1 Acid-Base Reactions Chapter 17. 2 3 Acid-Base Reactions Reactions always go from the stronger A-B...
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Transcript of 1 Acid-Base Reactions Chapter 17. 2 3 Acid-Base Reactions Reactions always go from the stronger A-B...
11Acid-Base ReactionsAcid-Base Reactions
Chapter 17
22
33
Acid-Base Reactions
Reactions always go from the stronger A-B pair
(larger K) to the weaker A-B pair (smaller K).
ACIDS CONJUGATE BASESACIDS CONJUGATE BASES
STRONGSTRONG
weakweak
weakweak
STRONGSTRONG
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Acid-Base ReactionsAcid-Base Reactions
A strong acid is 100% dissociated.
STRONG ACID = a good H+ donor—must have a WEAK CONJUGATE BASE
Or a poor H+ acceptor.
HNO3(aq) + H2O(l) H3O+(aq) + NO3-(aq)
STRONG A base acid weak B
•Every A-B reaction has two acids and two bases.
•Equilibrium always lies toward the weaker pair.•Here K is very large.
•Every A-B reaction has two acids and two bases.
•Equilibrium always lies toward the weaker pair.•Here K is very large.
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Acid-Base ReactionsAcid-Base ReactionsAcid-Base ReactionsAcid-Base Reactions
We know from experiment that HNO3 is a strong acid.
1. It is a stronger acid than H3O+
2. H2O is a stronger base than NO3-
3. K for this reaction is large
WEAK BASE
ACID
STRONG ACID
BASEH3O+ + NO3
-HNO3 + H2OWEAK BASE
ACID
STRONG ACID
BASEH3O+ + NO3
-HNO3 + H2O
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K and Acid-Base ReactionsK and Acid-Base ReactionsK and Acid-Base ReactionsK and Acid-Base Reactions
Acetic acid is only 0.42% ionized.
It is a WEAK ACID
HOAc + H2O H3O+ + OAc-
WEAK A base acid STRONG B
[H3O+] is small, this means
1. H3O+ is a stronger acid than HOAc
2. OAc- is a stronger base than H2O
3. K for this reaction is small
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Acid/Base ReactionsAcid/Base Reactions
Strong acid + Strong base
H+ + Cl- + Na+ + OH- H2O + Na+ + Cl-
Net ionic equation
H+(aq) + OH-(aq) H2O(l)
K = 1/Kw = 1 x 1014
Mixing equal molar quantities of a strong acid and strong
base produces a neutral solution.
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Acid/Base ReactionsAcid/Base Reactions
Weak acid + Strong base
CH3CO2H + OH- H2O + CH3CO2-
This is the reverse of the reaction of CH3CO2
- (conjugate base) with H2O.
OH- stronger base than CH3CO2-
K = 1/Kb = 5.6 x 104
Mixing equal molar quantities of a weak acid and strong base produces the acid’s conjugate
base. The solution is basic.
Mixing equal molar quantities of a weak acid and strong base produces the acid’s conjugate
base. The solution is basic.
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Acid/Base ReactionsAcid/Base Reactions
Strong acid + Weak base
H3O+ + NH3 H2O + NH4+
This is the reverse of the reaction of NH4+ (conjugate
acid of NH3) with H2O.
H3O+ stronger acid than NH4+
K = 1/Ka = 5.6 x 104
Mixing equal molar quantities of a strong acid and weak base produces the bases’s conjugate
acid. The solution is acid.
Mixing equal molar quantities of a strong acid and weak base produces the bases’s conjugate
acid. The solution is acid.
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Acid/Base ReactionsAcid/Base Reactions
Weak acid + Weak baseWeak acid + Weak base
•Product cation = CA of weak base.•Product anion = CB of weak acid.
pH of solution depends
on relative strengths of
cation and anion.
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Summary
1212
MX + H2O ----> acidic or basic??
Consider NH4Cl
NH4Cl(aq) NH4+(aq) + Cl-(aq)
(a) Reaction of Cl- with H2O
Cl- + H2O ----> HCl + OH-
base acid acid base
Cl- ion is a VERY weak base because its conjugate acid is strong.
Therefore, Cl- = neutral solution
SaltsSalts
1313
(b) Reaction of NH4+ with H2O
NH4+ + H2O NH3 + H3O+
acid base base acid
NH4+ ion is a moderate acid because its
conjugate base is weak.
Therefore, NH4+ = acidic solution
See TABLE 17.4 for a summary of acid-base properties of ions.
SaltsSalts
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1515
Calculate the pH of a 0.10 M Na2CO3.
A)
Na+ + H2O neutralB)
CO32- + H2O HCO3
- + OH-
base acid acid base
Kb = 2.1 x 10-4
Salts
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Calculate the pH of a 0.10 M solution of Na2CO3.
Kb = 2.1 x 10-4
Step 1. Set up ICE table
[CO32-] [HCO3
-] [OH-]
I 0.10 0 0
C -x +x +x
E 0.10 - x x x
SaltsSalts
1717SaltsSalts
Kb = 2.1 x 10-4 = [HCO3
- ][OH- ]
[CO32 ]
x2
0.10 - xKb = 2.1 x 10-4 =
[HCO3- ][OH- ]
[CO32 ]
x2
0.10 - x
Assume 0.10 - x ≈ 0.10,
because 100•Kb < Co
x = [HCO3-] = [OH-] = 0.0046 M
Step 2.Step 2. Solve the equilibrium expression
1818SaltsSalts
Step 3. Calculate the pH
[OH-] = 0.0046 M
pOH = - log [OH-] = 2.34
pH + pOH = 14,
so pH = 11.6
the solution is ________.
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