2011 topic 01 lecture 2 - empirical and molecular formulae

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Lecture 2 Empirical and Molecular Formulae IB Chemistry Power Points Topic 1 Quantitative Chemistry www.pedagogics.ca

Transcript of 2011 topic 01 lecture 2 - empirical and molecular formulae

Page 1: 2011 topic 01   lecture 2 - empirical and molecular formulae

Lecture 2

Empirical and Molecular Formulae

IB Chemistry Power Points

Topic 1

Quantitative Chemistrywww.pedagogics.ca

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Percent Composition by Mass

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Recall: the relative molecular mass of H2SO4 can be determined as follows:

Hydrogen 2 atoms × 1.008 = 2.01Sulfur 1 atom × 32.07 = 32.07Oxygen 4 atoms × 16.000 =64.00

MR 98.09

The percent composition by mass states the fraction of the total mass of each element in the compound.

For example % sulfur

32.07% 100 32.7%

98.09S

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Similarly:

2.016% 100 2.1%

98.09H

64.00% 100 65.2%

98.09O

Note the sum of these values should add to 100%

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Empirical Formula Determination

That is “empirical” not Empire you fool!

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Definition

The empirical formula is the formula that gives

the simplest whole number ratio of atoms in

a compound

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An example

Adipic acid contains 49.32% C, 43.84% O, and 6.85% H by mass. What is the empirical formula of adipic acid?

49.32 14.107

12.01

g C mol Cmol C

g C

Come to the dark

side

1. Assume 100g of the compound

2. So, in 100 g of adipic acid, there would be 49.32 g of C, 43.84 g of O and 6.85 g of H.

3. Determine moles of each element. For example: carbon

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An example continued

H mol 78.6mol g 1.01

H g 85.61-

Similarly:

I’m your father!

O mol 74.2mol g 16.00

O g 84.431-

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Step 4. Divide each value of moles by the smallest of the values.

1 2.74 mol 74.2 :

2.5 2.74 mol 78.6 :

1.5 2.74 mol .124 :

Oxygen

Hydrogen

Carbon

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Step 5. If necessary, multiply each number by an integer to obtain all whole numbers.

Carbon: 1.5 Hydrogen: 2.5 Oxygen: 1x 2 x 2 x 2

3 5 2

Empirical formula:C3H5O

2

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Alternatively, the empirical formula can be determined from mass composition data.

Using the same example: a 21.6 g sample of adipic acid is decomposed yielding some carbon, 9.5 g of oxygen gas and 1.5 g of hydrogen gas. What is the empirical formula of adipic acid?

First find the number of MOLES of each elementThen determine the lowest whole number ratio for the mole values

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A MOLECULAR FORMULA is the actual chemical formula of a compound. The molecular formula will contain elements in the same ratio as the empirical formula.

Molecular formulae are whole number multiples of empirical formulae.

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We have determined that the empirical formula for adipic acid is C3H5O2. If the molar mass of adipic acid is 146 g/mol, what is the molecular formula of adipic acid?

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1. Find the molar mass of C3H5O2

3(12.01 g) + 5(1.01) + 2(16.00) = 73.08 g

2. Divide the molecular mass by the mass given by the empirical formula.

146 ÷ 73.08 = 2

3. Multiply the empirical formula by this number to get the molecular formula.

(C3H5O2) x 2 = C6H10O4