at 1440rpm & on no load). However it is better toconsult the hydraulic product catalogue of standard manufacturerand choose a pump that meets this requirement.

    We have not considered the pressing speed 0.2 meters/minin the above calculation, as such as calculation would result in alower pump capacity and in turn speed.

    5. Calculating the electric horse power required:

    Standard Industrial drive speed 1440 rpm is assumed here.

    The actual horse power required to drive a pump delivering100 lpm at 1440 and at 210 bar can be obtained from theperformance curve of any hydraulic pump manufacuturescatalogue. However for theoretical purpose , the thumb rulecalculation is:

    PQ _ 210 k?/cm 2 x 100 lpmH.P. = 600 600

    35 KW

    = 50 H.P. say (Nearer)6. Now on to the Circuit,

    The circuit is simple and can be understood by the reader.But the importance is the selection of the pump capacity/motorHP/Flow and pressure capacity of elements.

    Please refer figure 7(1)

    56

    100.T UPSTROKING CURING PRESS

    SINGLE ACTIN(-, CV-NDER25O

    cE-cN-ARV RELEF TO PEGPC'NER CONSUMPTIGN

    PR CON?RCL MODU-E

    11G0AR 10 BAR

    FIGURE - 7 (4)

    57

  • The DC valve chosen is three position spring centre with allports connected in neutral position. By this we can start the electricmotor on no load and also the POC can normally be connected onlywith such DC valves. these DCV configuration helps the pilot lineof POC to drain in neutral position. As covered earlier the POCvalve hermetically seals so that the pressure is held throughout thecuring process.

    In this case the motor HP theoretically works out to about50HP. This is nothing but the power absorbed and can be illustratedin the PQ diagram as follows.

    Please refer figure 7(2)

    This can be interpreted that throughout the cycle or theoperation we are considering the full pressure and the full volume.The question is, whether this is required?

    In case we consider an option where the platon is movedrapidly using higher volume of oil but at low pressure and once thepressing commences, use a higher pressure but with lesser volumeof oil. This is possible with a hi-low circuit using a double pump.Accordingly the PQ diagram changes as in figure 7(3). When weconsider, a double pump, with high volume and low pressure forfaster approach and for pressing, the claculation is as follows :

    Assume the weight of platon and ram as 2 T

    The pressure required for lifting = LoadArea

    2T x 1000 kg490 cm 2

    (Bore Area of Cylinder)

    = 4.08 Kg/cm2(shown as 10 Kg/cm2 in figure 7 (3)

    The theoritical HP

    rapid closing =l0KK/cm2 X 1001pm

    600PQ600

    1.6 KW

    3 HP

    For pressing, volume of oil required at 0.2 m/mt

    Q = AxV= Area of Cylinder x Velocity

    490 cm2 x 20 cms/mt

    10 1pm (say)

    The HP requi red for pressing and locking will be ; P here600will be 210 Kg/cm2 and Q will be 10 lpm.

    210x10(i.e.) 600 = 3.5 KW

    = 5 HP (say)

    So if we choose a motor of 5 HP, we can run the system andachieve what we require but of course we would require doublepump. This double pump should be in a position to deliver 1001pmat 10 kg/cm2 while lifting and start giving 101pm at 210 kg/cm2.

    A double pump circuit is shown in figure 7(4). To fecilitateour requirement of 1001pm at 10 kg/cm2 and later on 101pm at 210kg/cm2 we must have two relief valves set at two pressure ratingsas above. A standard pressure control module (PCM) is available,wherein we get initially 100 lpm at 10 kg/cm2. Once pressingcommences , the relief valve on the large volume pumps startsunloading and the high pressure low volume pumps startsdelivering at a pressure of 210 kg/cm2. So the nett effect is thereduction in HP from 50 to 5 using a double pump.

    58 1 59

  • Chapter 8

    FEW MORE APPLICATIONS

    In this chapter we shall look at more applications - such astable feed drilling, press brake, rubber moulding, thread rolling andstacker hydraulic circuits. The idea behind choosing the variedapplications is that the reader understands the circuits, and giveshim a feeling that any other circuit similar is easy to understand andto appreciate.

    The reader should bear in mind that the more circuits helearns, and puts to use, it becomes easier for him to think of anapplication and try his hand in designing the circuit.

    Let us now look at the first application. Please refer fig (8.1)This is for table feed drilling machine.

    Table feed drilling machine application :

    Here the table with the component is lifted up rapidly. Afterthis rapid lift, the feed for drilling, milling etc., takes place. Oncethe operation is over, the table comes down rapidly. You look atfig 8(1), you will observe that all ingredients of a basic block andsimilarity with fig 5(6) feed / speed control are there. However,physically, the machine tool manufacturers opt for a free standingpumping set and all control values suitably manifolded to bemounted on the column of the drilling machine.

    The features here are,(1) The main DCV has a tandem open centre configuration

    whereby pump unloading is achieved. (ie.) the motor stantson no load when DCV is in neutral position.

    (2) Two speeds (rapid and feed) are possible in upward directionand rapid descent in opposite direction are possible.

    Xi;CJ

    -- - --- -

    HYDRAULIC CIRCUIT FOR TABLE FEED DRILLING M/CFIG. P-1

    61

    60

  • Press brake application

    Press brake are used for sheet metal working like bending,notching, punching etc.,

    Please refer figure 8(2)The customer for this press brake requires a rapid downward

    approach, and full tonnage for doing the work and thereafter a rapidreturn.

    Now look at the two cylinders doing the work. Herehydraulically, synchronising the movements of both cylinder ramsare not considered. This is achieved by mechanical means.

    The features of this circuit are

    I. High low double pumping system to minimise input power(please refer chapter 7)

    2. The main DCV is pilot operated (for handling larger flow)with tandem open centre configuration (i.e) P&T connectedin neutral position for no load start.

    3. Counter balance value (CBV) set for a value just to balancethe. weight. This is to avoid run away load tendencies.

    4. A secondary relief value (no 19) limits the maximum liftingtonnage to the desired value. What happens if this valve isnot provided?If the valve is not provided their the press works at the full

    set pressure of the main high pressure relief valve (i.e) at the endof the lift stroke.

    This also helps in not loading the structure of the machine tomax value at the upward end of the stroke.

    Thread rolling application

    Please refer figure 8.3

    Threading on metals can be done in many ways like threadturning, chasing and thread forming. For mass production normallythread forming is preferred using thread rolling machine.

    62

    M

    HV RAU_IC CIRCUIT FOR PRESS BRAKE

    FIG.. 9.2

    63

    I

  • The principle of the thread rolling is that [tic job is keptbetween two rotating full profile thread rolls. These !hread rolls aredriven with electric motors. However, hydraulics is used to formthe thread on the job by plunging in the rolls at low feed rate. Theserolls then return at rapid speed. The features are

    1. The pump starts at a low pressure (of about 10kgicm2)keeping the rolls away from each other.

    2. The rolls move together synchronised mechanically (not byhydraulics in this circuit)

    3. When the DCV is energised the rolls come towards eachother and towards the job at slow speed (and at higherpressure meter in circuit)

    4. Generally the thread rolling machine the tonnage can be highcompared to the HP. employed. For instance with a 2 HPmotor and with very slow feed corresponding to 40 bar andwith 300 mm bore cylinder we can get the desired hightonnage.

    Rubber moulding and curing application

    This hydraulic circuit is employed in a multiple platten,stream curing up stroking press. Please refer fig 8(4)

    In this press upstroking is done by large ram type singleacting cylinder. Lowering of the ram is by gravity.

    The features are

    1. A double pump with hi -low circuit , we have seen earlier isemployed.

    2. A special DC value manually operated with decompressionfeature is used.

    3. The DC value itself is a load holding zero leak value .

    4. With 18 inch ram diameter we are able to get load of 350tons at 220 Bar.

    SCR T ^.cA R^__iNT,

    F:G-8-3-

    65

    64

  • 5. The steam curing takes place in pressed (ie) load holdingcondition say for above 20 to 30 minutes This is called asvulcanising . The DCV can hold the pressure and the pumpis usually stopped to save power.

    6. Ram type single acting cylinder is used as we do not requireany power for lowering the plattem . This is achieved bygravity.

    Stacker application

    Please refer figure 8.5 This looks more complicated. Butonce the circuit is understood, the simplicity of the logic can beappreciated. In any large processing plant such as for examplecement plant, paper bags are used for packing the cement.

    For easy transportation, these cement bags have to be stackedin an appropriate manner. This is called Pellatisation. Thishydraulic circuit as in figure (8-5) helps us to achieve this objective.

    The features are

    1. We have two cylinder one for stacking and other fordestacking

    2. Here a double purp is employed (ie) two pumps are drivenby a single motor but two different outputs are taken forindependent operation.

    Cylinder 1 is for unloading pallet trays to the cruveyor. It isan independent operation. So an independent pump is used,

    Cylinder 2 is for stacker application, where as the load(cement bags) increases the stacker arm is brought down,step by step.

    After the job is done, the empty stacker arm is to be lifted uprapidly. To achieve this rapid speed, without load, aregenerative circuit is employed.

    66

    a

    HYDRAULIC CIRCUIT FOR RUBBER CURING M/C

    FIG.: 6- 4

    67

    I

  • 0ackEC_Y LIP.,F?2_L

    For positioning the stacker arm at mid intervals , a POC valveis used. A counter balance valve preset for maximum loadpressure assures smooth lowering . The proportional valve isprogrammed for acceleration and deceleration v ith varyingload conditions.

    3. We come across a new feature -- a preportional pressure an('flow control valve combination is used as a load sensingsystem. (9) for smooth acceleration and declaration withvarying load conditions. In addition to proportional control.PLCs (Program able logic controls) are used for differentprogramming for different sizes of cement bags . (loads)With PLC and proportional controls, smooth movement istaken care of.

    The number of hydraulic circuits can be limited only byimagination acid by actual requirements.

    There can he many solutions to one reuuirements and t`aenear optimum circuit designing Lames b years of oxposure.nd experience

    `1YOPAULIC C'RCUIT FOP ST.;CKER

    'IG: 6-5 -

    08

    b:?

  • CHAPTER 9

    THIS WAY TO HYDRAULIC CIRCUITS

    This book is meant to give basic knowledge on designing ahydraulic circuit. But a hydraulic circuit designer should have solidinformation base about the hydraulic elements, their symbols,functions and certain fundamentals. The reason that this chaptercomes almost at the end of the book is that we have assumed thereaders have a working knowledge of hydraulics principles,theories and the functional aspects of hydraulic elements. Howeverour thinking is also to show the way to the building of hydrauliccircuits.

    It is possible to write a separate book on the principles,constructions , functions of oil hydraulics and the elements used.But we are going to make an attempt to give a concise account ofthese fewer aspects.

    9.1 The symbols :

    The Hydraulic circuit designer should be thorough with thesymbols and we have reproduced these symbols in the annexure.

    9.2 Pascals Law

    This is a simple law and means this :

    Pressure applied on a confined fluid is transmittedundiminished in all directions and acts with equal force on equalareas and at right angles to them.

    How is this applicable to everyday usage of hydraulics`!

    If we apply a small force on a small area we can get ittransmitted to larger area and you will get higher force available to

    A .CAD OF 1OCKG

    ON1CS0 CMPISTON

    10SO CM

    L--- DD7E'_CPES

    Qt I

    - CONS NEJ

    FIG_ 9.1

    LONG PIPE LINE

    FIG- 9 2

    71

    'C00 KG

    PRES-:PE

    yy_ SDP PCPT

    7!a .ISTCN

    i

    70

  • work foryou (of course it should be a force on confined fluid) pleaserefer figure 9.1

    9.3 Positive displacement pumps

    We have come across, in cur daily living domestic pump sets- which are centrifugal pumps.

    How are the pumps used in hydraulic power units differentfrom this centrifugal pumps. The differences are,

    1. Most pumps used in hydraulic systems are positivedisplacement pumps

    2. The pump output is normally constant irrespective of thepressure.

    3. The outlet is positively sealed from the inlet, so that whatevergets into the pump is forced out through the outlet port.Th,.re is a misconception or shall we say a wrong expression

    gzrerally voiced by many users of oil hydraulic systems.

    They come with a complaint, at times, that the pump doesnot develop pressure. We must understand very clearly that thepumps here, create only flow; and not pressure. The pressure in thesystem is due to the resistance to the flow. The resistance or thepressure is created when the hydraulic oil has to flow thro' pipes(pipe friction), thro' bends and joints and thro' orifices of thevalves; and from the load of an actuator. You will come acrosspump specification of manufactures that the max. pressure of thepump is say 160 bar. This only means that the pump can withstanda pressure of 160 bar and not that it creates a pressure of 160 bar.

    If this complaint is that the pump is net developing pressure,then the user is trying to tell us that with his system. he is net ableto get the work done. If the problem is with the pumps internals, itcan be because the pump is womout and the sealing between suctionand delivery is no forger effective. But the problem can beanywhere along the lire from suction strainer to the cylinder. Weshall discuss this subject separately.

    72

    -=---1 L-_ 1-- - --^

    THE PRESSURE -_-- __ PRESSURE HERE

    HERE - --- - _ - `--- -- - THEN NO FLOW

    FIGURE-9 3 (1 )

    AN WCREASE _ - .PRESSURE -- - 'IE OIL TO F^_OW -- - TO THIS PLACE

    HERE CASES TORO THE ORIFICE

    FIGURE-9 3 (2)'HE PRESSURE DROP_-_ 7

    A_TND R ARE EGUAL SIZE CYL'.NDERSLOA[_' CS A_IS_ IOC.-?,___ SAD _N

    57C D[I L EST TAKETHE PATH OP LEAST RESISTANT E(,e )CIL WILL ALOW TO_A __F_RST. UFTLIFT ^ IULLY AND THEN WILL

    FLOW T0 BPUMP

    FIGURE_9-4

    73

    e

    N

  • 9.4 Pressure drops and orifices :

    Any Hydraulic power unit has flow of oil thro' Orifices (Anyvalve has an orifice and the more the valves are in a power unit, thegreater is the emphasis on pressure drops.

    Even on a normal flow of fluid through a long pipe line, therewill be a pressure drop. Refer figure 9.2.

    The pressure drop is because of the friction of the pipe.

    As the oil, flows thro' the pipe, fittings, manifolds andvalves, there is a reduction in the final pressure available to theactuator. It is not possible to avoid the pressure drop. However byproper sizing of the pipe and the valves it is possible to reduce thispressure drop. Energy lost due to pressure drop is converted to heat.To reduce this pressure drop, proper selection of valve and pipingare important.

    The heat produced due to energy lost results in viscosityreduction of oil. This reduction of viscosity results in leakages, lossin lubricity and cause wear and tear and inefficiency.

    Then, can we use the orifices to adjust speed?Yes. This is the right question. To tune the system for speeds,

    we can open and close the restrictions.

    9.5 Path of Least Resistance

    Fluid flows through the path of least resistance when thereis more than one possible flow path in the system. please refer figure9.4

    A and B are equal size cylinders load on A 100 Kg. Load onB is 500 Kg.

    Oil will first take the path of least resistance (ie) oil will flowto A first lift it fully, and then will flow to B.

    A'.,GE aRESSURE

    EKG CIO

    "

    ;.UGE PRESSURE

    FIGURE-9 5

    GAUGE PRESSUREG:^1 CRFS A?41 PP

    FRICTION REDJCES THEHEAD AT SUCCEEDINGPOINTS EXCEPT WHERE

    LARGE? PIPE REDUCESVELOOCT-- -, THE P'.-0 "AND PRESSURE INCREASE

    A`vr'SL I, rt

    ABSOLUTE PRESSURE

    760r 10M!s '1 27MIsIN HG VACUMN SCALE. WATERCCWMN 0IL COLUMN

    BAROMETER SCALEVACUMN CAI;GESVACUMN I^N7-'S RANGE

    FIGURE 9 6

    ATMOSPHERIC PRESSURE = 1.03 AC;CMBAR

    76CmmCF HG'-0 "E'ERS GF WATER COLUMN1127 METERS CF OIL COLUMN

    GAUGE PRESSURE IN BG/CM2+1.03 NO'CM ABSOUJTE PRESSURE IN NGrrCM

    75

    74

  • 9.b Bernoulli's Principle of oil flow'

    Understanding Bernoulli's principle is an important factor inthe design of hydraulic valves. In such valves the oil path sizeschange and Bernoulli's principle tells us, what happens if there isan increase or decrease in the size cf the oil path. We have earlierin the chapter seen the changes in pressure drops across orifices.Here we shall discuss the path ways.

    We must first understand that the fluid in a working systemcontains energy (ie;i Kinetic energy by virtue of velocity and itsweight and potential energy in the form of pressure.

    Bern-)ulli's principle states that if the flow rate is constant,the sums of the kinetic energy and the pressure energy at variouspoints in a system must be constant. Therefore, if the kinetic energydecreases, it results in an increase in the pressure energy.

    Please refer figure 9.5

    As in figure 9.5, when the Cross Sectional area of a flow pathincreases, the decrease in Kinetic energy (velocity) iesuits incoirespond-iig increase of pressure energy as shower by a higherheat;4.7 The effects of pressure

    In a hydraulic power unit, pressure is generated by resistanceto the flow of oil and mainly by the load. In other words pressureis proportional to the work load, and a pressure guage readingindicates generally the work load.

    In many places, the user of a hydraulic power unlit ignorestLe importance of apressure guage and normally the pressure guagecf a system does not work.

    Only when there is a problem in the power unit, theimportance of the pressure guage will be realised.

    The pressure guage normally ignores atmospheric pressure.(ie) The standard guage points to zero at atmospheric pressure.

    76

    TI

    FfGURE.97( Ii

    GU^F.9 ! 2)

    ATMOSPHERIC PRESSURE

    PUSHES MERCURY IN TO

    THE TUOE_

    MERCURY RISES BY 760 mm

    ST_MO_SP_HERIC PRESSUREPUSHES_ODU iN TO THEPJMP Li IE

    A

  • 9.7.1 Atmospheric pressure :

    It is the weight of air, atmosphere outside, that exists. We areused to it, so we do not feel it.

    This is actually the weight of air in the atmosphere that actson every square centimeter.

    In terms of value, this atmospheric pressure works out to 1.03Kg/cm2. Please refer figure 9.6

    * One atmospheric Pressure = 1.03 kg/cm2

    1. BAR

    760 mm of Hg

    10 meter of water column

    11.27 meter of oil column

    * Guage pressure in Kg/cm2 + 1.03 Kg/cm2 = Absolutepressure in kg/cm2

    Most of the hydraulic oil pumps used are capable of creatingonly a partial vacuum. Air pressure on the oil in the reservoir pushesoil up the suction line. As the pump cannot suck the oil all the waythrough, the height of pump installation above oil level is a matterof concern.

    Pumps available today can normally create a partial vacumnequivalent to about 150 mm of mercury which is one fifth on thevacumn scale. In terms of oil height one fifth of the oil height worksout to about 2.25 metres. This is in ideal conditions. But when wetalk of practicalities, considering the suction pipe and fitting losses,when suction strainer is also in use, we can consider only about onemetre or there about.

    Therefore a hydraulic pump with adequately sized inlet pipeand suction strainer should never be mounted higher than one meterabove the oil level.

    For information the suction pipes are selected for amaximum oil velocity of 1 meter per second.

    Cavitation and aeration in a pump

    A pump with adequate suction characteristics (ability toincrease partial vacumn to the extent of one fifth in vacumn scale(ie) six inches of Hg or 150 mm of Hg)-can be installed in withinone meter height of oil level. If the pump does not have suchcharacteristics, the pumps can be mounted below the oil level.

    We must remember here that for every foot of oil, oil createsa static head pressure of 0.4 psi.

    As we try to locate the pumps below the oil level, for eachfoot, we add a positive pressure of 0.4 psi available to the inlet ofthe pump.

    Under these conditions the pressure losses due to strainer,suction line and fittings still to be substracted from the totalpressure available at the inlet conditions.

    In a partial Vacumn Condition, when the pump is locatedabove the oil level, then this less than atmospheric pressure acts onthe oil.

    The mineral based hydraulic oil, which we use, contain about8 to 9% of dissolved air. Now, when the `less than atmosphericpressure' acts on the oil, the air in the oil expands and becomes ahigher percentage of volume. This means, more air in oil gets intothe pump chamber. At the outlet of the pump is the system pressurewhich is considerably more. The air bubbles in the oil will nowcollapse at considerable pressure in the pumping chamber. Thisrapid collapsing of air bubbles results in rapid energy losses in theform of heat and noise. This heat can result in combustion of oilleading to carbonisation.

    When the pressure gets low on the suction side, it can alsoresult in vaporisation of oil, the combined effect of all this is knowas cavitation effects.

    78 1 79

  • Chapter 10

    TROUBLE SHOOTING

    It is only appropriate that a person who designs the circuits,knows what can go wrong with the power units.

    In the pages to follow we are giving charts descrih,ngcommon problems and remedies that can solve these problems.

    These charts also will be very useful for maintananceengineers using hydraulic power units in their shops.

    Most of the problems in hydraulic machinary are relates; tooil contamination. The suction strainer can clog du,; tocontamination. This can result in cavitation of pump.Contamination can also make th,, valve sticky. The DC valve 'oilscan bum due to sticky valves.

    Anotherpoint is that we should ensure oil and airdo not mix.They are not made for each other.

    A loose suction joint can allow system toaerate causingsevere pump noise and jerky movement of actuator.A word of Caution

    We have come across problems that are not associated withpower units but are machine problems or relating to electricalcircuits. Therefore it is essential that before trouble shooting, theproblem is identified to be relating the hydraulics side of hemachine.

    80

    REMEDY : d

  • CHART I - REMEDIES

    a. Any or all of the following : Replace dirtyfilters - Washstrainers in solvent compatible with system fluid - Cleanclogged inlet line - Clean reservoir breather vent - Changesystem fluid - Change to proper pump drive motor speed -Overhaul or replace superchange pump - Fluid may be toocold

    b. Any or all of the following: Tighten leaky inlet connections- Fill reservoir to proper level (with rare exception all returnlines should be below fluid level in reservoir) - Bleed air fromsystem - Replace pump shaft seal (and shalft if worn at sealjournal)

    c. Align unit and check condition of seals, bearings andcoupling

    d. Install pressure guage and adjust to correct pressuree. Overhaul or replace

    CHART II - REMEDIES

    a. Any or all of the following : Replace dirty filters - Cleanclogged inlet line - Clean reservoir breather vent - Changesystem fluid - Change to proper pump drive motor speed -Overhaul or replace supercharge pump

    b. Any or all of the following: Tighten leaky inlet connections- Fill reservoir to proper level (with rare exception all returnlines should be below fluid level in reservoir) - Bleed air fromsystem - Replace pump shaft seal (and shaft if worn at sealjournal)

    c. Align unit and check condition of seals and bearings Locateand correct mechanical binding - Check for work load inexcess of circuit design.

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  • d. Install pressure guage and adjust io correct pressure (Keepatleast 125 PSI difference between valve settings)

    e. Overhaul replace

    f. Change filters and also system fluid if of improper viscosity-Fill reservoir to proper level

    g. Clean cooler and/or cooler strainer - Replace cooler controlvalve - Repair or replace cooler.

    CHART III - REMEDIES

    a. Any or all of the following : Replace dirty filters - Cleanclogged inlet line - Clean reservoir breather vent - Fillreservoir - proper level - Overhaul or replace superchargepump

    b. Tighten leaky connections - Bleed air from system

    c. Check for damaged pump or pump drive - replace and aligncoupling

    d. Check for damaged pump or pump drive - replace and aligncoupling

    d. Adjuste. Overhaul or replace

    f. Check position of manually operated controls - checkelectrical circuit on solenoid operated controls - Repair orreplace pilot pressure pump

    g. Reverse rotation

    h. Replace with correct unit

    CHART - III

    HNCORF,ECT FLOW

    A S

    ENO FLOW

    PUMP NOT RECEIVINGFLUID I

    REMEDY a

    PJHP CRIVE MOTORNOT CPERATIN G

    REMEDY c

    P PDRIVE MOTORP RNING IN WRONG

    DIRECTIONREMEDY g

    DIRECTION CONTROLSET IN WRONG

    POSITION

    REMEDY :f

    ENTIRE FLOW PASSINGOVER RELIEF VALVE

    REMEDY d

    DAMAGED PUMP

    REMEDY c

    IMPROPERLYASSEMBLED PUMF

    REMEDY e

    LOW FLOW

    P FLCV CONTROL SETTOO LOW

    REMEDY d_

    RELIEF OR UNLOAD:NGV V SET TOO LOW

    REMEDY e ar f

    EXTERNAL LEAX INSYSTEM

    REMEDY

    YOKE ACTUATINGDEVICE INOPERATIVE

    (VARIABLE DISPLACEMENTPUMPS)

    REMEDY

    RPM OF PUMPDRIVE MOTORINCORRECT

    REMEDY h

    WORN. PUMPV V, MOTOR, CYLINDEROR OTHER COMPONENT

    REMEDY : e

    C

    L EXCESSIVE FLOW I

    FLOW CONTROL SETTO HIGH

    REM E!'Y d

    I YOKE ACTUATINGDEVICE INOPERATIVE

    (VARWBLF ISPLAC MEN''PUMPS)

    REMEDY

    IMPROPER SIZEPUMP USED 'ORREPLACEMENT

    REMEDY 'I

    ERPM OF PUMP DRIVMOTOR INCORRECT

    REMEDY h

    i

    84

  • CHART - V

    FAULTY OPERATION

    in

    u

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    VfU,

    3 w JO ..O

    a I- HG' O W =Z uOf

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    86

    0

    A

    NOMOVEMENT

    NO FOLW ORPRESSURE

    REMEDY : SEECHART III COL A

    LIMIT ORSEQUENCE DEVICE

    (MECHANICALELECTRICAL ORHYDRAULIC)

    INOPERATIVE ORMISADJUSTED

    REMEDY e

    MECHANICALBIND

    REMEDY b

    NO COMMANDSIGNAL TO SERVO

    AMPLIFIER

    REMEDY f

    INOPERATIVE ORMISADJUSTED

    SERVO AMPLIFIERREMEDY c

    INOPERATIVESERVO V V

    REMEDY c

    IWORN OR DAMAGED

    CYLINDER ORMOTOR

    REMEDY e

    c

    SLOWMOVEMENT

    LOW FLOW

    REMEDY : SEECHART Ill COL 8

    FLUID VISCOSITYTOO HIGH

    REMEDY : a

    INSUFFICIENTCONTROL PRESSURE

    FOR VVREMEDY : SEE

    CHART IV

    NO LUBRICATIONOF MACHINE

    WAYS OR LINKAGEREMEDY g

    MISADJUSTED ORMALFUNCTIONINGSERVO AMPLIFIER

    REMEDY : c

    STICKING SERVOVALVE

    REMEDY : d

    WORN OR DAMAGEDCYLINDER OR

    MOTORREMEDY : e

    ERRATICMOVEMENT

    ERRATICPRESSURE

    REMEDY : SEECHART IV COL C

    AIR IN FLUID

    REMEDY : SEECHART 1

    D

    EXCESSIVE SPEEDOR MOVEMENT

    EXCESSIVE FLOW

    REMEDY : SEECHART III COL C

    FEED BACKTRANSDUCER

    MALFUNCTIONING

    REMEDY e

    NO LUBRICATION MISAD^ JUSTED IOF M/C WAYS OR MALFUNCTIONING(OR LINKAGE I SERVO AMPLIFIERREMEDY : g REMEDY : ..

    I

    ERRATIC COMMANDSIGNAL

    REMEDY f

    MISADJUSTED ORMALFUNCTIONINGSERVO AMPLIFIER

    REMEDY c

    I MALFUNCTIONING(FEEDBACK TRANSDUCER

    REMEDY

    STICKING SERVO VALVEREMEDY d

    WORK OR DAMAGEDCYLINDER OR MOTOR

    87REMEDY : e

    OVER-RIDINGWORK LOAD

    REMEDY h

  • CHART IV - REMEDIES

    a. Replace dirty filters and system fluid

    b. Tighten leaky connections (fill reservoir to proper love; andbleed air from system)

    c. Check gas valve for leakage Charge to correct pressureOverhaul if defective

    d. Adjust

    C. Overhaul or replacc

    CHART V - REMEDIES

    a. fluid may be too cold or sl.ou:d be changed to clean fluid of';orrcct viscosity

    b. Locate hind and repair

    c. Adjust, repair, or replace

    d. Clean and adjustor replace - Check condition of system fluidand filters

    e. Overhaul or replace

    f. Repair command console or interconnecting wires

    g. Lubricate

    h. Adjust, repair, or replace counterbalance valve.

    STANDARD GRAPHICAL S''MBOLS

    88

  • RESERVOIR VENTED

    PRESSUR GAUGE

    ACCUMULATOR

    GAS CHARGED

    FALTER OR STRAINER

    PRESSURE SWITCH

    CHECK VALVE

    MANUAL SHUT OFFVALVE

    VALVE , MAXIMUM

    PRESSURE (RELIEF)

    l-----]

    0

    4

    90

    MULTIPLE FLOW PATHS(ARROW SHOWS FLOWDIRECTION)

    UNLOADING VALVE,

    INTERNAL DRAIN,

    REMOTELY OPERATED

    DECELERATION VALVE,NORMALLY OPEN

    SEQUENCE VALVE

    DIRECTLY OPERATED

    EXTERNAL DRAIN

    PR. REDUCING VALVE

    COUNTER BALANCEVALVE WITH INTEGRALCHECK

    FTFMlEllTURE ANDPR COMPENSATED

    FLOW CONTROL WITH

    INTEGRAL CHECK

    I DIRECTIONAL VALVE .TWO POSITION, THREECONNECTION

    DIRECTIONAL VALVE,THREE POSITION,FOURCONNECTION

    VALVE, INFINITEPOSITIONING (INDICATEDBY HORIZANTAL BARS)PROPORTIONAL CONTROL

    PRESSURE COMPENSATOR,

    DETENT

    i LEVER

    I

    SOLENOID

    SOLENOID CONTROLLEDPILOT PRESSUREOPERATED

    SPRING

    --

    f1

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