2. Location M
Transcript of 2. Location M
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FACILITY LOCATION
MODELS
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Identify important factors
Weight factors(0.00 - 1.00)
Subjectively score each factor(0- 100)
Sum weighted scores
Location ModelsA. Qualitative Model
i) Weighted Rating Method (Point rating)
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Location ModelsI. Qualitative Model
Example:
Relevant Factors Assignedweight
Scores for Locations
A B C D
Production cost
Raw material supply
Labour availability
Cost of living
Environment
Markets
0.35
0.25
0.20
0.05
0.050.10
50
70
60
80
5070
40
80
70
70
6090
60
80
60
40
7080
30
60
50
80
9050
1.0
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ii) Factor Rating Method
Table gives the various factors considered for location decision and the factor
ratings assigned to each factor based on its importance for location decision
and location rating for the location alternatives based on the merit of each
location in each of the factors considered.
i) Factor Rating Method
Identify important factors
Factor Rating (0 - 5)
Location Rating (0 - 10)
Product Rating
Sum product scores
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Example:
Factor Factor Rating
Location Rating Product of Rating
Location A Location B Location A Location B
1. Tax advantage 4 8 6 32 24
2. Suitability oflabour skill
3 2 3 6 9
3. Proximity tocustomers
3 6 5 18 15
4. Proximity to
suppliers
5 2 4 10 20
5. Adequacy ofwater
1 3 3 3 3
6. Receptivity ofcommunity
5 4 3 20 15
7. Quality ofeducationsystem
4 1 2 4 8
8. Access to rail andtransportation
3 10 8 30 24
9. Suitability ofclimate
2 7 9 14 18
10. Availability ofpower
2 6 4 12 8
Total score 149 144
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Locate facility at center of geographic area
Based on weight and distance traveled
Establish grid-map of area Identify coordinates
and weights shipped
for each location
B. Quantitative Model
i) Center-of-Gravity Technique
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Grid-Map Coordinates
where,x, y= coordinates of the new
facility at center of gravityx
i
, yi
= coordinates of existingfacility i
Wi= annual weight shipped fromfacility i
n
Wii =1
xiWii =1
n
x = n
Wii =1
yiWii =1
n
y =
x1 x2 x3 x
y2
y
y1
y3
1 (x1, y1), W1
2 (x2, y2), W2
3 (x3, y3), W3
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Center-of-Gravity Technique
A B C D
x 200 100 250 500y 200 500 600 300Wt 75 105 135 60
y
700
500
600
400
300
200
100
0 x700500 600400300200100
A
B
C
D
(135)
(105)
(75)
(60)
Miles
Miles
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Center-of-Gravity Technique
y
700
500
600
400
300
200
100
0 x700500 600400300200100
A
B
C
D
(135)
(105)
(75)
(60)
Miles
Miles
A B C D
x 200 100 250 500y 200 500 600 300Wt 75 105 135 60
Example S5.2
x= = = 238n
Wii =1
xiWii =1
n
n
Wii =1
yiWii =1
n
y= = = 444(200)(75) + (500)(105) + (600)(135) + (300)(60)
75 + 105 + 135 + 60
(200)(75) + (100)(105) + (250)(135) + (500)(60)
75 + 105 + 135 + 60
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Center-of-Gravity Technique
A B C D
x 200 100 250 500y 200 500 600 300Wt 75 105 135 60
y
700
500
600
400
300
200
100
0 x700500 600400300200100
A
B
C
D
(135)
(105)
(75)
(60)
Miles
Miles Center of gravity(238, 444)
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Question: What is the best location for a new Z-Mobilewarehouse/temporary storage facility considering only
distances and quantities sold per month?
Centroid method example Several automobile showrooms are located according to
the following grid which represents coordinate locations
for each showroom
S howroom No of Z-Mobile s
s old pe r month
A 1250
D 1900
Q 2300X
Y
A(100,200)
D(250,580)
Q(790,900)
(0,0)
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Economic Analysis Method
Particulars Site
A B Ci) Total Investments inland, building, Plant &m/c (Rs.0000)
ii) Revenues (0000)
iii) Expenses on rawmaterials (0000)
iv) Distribution cost(0000)
v) Expenses onutilities (0000)
vi) Wages & Salaries
250
410
89
40
5025
325
515
100
60
4030
270
360
98
25
2528
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Median ModelFacility (F) Coordinates Cost of moving one unit Annual load
of Location by unit distance (Rs) (L) Units
Bareilly (10, 80) 10 452
Shahjanpur (30, 60) 10 678
Gonda (80, 50) 10 483
Kanpur (50, 10) 10 711
Sultanpur (80, 10) 10 539
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2863-----------------------------
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Load-Distance
Technique Compute Load x Distance for each site
Choose site with lowestLoad x Distance
Distance can be actualor straight-line
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Load-Distance Example
Potential SitesSite X Y1 360 1802 420 450
3 250 400
SuppliersA B C D
X 200 100 250 500Y 200 500 600 300
Wt 75 105 135 60
Compute distance from each site to each supplier
= (200-360)2 + (200-180)2dA = (xA - x1)2 + (yA - y1)
2Site 1 = 161.2
= (100-360)2 + (500-180)2dB = (xB - x1)2 + (yB - y1)
2 = 412.3
dC = 434.2 dD = 184.4
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Load-Distance Example
Site 2 dA = 333 dC = 226.7dB = 323.9 dD = 170
Site 3 dA = 206.2 dC = 200dB = 180.4 dD = 269.3
Compute load-distance
i = 1
nli diLD =
Site 1 = (75)(161.2) + (105)(412.3) + (135)(434.2) + (60)(434.4) = 125,063Site 2 = (75)(333) + (105)(323.9) + (135)(226.7) + (60)(170) = 99,789
Site 3 = (75)(206.2) + (105)(180.3) + (135)(200) + (60)(269.3) = 77,555*
* Choose site 3
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Location Analysis
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Location Analysis
Exhibit S5.2
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Location Analysis
Exhibit S5.3
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Location Analysis