02 ChE421 - Flash Distillation
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Transcript of 02 ChE421 - Flash Distillation
1
Separation Processes
Simple Equilibrium Stage Operationsp
Flash Distillation
Course Slides of Prof. Alberto A. Laurito w/ modifications by MF Benjamin
Separation Processes
Lecture Objectives To be able to define and describe the flash
distillation process;To be able to calc late b bble and de points To be able to calculate bubble and dew points of a multicomponent feed;
To be able to derive and apply the working equation for multicomponent flash distillation and be able to apply the equation in specific cases.
Separation ProcessesWhat is Flash Distillation?
It is a simple distillation process where a liquid multicomponent feed is partially vaporized and the resulting liquid-vapor p g q pmixture is separated in a flash drum at a specified pressure and temperature.
The vapor is passed through a total condenser to obtain the distillate; while theliquid portion becomes the residue.
Separation Processes
Isothermal Flash DistillationTotal Condenser
V, yVi
Heater
FlashDrumF, xFi
D, xDi
L, xLi
P, TPartial
Vapor
Separation Processes
NomenclatureF = feed rate xFi = fraction of I in F
V = overhead rate yVi = fraction of I in V
L = bottoms rate xLi = fraction of I in L
D = distillate rate xDi = fraction of I in D
P = operating pressure T = operating temperature
f = fraction of F that is vaporized (or distilled)
Ki = Equilibrium Constant = f (P,T)
Separation Processes
Basic Equations1. Over-all Material Balances:
F = V + L but V = D F = D + L
2 Component Balance:2. Component Balance:
F xFi = V yVi + L xLi = D xDi + L xLi
3. Equilibrium Relation:
yVi = Ki xLi
4. f relation:
f = V/F = D/F and L/F = 1 – f
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Separation ProcessesWorking Equations
xLi =xFi
1 + f (Ki - 1)
where f is a fraction, Ki = f (P,T)
If f = 0, start of vaporization = Bubble Point
If f = 1, complete vaporization = Dew Point
for f to be a fraction, the flash drum must operate between the bubble and dew points
Calculation Check: xLi = 1.0
Separation Processes
Bubble Point Algorithm Given Data: xFi and P or T Required: Bubble Point T or P, yFi
A T P ( b ili t id ) Assume T or P (use pure boiling pts as guide) Evaluate Ki using P and T Solve yFi = Ki xFi (1st bubble composition) Check if Sum of yFi is equal to 1.0 If Yes, assumed T or P and yFi are correct If Not, assume another T or P and repeat
Separation Processes
Dew Point Algorithm Given Data: yFi and P or T Required: Dew Point T or P, xLi
Assume T or P (use pure boiling pts as guide) Evaluate Ki using P and T Solve xLi = yFi/Ki (last bubble composition) Check if Sum of xLi is equal to 1.0 If Yes, assumed T or P and xLi are correct If Not, assume another T or P and repeat
Separation Processes
Typical Flash Distillation Problems Given xFi, f, P or T Unknown T or P, xLi,
and xDi
Given xFi, P and T Unknown xLi, and xDiand xDi
Assume T or P Evaluate Ki
Solve xLi and check if Sum will equal one
Repeat trial if needed
Evaluate Ki
Assume f (fraction) Solve xLi and check
if Sum will equal one Repeat trial if
needed
Separation Processes
Practice ProblemA liquid mixture containing 20 mole% benzene (B), 30 mole%toluene(T), and 50 mole% o-xylene (X) shall be flash distilled at 1 atm. Assuming ideal system, determine:g y ,
a. Bubble and dew points of mixtureb. Flash drum temperature and mole% compositionof the products in order that 40% of the feed will be distilledc. Mole% of the feed to be distilled and the mole% compositions of the products if flash drum temperature is 125oC.d. Percent recovery of benzene in operations (b) and (c)
Separation ProcessesSolution for Bubble Point
Bubble Point (TB)Use the individual normal boiling points (1 atm) of the components as the initial trial for the bubble point of the mixture
Component A B C Boiling PointBenzene 6.9057 1211.033 220.7900 80.100Toluene 6.9546 1344.800 219.4820 110.625O-xylene 6.9989 1474.679 213.6880 144.409
Component xfi Boiling Point Trial TbBenzene 0.20 80.100 121.412Toluene 0.30 110.625O-xylene 0.50 144.409
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Separation ProcessesSolve for Ki’s using the trial bubble point and check if theyfi = 1.0. If not assume another value for TB
Formulas: Ki = Po/PT yFi = Ki xFi
Component xfi Po Ki yfiBenzene 0.20 2326.527 3.061 0.612Toluene 0.30 1022.630 1.346 0.404O-xylene 0.50 396.458 0.522 0.261
yfi 1.277Not OK
Trial 1: 121.412oC
Separation Processes
Final Trial: 112.266oC = Bubble Point
Component xfi Po Ki yfiBenzene 0.20 1860.055 2.447 0.489Toluene 0 30 796 087 1 047 0 314Toluene 0.30 796.087 1.047 0.314O-xylene 0.50 298.343 0.393 0.196
yfi 1.000OK!
Separation Processes
Dew Point (TD)To solve for the dew point, assume a temperature higher than the bubble point for the first trial. Check if xLi = 1.0, if not, assume another TD
Solution for Dew Point
, D
Formulas: Ki = Po/PT xLi = yFi/Ki
Component yfi Po Ki xliBenzene 0.20 2249.288 2.960 0.068Toluene 0.30 984.715 1.296 0.232O-xylene 0.50 379.818 0.500 1.000
xli 1.300 Not OK
Trial 1: 120oC
Separation Processes
Final Trial: 129.128oC = Dew Point
Component yfi Po Ki xliBenzene 0.20 2784.485 3.664 0.055Toluene 0 30 1250 357 1 645 0 182Toluene 0.30 1250.357 1.645 0.182O-xylene 0.50 498.020 0.655 0.763
xli 1.000OK!
Separation ProcessesFlash Drum Temperature
Flash Drum Temperature (T)To solve for the flash drum temperature, assume atemperature between the bubble point and the dew point forthe first trial. Check if xLi = 1.0, if not, assume another TLi , ,
Formulas: Ki = Po/PT xLi = xFi/[1 + f(Ki – 1)]
Trial 1: 120oC using given f = 0.4
Component xfi Po Ki xliBenzene 0.20 2249.288 2.960 0.112Toluene 0.30 984.715 1.296 0.268O-xylene 0.50 379.818 0.500 0.625
xli 1.005 Not OK
Separation Processes
Final Trial: T = 120.553oC using given f = 0.4
Component xfi Po Ki xliBenzene 0.20 2279.304 2.999 0.111Toluene 0 30 999 431 1 315 0 266Toluene 0.30 999.431 1.315 0.266O-xylene 0.50 386.266 0.508 0.622
xli 1.000OK!
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Separation ProcessesCompositions
Formulas:xDi = xLi Ki
%Rec = DxDi/FxFi*100 = fxDi/xFi*100
Component xfi xli Ki xdiBenzene 0.20 0.111 2.999 0.333Toluene 0.30 0.266 1.315 0.350O-xylene 0.50 0.622 0.508 0.316
xdi 1.000
Component T f = D/F xfi xdi %RECBenzene 120.553 0.400 0.200 0.333 66.600
Separation ProcessesFraction of Feed Distilled
Percent of Feed that was distilled (f)Using the given flash drum temperature (125oC) assume avalue for f. Check if xLi = 1.0, if not, assume another f
Formulas: Ki = Po/PT xLi = xFi/[1 + f(Ki – 1)]
Trial 1: f = 0.6 using given T = 125oC
Component xfi Po Ki xliBenzene 0.20 2531.798 3.331 0.083Toluene 0.30 1124.107 1.479 0.233O-xylene 0.50 441.385 0.581 0.668
xli 0.984Not OK
Separation Processes
Component xfi Po Ki xliBenzene 0.20 2531.798 3.331 0.078Toluene 0.30 1124.107 1.479 0.227
Final Trial: f = 0.668 using given T = 125oC
Toluene 0.30 1124.107 1.479 0.227O-xylene 0.50 441.385 0.581 0.694
xli 1.000OK!
Separation ProcessesCompositions
Formulas:xDi = xLi Ki
%Rec = DxDi/FxFi*100 = fxDi/xFi*100
Component xfi xli Ki xdiBenzene 0.20 0.078 3.331 0.261Toluene 0.30 0.227 1.479 0.336O-xylene 0.50 0.694 0.581 0.403
xdi 1.000
Component T f = D/F xfi xdi %RECBenzene 125.000 0.668 0.200 0.261 87.018
Separation Processes
AssignmentA liquid mixture containing 35 mole% n-pentane (A), 35 mole% n-hexane(B), and 30 mole% n-heptane (C) shall be flash distilled at 2585 Torrs. Determine:
a. Bubble and Dew points of mixtureb. Flash drum temperature and mole% compositionof the products in order that 50% of the feed will be distilledc. Percent Recovery of n-pentane