18 SG With Round Rotor Design
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Transcript of 18 SG With Round Rotor Design
Design of Synchronous Generator with Round Rotor
Part 1 – General Considerations
Synchronous Generator System
Rotor Peripheral Speed
The maximum allowable peripheral speed of the rotor is a central consideration in machine design. With present-day steel alloys, rotor peripheral speeds of 50,000 ft/min (or about 250 m/s) represent the design limit.
1 ft/min = 0.0051 m/s
Resistivity of Copper vs TemperatureThe resistivity of copper versus temperature can be calculated using the following formula:
)()()( 00 TTTT CuCuCu
where is a reference temperature and is a constant give by
0T Cu
Cin/ 10668.2 o9 Cu
or:Cm/ 10775.6 o11
Cu
At , we have C20o0 T
Cin/ 10679.0)( o60 TCu
or:Cm/ 10724.1)( o8
0 TCu
Part 2 – Armature Design
Number of Armature Slots For a m-phase synchronous machine, the number of armature slots (S) must be multiples of m. This will guarantee all the phases are balanced.
Example: For a 2 pole, 3 phase machine, the number of slots can be 6,12,18,24,30,36… For a 4 pole, 3 phase machine, the number of slots can be 12, 24,36,48,60…
A. Integral S/P
B. Fractional S/PS/P takes a fractional number.
Integral S/P may cause extensive cogging or detent torque since all pole faces will line up with slot openings at the same time.
S is multiples of mP.
Cogging torque: torque from the interactions between rotor poles and stator teeth. Use slot skew or fractional S/P can reduce it.
Number of Turns per Coil
pkgaepkgaerated NfNfV ,,,ˆ44.4ˆ2
,,
2 g pkg pk
B DlP
1.1/ˆawa NkN sdpw kkkk
where
DlBqkfCV
Npkgwe
ratedc
,
,
221.1
Na is the number of series turns per phase of armature windingC is the number of parallel circuits of armature winding
CPqNN ca /
To consider leakage flux
Number of Conductor Positions per Slot on Stator
aNC cs 2 for double layer winding.
In the above expression, Cs includes hollow conductor positions for cooling (about 25%) and additional 15% - 25% of both height and width tolerance of conductors (for insulation, slot liner, etc.) in factor a. a can take about 1.6 – 2.
,
,
1.12
rateds
e w g pk
aV CC
f qk B Dl
Maximum and Average Flux Density Average flux per pole:
pkgaeaepkg
avg
d,
0 ,,
2sin
0
pkg ,
Average flux density per pole:
DlP
PDlB pkgavg
avg 2,,
,
2/
or:P
DlB avgpkg 2
,2
,
P
DlB pkgpkg
,,
2Since
pkgpkgavg BBB ,,2, 4.04
Specific magnetic loading
Typically, take TB avg 6.0, or TB pkg 5.1, in design.
Machine Size (1)
rms current per unit length of the armature circumference, ,(2 )( / ) 2a A rated a A rated
a
m N C I C mN IK
D D
Na is the number of series turns per phase of armature windingC is the number of parallel circuits of armature winding
, 2a
A rateda
DKImN
Specific electric loading:
Machine Size (2)
Apparent power , ,rated rated A ratedS mV I
, 2a
A rateda
DKImN
pkgaerated NfV ,,
ˆ2 PDlB pkg
pkg,
,
2
a
apkaerated mN
DKP
DlBNfmS
22ˆ2
mpkgawm
rated BKknlD
S 60120
2)(
2
,
2
2
proportional to power density
awa NkN ˆ
PlDKkBfS awpkgerated
2
,22
120Pnf m
e
2 where , pkg
awm
BKk
Defined as: magnetic shear stress
Machine Size (3)
Machine of Volume 260
,2
2
pkgam
rated
w BKnS
klD
Discussions: The more advanced cooling technology (larger Ka), the
smaller the volume. The larger the rated apparent power Srated, the larger the
volume. The faster the machine speed nm , the smaller the volume. The larger the gap magnetic field Bg,pk (through using
advanced materials with larger magnetic saturation, etc.), the smaller the volume.
Generator Size - Experience
coolingon depends
12
1 , 200
2
amerated KfCC
PSlD
fe = 60 Hzcommon steel
cooled)-(liquid/MVA in 375
cooled)-(hydrogen/MVA in 700
cooled)-(air/MVA in 1400
30
30
30
C
C
C
Length/Diameter Ratio (1)The length/diameter ratio of a machine is defined as the ratio of the length and the stator bore diameter:
DlrlD
Discussions:
For fixed mechanical speed, the machine power rating depends on D2l.•As the l/D increases, the rotor diameter decreases and thus the
moment of inertia decreases. Also the rotor peripheral speed decreases. •As the l/D increases, the machine length increases and the rotor is prone to
exhibit critical frequencies at lower speeds that can result in shaft flexure to the point that the rotor strikes the stator bore.
• If the l/D is too large, it is difficult to cool. • If the l/D is too small, the leakage inductance of end turns can severely
affects machine performance.
Length/Diameter Ratio (2)Some people use aspect ratio, which is defined as the ratio of the lengthand the pole pitch:
P
lr
asp wherePD
P
We can find the relationship between aspect ratio and length/diameter ratio:
PrP
Dllr lD
P
asp
Stator Core DiameterStator Core diameter (outer diameter) 0D
0
0
Two-pole: 2.1Four-pole: 1.7
D DD D
Stator Slot Design
sDS
Use 65 V/mil ground insulation Use 0.375-in slot wedge Use 0.125-in coil separator and top stick
sss bdb 73
0.4 0.6s s sb
sss bt
Stator Conductor Size
, /A rateds
a
I CJ
aA
where Aa is stator (armature) conductor cross section area and can be determined from the above formula together with:
2
2
2
Air-cooled: 2500 A /in
Hydrogen-cooled: 4000 A /in
Water-cooled: 7000 A /in
s rms
s rms
s rms
J
J
J
1 A/in2 = 0.00155 A/mm2
J. J. Cathey, Electric Machines: Analysis and Design Applying MatLab, pp. 482,McGraw Hill, 2001.
Round Wire Structure
This figure shows the wire structure, including the bare conductor, an insulation layer and an optional bonding layer.dwb: bare conductor diameterdwc: covered wire diameterAwb: bare conductor cross section areaAwc: covered conductor cross section area
American Wire Gauge (AWG) 8.251463 0.8905257 G
wbd
log8.251463
log 0.8905257
wbd
G
Or
G: wire gauge (typically an integer)dwb: bare wire diameter in mm.
Relative Wire Resistance versus Wire Gauge
Increasing wire gauge by 1, increases copper loss by 26%. Decreasing wire gauge by 1, decreases copper loss to about 79% of
the previous gauge.
Current Capacity versus Wire Gauge
The maximum allowable current density varies roughly between 1 Arms/mm2 to 10 Arms/mm2. In confined volumes, the lower limit 1Arms/mm2 may be too high. Similarly, with active cooling, the upper limit 10 Arms/mm2 may be too conservative.
Round Wire with Film Insulation (1)
Round Wire with Film Insulation (2)
Square Wire with Film Insulation
Air Gap Size
An empirical formula for effective air gap size:
The actual air gap size can be further tuned using an electromagneticsimulation software.
0, ,
ˆ4 1.5 2aa pk A rated
eff
NB Ig P
From
0,
,
ˆ4 1.5 2aeff A rated
a pk
Ng IB P
eff cg k g
/eff cg g k
Part 3 – Round Rotor Designfor Generator with Field
Winding
Number of Poles
For round rotor machine with field winding, take P = 2 or 4.
Phasor Diagram
,From cos sin cos / sins A A A B s A BX I E E K X I K
AE
AIV
S AjX I
cos sin ( cos sin )A s A B s AV E X I K X I
,
,
1cos sin
a pk s A
g pk B
B X IB V K
A s AjX E V I
maxPick up torque angle ( = sin ) and power factor cos .full loadT T pf
, ,Steady Steady
A B s A f pk B a pkE K X I B K B
oExample: If =30 , pf=0.85 lagging, 1.7.BK
Rotor Slot Selection (1)
integer is 2rotor on slots ofnumber total
r
rr
nPnN
PNn r
r 2 :half poleper rotor on slots
rr
fr
rr
fr
nDPWDP
DPnPWD
22)2/(1
2
:radian) elec.(in pitch slot Angular
2
PDr
r
:pitch polerotor
rfr W 3.00.2 : widthpole
PD
t r2 :slotsadjacent obetween twlength Arc
ff b tt :h widthrotor toot t.bt. f 5040 :slot widthrotor
Number of Conductors in Rotor (1)
The length of the ith field coil: )(2 2
PDiWlL r
ffi
Assume the number of conductors (Cf ) are the same in the each slot
Total length of the field winding:
rn
i
rffF P
DiWlPCL
1
2 )(2
Note: use single layer concentric winding on rotor.
Number of Conductors in Rotor (2)
)1()(2)(2 where 21
2
rrrfr
n
i
rff
ffF
nnDWlPnPD
iWlPX
XCLr
max ,0.7 FF F rated f f f
f
LV I J C XA
ff
Ff XJ
VC
max7.0
The calculated results will be rounded to an integer. Jf depends on rotor cooling. See next slide
where is the cross section area of the field conductor, is the allowable
current density, and is the resistivity of copper at working temperature. f fA J
Rotor Cooling
1 A/in2 = 0.00155 A/mm2
Rotor Rated Field Current and Slot Size Empirical design requires maximum magnetic field from field winding is about KB times maximum magnetic field from armature winding:
, ,Steady Steadyf pk B a pkB K B
0, ,
ˆ4 1.5 2 Steady aa pk A rated
eff
NB Ig P
0, ,
4 wf fSteadyf pk f rated
eff
k NB I
g P
, ,,
ˆ ˆ1.5 2 2.12B a A rated B a A ratedf rated
wf f wf f
K N I K N II
k N k N
where Nf is total number of series turns in field winding: rff nPCN
kwf is rotor winding factor given is next page.
rotor slot cross section area Af :,f rated
ff
IA
J
Round Rotor Winding Factor
1
1
cos[(2 1) / 2]r
r
n
r
wf n
Nk
N
This is the case when sr is even.
2r rs n
1 2If rnN N N
1
cos[(2 1) / 2]rn
r
wfr
kn
Comprehensive Design Example
Design a 3 phase turboalternator with the following specifications:
500 MVA Y connected 24 kV (terminal voltage) 60 Hz 3600 rpm 2 pole 0.85 pf laggingMaximum allowable rotor peripheral speed 50,000 ft/minfor 20% overspeedDirectly cooled stator (water)Directly cooled rotor (hydrogen)
In the design, initially picked up48 stator slots, 20 rotor slots5/6 stator coil pitchVfmax = 600V Not skewed
Details in sgDesign.m
Part 4 – Round Rotor Designfor Surface Mount Permanent
Magnet Generator
Magnetic Circuit Analysis
For a multi-pole surface mount rotor
md
Poles
aD
D
0g m mgH H d 0 0g m mgB H d
g
0
m m m
m g
d B Ag H A
m m g gB A B A
Working Point for Permanent Magnetics (1)
B
0H0 cH
rB
)( cc
r HHHBB HHH
HBBH c
c
r )(
max( )To get (BH) 0 ,
2 2r c
m mBH B HB HH
0 mRH
mRB
Maximum Energy Point
Working Point for Permanent Magnetics (2)
Load Line:
0
0
gmm m
m
c m
AdB Hg A
P H
1 1.2rm
Pc is called permeance coefficient
//
g g gm mc
m m m g m
A A gdPg A A d
RR
PP
Define: (1 )m m r m m cB B H H
0.5 0.8m Typically pick up:
0
rrm
c
BH
0 1m m
c rmm m
BPH
Airgap Magnetic Field from PM Rotor
/2 /2
/2 /2
2 cos( ) ( ) cos( )2
sin4 2
PM PM
PM PMrh m ae ae m ae ae
PM
m
B B h d B h d
hB
h
, 1,3,5...
cos( ) cos( )2
g rotor Rhh
Rh rh de rh d
B B
PB B h B h
sin2PM
phk h
pitch factor for the hth harmonic
, g rotorBmB
mB2
2P M
PM
2PM
22PM
de2
P M
2de dP
2PM
PM embrace: PM
electrical angle
Phasor Diagram
,From cos sin cos / sins A A A B s A BX I E E K X I K
AE
AIV
S AjX I
cos sin ( cos sin )A s A B s AV E X I K X I
,
,
1cos sin
a pk s A
g pk B
B X IB V K
A s AjX E V I
maxPick up torque angle ( = sin ) and power factor cos .full loadT T pf
, ,Steady Steady
A B s A f pk B a pkE K X I B K B
oExample: If =30 , pf=0.85 lagging, 1.7.BK
Air Gap Size and PM Thickness
Initial total effective air gap size:
0, ,
ˆ4 1.5 2ˆ
aa pk A rated
total
NB Ig P
ˆ ' ' /ctotal total total m rmg k g g g d
0,
,
ˆ4ˆ 1.5 2atotal A rated
a pk
Ng IB P
From:
From: mc
d Pg
(1 ) ' '
m total
m m total rm
g gd g
( )g mA A
1m
c rmm
P
Carter’s coefficient
totalg
sdst
s
0sb 0sd 1sd
Effective Air Gap ˆ 'total c totalg k g
where the Carter’s coefficient
2
0 0 0
0
2 'atan ln 12 ' 2 '
sc
s s total ss
total s total
kb b g b
g b g
20
05 '
sc
ss
total s
kb
g b
approximately