Prepared by Dr.Numan Behll BEKTA 1 THERMAL ENVIRONMENT CRATING GEOMETRY, DEFINING ELEMENT TYPE,DEFINING MATERIAL MODEL INCLUDE THERMAL PROPERTIES, MESHING; WRITE ENVIRONMENT AS THERMAL STRUCTURAL ENVIRONMENT SWITCH ELEMNT TYPE,DEFINING MATERIAL MODEL INCLUDE STRUCTURAL PROPERTIES, WRITE ENVIRONMENT AS STRUCT CLEAR ENVIRONMENT PREPROCESSING PHASE SOLUTION PHASE DEFINE ANALYSIS TYPE READ THERMAL ENVIRONMENT APPLY CONSTRAINTS SOLVEREAD STRUCTURAL ENVIRONMENT APPLY CONSTRAINTS APPLY COUPLING CONSTRAINTS INCLUDE THERMAL EFFECTS SOLVEPOSTPROCESSING PHASE COUPLED STRUCTURAL / THERMAL ANALYSIS Prepared by Dr.Numan Behll BEKTA 2 Coupled Structural / Thermal Analysis of A Long Cylinder PREPROCESSING PHASE Thermal Environment Create Geometry and Define Thermal Properties 1.Give example a title Utility Menu>File>Change Title 2.Create geometry Preprocessor>Modelling>Create>Regtangle>By 2 Coarners> X=0.03, Y=0, W=0.09, H=0.01 3.Define the type of element Preprocessor>Element Type>Add/Edit/Delete.. Select: Thermal mass Solid, Quad 4 Node55 ,(Axisymmetric) 4.Define Element Material Properties Preprocessor>Material Props>Material Models>Thermal>Conductivity>Isotropic KXX:60.5 5.Define Mesh Size and Meshing Preprocessor>Meshing>Size Cntrls>Manual Size>Areas>All Areas.. (SIZE=0.01) Preprocessor>Meshing>Mesh>Areas>Pick All 6.Write Environment Preprocessor>Physics>Environment>Write Title Physics file title :Thermaland OK. a b t a= 0.03m, b= 0.09m, t= 0.01m Ti=473K To=300K Mechanical and Thermal Properties of Steel Disc Thermal Conductivity: 60.5W/mK Thermal Expansion Coefficient: 12e-6/K Modulus of Elasticity : 200000MPa Environment Temperature: 300KPrepared by Dr.Numan Behll BEKTA 3 7.Clear Environment Preprocessor>Physics>Environment>Clear>OK Structural Environment Define Physical Properties 1.Switch Element Type Preprocessor>Element Type>Switch Elem Type Choose Thermal to Struc from the scoll down list 2.Define Element Material Properties Preprocessor>Material Props>Material Models>Structural>Linear>Eleatic>Isotropic EX:200000 PRXY:0.3 Preprocessor>Material Props>Material Models>Structural>Thermal>Expansion Coef>Secant Coef..>Isotropic ALPX:12e-6 3.Write Environment Preprocessor>Physics>Environment>Write Title Physics file title :Structand OK. SOLUTION PHASE 1.Define Analysis Type Solution>Analysis Type>New Analaysis>Static 2.Read in the Thermal Environment Solution>Unabridged Menu Solution>Physics>Environment>Read Choose thermal and click OK. (Read Physics file with Title: thermal) 3.ApplyConstraints Solution>Define Loads>Apply>Thermal>Temperature>On Lines Set inner line473 Kelvinand outer line 300 Kelvin Prepared by Dr.Numan Behll BEKTA 4 4.Solve the System Solution>Solve>Current LS 5.Close the Solution Menu Mein Menu>Finish 6.Read in the Structural Environment Solution>Physics>Environment>Read Choose struct and click OK. (Read Physics file with Title: struct) 7.Apply Constraints Solution>Define Loads>Apply>Structural>Displacements>On Lines (Fix bottom line in UY direction) 8.Apply Coupling Constrains Preprocessor>Coupling/Ceng>Couple DOFs (Choose nodes at iner line and fix them in UX direction, NSET=1 and OK, than nodes at upper line and fix them in UY direction, NSET=1 and OK) 9.Include Thermal Effects Solution>Define Loads>Apply>Structural>Temperature>From Therm Analy Browse file.rth from rest of computer or directory.. 10. Define Reference Temperature Preprocessor>Loads>Define Loads>Settings>Reference Temp (Fort his exaple set the reference temp to 300K ) 11. Solve the System Solution>Solve>Current LS POSTPROCESSING PHASE USE YOUR EXPERIENCE TO SEE RESULTS