22022012-Lecture 1

download 22022012-Lecture 1

of 27

Transcript of 22022012-Lecture 1

  • 8/2/2019 22022012-Lecture 1

    1/27

    Lecture 1Dr Muhammad Adil Khattak

    Plane Stress

    Stress Transformation in Plane Stress

    Principal Stresses & Maximum Shear Stress

    Stress Transformation

  • 8/2/2019 22022012-Lecture 1

    2/27

    Stress Analysis - Review1. Determine critical point

    2. Solve for internal forces at that point (orreduce to cantilever)

    3. Solve for stresses at that point

    4. Add like stresses, i.e.:

    Wtotal = W1 +W2 +W3 + ...

    Xtotal = X1 +X2 +X3 + 5. Summarize stresses at that point on a stress

    element.

    6. May be necessary to use Stress

    Transformation or Mohrs circle to get max

    Chapter 8

    Chapter 9

  • 8/2/2019 22022012-Lecture 1

    3/27

    Drill Bit Isolator (

    Thrust Load = 8,000 to

    10,000 lb

    Bending Load= 125 lbs)=K*H

    Torsion Load= 300 lb-ft

    Drill Rod

    Chuck

    Isolator

    Drill Bit

    HOT

    SPOT!

    Recall from Chapter 8, already did steps 1 5:

  • 8/2/2019 22022012-Lecture 1

    4/27

    Now What????

    Solve for stress at a

    point using standard

    Equations.

    Summarize these

    stresses on an initial

    stress element or

    alignedstress element.

    Must find MAXIMUM

    stresses at that point,may be different then

    the applied stresses can

    occur at some other

    orientation plane or

    angle.

    Compare

    max stresses

    to material

    allowablesto

    determine:

    Is it safe,

    will it fail???

    step 6

  • 8/2/2019 22022012-Lecture 1

    5/27

    Introduction

    We have learned Axially

    In Torsion

    In bending

    These stresses act on cross sections of

    the members. Larger stresses can occur on inclined

    sections.

  • 8/2/2019 22022012-Lecture 1

    6/27

    Concrete Beam subject to Bending and Shear

  • 8/2/2019 22022012-Lecture 1

    7/27

    Ductile material failed in Axial loading

    Brittle Material failed in Axial Loading

  • 8/2/2019 22022012-Lecture 1

    8/27

    Ductile Material failed in Torsion

    Brittle Material failed in Torsion

  • 8/2/2019 22022012-Lecture 1

    9/27

    State of stresses varies in the body

  • 8/2/2019 22022012-Lecture 1

    10/27

    6Stress Components

  • 8/2/2019 22022012-Lecture 1

    11/27

    Plane Stress Plane Stress The state of stress

    when we analyzed bars in tension

    and compression, shafts in torsion,and beams in bending.

    Consider a 3 dimensional stresselement

    Material is in plane stress in the xy

    plane Only the x and y faces of the element

    are subjected to stresses

    All stresses act parallel to the x and yaxis

  • 8/2/2019 22022012-Lecture 1

    12/27

    Plane Stress

    Normal stress

    subscript identifies the face on which thestress acts

    Sign Convention

    Tension positive

    compression negative

    xW

  • 8/2/2019 22022012-Lecture 1

    13/27

    Plane Stress

    Shear Stress - Two subscripts

    First denotes the face on which the stress acts

    Second gives the direction on that face

    xyX

  • 8/2/2019 22022012-Lecture 1

    14/27

    Plane Stress

    A2-dimensionalview can depict therelevant stressinformation, fig. 9.1c

  • 8/2/2019 22022012-Lecture 1

    15/27

    A. Given Plane Stress State: B. What are new stresses at

    element rotation ofU??:

    Note, positivestress

    directionsshown.

    Note, positive angle (ccw)

    shown.

    Sign convention

  • 8/2/2019 22022012-Lecture 1

    16/27

    Stresses onInclined Planes

    First we know Wx, Wy, andXxy,

    Consider a new stresselement Located at the same point in

    the material as the original

    element, but is rotatedabout the z axis

    x and y axis rotatedthrough an angle U

  • 8/2/2019 22022012-Lecture 1

    17/27

    Stresses onInclined Planes

    The normal and shear stresses acting

    on they new element are:

    Using the same subscript designations

    and sign conventions described.

    Remembering equilibrium, we knowthat:

    '''' ,,

    yxyxXWW

    ''''xyyx

    XX !

  • 8/2/2019 22022012-Lecture 1

    18/27

    Stresses onInclined Planes

    The stresses in the xyplane can be expressed interms of the stresses onthe xy element by usingequilibrium.

    Consider a wedge shapedelement

    Inclined face same as the xface of inclined element.

  • 8/2/2019 22022012-Lecture 1

    19/27

    Stresses onInclined Planes

    Construct a FBD showing all theforces acting on the faces The sectioned face is (A.

    Then the normal and shearforces can be represented onthe FBD.

    Summing forces in the x and ydirections and rememberingtrig identities, we get:

  • 8/2/2019 22022012-Lecture 1

    20/27

    UX

    U

    WWWWW

    2sin2cos22' xyyxyx

    x

    !

    UXUWW

    X 2cos2sin2

    ''xy

    yx

    yx

    !

    UXUWWWWW 2sin2cos22

    ' xy

    yxyx

    y

    !

    (9.1)

    (9.2)

    (9.3)

    1.990 equationinforSubstitute UUU !

    0'

    !Y

    F

  • 8/2/2019 22022012-Lecture 1

    21/27

    Stresses onInclined Planes

    These are called the transformation equationsfor plane stress.

    They transfer the stress component form one setof axes to another.

    The state of stress remains the same.

    Based only on equilibrium, do not depend onmaterial properties or geometry

    There are Strain Transformation equations thatare based solely on the geometry of deformation.

  • 8/2/2019 22022012-Lecture 1

    22/27

    Mohrs Circle for Plane Stress

    The transformation equations for plane

    stress can be represented in a graphicalformat known as Mohrs circle.

    This representation is useful invisualizing the relationships betweennormal and shear stresses acting onvarious inclined planes at a point in astressed body.

  • 8/2/2019 22022012-Lecture 1

    23/27

    Mohr s CircleRules

  • 8/2/2019 22022012-Lecture 1

    24/27

    Construction of Mohrs circle 1.Determine the point on the body in which the principal stresses are to be determined. 2. Treating the load cases independently and calculated the stresses for the point

    chosen. 3. Choose a set of x-y reference axes and draw a square element centered on the axes. 4.Identify the stresses x, y, and xy = yx and list them with the proper sign. 5.Draw a set of - coordinate axes with being positive to the right and being

    positive in the upward direction. Choose an appropriate scale for the each axis. 6.Using the rules on the previous page, plot the stresses on the x face of the element in this coordinate system (point V).Repeat the process for the y face

    (point H). 7.Draw a line between the two point V and H. The point where this line crosses the axis establishes the center of the circle.

    8.Draw the complete circle. 9. The line from the center of the circle to point V identifies the x axis or reference axis for angle measurements (i.e. = 0). Note: The angle between the reference axis and the axis is equal to 2p.

  • 8/2/2019 22022012-Lecture 1

    25/27

  • 8/2/2019 22022012-Lecture 1

    26/27

  • 8/2/2019 22022012-Lecture 1

    27/27