3.1 Day 2 Applications and properties of a Kernel.
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Transcript of 3.1 Day 2 Applications and properties of a Kernel.
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3.1 Day 2 Applications and properties of a Kernel
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3.1 day 2 Applications and properties of a Kernel
…Wait…
No, wrong slide…
not that kind of a kernel…
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Properties of invertible matrices
The following statements are equivalent for an nxn matrix
1 A is invertible2 The linear system Ax = b has a unique solution x
for all b3 rref(A) = I4 Im(A) = Rn
5 Rank (A) = n6 Ker(A) = 0
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Properties of an image of a Linear Transformation
1. The zero vector is in the image of T
2. The image of T is closed under addition.
(if two vectors are in the image of T then the sum of those two vectors is also in the image of T)
3. The image of T is closed under scalar multiplication. if a vector is in the image then any scalar multiple of that vector is also in the image)
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Prove Ker(A)= 0 for all invertible matrices
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Problem 22
Find the image by both inspection and rref
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Solution to Problem 22
To see if the last column is a scalar multiple of the first two use2x +y =3 x =2 y = -13x+4y = 2Find the values of x and y and see if they work in the equation6x+5y = 7
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Example 7
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Example: 7 Solution
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Use your library of basic matrices to find a basis for the kernel and image
Find the kernel and image of a matrix in R2
9/25 12/25
12/25 16/25
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Use your library of basic matrices to find a basis for the kernel and image
Find the kernel and image of a matrix in R2
9/25 12/25
12/25 16/25
(Hint this is a projection matrix onto <3,4>
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Use your library of basic matrices to find a basis for the kernel and image
Find the kernel and image of a matrix in R2
9/25 12/25
12/25 16/25
This matrix is a projection matrix onto the line that consists of the scalar multiples of <3,4>
The image is the line (the scalar multiples of <3,4>)The kernel are vectors that are perpendicular to the given line.
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Find the image and kernel of the following matrix
-3/5
3/5 4/5
4/5
Use your library of basic matrices to obtain the answer
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Find the image and kernel of the following matrix
-3/5
3/5 4/5
4/5This is a rotation matrix the image is R2
The Kernel is the zero vector
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Problem 24
Describe the Image and the Kernel of the transformation
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Problem 24 Solution
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Problem 37
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37 Solution
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Problem 38
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38 Solution
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Homework p. 110 23,25,27,29,39,41,44,49
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