22219477 Aircraft Design Day4
Transcript of 22219477 Aircraft Design Day4
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DAY 4
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LOAD FACTOR
L=W L+ L=W+F
LOAD FACTOR :
A factor which defines load in terms of weight
W
L
g
An
+=+= 11
zAg
WF==L
+=+g
AW z1LL
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V-n DIAGRAM
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SIGN CONVENTIONS
C) BENDING MOMENTB) SHEAR FORCEA) AXIAL FORCE
F) ANGLE & ROTATIOND) TORQUE E) SHEAR FLOW
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SIGN CONVENTIONS
(REACTION LOADS)
A) AXIAL & SHEAR
C) TORQUE
B) BENDING MOMENT
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EQUILIBRIUM OF FORCES
THE FORCE EQUILIBRIUM EQUATIONS ARE
0
0
0
=
=
=
M
F
F
Y
X
STRUCTURE
FREE BODY DIAGRAM
PL
1200 lb40000 lb-in
W=8000 lb
A BC T
lb1200
0
=
=T
Fx
506P
006715P
400006*8000150*10*1200
0
=
=
=+
=P
MB
9447L
8000
0
=
=+
=PL
FY
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TRUSSTRUSSES ARE CLASSIFIED AS
- STATICALLY DETERMINATE- STATICALLY INDETERMINATE
32 = jm m= Number of membersj= Number of jointsm < 2j-3 Structure is unstablem > 2j-3 Structure is statically indeterminate
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TRUSSES (Contd)
Identify whether the structure is statically
determinate / indeterminate
C
A B
RAH
RAV
RBH
RBV
P PPPPP
A B C D
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TRUSS ANALYSIS
TRUSSES CAN BE ANALYSED BY- METHOD OF JOINTS
- METHOD OF SECTIONS
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SPACE TRUSS The six equilibrium eqns are
0
00
=
==
Z
Y
X
F
FF
0
0
0
=
=
=
Z
Y
X
M
M
M
RCosF
RCosF
RCosF
Z
Y
X
=
=
=
222
zyX FFFR ++=Resultant force
Component forces
Z
F
Y
F
X
F
L
R ZYX ===Geometric relation
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LANDING GEAR
Resolving the forces in V direction
Resolving the forces in D direction
lbcos*F
F
AV
V
193161520000
0
==
=
lbsin*F
F
AD
D
517615200000
==
=
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LANDING GEAR (FREEBODY DIAGRAM)
C.
.
.
.
... .H
A A
BB
C
FBH
FCG
19318 lb19318 lb
5176 lb
I
I
J
J
FJV
FIV
FJD
FID
FGV
FEDFES
FES
TE
TEFED
FEV
FEV
FIS
FGS
E
E
G
G
5176 lb
8"
3"
3"
20"
23"
44"
45
V
D
S
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LANDING GEAR (FORCE ESTIMATION)
A
B
C
FBH
FCG
19318 lb
FEDFES
TE
FEV
in-lb41408
08*5176
0
=
=
=
E
E
EV
T
T
M
V
D
S
lb14003
03*)45(*20*)45(*44*5176
0
=
=
=
BH
BHBH
ES
F
SinFCosF
M
lb11370
020*)7.33(*3*)7.33(*8*19318
0
=
=
=
CG
CGCG
ED
F
SinFCosF
M
lb19760
45Cos7.3319318
0
=+=
=
EV
BHCGEV
V
F
FCosFF
F
lb4730
45Cos5176
0
= +=
=
ED
BHED
D
F
FF
F
5176 lb
56.3
45
lb6309
33.7Sin
0
==
=
ES
CGES
S
FFF
F
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LANDING GEAR (FORCE CALCULATIONS)
I
J
FJV
FIV
FJD
FID
FCG =11370 lb
FES =6309 lb
TEFED =4730 lb
FEV =19760 lb
FIS
E
G
00 == ISS FF
lb1361-
203*4730
0
=
==
JD
JDE
IV
F
FT
M
lb6091
13614730
0
=+=
=
ID
ID
D
F
F
F
lb12109
*202*)7.33(*18*)7.33(*3*19760
0
=
=++
=
JV
JVCGCG
ID
F
FSinFCosF
M
lb17110
7.3319760
0
=
+=
=
EV
JVCGIV
V
F
FCosFF
F
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WING STRUCTURES
WING STRUCTURES
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WING STRUCTURES
(FREEBODY DIAGRAM)
FAZ
FAY
FGZ
A
C
G
60
100
180
16 lb/in
lb2592
90*180*16*100
0
=
=
=
GZ
GZ
A
F
F
M
FRONT SPAR
Using Geometric relation
lbFGY 4320100*60
2592 ==
lb288
2592180*16
0
==
=
AZ
AZ
Z
F
F
F
FGY
Z
F
Y
F
X
F
L
R ZYX ====
WIN TRU TURE
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WIN TRU TURE(FREEBODY DIAGRAM)
FBZ
FBY
FEZ
B E
100
180
4 lb/inREAR SPAR
Using Geometric relation
lb648
90*180*4*100
0
=
=
=
EZ
EZ
B
F
F
M
lb1080
lb324
60648
10030
=
=
==
EY
EX
EYEX
F
F
FF
lb72
648180*4
0
==
=
BZ
BZ
Z
F
F
F
FEX
FEY
WING STRUCTURES (TRUSS)
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WING STRUCTURES (TRUSS)
G
EB
30 30 40 40 40A
L
KI
JP
O
N
MFGY =4320
FBY
FAY
17515075 200200
FEY =1080
FEX =324 100
X
Y
00 == PNY FF
1000 == POX FFJOINT O
167
10013.53
0
=
=
=
ON
ON
X
F
CosF
FJOINT P JOINT E
JOINT N
JOINT M300
02001.53
0
=
=++
=
NM
ONNM
X
F
CosFF
F
133
13.53Sin
0
=
=
=
NE
ONNE
Y
F
FF
F
50013.53
0
=
=
=
ME
MENM
X
FCosFF
F
lbF
SinFF
F
OM
ONOM
Y
133
13.53
0
==
=
lbF
FSinFF
F
MG
OMMNMG
Y
533
13.53
0
= +=
=
824
52413.53
0
=
+=
=
GE
MEGE
X
F
CosFF
F
lbF
FSinFF
F
MG
NEMEEL
Y
547
108013.53
0
=+= =
WING STRUCTURES (TRUSS)
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WING STRUCTURES (TRUSS)
lbF
SinFF
F
LJ
GJLJ
Y
547-
551
13.53
0
=
=
=
G
EB
30 30 40 40 40A
L
KI
JP
O
N
MFGY =4320
FBY
FAY
17515075 200200
FEY =1080
FEX =324 100
X
Y
lb1373
13.53
0
=
=
=
GL
GEGL
X
F
FCosF
F
lbF
SinFF
F
GK
GLGK
Y
533
5951
432013.53
0
==
=
JOINT G
lb998
017513.53
0
=
=++
=
LK
LKGL
X
F
FCosF
F
JOINT L
JOINT K
lb1412
045
0
==
=
KJ
LKKJ
X
F
FCosF
F
lbF
SinFF
F
KI
KJKI
Y
05950
6948
45
0
==++
=
WING STRUCTURES (TRUSS)
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WING STRUCTURES (TRUSS)
G
EB
30 30 40 40 40A
L
KI
JP
O
N
MFGY =4320
FBY17515075 200200
FEY =1080
FEX =324 100
X
Y
JOINT J
JOINT I
lb1148
015045
0
=
=++
=
IJ
IJKJ
X
F
FCosF
F
lbF
SinFF
F
JB
KJJB
Y
551
1550
45
0
=+=
=
lb1624
45
0
=
=
=
IB
IJIB
X
F
FCosF
F
lbF
SinFF
F
IA
KJIA
Y
8096
6
=
=
=94845
0
lbFF
F
IAAy
Y
8096==
= 0JOINT A
JOINT B
lb2698
45
0
=+=
=
BY
JBIBBY
X
F
FCosFF
F
FAY
FAX
lbF
F
BA
Y
1225-=
= 0
lbF
F
AX
Y
1225=
= 0