3-4 Solving Two-Step and Multi-Step Inequalities Warm Up Warm Up Lesson Presentation Lesson...

3-4 Solving Two-Step and Multi-Step Inequalities

Warm UpWarm Up

Lesson PresentationLesson Presentation

Lesson QuizLesson Quiz


Warm UpSolve each equation. 1. 2x – 5 = –17

2.

Solve each inequality and graph the solutions.

4.

3. 5 < t + 9

–6

14

t > –4

a ≤ –8


MA.912.A.3.5 Symbollically represent and solve multi-step and real-world applications that involve linear…inequalities.Also MA.912.A.3.4, MA.912.A.10.2.

Sunshine State Standards


Solve inequalities that contain more than one operation.

Objective


Inequalities that contain more than one operation require more than one step to solve. Use inverse operations to undo the operations in the inequality one at a time.


Additional Example 1A: Solving Multi-Step Inequalities

Solve the inequality and graph the solutions.

45 + 2b > 61

45 + 2b > 61–45 –45

2b > 16

b > 8

0 2 4 6 8 10 12 14 16 18 20

Since 45 is added to 2b, subtract 45 from both sides to undo the addition.

Since b is multiplied by 2, divide both sides by 2 to undo the multiplication.


8 – 3y ≥ 298 – 3y ≥ 29–8 –8

–3y ≥ 21

y ≤ –7

Since 8 is added to –3y, subtract 8 from both sides to undo the addition.

Since y is multiplied by –3, divide both sides by –3 to undo the multiplication. Change ≥ to ≤.

–10 –8 –6 –4 –2 0 2 4 6 8 10

–7

Additional Example 1B: Solving Multi-Step Inequalities



Check It Out! Example 1a


–12 ≥ 3x + 6–12 ≥ 3x + 6– 6 – 6

–18 ≥ 3x

–6 ≥ x

Since 6 is added to 3x, subtract 6 from both sides to undo the addition.

Since x is multiplied by 3, divide both sides by 3 to undo the multiplication.

–10 –8 –6 –4 –2 0 2 4 6 8 10


Check It Out! Example 1b


x < –11

–5 –5x + 5 < –6

–20 –12 –8 –4–16 0

–11

Since x is divided by –2, multiply both sides by –2 to undo the division. Change > to <.

Since 5 is added to x, subtract 5 from both sides to undo the addition.


Check It Out! Example 1c


1 – 2n ≥ 21–1 –1

–2n ≥ 20

n ≤ –10

Since 1 – 2n is divided by 3, multiply both sides by 3 to undo the division.

Since 1 is added to −2n, subtract 1 from both sides to undo the addition.

Since n is multiplied by −2, divide both sides by −2 to undo the multiplication. Change ≥ to ≤.

–10

–20 –12 –8 –4–16 0


To solve more complicated inequalities, you may first need to simplify the expressions on one or both sides by using the order of operations, combining like terms, or using the Distributive Property.


Additional Example 2A: Simplifying Before Solving Inequalities


2 – (–10) > –4t

12 > –4t

–3 < t (or t > –3)

Combine like terms.Since t is multiplied by –4, divide

both sides by –4 to undo the multiplication. Change > to <.

–3

–10 –8 –6 –4 –2 0 2 4 6 8 10


Additional Example 2B: Simplifying Before Solving Inequalities


–4(2 – x) ≤ 8

−4(2 – x) ≤ 8

−4(2) − 4(−x) ≤ 8 –8 + 4x ≤ 8

+8 +84x ≤ 16

x ≤ 4

Distribute –4 on the left side.

Since –8 is added to 4x, add 8 to both sides.


–10 –8 –6 –4 –2 0 2 4 6 8 10


Additional Example 2C: Simplifying Before Solving Inequalities


4f + 3 > 2–3 –3

4f > –1

Multiply both sides by 6, the LCD of the fractions.

Distribute 6 on the left side.

Since 3 is added to 4f, subtract 3 from both sides to undo the addition.


4f > –1Since f is multiplied by 4, divide both

sides by 4 to undo the multiplication.

0

Additional Example 2C Continued


Check It Out! Example 2a


– 5 > – 5

2m > 20

m > 10

Since 5 is added to 2m, subtract 5 from both sides to undo the addition.

Simplify 52.

Since m is multiplied by 2, divide both sides by 2 to undo the multiplication.

0 2 4 6 8 10 12 14 16 18 20

2m + 5 > 52

2m + 5 > 25


Check It Out! Example 2b


3 + 2(x + 4) > 3

3 + 2(x + 4) > 33 + 2x + 8 > 3

2x + 11 > 3– 11 – 11

2x > –8

x > –4

Distribute 2 on the left side.

Combine like terms.Since 11 is added to 2x, subtract

11 from both sides to undo the addition.


–10 –8 –6 –4 –2 0 2 4 6 8 10


Check It Out! Example 2c


5 < 3x – 2+2 + 2

7 < 3x

Multiply both sides by 8, the LCD of the fractions.

Distribute 8 on the right side.

Since 2 is subtracted from 3x, add 2 to both sides to undo the subtraction.


Check It Out! Example 2c Continued


7 < 3x

4 6 82 100



Additional Example 3: Application

To rent a certain vehicle, Rent-A-Ride charges $55.00 per day with unlimited miles. The cost of renting a similar vehicle at We Got Wheels is $38.00 per day plus $0.20 per mile. For what number of miles in the cost at Rent-A-Ride less than the cost at We Got Wheels?

Let m represent the number of miles. The cost for Rent-A-Ride should be less than that of We Got Wheels.

Cost at Rent-A-Ride

must be less than

daily cost at We Got Wheels

plus$0.20

per miletimes # of

miles.

55 < 38 + 0.20 m


85 < m

Since 38 is added to 0.20m, subtract 38 from both sides to undo the addition.

Since m is multiplied by 0.20, divide both sides by 0.20 to undo the multiplication.

Rent-A-Ride costs less when the number of miles is more than 85.

Additional Example 3 Continued

55 < 38 + 0.20m

–38 –38

55 < 38 + 0.20m

17 < 0.20m


Check

Additional Example 3 Continued

Check the endpoint, 85.

55 38 + 17

55 55

55 = 38 + 0.20m

55 38 + 0.20(85)

Check a number greater than 85.

55 < 38 + 1855 < 56

55 < 38 + 0.20(90)

55 < 38 + 0.20m


Check It Out! Example 3

The average of Jim’s two test scores must be at least 90 to make an A in the class. Jim got a 95 on his first test. What grades can Jim get on his second test to make an A in the class?

Let x represent the test score needed. The average score is the sum of each score divided by 2.

First test score

plussecond test score

divided

by

number of scores

is greater than or equal to

total score

(95 + x) 2 ≥ 90


Check It Out! Example 3 Continued

The score on the second test must be 85 or higher.

Since 95 is added to x, subtract 95 from both sides to undo the addition.

95 + x ≥ 180–95 –95

x ≥ 85

Since 95 + x is divided by 2, multiply both sides by 2 to undo the division.


Check

Check It Out! Example 3 Continued

Check the end point, 85.

Check a number greater than 85.

90.5 ≥ 90

90

90

90 90


Standard Lesson Quiz

Lesson Quizzes

Lesson Quiz for Student Response Systems


Lesson Quiz: Part ISolve each inequality and graph the solutions.

1. 13 – 2x ≥ 21 x ≤ –4

2. –11 + 2 < 3p p > –3

3. 23 < –2(3 – t) t > 7

4.


Lesson Quiz: Part II

5. A video store has two movie rental plans. Plan A includes a $25 membership fee plus $1.25 for each movie rental. Plan B costs $40 for unlimited movie rentals. For what number of movie rentals is plan B less than plan A?

more than 12 movies



1. Identify the solution for the given

inequality.

A.

D.

a ≤ –7

B.

a < –7

C. a < –7

26 + 2a ≥ 12

a ≥ –7




inequality.

A.

D.

s < -1

B.

s ≤ 1

C. s < 1

15 + 5s < 10

s > -1




inequality.

A.

D.

x > 75

B.

x > 25

C. x > 9

x > 87

34 > 3(3x)




inequality.

A.

D.B.

C.


5. A cell phone provider offers two plans.

Plan A includes a fee of $25 per month

and charges $0.25 for every call. Plan B

includes a fee of $40 per month and

offers unlimited calls. For what number

of phone calls is the cost of plan B less

than the cost of plan A?


A. more than 100 calls

D.B.

C. more than 60 calls

more than 120 calls more than 160 calls

3-4 Solving Two-Step and Multi-Step Inequalities Warm Up Warm Up Lesson Presentation Lesson...

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