1) Hypothesis testing for population mean when population variance is known ( Z-test ) ( large...
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Transcript of 1) Hypothesis testing for population mean when population variance is known ( Z-test ) ( large...
1) Hypothesis testing for population mean when population variance is known ( Z-test )
( large sample size or assume population is normal )
2) Hypothesis testing for population mean when population variance is unknown ( T-
test )( large sample size or assume population is
normal )
3) Hypothesis testing for population proportion ( Z-test )
( need large sample size )
We’ve learned:
Review Questions:
What is the parameter of interest? )a
b) p
Boys of a certain age are known to have a mean weight of 85 pounds. A complaint is made that the boys living in a municipal children's home are underfed. As one bit of evidence, n = 25 boys (of the same age) are weighed and found to have a mean weight of 80.94 pounds. It is known that the population standard deviation σ is 11.6 pounds (the unrealistic part of this example!). Based on the available data, what should be concluded concerning the complaint?
Review Questions:
What is the null and alternative hypothesis? a) H0: = 85 , H1: ≠ 85 b) H0: = 85 , H1: < 85 c) H0: p = 85 , H1: p ≠ 85 d) H0: p = 85 , H1: p > 85
Boys of a certain age are known to have a mean weight of 85 pounds. A complaint is made that the boys living in a municipal children's home are underfed. As one bit of evidence, n = 25 boys (of the same age) are weighed and found to have a mean weight of 80.94 pounds. It is known that the population standard deviation σ is 11.6 pounds (the unrealistic part of this example!). Based on the available data, what should be concluded concerning the complaint?
Review Questions:
What is the test statistics under the null?
a) b) c) d)
Boys of a certain age are known to have a mean weight of 85 pounds. A complaint is made that the boys living in a municipal children's home are underfed. As one bit of evidence, n = 25 boys (of the same age) are weighed and found to have a mean weight of 80.94 pounds. It is known that the population standard deviation σ is 11.6 pounds (the unrealistic part of this example!). Based on the available data, what should be concluded concerning the complaint?
𝑍 0=𝑋−0
𝜎 /√𝑛𝑍 0=
𝑋−𝜇𝜎 /√𝑛 𝑍 0=
𝑋−0
𝑠 /√𝑛𝑇 0=
𝑋−0
𝑠 /√𝑛
Review Questions:
Which picture corresponds to our test?
H0: = 85 , H1: < 85
A) B) C)
Review Questions:
What is the value of the test statistic?
a) −1.75 b) −1.65
Boys of a certain age are known to have a mean weight of 85 pounds. A complaint is made that the boys living in a municipal children's home are underfed. As one bit of evidence, n = 25 boys (of the same age) are weighed and found to have a mean weight of 80.94 pounds. It is known that the population standard deviation σ is 11.6 pounds (the unrealistic part of this example!). Based on the available data, what should be concluded concerning the complaint? 𝑍 0=
𝑋−0
𝜎 /√𝑛
Review Questions :
Find p-value for the computed test statistic = −1.75
a) 0.04b) 0.96
H0: = 85 , H1: < 85
p-value < Reject H0
p-value > Do not Reject H0
Review example:
The p-value is P(Z < −1.75) = 0.04, Under significance level 0.05
a) Rejectb) Fail to reject
H0: = 85 , H1: < 85
Review Questions :
We can construct the rejection region to reach the same conclusion Rejection region is a) (1.65, )b) (--1.65)
H0: = 85 , H1: < 85
Since = -1.75 falls in the rejection region. We reject the null. Reach the same conclusion
= 0.05
−𝑍𝛼
Review Questions :
We can also construct the confidence interval. Note here is one-sided.Upper bound =
a) CI = ( , 84.76 )b) CI = ( 84.76 , )
H0: = 85 , H1: < 85
• With 95% confidence level, the population mean lies in the confident interval• Null value is not in the 95% confidence interval. We can reject the null hypothesis
𝑋+𝑍 0.05𝜎√𝑛
Review Questions:
If we assume σ is unknown. What is the test statistics under the null?
a) b) c) d)
Boys of a certain age are known to have a mean weight of 85 pounds. A complaint is made that the boys living in a municipal children's home are underfed. As one bit of evidence, n = 25 boys (of the same age) are weighed and found to have a mean weight of 80.94 pounds. It is known that the population standard deviation σ is 11.6 pounds (the unrealistic part of this example!). Based on the available data, what should be concluded concerning the complaint?
𝑍 0=𝑋−0
𝜎 /√𝑛𝑍 0=
𝑋−𝜇𝜎 /√𝑛 𝑍 0=
𝑋−0
𝑠 /√𝑛𝑇 0=
𝑋−0
𝑠 /√𝑛
Review Questions:
If we assume σ is unknown. What is the test statistics under the null?
a) Z distribution b) T distribution with df = 25c) T distribution with df = 24
Boys of a certain age are known to have a mean weight of 85 pounds. A complaint is made that the boys living in a municipal children's home are underfed. As one bit of evidence, n = 25 boys (of the same age) are weighed and found to have a mean weight of 80.94 pounds. It is known that the population standard deviation σ is 11.6 pounds (the unrealistic part of this example!). Based on the available data, what should be concluded concerning the complaint?
𝑇 0=𝑋−0
𝑠 /√𝑛
Review Questions: Writing Hypotheses
a) H0: p = 0.8 , H1: p > 0.8b) H0: p = 0.8, H1: p >= 0.8c) H0: p = 0.8, H1: p <= 0.8d) H0: p = 0.8, H1: p < 0.8
Are more than 80% of American’s right handed?
Review Questions: Writing Hypotheses
a) H0: p = 0.5, H1: p ≠ 0.5b) H0: p = 0.5, H1: p > 0.5c) H0: p = 0.5, H1: p < 0.5
Is the proportion of babies born male different from .50?
Review Questions: Writing Hypotheses
Is the percentage of Creamery customers who prefer chocolate ice cream over vanilla less than 80%?
a) H0: p = 0.8 , H1: p > 0.8b) H0: p = 0.8, H1: p >= 0.8c) H0: p = 0.8, H1: p <= 0.8d) H0: p = 0.8, H1: p < 0.8
Hypothesis Testing on a Binomial Proportion
Are you ready for something different?• What if we are more interested in testing the variation (spread) in our
population distribution.• This is especially in quality control. • For example, we want a coffee dispenser to fill up a cup of coffee with
a standard deviation less than 0.02 oz • How do we test if the coffee dispenser satisfy our expectation• We want to test the population variance