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Transcript of 1 In a vortex system a force applied on a vortex by all the others can be written within London...
1
In a vortex system a force applied on a vortex by all the others can be written within London appr. as a sum:
IV. FLUX LINE LATTICE
1
2 iji j
F V
i ijj
f f
The total energy of the vortex system is:
A. General overview of phase diagram and magnetic
properties
2
minimal magntic field H at which vortices appear
To minimize this energy distribution is likely to be as homogeneous as possible : triangular or (sometimes) square lattice (FLL).
maximal magnetic field H at which vortices disappear
0
1 2 ( )4
cH T LogT
0
2 22
cH TT
Critical fields
H
T
Mixed
Meissner
Hc2
Hc1
Tc
Normal
3
Steep second order phase transition at Hc1.
B
H1cH 2cH
H
M4
Magnetization curves
1cH 2cH
4
Magnetization of BSCCOMagnetization of BSCCOB
- H
[G]
H [G]
Bm(75K)=92G
Bm(70K)=140G
Bm(60K)=250G
T = 60, 70, 75, 80 KT = 60, 70, 75, 80 K
5
214
2c
c
HM B H H Log
H
For the “strongly bound” lattice (London)
2 2c cfraction of H H H
For the “sparse” lattice (London)
1 1c cH H several H
For “weakly superconducting” lattice (LLL)
1 2c cH H H
2 11
1
cc
c
HB H Log
H H
22
2
4 12
c
c c
H H TM
H T
6
B. Relatively sparse lattice. London appr.
a
1. Lower critical field.
7
1cH
2 0
0
cBa
B
Due to flux quantization, the fluxon density is
When first vortices appear at , the distances are large and interactions exponentially negligible for
triangular
012 ca B H
square1
2
3
c
c
The transition field therefore will be determined by the energy magnetic field has to overcome to push vortices through the material.
8
Meissner no first Abrikosovfluxon fluxon
G G G G
BHdFG 3
4
1
A - Surface area
-line energyLH
The condition of the phase transition is:
9
2
0 01 2
0 0
4 4( ) ( )
4 4
A M
c
G G
H Log Log
31
1 0
1
41
4
A M c
M c
G G A L H B d x
G H A L
One therefore obtains an expression for the lower critical field
10
Since for a very sparse lattice, (near Hc1) there is just exponentially small repulsion,
only nearest neighbors contribute significantly
2. FLL energy and magnetization just above Hc1
a
Number of vortices
20
int 02 20 2 8
B z aF A K
4,6 口zz
z- coordination number ( # of nearest neighbors)
11
1/ 4 5/ 4 0int
1~ expF z
cc B
B
Since this is exponential in c and just linear in z, the hexagonal (triangular) FLL is preferable energetically, at least for sufficiently small B. We will see that at larger fields B this feature still holds for rotation invariant interactions (Kepler’s theorem).
Using the asymptotic expression for large separations and the expression for the lattice spacing a one obtains:
12
int0
[ ] 1[ ]
4
G B A BF B A B H
L
For a given external field H, the induction B should minimize G[B]
Since for , B=0 is the minimum.
int
0
0 04
dFdG H
dB dB
int 0F 10
4cH H
However for H>Hc1, the minimum is nontrivial and is defined by:
Magnetization
13
01( )1 int
1~4
leadingcin a B
c Bc
H H dFH e
dB
2 11
1
cc
c
HB H Log
H H
14
3. Intermediate vortex densities. London eqs. And energy.
a The “logarithmic repulsion” dominates FLL for
Magnetic field becomes quite homogeneous
15
In high Tc SC this region is very wide. Example: In high Tc SC this region is very wide. Example: BSCCOBSCCO at at T=70KT=70K
B [G
]
H [G]
to Bc2(70K)
Normal
materia
l: Bcen
ter = B ext
Hc1(70K)
MeissnerB=0
16
Q
rQiz eQBrB
)()(
)(2
ynxma
Q
口
口a
2 x
y
Unit cell
For the square array
In this case one still can use London approximation neglecting cores, but not only nearest neighbors now interact. Summations over whole lattice can be performed using Fourier transform.
London equations
17
For the hexagonal FLL array two reciprocal lattice vectors perpendicular to hexagonal translation symmetry vectors are:
1 2
1 2
2( ),
ˆ 2,
3 3
Q mQ nQa
y yQ x Q
x
y 2Q
1Q
18
London’s equations are:
2 20
2
ˆ( ) ( ),
( ) ,
ilattice
iQ ri
lattice Q
B B z r r
r r e
2 2( ) ( ) iQ r iQ r
Q Q
B Q Q B Q e B e
2 2 2 2( ) ( )
1 1
iQ r
zQ
B eB Q B r B
Q Q
Solution is a sum over reciprocal lattice
(*)
Where is the density of vortices
19
2 2 2 2int
2
02 2
1[ ( ) ]
8
1( )
8 8 1ilattice Q
F B B d x
BB r A
Q
Using (*) for one obtains::0r
2
int2 2
1
8 1Q
F B
A Q
London interaction energy
20
It logarithmically diverges at due to
neglect of the core cut off
max
1Q
Q
Minimization of the Gibbs energy with respect to B gives
Q QB
Bd
dFH
221
14
4. A problem with London approximation and its solution
21
2 20
11
1Q
H BQ
Since the field is rather uniform, especially for
the term dominates and better to be separated.
1cB H0Q
“Rounding” the Brillouin zone gives a good approx.:
0Q
minQmaxQ
Approximation of the “round Brillouin zone”
22
Performing the integral one obtains
max max
min min
0
0
2( ) ( ) ( )
/ 2
Q Q
Q Q Q
f Q f Q QdQ f Q QdQarea site B
2
min0
4B
Q
2max
min
0
1/ 20 0
2 2 2 24
0 0 1 22 2
( )
2 1 4 1
4 log4 2
Q
BQ
c c
Q dQ d QH B B
Q Q
H HB Log B Log
B B
Where the expression for the upper critical field was used (see next section) 0
2 22cH
23
C. Dense lattice. The LLL appr. and Hc2.
a Order parameter is greatly reduced and only small
“islands” between core centers remain superconducting. Still superconductivity dominates electromagnetic properties of the material
24
Some historySome history
1967BitterDecoration
U. EssmannH. Trauble
1989STM
H.F. HessBell labs
A.A. Abrikosov 1957 2003
25
2cB H H
Supercurrent in turn is very small since it is proportional to 2 2
0
Since magnetization is small we replace the field inside superconductor B by external field H which is essentially homogeneous.
magnetization is relatively small (smaller than field)
We will use the Landau gauge
0x
y
A
A H x
extA A
26
Since order parameter is small everywhere Naively we can drop nonlinear higher powers of
1. Linearization of the GL eqs. Near Hc2.
2
22 2 2
2
*12
2
1
2
cm T Tx xi
y
t
22
0
20
2 * ci A T Tm
This is the usual linear Schrodinger equation of quantum mechanics.
20
1 2 H
27
In the Landau gauge it still has the manifest translation symmetries in both z and y directions, while the x translation invariance is “masked” by the choice of gauge. Therefore one can disentangle variables:
( , , ) ( )y zik y ik zx y z const e e f x
getting the shifted harmonic oscillator equation
22
4 2
1 1 1''( ) ( )
2 2 22
zktf x x X f f f
eigenvalue2yX k
28
2
, 2
( )exp
2N X
x X x Xf const
solved by the Landau harmonics
Eigenvalues of harmonic oscillator are (for any shift):
2
2 2
1 1 1
2 2 2z
N
ktN
20 0
2 2
1( , )
2 (2 1)2z z
tH N k k
N
The corresponding magnetic fields are
0, 0zk N The highest such value of H is for
29
For yet higher fields the only solution of GL equations is normal:
2 2
02 2
1
2
2
c c
c
typeII
c c
H T H t
H
H H
0
This is Hc2 – the highest field for which a nontrivial solution exists obtained for
Hc2 and the LLL appr.Hc2 and the LLL appr.
0
/ ct T T
1
2 2/ /c cb B H H H
1
normal
lattice0
30
1t b
The two pair breaking phenomena, temperature and magnetic field appear symmetrically, the second order transition line being a straight line
For N=0 and one has and the Larmor orbital center X still can be anywhere inside the sample.
0zk 2 22 / 1 t T
2
22
( )exp
2 / 1X
x Xf
t
Eigenvalues of the linearized GL equation however are still highly degenerate (the Landau degeneracy):
How should we chose the correct one and its normalization?
31
Below the nonlinear term will lift the degeneracy. It is reasonable to try an Ansatz: most general state on the lowest Landau level (LLL):
42cH
However the number of the variational parameters is unmanageble. To narrow possible choices of coefficients one has to utilize all the symmetries of the lattice solution.
2. The Abrikosov lattice solution. Heuristic approach
X XX
C
32
2
2 /
222
22;
2exp / 2
y y yik y a ik y ik ay n
i n y an n n
n n
Tne e e k X n
a a
C C e
Tx n T
a
Periodicity in the y direction with lattice constant a means that X is quantized:
Periodicity in the x direction is possible when absolute values of coefficients C are the same and in addition phases are periodic in n.
33
For the square FLL:
For the hexagonal (also called sometimes triangular) FLL:
1n nC C C
1 0
2n n
C iC
C C
Geometry + flux quantization gives us, as before in units of lattice spacing a instead of customary :
2 2exp ( )i yn
n
C e x n
22 0
2
2
1
2
c
a TH
T
a
Square lattice
22n
TX n a n
a
34
)1,( yx
),( yx ( 1, )x y The x direction
translation takes a form
2 2
2 ( 1) 2 2
( 1, ) exp ( 1 )
exp ( ) ( , )
iyn
n
iy n iy
n
x y C e x n
C e x n e x y
This is “regauging” which generally accompany a symmetry transformation.
35
The symmetry is not “manifest”, for example in our Landau gauge the symmetry along the x direction is “hidden”. The gauge invariant quantities like modulus is invariant and, in particular, zeros are repeated.
Hexagonal lattice
)1,( yx
),( yx( 3 / 2, 1/ 2)x y
22 0
2
1/ 4
32
2
3
2
c
a TH
T
a
22 3
2n
TX n a n
a
36
2
2
2
2
2 3exp
23
2 3exp
23
i yn
n even
i yn
n odd
C e x n
i e x n
The y direction translation is the same with different a as a unit of length:
The translation in diagonal direction is
2
2 1/ 2
2
2 1/ 2
3 1 2 3 3, exp
2 2 2 23
2 3 3exp
2 23
in y
n even
in y
n odd
x y C e x n
i e x n
37
2
2 ' 1 1/ 2
'
2
2 ' 1 1/ 2
'
3 1 2 3, exp '
2 2 23
2 3exp '
23
i n y
n odd
i n y
n even
x y C e x n
i e x n
Shifting n by 1 switches even and odds:
2
2 1/ 2 ' 2 '
'
2
' 2 '
'
2 3exp '
23
2 3exp '
23
i y in in y
n odd
in in y
n even
Ce e e x n
i e e x n
38
2
2 2 '
'
2
2 '
'
3 1 2 3, exp '
2 2 23
2 3exp '
23
iy in y
n odd
in y
n even
x y Ce e x n
i e x n
2 iyie
Again regauging.
Exercise 3: construct the Abrikosov lattices for the rhombic symmetry with an arbitrary angle
[0,1]
[0,1]
[1,0]
39
First let us write the GL for constant magnetic field using dimensionless variables with as the unit of length, as unit of magnetic field as the unit of energy and
221 10
2 2
tD
2
2
0
1,
2
h
hc c
H a
T B t bt b a
T H
,
2cH cT
3. Abrikosov lattice solution: a systematic expansion approach
2 2 20/ 2
40
Here21
2 2
bH D
, (0, , 0),D iA A bx ��������������������������������������������������������
is the (shifted) Schroedinger operator of an electron in magnetic field with nonnegative Landau spectrum:
NE b N
With the hexagonal symmetric eigenfunctions that we will normalize as
2( , ) 1Nunit cellx y
41
For the positive and small the energy of a LLL lattice
ha
becomes negative provided it is proportional to the Abrikosov solution.
ha
2 41
2hG H a
t
1
b
1
normal
lattice
2 ha
42
20 1 2 .... .h h ha a a
One therefore develops perturbation theory in small around the Hc2 line:
The leading ( ) order equation gives the lowest LLL restriction already motivated in the heuristic approach:
0 00H C
order equation is:
ha
3/ 2ha
With normalization undetermined. The next to leading
22 *1 0 0 0 0H C C C
ha
43
Multiplying it with and integrating one obtains *
2* 2 *1 0 0 0 0
unit cell
H C C C
0
1
A
C
2 4
01 0unit cell
C
4
22
1.16
1.18A
Exercise 4: Fix the normalization of andcalculate the Abrikosov ratio for the square lattice.
44
Free energy of the leading order solution is indeed negative
2 4
222 4
0 0
1
2
11
2 2 8
unit hcell
hh A
A A
g unit cell vol H a
t baa C C
A To find the most favorable lattice symmetry (the minimum of free energy) one should minimize
Free energy
45
Therefore since
the hexagonal lattice energy is slightly (by about 2%) lower than that of the square lattice. This sound small, but for comparison typical latent heat at melting (difference between lattice and homogeneous liquid) is of the same order of magnitude.
One can show that energies of other lattices are also higher than that of the hexagonal. Autler et al (67)
One also observes that while the first derivative with respect to T is smooth, while the second jumps:
0 0;2
h
c A c A
g a gS C
T T
46
2 2 2 222
( ),
2 2 4c h
A
H a b hG
To calculate magnetization we return to standard units for energy ensity and add the Maxwell term
Minimizing G with respect to b one obtains2
2
22 2 22 2
( )0
2 2
( )4 , ( ) 1
2
h h
A A
h cc c c
A c
a b h ab h
a H T H TB H M H H T H
T
Magnetization
47
22 2 2
2
4 12
h cc
A c c
a H T HM H
T H
48
Multiplying the GL equation with and integrating over unit cell, then using orthonormality relations one obtains:
* , 0N N
Higher order correction will include higher Landau level contributions
Corrections
1 10
NN
N
C
2* *1 1 0 0
3/ 220
1
1NN N
NN
period
H N bC C C
C
N b
C
49
The LLL component is found from the order etc.
All the corrections are very small numerically partially due to factor 1/n with multiples of 6 contributing due to symmetry
5 / 2ha
(6) (12)1 1
0.279 0.025;
6 12c c
b b
LLL leading LLL next to leadings 6th LL
2/ 0.5 / 0.1 0.2c c hT T B H a
50
ha Therefore the perturbation theory in
LLL is by far the leading contribution above this line.
converges well up to surprisingly low fields
and temperatures, roughly above the line
11
13b t
51
Summary
1. Vortex lattice is a strongly bound elastic medium. Not too close to Hc1 the field becomes homogeneous due to the vortex overlaps.
2. The diamagnetism in the mixed is far from ideal but still very strong compared with the normal state one.
3. One can rely on standard solid state methods far from Hc2.
4. One must use a delicate bifurcation perturbation theory in an interesting region not far from Hc2.