1.Maharani Asmara(4101414004) 2.Ika Deavy M(4101414013) 3.Shiyanatussuhailah(4101414015) 4.Arum...

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KELOMPOK 1 1. Maharani Asmara (4101414004) 2. Ika Deavy M (4101414013) 3. Shiyanatussuhailah (4101414015) 4. Arum Diyastanti (4101414017) ANGGOTA :

description

A B C O l’ l L’’

Transcript of 1.Maharani Asmara(4101414004) 2.Ika Deavy M(4101414013) 3.Shiyanatussuhailah(4101414015) 4.Arum...

Page 1: 1.Maharani Asmara(4101414004) 2.Ika Deavy M(4101414013) 3.Shiyanatussuhailah(4101414015) 4.Arum Diyastanti(4101414017) 5.Novia Wulan Dary(4101414019) ANGGOTA.

KELOMPOK 1

1. Maharani Asmara(4101414004)

2. Ika Deavy M(4101414013)

3. Shiyanatussuhailah(4101414015)

4. Arum Diyastanti(4101414017)

5. Novia Wulan Dary(4101414019)

ANGGOTA :

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Theorem 7-5

The perpendicular bisectors of the sides of a triangle intersect in a point O that is equidistant from the three vertices of the triangle.

ProofGiven: ABC with perpendicular bisectors 𝜟 l, l’,

and l’’, Proof: l, l’, and l’’ are concurrent in a point O

and that OA = OB = OC.

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A B

C

O

l’

l

L’’

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Statement Reasons

L is the perpendicular bisector of Given

L’ is the perpendicular bisector of Given

L dan L’ intersect in a point O If ∦ then

OA = OB A point a perpendicular bisector is equidistant from the endpoints

OB = OC Why?

OA = OC Transitive property of equality

O is on the perpendicular bisector of A point equidistant from two points is on the perpendicular bisector of the segment determined by those points.

O lies on L, L’, L’’ and OA = OB = OC Statements 4 - 8

L∦L’

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Theorem 7-6

The angle bisectors of the angles of a triangle

are concurrent in a point I that is equidistant from

the three sides of the triangle.

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PROOFGiven : with angle bisectors Prove : are concurrent in a point I that is equidistant from the three sides of the triangle.

Page 7: 1.Maharani Asmara(4101414004) 2.Ika Deavy M(4101414013) 3.Shiyanatussuhailah(4101414015) 4.Arum Diyastanti(4101414017) 5.Novia Wulan Dary(4101414019) ANGGOTA.

If you were to construct a triangle and its three altitudes, you would see that the lines containing the altitudes are concurrent.

Theorem 7-7The lines that contain the altitudes of a triangle intersect in a point.

Page 8: 1.Maharani Asmara(4101414004) 2.Ika Deavy M(4101414013) 3.Shiyanatussuhailah(4101414015) 4.Arum Diyastanti(4101414017) 5.Novia Wulan Dary(4101414019) ANGGOTA.

Definition 7-1

A medians of a triangle is a segment joining a

vertex to the midpoint of the opposite side

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Theorem 7-8

The medians of a triangle intersect in a

point that as two thirds of the way from

each vertex to the opposite side

Page 10: 1.Maharani Asmara(4101414004) 2.Ika Deavy M(4101414013) 3.Shiyanatussuhailah(4101414015) 4.Arum Diyastanti(4101414017) 5.Novia Wulan Dary(4101414019) ANGGOTA.
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Theorem 7 - 9

If the measures of two angles of a triangle are unequal, then the length of the side opposite the smaller angle is less than the length of the side opposite the larger angle.

ProofGiven: ABC with m 𝜟 ∠ B < m ∠ AProve: AC < BC

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A B

C

D

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Statement Reasons

m ∠ B < m ∠ A Given

There exists a point D on so that m ∠ BAD = m ∠ B Protractor Postulate

≅ If two angles of a triangle are congruent, then the sides opposite them are congruent

AD = BD Why?

AC < AD + DC Why?

AD + DC = BD + DC Addition of equals property

BD + DC = BC Definition of between for points

AC < BC Substitution Principle

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Theorema 7-10

If the lengths of two sides of a triangles are

unequal then the measure of the angle

opposite the shorter side is less than the

measure of the angle opposite the longer side

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PROOF

Coba kita buat segitiga sembarang, misalnya segitiga

ABC seperti gambar berikut ini.