( )293 g

1 mol( )150.0 g

1

THANKSGIVING H.W. ANSWERS

K 2 mol x 39.00 g/mol = 78.00 g

Cr 2 mol x 51.996 g/mol= 103.992 g

O 7mol x 15.99 g/mol= 111.93 g

1a) Molar mass (GFM) = 293.992 g/mol

K2Cr2O7

1b) 2 moles of K are in I mole of K2Cr2O7

1c)How many moles are in the 150.00 grams of

K2Cr2O7

=0.5102mol K2Cr2O7

( )1 mol

6.02 x 1023

particles( )293 g

1 mol( )150.0 g

1

= 3.07 x 1023 molecules K2Cr2O7

1c) How many particles are in the 150.00 g

1d) What is the mass of 12.04 x 1023 particles of K2Cr2O7

( )1 mol( ) 293 g1 mol( ) 12.01 x 1023

particles

1 6.02 x 1023

particles

= 3.07 x 1023 molecules K2Cr2O7

( )1 mol( ) 17 g1 mol( ) 51.0 g NH3

1

18.06 x 1023

PARTICLES

2a-b)what is the mass of 18.06 x 1023 particles of NH3 (gfm=17g/mol)

2c) What is the mass of 12.04 x 1023 particles of K2Cr2O7

( )1 mol( ) 22.4L1 mol

6.02 x 1023

particles

=67.2 L NH3( )18.06 x 1023

particles

1

6.02 x 1023

PARTICLES

Pb 1 mol x 207.2 g/mol = 207.20 g

N 2 mol x 14.006 g/mol= 28.012 g

O 6mol x 15.99 g/mol= 95.94 g

Molar mass (GFM) = 331.152 g/mol

Pb(NO3)2

( )293 g

1 mol( )150.0 g

1 =0.5102 mol K2Cr2O7

( )331.152 g

1 mol( )0.5102 mol

1

168.954 g= Pb(NO3)2

3)How many grams of lead nitrate = the moles of 150.00 grams of K2Cr2O7 ?