1 Example 2 Estimate by the six Rectangle Rules using the regular partition P of the interval [0, ]...
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Transcript of 1 Example 2 Estimate by the six Rectangle Rules using the regular partition P of the interval [0, ]...
1
Example 2 Estimate by the six Rectangle Rules using the regular
partition P of the interval [0, ] into 6 subintervals.
Solution Observe that the function with g(0)=1 is continuous at
x=0 because Note that P = {0, /6, /3, /2, 2/3, 5/6, } with
each subinterval of width /6. The six subintervals are:
[0, /6 ], [/6, /3], [/3, /2], [/2, 2/3], [2/3, 5/6] and [5/6, ].
Then
The Lk are the heights of the rectangles used to approximate this definite integral.
dxxx
0
sin
xx
xgsin
)(
. sin
6543210LLLLLL
6dx
xx
In the Left Endpoint Rule the Lk are the values of g on the left endpoints of the six subintervals: g(0), g(/6), g(/3), g(/2), g(2/3), g(5/6).
y
x0
1
.sin
lim 1xx
0x
xx
ysin
2
In the Right Endpoint Rule the Lk are the values of g on the right endpoints of the six subintervals: g(/6), g(/3), g(/2), g(2/3), g(5/6), g().
In the Midpoint Rule the Lk are the values of g on the midpoints of the six subintervals: g(/12), g(/4), g(5/12), g(7/12), g(3/4), g(11/12).
In the Trapezoid Rule the Lk are the averages of the values of g on the endpoints of each of the six subintervals:
½[g(0)+ g(/6)], ½[g(/6)+ g(/3)], ½[g(/3)+ g(/2)],
½[g(/2)+ g(2/3)], ½[g(2/3)+ g(5/6)], ½[g(5/6)+ g()].
Therefore, the Lower Riemann sum coincides with the estimate of the Right Endpoint Rule and the Upper Riemann sum coincides with estimate of the Left Endpoint Rule.
Since the function g is decreasing on [0,1], it has its maximum value at the left endpoint of each subinterval and its minimum value at the right endpoint of each subinterval.
The values of the Lk are summarized in the table on the next slide
The six subintervals are: [0,/6 ], [/6,/3], [/3,/2], [/2, 2/3], [2/3,5/6], [5/6,].
y
x0
1
xx
ysin
3
The Left Endpoint Rule and Upper Riemann Sum give the same estimate:
The Right Endpoint Rule and Lower Riemann Sum give the same estimate:
The Midpoint Rule gives the estimate:
The Trapezoid Rule gives the estimate:
107219141463782795516
LLLLLL6
dxxx
6543210......
sin
LeftEndpoint
Rule
RightEndpoint
Rule
Midpoint Rule
Trapezoid Rule
LowerRiemann
Sum
UpperRiemann
Sum
L1
L2
L3
L4
L5
L6
g(0)=1
g(/6).955
g(/3).827
g(/2).637
g(2/3).414
g(5/6).191
g(/6).955
g(/3).827
g(/2).637
g(2/3).414
g(5/6).191
g()=0
g(/12) .989
g(/4) .900
g(5/12) .738
g(7/12).527
g(3/4) .300
g(11/12) .090
½(1+.955)
½(.955+.827)
½(.827+.637)
½(.637+.414)
½(.414+.191)
½(.191+0)
g(/6).955
g(/3).827
g(/2).637
g(2/3).414
g(5/6).191
g()=0
g(0)=1
g(/6).955
g(/3).827
g(/2).637
g(2/3).414
g(5/6).191
583101914146378279556
LLLLLL6
dxxx
6543210......
sin
85610903005277389009896
LLLLLL6
dxxx
6543210.......
sin
84610963035267328919786
LLLLLL6
dxxx
6543210.......
sin