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TUGAS 4 KONSEP JARINGAN

JUDUL : SUBNETTINGPERCOBAAN :N = sum of borrowed host bit .n = sum of host bit .1. How many usable subnets (not theoretical) do you have when using a subnet mask of255.255.255.240 on Network ID 201.114.168?Pinjam = 32 – 28 = 4;Subnet yang digunakan = 24 – 2 = 16-2=14;2. You are given Network ID 222.72.157, with a subnet mask of 255.255.255.248 to setup.How many subnets and hosts will you have?32-3=29;Network = 222.72.157.0/29Sum of host in a Subnet = 23 – 2 = 8-2 = 6Sum of subnet = 25 – 2 = 32 – 2 = 3030 useable subnets and 6 useable hosts on each subnet3. You are assigned a Network ID of 198.162.10 and asked to configure the network toprovide at least six useable subnets with at least 25 hosts on each subnet. What is theBEGINNING IP address of the LAST useable subnet in the network?Sum of host in a subnet = 25Sum of subnet = 6Search borrowed network bit => 6 = 2N - 28 = 2NN = 3192.168.10 000 0001 32010 64011 96100 128101 160110 192111 224first ip for last subnet = 198.162.10.193

4. How many useable hosts are on each subnet when the Network ID is 199.215.210 and thesubnet mask is 255.255.255.252?Class = CNetwork = 199.215.210.0/30Sum of host in each subnet= 22 – 2 = 4 -2 = 2

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5. You are given Network ID 190.90, with a subnet mask of 255.255.192.0 to setup. What arethe high-order bits (Leading Bit Values) for this network?Binary 10Class B ,high order bits = Binary “10”,network bit = 14 ,host bit = 16.6. You are assigned a Network ID of 162.160 and asked to configure the network to provide atleast 60 useable subnets? What would be the subnet mask for this network?Network = 162.160.0.026 – 2 = 64 -2 = 62 , so the sum of borrowed host bit is 6So the subnetmask is 255.255.252.07. How many useable hosts are on each subnet when the Network ID is 150.150 and thesubnet mask is 255.255.192.0?Network = 150.150.0.0Borrowed host bit = 18Sum of host bit = 32 – 18 = 14.So the sum of host is2n – 2 = 214 – 2 = 16.3828. You are assigned a Network ID of 145.19 and asked to configure the network to provide atleast 100 useable subnets with at 500 hosts on each subnet. What is the ENDING IP addressof the EIGHTH useable subnet in the network?Network = 145.19.0.0Class = BNormal mask = 255.255.0.0Sum of subnet = 2N – 2 =27 – 22N = 102N = 7So sum of borrowed network bit is 7 .Range from each subnet is plus 28th SubnetIp first = 145.19.17.1Ip last = 145.19.17.254Ip broadcast = 145.19.17.255

3NANDA AFIF ASHARI | 1 D4 LJ IT | 2110165028

9. You are a private contractor hired by the large company to setup the network for theirenterprise. The Network ID is 33 and you need at least 125 subnets in their large networkwith at least 125,000 hosts on each of the subnets. What would be the subnet mask for thisnetwork?Network = 33.0.0.0Class = ANormal subnet = 255.0.0.0Sum of subnet = 125 ,Sum of host = 125.000Sum of subnet = 2N – 22N = 125 +22N = 127N = 7.Subnetmask = 255.254.0.010. You are given Network ID 55.0.0.0, with a subnet mask of 255.240.0.0 to setup. How manysubnets and hosts will you have?Network = 55.0.0.0Subnetmask = 255.240.0.0Sum of subnet = 2N – 2 = 24 – 2 = 16 - 2 = 14Sum of host = 2n – 2 = 220 – 2 = 1.048.576 - 2 = 1.04.,57414 useable subnets and 1,048,574 useable hosts on each subnet