1 16.5 Cyclic Structures of Monosaccharides 16.6 Chemical Properties of Monosaccharides Chapter 16...
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Transcript of 1 16.5 Cyclic Structures of Monosaccharides 16.6 Chemical Properties of Monosaccharides Chapter 16...
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16.5 Cyclic Structures of Monosaccharides16.6 Chemical Properties of
Monosaccharides
Chapter 16 Carbohydrates
o
OH
OH
CH2OH
OH
OH
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Cyclic Haworth Structures
Stable cyclic hemiacetals form when the C=O group and the -OH are part of the same molecule.
For hexoses, the hydroxyl group on C-5 reacts with the aldehyde group or ketone group.
The cyclic structure of a D-isomer has the last CH2OH group located above the ring.
oCH2OH
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Formation of Cyclic Glucose
The Haworth structure can be written from theFischer Projection. The –OH group on the left (C3) is drawn up. The –OH groups on the right (C2, C4) are
drawn down.
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and Anomers for D-Glucose
The new –OH on C1 is drawn down for the anomer, and up for the anomer.
-D-Glucose -D-Glucose
OCH2OH
OHOH
OH
OH
OCH2OH
OHOH
OH
OH
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Mutarotation In solution, -D-glucose is in equilibrium with
β-D-glucose. Mutarotation involves the conversion of the cyclic
anomers into the open chain. At any time, there is only a small amount of open
chain.
-D-glucose D-glucose (open) β-D-glucose (36%) (trace) (64%)
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Cyclic Structure of Fructose
As a ketohexose, fructose forms a cyclic structure when the —OH on C-5 reacts with the C=O on C-2.
CH2OH
C
C
C
C
CH2OH
O
HO H
OHH
OHH
D-Fructose
CH2OH
OH
OH
OH
CH2OHO
CH2OH
OH
OH
CH2OH
OHO
-D-Fructose -D-Fructose
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Oxidation of Monosaccharides Monosaccharides are reducing sugars if their
carbonyl groups oxidize to give carboxylic acids. In the Benedict’s text, D-glucose is oxidized to
D-gluconic acid. Glucose is a reducing sugar.
C
C
C
C
C
CH2OH
HO
OHH
HO H
OHH
OHH
C
C
C
C
C
CH2OH
OHO
OHH
HO H
OHH
OHH
+ Cu2+
D-Glucose D-Gluconic acid
+ Cu2O(s)
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Oxidation – Reduction Oxidation (LEO)
Loss of electrons Gain of O Loss of H (H+ & e)
Increase of the oxidation number (state)
Reduction Gain of electrons Loss of O Gain of H (H+ & e)
Decrease of the oxidation number (state)
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Oxidation - Reduction In simple ionic compounds, the chemical bond is formed by a complete
transfer from the more electropositive to the more electronegative element – the actual charge of the ion is equal to its oxidation number (e.g. NaCl – the oxidation number of Na+ is +1 and that of Cl- is -1.
In covalent compounds (such as CH4) and in polyatomic ions with covalent bonds (such as SO4
2-), electrons are shared between bonded atoms. For calculations of oxidation numbers, the electrons are assigned completely to the more electronegative atom (electron hog). In CH4 the oxidation number of C is -4 and that of H is +1. In SO4
2- the oxidation number of S is +6 and that of O is -2. The sum of the oxidation numbers in the polyatomic ion is equal to the charge of the ion. The sum of the oxidation numbers in the compound is equal to zero. (In most compounds hydrogen is assigned the oxidation number of +1 and oxygen is -2.)
For an element (Ag, Na, Cl2, O2, etc.), the oxidation number of each atom is equal to zero.
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Half – reactions (Reduction) Gain of Electrons
Ag+ + e → Ag(+1) (0)
Loss of OxygenNO3
- + 2H+ + 2e → NO2- + H2O
(+5) (+3) Gain of Hydrogen
2 CO2 + 2H+ + 2e → H2C2O4
(+4) (+3)
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Oxidation – Reduction in organic chemistry
Reduction of an organic molecule usually corresponds to increasing its hydrogen content or to decreasing its oxygen content.
Oxidation is the opposite of reduction, thus increasing the oxygen content of organic molecule or decreasing its hydrogen content is an oxidation.
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Method of assigning an oxidation state to a carbon atom of an organic compound: Base the assignment on the groups attached to carbon.
A bond to hydrogen (or anything less electronegative than carbon) makes it -1. A bond to oxygen (or anything more electronegative than carbon, like nitrogen or halogen)
makes it +1. A bond to another carbon makes it 0.
H |
Methane, CH4 (H – C – H) – oxidation state of carbon is -4. |
H Carbon dioxide, CO2 (O=C=O) – oxidation state of carbon is +4.
H |
Methanol, CH3OH (H – C – OH) – oxidation state of carbon is | H
3(-1)+1=-2.
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Oxidation of aldehyde to carboxylic acid
R – C = O → R – C = O (oxidation)
| |
H OH
(+1) (+3) Cu2+ + 1e → Cu1+ (reduction)
(+2) (+1)
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Reduction of Monosaccharides
The reduction of the carbonyl group produces sugar alcohols, or alditols.
D-Glucose is reduced to D-glucitol also called sorbitol.
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Glycosides and Glycosidic Bonds
When a cyclic monosaccharide reacts with an alcohol: A glycoside is produced. The bond is a glycosidic bond.
-D-Glucose Methanol Methyl--D-glucoside
glycosidic bond
O
OH
OH
CH2OH
O
OH
CH3
HOCH3+
O
OH
OH
CH2OH
OH
OH