7/31/2019 3 walid

1/13

Computing For Engineers

Control Structures

COMPUTING FOR ENGINEERS (EE209)

Laboratory report

LAB ACTIVITY 3: CONTROL STRUCTURES

Walid Nabil Osman Ali

ID #: 1000924355

SCHOOL OF ENGINEERING

FACULTY OF ENGINEERING, ARCHITECTURE & BUILT

ENVIRONMENT

16/2/2012

7/31/2019 3 walid

2/13

Computing For Engineers

Control Structures

Computing For Engineers

Lab Activity3: Control Structures

Objectives:

To be familiar with one of the control structures type: selection statements.Learning Outcomes: At the end of the session, the students are able:-

To understand and use the control structures in programming. To understand the concept ofif, ifelse, ifelse if - else and switch - case statement.

Apparatus:

PC with C++ compilerSample Code 1: If statement

The program code shown below reads an integer and determines and prints whether it is odd oreven.(Hint: Use the modulus operator. An even number is a multiple of two. Any multiple of two

leaves a remainder of zero when divided by 2.)

#include

using namespace std;

int main()

{

int num;

cout

7/31/2019 3 walid

3/13

Computing For Engineers

Control Structures

Sample Code 2: Ifelse statement

int main()

{

int num;

cout

7/31/2019 3 walid

4/13

Computing For Engineers

Control Structures

else

{

cout

7/31/2019 3 walid

5/13

Computing For Engineers

Control Structures

The program code shown below uses the switch case using characters.int main()

{

Char y;

cout

7/31/2019 3 walid

6/13

Computing For Engineers

Control Structures

Sample Code 3 : Switch case

# include

using namespace std;

int main ()

{

char mood;

cout

7/31/2019 3 walid

7/13

Computing For Engineers

Control Structures

Sample Code 4a: Ifelse statement

# include

using namespace std;

int main ( )

{

int y = 0;

cout y;

cout

7/31/2019 3 walid

8/13

Computing For Engineers

Control Structures

Sample Code 4b : Ifelse-if - else

# include

using namespace std;

int main ()

{

char y;

cout y;

cout

7/31/2019 3 walid

9/13

Computing For Engineers

Control Structures

Flowchart 1

Yes

No

Yes

No

Num

%2 == 0

Start

Enter a number

Display number is even

Display number is odd

End

Num

%2! = 0

7/31/2019 3 walid

10/13

Computing For Engineers

Control Structures

Flowchart 2

Yes

No

Start

Enter a number

Number is less and equal to

10

Number is greater than 10

End

Num

7/31/2019 3 walid

11/13

Computing For Engineers

Control Structures

Flowchart 3

Yes

No

Yes

No

Y y

Start

Enter y for yes, or N for No

Are you happy?

I am happy too!

N n

Cheer up!

You entered a wrong

character.

End

7/31/2019 3 walid

12/13

Computing For Engineers

Control Structures

Flowchart 4a

Yes

No

Yes

No

Yes

No

Start

Enter a character

A a

B b

C c

Default

End

Range is: 100 - 70

Range is: 69 - 40

Range is: 39 0

7/31/2019 3 walid

13/13

Computing For Engineers

Control Structures

Flowchart 4b

Yes

No

Yes

No

Yes

No

Start

Enter number

Case 0

Case 1

Case 5

Default

End

You entered zero.

You entered one.

You entered five.