2014 Geometry Practice SOL version 2 P Q - Quia · Triangles PNU, PGU, ... 2014 Geometry Practice...
Transcript of 2014 Geometry Practice SOL version 2 P Q - Quia · Triangles PNU, PGU, ... 2014 Geometry Practice...
2014 Geometry Practice SOL version 2
Name: __________________________
1. Given: Parallelogram SBHE where
and .
What value of x proves this
parallelogram is a rhombus?
____ 2. The figure represents a ramp
with handrails.
Segments PQ and ST are
parallel to VW.
Segments QR and TU are
parallel to WX.
Segments PV and QW are
parallel to RX.
If , what is
?
a. 69º b. 90º c. 111º d. 159º
____ 3. Three triangles that do not overlap
are shown on the coordinate grid.
The coordinates of all vertices are
integers.
Which statement is true?
a. b. c. d.
____ 4. Which of the following sets of lengths can represent the measures of the sides of a right triangle?
a. 12, 16, 20 b. 8, 10, 17 c. 4, 5, 6 d. 5, 10, 13
S
B
E
H
2x + 14
3x + 8
111
P Q
R
ST
U
V W
X
R K A
T
M
1 2 3 4 5 6–1–2–3–4–5–6 x
1
2
3
4
5
6
–1
–2
–3
–4
–5
–6
y
2014 Geometry Practice SOL version 2
____ 5. An angle congruent to
angle C is being
constructed.
Which ray could be
drawn to construct an
angle congruent to ?
a.
b.
c.
d.
6. Line l and z are cut by a transversal
What value of x proves that l // z ?
____ 7. A polygon is shown:
What is the measure
of ?
a. 57° b. 246° c. 123° d. 90°
____ 8. A rectangular pyramid is shown.
What is the volume of the pyramid?
a. 336 m³ b. 144 m³ c. 504 m³ d. 1008 m³
C
M
A
P
H
Q
l
z
137
(5x - 123)
147
P U
YT
CF
18 m
8 m
7 m
2014 Geometry Practice SOL version 2
____ 9. The Venn diagram represents students
who play instruments in the orchestra.
Identify each region of the Venn
diagram that represents students who
play only the viola and the harp.
a. 6 b. 12 c. 6, 9, 10, 12 d. none
____ 10. An architect used this diagram to
design a curved balcony. He drew a
circle with a radius of 30 feet and a
central angle of 63° to determine the
length of railing needed for the
balcony.
Which is the closest to the length of
railing needed for the curved section
of the balcony?
a. 188 ft b. 16 ft c. 495 ft d. 33 ft
____ 11. Given: H lies on and G lies on
Which condition proves ?
a. c. b. d.
____ 12. Given : B(–9, –5) and K(5, 7) What is the slope of ?
a.
b.
c.
d.
cornet oboe
viola harp
63
30
Y
H
RG
S
7
6
7
6
6
7
6
7
2014 Geometry Practice SOL version 2
____ 13. Look at this triangle.
Which triangle is similar to the given triangle?
a.
c.
b.
d.
____ 14. The floor plan for a modern home
is modeled by the composite of
the regular octogon and triangle
shown.
What is closest to the measure of
?
a. 170º b. 165º c. 155º d. 175º
J
F
D
15
cm
20.63 cm
20.63 cm
11.25 cm
21.87 cm
21.87 cm
8.44 cm 10.61 cm
14.15 cm
11.25 cm
15.47 cm15.47 cm15 cm
15 cm
20.63 cm
R
B
L
2014 Geometry Practice SOL version 2
____ 15. Given: Circle U with center at (3, –8)
What equation could represent circle U?
a. c.
b. d.
____ 16. Which is a valid conclusion that can be drawn from these statements?
If a quadrilateral is a rectangle, then it is a parallelogram.
If a quadrilateral is a parallelogram, then its opposite sides are congruent.
a. Opposite sides of a rectangle are congruent.
b. Every parallelogram is a rectangle.
c. Opposite sides of a quadrilateral are congruent.
d. Every quadrilateral is a rectangle.
____ 17. Given X (–4, 8) and B (7, –3)
What is the length of ?
a. b. c. d.
____ 18. This figure is composed of
an isosceles trapezoid and a
regular octagon.
What is the value of x ?
a. 123 b. 174 c. 96 d. 102
X
B
1 2 3 4 5 6 7 8 9–1–2–3–4–5–6–7–8–9 x
1
2
3
4
5
6
7
8
9
–1
–2
–3
–4
–5
–6
–7
–8
–9
y
51 51
2014 Geometry Practice SOL version 2
____ 19. The volume of a cube is 27 cubic centimeters. What is the surface area of the cube?
a. 162 cm² b. 54 cm² c. 81 cm² d. 9 cm²
____ 20. Which diagram shows a pair of angle measures that prove lines w and n are parallel?
a.
c.
b.
d.
21. The ratio of the lengths of the radii of two sphere is 5:9. What is the ratio of the volumes of these two spheres?
____ 22. This container is composed
of a right circular cylinder and
a right circular cone.
Which is closest to the surface
area of the contianer?
a. 1832 in² b. 1451 in² c. 1071 in² d. 2212 in²
w n
k
h
124°
56°
w n
k
h
124° 56°
w n
k
h
124°
124°
w n
k
h
124°
124°
1 5 9 25 45 81 125 729
15 in
in8
in22
2014 Geometry Practice SOL version 2
____ 23. Let p represent:
Two angles are vertical angles.
Let q represent:
The angles are congruent.
What is the symbolic representation of the following statement?
If two angles are vertical angles, then the angles are congruent.
a. b. c. d.
____ 24. Quadrilateral JXGZ is shown.
If JXGZ is reflected across the
x-axis , what are the
coordinates of J’ ?
a. b. c. d.
____ 25. This figure show parallel
stair railings through points
G, V, U, and X.
What is the value of x ?
a. 25 b. 115 c. 65 d. 45
J
X
G
Z
1 2 3 4 5 6 7 8 9–1–2–3–4–5–6–7–8–9 x
1
2
3
4
5
6
7
8
9
–1
–2
–3
–4
–5
–6
–7
–8
–9
y
G V U X
65
2014 Geometry Practice SOL version 2
26. Click and drag each selected reason to the correct box
Given: Figure KAQE with diagonal
;
Complete the proof of by selecting the
reasons for the last two statements.
Statements Reasons
Given
____ 27. Which could be the lengths of three sides of a triangle?
a. 14 ft, 3 ft, 11 ft c. 28 ft, 7 ft, 20 ft
b. 21 ft, 15 ft, 12 ft d. 18 ft, 9 ft, 6 ft
____ 28. Part of a marching band formed by a triangle made with clarinet players on one side, cornet players on one side,
and oboe players on the third side.
• The angle formed by the clarinet and oboe players measured 43º
• The angle formed by the oboe and cornet players measured 72º
Which orders the sides of this triangle from least to greatest using the instrument names?
a. cornet, oboe, clarinet c. cornet, clarinet, oboe
b. clarinet, oboe, cornet d. oboe, clarinet, cornet
____ 29. An equilateral triangle is folded in half.
What is x, the height of the equilateral
triangle?
a. cm b. 30 cm c. cm d. 15 cm
K
E
A
Q
cm30
2014 Geometry Practice SOL version 2
____ 30. Circle V has a center at (3, –5) and a diameter of 10 units. Which point lies on circle V?
a. (3, –5) b. (13, 5) c. (11, 1) d. (–1, –8)
____ 31. A spectator is viewing the six cars
of a roller coaster as it travels down a
hill at an amusement park.
Which is the closest to the total
length of the six cars?
a. 34.2 ft b. 26.1 ft c. 14.1 ft d. 15.3 ft
____ 32. What type of construction
is illustrated in the figure?
a. An angle congruent to c. The bisection of
b. A line segment congruent to d. The bisection of
____ 33. Parallelogram ZNXE is a
rhombus with
What is the ?
a. 34° b. 146° c. 112° d. 56°
22 ft
40
K B
QV
Z N
XE
D
34
2014 Geometry Practice SOL version 2
____ 34. Triangles PNU, PGU, and ZNU
are show on the coordinate grid,
and all the vertices have
coordinates that are integers.
Which statement is true?
a. Only and are congruent.
b. Triangle PNU, , and are all congruent
c. No two triangles are congruent.
d. Only and are congruent.
____ 35. Using the information given,
which congruence postulate or
theorem can be used to prove
that ?
a. Side-Angle-Side Postulate c. Hypotenuse-Leg Theorem
b. Side-Side-Side Postulate d. Angle-Angle-Side Theorem
____ 36. In this figure, parallel lines s and t
are intersected by line j.
Which pair of angles is NOT
supplementary?
a. and b. and c. and d. and
P
N Z
G
U
1 2 3 4 5–1–2–3–4–5 x
1
2
3
4
5
–1
–2
–3
–4
–5
y
A
L
Y
M
E
s
t
j
2014 Geometry Practice SOL version 2
37. Click on the grid to plot the point you want to select.
Plot the center of the circle
defined by the equation:
____ 38. The diagonals of rectangle UBJR intersect
at the point (0, 3). One of the vertices
of the rectangle UBJR is located at (–4,
5).
Which of the following could be the
location of another vertex of this
rectangle?
a. (0, 1) b. (–2, 4) c. (0, 5) d. (4, 1)
39. The lengths of two sides of a triangle are 13 feet and 47 feet. What is the range of possible lengths, in feet, for
the third side, x, of this triangle?
1 2 3 4 5 6 7 8 9 10–1–2–3–4–5–6–7–8–9–10 x
1
2
3
4
5
6
7
8
9
10
–1
–2
–3
–4
–5
–6
–7
–8
–9
–10
y
1 2 3 4 5 6 7 8 9 10–1–2–3–4–5–6–7–8–9–10 x
1
2
3
4
5
6
7
8
9
10
–1
–2
–3
–4
–5
–6
–7
–8
–9
–10
y
2014 Geometry Practice SOL version 2
____ 40. Given: Circle A
Which is the closest to the area
of the shaded sector of circle A
?
a. 249 in² b. 131 in² c. 24 in² d. 380 in²
____ 41. Given: Circle M
What is the value of y?
a. 50 b. 86 c. 94 d. 36
____ 42. Given the measures shown in the diagram, which two triangles are congruent?
a. T and W b. X and E c. T and E d. X and W
A
124
11 in
MF
W
V
G
50
94
T X
11
44
1163
63 44W E
1111
44 44
73
63
2014 Geometry Practice SOL version 2
____ 43. Dani is drawing the
perpendicular bisector of .
Which point is on the
perpendicular bisector of ?
a. G b. E c. Z d. F
____ 44. Which best describes
the construction in the
diagram shown?
a. The bisector of a line segment
b. A line segment congruent to a given line segment
c. A perpendicular to a given line at a point on the line
d. A perpendicular to a given line from a point not on the line
____ 45. Bofur attached a wire
between two poles on a hill
as shown.
Which is closest to x, the
distance between the two
poles?
a. 43 yd b. 41 yd c. 134 yd d. 123 yd
Y L
F
Z
G
E
Z F
140
17
yd
2014 Geometry Practice SOL version 2
____ 46. For which polygon are both and lines of symmetry?
a.
c.
b.
d.
____ 47. A cell phone box in the shape of a rectangular
prism is shown. The height of the box is 2 cm.
The height of the original box will be increased
by 3.5 centimeters so a new instruction manual
and an extra battery can be included. Which is
closest to the total surface area of the new box?
a. 464 in² b. 800 in² c. 586 in² d. 677.5 in²
____ 48. What is the contrapositive of the following statement?
If the measure of an angle is 90º, then it is a right angle.
a. If the measure of an angle is not 90º, then it is not a right angle.
b. If it is not a right angle, then the measure of an angle is not 90º.
c. If the measure of an angle is not 90º, then it is a right angle.
d. If it is a right angle, then the measure of an angle is 90º.
2 in
16 in
14.5in
2014 Geometry Practice SOL version 2
49. Line h contains the points
(–6, 5) and (8, –2).
Plot a point other than point Z
with integral coordinates that
is on a line parallel to h and
passes through point Z.
____ 50. A company is creating a new cylindrical container to replace its original cylindrical container.
• The new container will have 9 times the volume of the original container.
• The height of the new container will remain the same as the height of the original container.
The length of the radius of the new container will be --
a. 3 times the length of the radius of the original container
b. 81 times the length of the radius of the original container
c. 9 times the length of the radius of the original container
d. 27 times the length of the radius of the original container
(2, –8)
Z
h
1 2 3 4 5 6 7 8 9 10–1–2–3–4–5–6–7–8–9–10 x
1
2
3
4
5
6
7
8
9
10
–1
–2
–3
–4
–5
–6
–7
–8
–9
–10
y
2014 Geometry Practice SOL version 2
2014 Geometry Practice SOL version 1
Answer Section
1. ANS:
6
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Polygons and Circles
KEY: quadrilaterals MSC: Question 33 NOT: Technology assisted question
2. ANS: D
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: parallel lines MSC: Question 18
3. ANS: B
Match 90º angles and then short to short and long to long legs
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Triangles and Logic
KEY: similar triangles MSC: Question 29
4. ANS: A
Must satisfy the Pythagorean theorem.
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 8
TOP: Triangles and Logic KEY: Pythagorean MSC: Question 22
5. ANS: D
1) Place the compass on point C and draw an arc across both sides of the angle. Without changing the
compass radius, place the compass on point M and draw a long arc crossing the ray. 2) Set the
compass so that its radius is intersections on the two rays in the drawn angle. Place the compass on
intersection point on the new ray and draw an arc intersecting the one drawn in the previous step.
Label the intersection point 3) Use the straightedge to draw ray that completes the angle
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: construction MSC: Question 6
6. ANS:
52
2014 Geometry Practice SOL version 2
Alternate exterior angles are congruent in parallel lines;
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: parallel lines MSC: Question 15 NOT: Technology assisted question
7. ANS: C
Interior angles of a hexagon (6-sided figure) is found with (n-2) x 180 = 720
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Polygons and Circles
KEY: interior angles MSC: Question 42
8. ANS: A
Volume of a pyramid: where B is area of the base and h is the height
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Three-Dimensional Figures
KEY: volume MSC: Question 49
9. ANS: B
Have to eliminate any area that has instruments other than viola and harp.
Only Group 12 plays the viola and the harp.
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 2
TOP: Triangles and Logic KEY: Venn diagram
MSC: Question 5 NOT: Technology assisted question
10. ANS: D
We are finding the length of the arc(railing) in a circle with a radius of 30 feet and a central angle of the arc of
63°.
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 10
TOP: Polygons and Circles KEY: circles | arc length
MSC: Question 41
11. ANS: A
AA Triangle similarity theorem; included angle R is the shared angle.
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Triangles and Logic
KEY: similar triangles MSC: Question 32
2014 Geometry Practice SOL version 2
12. ANS: D
Slope =
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: slope MSC: Question 16
13. ANS: B
Isosceles triangle. Base side is smaller than original base side, so other sides (isosceles) must be smaller than
original.
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Triangles and Logic
KEY: similar triangles MSC: Question 26
14. ANS: B
Once around a point is 360. Interior angles for triangle is 60 and for octogon is 135 for a total of 195.
Remaining angle is 360 - 195 = 165
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Polygons and Circles
KEY: interior angles MSC: Question 34
15. ANS: B
From SOL formula sheet equation of a circle:
center at (3, –8): with
Remember that a negative of a negative is a positive.
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 10
TOP: Polygons and Circles KEY: circles | circle equation
MSC: Question 35
16. ANS: A PTS: 1 REF: 2014 Geometry SOL Exam
LOC: Ch 2 TOP: Triangles and Logic KEY: Law of Syllogism
MSC: Question 8
17. ANS: C
Distance formula:
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: distance MSC: Question 10
18. ANS: C
Leg angles in an isosceles trapezoid are supplementary; so the angle in the trapeziod next to x is 129°. A
regular octagon has an interior angle of 135° (Int + Ext = 180 and Ext = 360/8 = 45)
Once around a point is 360°; so °
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Polygons and Circles
KEY: interior angles | exterior angle MSC: Question 47
19. ANS: B
6
7
2014 Geometry Practice SOL version 2
The formula for the volume of a cube is V = s³. The formula for surface area is SA = 6s².
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 12
TOP: Three-Dimensional Figures KEY: volume | surface area
MSC: Question 43
20. ANS: C
Angles have to involve both line w and line n and have the transversal as a common line. Using combinations
of linear pairs and/or vertical angles, they need to form consecutive interior angles (since no consecutive
exterior angles theorem exists).
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: parallel lines MSC: Question 7
21. ANS:
125
Volume is a cubic relationship, so the ratio of the radii (5:9) must be cubed: 125:729
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 13
TOP: Three-Dimensional Figures KEY: spheres | ratios
MSC: Question 46 NOT: Technology assisted
22. ANS: B
Surface area = surface area of cylinder - base covered by the cone + lateral area of cone
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Three-Dimensional Figures
KEY: surface area MSC: Question 36
23. ANS: B
Order the same and no nots in the statements.
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 2
TOP: Triangles and Logic KEY: symbols MSC: Question 1
24. ANS: B
Reflection over x-axis , then you negate the y values
PTS: 1 REF: 2014 Geometry SOL Exam STA: G.3
LOC: Ch 9 TOP: Coordinate Relations and Transformations
KEY: reflections MSC: Question 14
25. ANS: C
Corresponding angles are congruent, so x = 65
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: parallel lines MSC: Question 9
26. ANS:
2014 Geometry Practice SOL version 2
Reflexive and SSS
A side is congruent to itself because of the Reflexive property
3 Sides are congruent; so the SSS Thrm needs to be used
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 4
TOP: Triangles and Logic KEY: congruent triangles | proof
MSC: Question 27 NOT: technology assisted
27. ANS: B
The rule is that any two sides must be greater than the third in a triangle. We add the two smallest two numbers
together and if its bigger than the largest number then those numbers will form a triangle. Only 12 ft, 15 ft, 21
ft meets that rule.
PTS: 1 REF: 2014 Geometry SOL Exam STA: G.6
LOC: Ch 5 TOP: Triangles and Logic KEY: triangles
MSC: Question 31
28. ANS: A
Missing angle is 65 and represents the middle angle; cornet players (ones not mentioned in the smallest angle)
form the smallest side and clarinet players (ones not mentioned in the largest angle) form the largest side.
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 5
TOP: Triangles and Logic KEY: triangle sides
MSC: Question 24
29. ANS: C
Pythagorean Theorem, special case right
triangles or trig can solve this
Since all sides of an equilateral triangle are
congruent, then the hypotenuse of the folded
triangle is 30.
The side opposite a 60 degree angle is .
Another way to solve it is using trig:
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 8
TOP: Triangles and Logic KEY: trigonometry | special case right triangles | Pythagorean
MSC: Question 25
30. ANS: D
Given the center and the diameter (twice the radius) we can figure out the equation of circle V.
Now plug in the given points and see which satisfy the equation:
2014 Geometry Practice SOL version 2
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 10
TOP: Polygons and Circles KEY: circle equation
MSC: Question 40
31. ANS: A
Need to use trig: sin --> opposite side and hypotenuse
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 8
TOP: Triangles and Logic KEY: trigonometry
MSC: Question 28
32. ANS: C
The three arcs that have been drawn are the first three steps to bisect .
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: construction MSC: Question 4
33. ANS: D
Since the diagonals of a rhombus bisect opposite angles, then angles DEZ, DEX and DNZ are all 34°. The three
angles inside each triangle must add to 180° and the diagonals are perpendicular, so all angle D’s are 90°.
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Polygons and Circles
KEY: angles | quadrilaterals MSC: Question 39
34. ANS: B
These are three of the four congruent triangles in a rhombus. SSS or SAS (with perpendicular diagonals)
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 4
TOP: Triangles and Logic KEY: triangle congruence
MSC: Question 20
35. ANS: D
Given an angle and a non-included side; the vertical angles add the final angle for AAS
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Triangles and Logic
KEY: congruent triangles MSC: Question 30
36. ANS: C
Both 4 and 8 are obtuse angles and cannot add to 180.
2014 Geometry Practice SOL version 2
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: parallel lines MSC: Question 3
37. ANS:
(–1, –4)
From the Geometry equation sheet:
Equation of a circle
so center is
(h, k) or (–1, –4) with radius = 2
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 10
TOP: Coordinate Relations and Transformations KEY: circle equation
MSC: Question 48 NOT: Technology assisted question
38. ANS: D
Diagonals in a rectangle are the same length and bisect each other. The intersection is the mipoint between the
two vertices along that diagonal. If one vertex is located at (–4, 5), then it was right 4 and down 2 to get to the
midpoint (0, 3). We have to travel the same distance to get to the other endpoint (0 + 4, 3 - 2) or (4, 1).
PTS: 1 REF: 2014 Geometry SOL Exam
TOP: Coordinate Relations and Transformations KEY: quadrilaterals | diagonals
MSC: Question 44
39. ANS:
34 60
Largest side - smallest side < x < smallest side + largest side
47 - 13 < x < 13 + 47
34 < x < 60
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 5
TOP: Triangles and Logic KEY: triangle sides
MSC: Question 21 NOT: Technology assisted question
40. ANS: B
Area of a sector is the area of the circle times the ratio of the central angle divided by 360.
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 10
TOP: Polygons and Circles KEY: circles | sector area
(–1, –1)1 2 3 4 5 6 7 8 9 10–1–2–3–4–5–6–7–8–9–10 x
1
2
3
4
5
6
7
8
9
10
–1
–2
–3
–4
–5
–6
–7
–8
–9
–10
y
2014 Geometry Practice SOL version 2
MSC: Question 45
41. ANS: D
Inscribed angles WGF and WVF share the same arc and therefore have the same measure.
The 3 angles inside the triangle not containing y must add to 180; so
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 10
TOP: Polygons and Circles KEY: circles | angles
MSC: Question 37
42. ANS: B
Same lengths opposite same angle measures (even if triangles have been flipped -- put in the third angle
measures!)
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Triangles and Logic
KEY: congruent triangles MSC: Question 23
43. ANS: C
Construct a isosceles triangle with the same legs above and below the line. Connect the extreme angles. The
point, Z, lies on that line, which is a perpendicular bisector of .
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Triangles and Logic
KEY: construction MSC: Question 2
44. ANS: A
Perpendicular bisector cuts line segment in half
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: construction MSC: Question 12
45. ANS: C
x is the adjacent side in the right triangle, so we use trigonometry:
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 8
TOP: Triangles and Logic KEY: trigonometry
MSC: Question 19
46. ANS: C
x = k is a vertical line and y = h is a horizontal line. Lines of symmetry cut the figure in half.
PTS: 1 REF: 2014 Geometry SOL Exam
TOP: Coordinate Relations and Transformations KEY: symmetry
MSC: Question 17
47. ANS: B
Rectangular prism surface area: new height is 5.5 cm (2 + 3.5).
2014 Geometry Practice SOL version 2
New SA:
PTS: 1 REF: 2014 Geometry SOL Exam KEY: surface area
MSC: Question 38
48. ANS: B
Original statement: If the measure of an angle is 90º, then it is a right angle.
contrapositive tells us to flip and negate clauses and we get: If it is not a right angle, then the measure of an
angle is not 90º.
PTS: 1 REF: 2014 Geometry SOL Exam STA: G.1 | G.1.a
LOC: Ch 2 TOP: Triangles and Logic KEY: inverse | logic
MSC: Question 13
49. ANS:
(–8, –3)
Line h has a slope of .
Any point satisfying will be correct.
(–8, –3) is one point that solves that equation.
Go left 2 and up 1 or right 2 and down 1 from point Z to get another point.
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: parallel lines MSC: Question 11 NOT: Technology assisted question
50. ANS: A
Volume of a cylinder:
If height stays the same and the volume is 9 times as large, then the radius has to triple -- 3 times the length of
the radius of the original container
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Three-Dimensional Figures
KEY: volume MSC: Question 50
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