2. Location M

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    FACILITY LOCATION

    MODELS

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    Identify important factors

    Weight factors(0.00 - 1.00)

    Subjectively score each factor(0- 100)

    Sum weighted scores

    Location ModelsA. Qualitative Model

    i) Weighted Rating Method (Point rating)

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    Location ModelsI. Qualitative Model

    Example:

    Relevant Factors Assignedweight

    Scores for Locations

    A B C D

    Production cost

    Raw material supply

    Labour availability

    Cost of living

    Environment

    Markets

    0.35

    0.25

    0.20

    0.05

    0.050.10

    50

    70

    60

    80

    5070

    40

    80

    70

    70

    6090

    60

    80

    60

    40

    7080

    30

    60

    50

    80

    9050

    1.0

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    ii) Factor Rating Method

    Table gives the various factors considered for location decision and the factor

    ratings assigned to each factor based on its importance for location decision

    and location rating for the location alternatives based on the merit of each

    location in each of the factors considered.

    i) Factor Rating Method

    Identify important factors

    Factor Rating (0 - 5)

    Location Rating (0 - 10)

    Product Rating

    Sum product scores

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    Example:

    Factor Factor Rating

    Location Rating Product of Rating

    Location A Location B Location A Location B

    1. Tax advantage 4 8 6 32 24

    2. Suitability oflabour skill

    3 2 3 6 9

    3. Proximity tocustomers

    3 6 5 18 15

    4. Proximity to

    suppliers

    5 2 4 10 20

    5. Adequacy ofwater

    1 3 3 3 3

    6. Receptivity ofcommunity

    5 4 3 20 15

    7. Quality ofeducationsystem

    4 1 2 4 8

    8. Access to rail andtransportation

    3 10 8 30 24

    9. Suitability ofclimate

    2 7 9 14 18

    10. Availability ofpower

    2 6 4 12 8

    Total score 149 144

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    Locate facility at center of geographic area

    Based on weight and distance traveled

    Establish grid-map of area Identify coordinates

    and weights shipped

    for each location

    B. Quantitative Model

    i) Center-of-Gravity Technique

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    Grid-Map Coordinates

    where,x, y= coordinates of the new

    facility at center of gravityx

    i

    , yi

    = coordinates of existingfacility i

    Wi= annual weight shipped fromfacility i

    n

    Wii =1

    xiWii =1

    n

    x = n

    Wii =1

    yiWii =1

    n

    y =

    x1 x2 x3 x

    y2

    y

    y1

    y3

    1 (x1, y1), W1

    2 (x2, y2), W2

    3 (x3, y3), W3

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    Center-of-Gravity Technique

    A B C D

    x 200 100 250 500y 200 500 600 300Wt 75 105 135 60

    y

    700

    500

    600

    400

    300

    200

    100

    0 x700500 600400300200100

    A

    B

    C

    D

    (135)

    (105)

    (75)

    (60)

    Miles

    Miles

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    Center-of-Gravity Technique

    y

    700

    500

    600

    400

    300

    200

    100

    0 x700500 600400300200100

    A

    B

    C

    D

    (135)

    (105)

    (75)

    (60)

    Miles

    Miles

    A B C D

    x 200 100 250 500y 200 500 600 300Wt 75 105 135 60

    Example S5.2

    x= = = 238n

    Wii =1

    xiWii =1

    n

    n

    Wii =1

    yiWii =1

    n

    y= = = 444(200)(75) + (500)(105) + (600)(135) + (300)(60)

    75 + 105 + 135 + 60

    (200)(75) + (100)(105) + (250)(135) + (500)(60)

    75 + 105 + 135 + 60

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    Center-of-Gravity Technique

    A B C D

    x 200 100 250 500y 200 500 600 300Wt 75 105 135 60

    y

    700

    500

    600

    400

    300

    200

    100

    0 x700500 600400300200100

    A

    B

    C

    D

    (135)

    (105)

    (75)

    (60)

    Miles

    Miles Center of gravity(238, 444)

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    Question: What is the best location for a new Z-Mobilewarehouse/temporary storage facility considering only

    distances and quantities sold per month?

    Centroid method example Several automobile showrooms are located according to

    the following grid which represents coordinate locations

    for each showroom

    S howroom No of Z-Mobile s

    s old pe r month

    A 1250

    D 1900

    Q 2300X

    Y

    A(100,200)

    D(250,580)

    Q(790,900)

    (0,0)

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    Economic Analysis Method

    Particulars Site

    A B Ci) Total Investments inland, building, Plant &m/c (Rs.0000)

    ii) Revenues (0000)

    iii) Expenses on rawmaterials (0000)

    iv) Distribution cost(0000)

    v) Expenses onutilities (0000)

    vi) Wages & Salaries

    250

    410

    89

    40

    5025

    325

    515

    100

    60

    4030

    270

    360

    98

    25

    2528

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    Median ModelFacility (F) Coordinates Cost of moving one unit Annual load

    of Location by unit distance (Rs) (L) Units

    Bareilly (10, 80) 10 452

    Shahjanpur (30, 60) 10 678

    Gonda (80, 50) 10 483

    Kanpur (50, 10) 10 711

    Sultanpur (80, 10) 10 539

    -----------------------------

    2863-----------------------------

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    Load-Distance

    Technique Compute Load x Distance for each site

    Choose site with lowestLoad x Distance

    Distance can be actualor straight-line

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    Load-Distance Example

    Potential SitesSite X Y1 360 1802 420 450

    3 250 400

    SuppliersA B C D

    X 200 100 250 500Y 200 500 600 300

    Wt 75 105 135 60

    Compute distance from each site to each supplier

    = (200-360)2 + (200-180)2dA = (xA - x1)2 + (yA - y1)

    2Site 1 = 161.2

    = (100-360)2 + (500-180)2dB = (xB - x1)2 + (yB - y1)

    2 = 412.3

    dC = 434.2 dD = 184.4

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    Load-Distance Example

    Site 2 dA = 333 dC = 226.7dB = 323.9 dD = 170

    Site 3 dA = 206.2 dC = 200dB = 180.4 dD = 269.3

    Compute load-distance

    i = 1

    nli diLD =

    Site 1 = (75)(161.2) + (105)(412.3) + (135)(434.2) + (60)(434.4) = 125,063Site 2 = (75)(333) + (105)(323.9) + (135)(226.7) + (60)(170) = 99,789

    Site 3 = (75)(206.2) + (105)(180.3) + (135)(200) + (60)(269.3) = 77,555*

    * Choose site 3

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    Location Analysis

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    Location Analysis

    Exhibit S5.2

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    Location Analysis

    Exhibit S5.3

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    Location Analysis