0 nbb decay to the excited state 0 + of 130 Xe
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Transcript of 0 nbb decay to the excited state 0 + of 130 Xe
0 decay to the excited state 0+ of 130Xe
Comparison of the GE and SC analyses
S. Di Domizio, December 2010
2
Part 1: comparison of the methods
In the following slides I will evaluate the efficiencies using the SC cuts with the GE and SC algorithms
3Efficiency – scenario1 – SC – 536
= (0.82 +/- 0.03)%
4Efficiency – scenario1 – SC – 734
= (0.82 +/- 0.02)%
5Efficiency – scenario1 – SC – 1257
= (0.80 +/- 0.03)%
6Efficiency – scenario2 – SC - 1257
= (2.58 +/- 0.04)%
7Efficiency – scenario2 – SC – 1270
= (2.56 +/- 0.03)%
8Efficiency – scenario3 – SC – 536
= (1.72 +/- 0.03)%
9Efficiency – scenario3 – SC – 1991
= (1.76 +/- 0.03)%
10GE – scenario1 - 1257
Using GE algorithms and SC cuts
11GE – scenario2 - 1270
Using GE algorithms and SC cuts
12GE – scenario3 - 1257
Using GE algorithms and SC cuts
13
Part 2: comparison of the results
In the following slides I will summarize the differences in the two approaches and will extract the half life limits
14Comparison
scenario1
scenario2
scenario3
GE SC
N·t = 9.11 x 1025 y N·t = 8.74 x 1025 y
N·t = 8.96 x 1025 y
0.60%
2.29%
1.41%
0.80%
2.58%
1.75%
scenario1
scenario2
scenario3
GE SC
0.48%
1.93%
1.19%
0.64%
2.18%
1.48%
Geometric only total (with psa, noise, etc.)
statistics
N·t = 9.50 x 1025 y
values reported in the note
Forgot to include the three “dead” channels 2, 3 and 50
“My” evaluation with “SC” method
efficiency
GE SC
15Result (GE)
Posterior pdf for
< 6.74 x 10-25 y-1 90%CL
> 1.03 x 1024 y 90%CL
16Result (SC)
Posterior pdf for
< 5.98 x 10-25 y-1 90%CL
> 1.16 x 1024 y 90%CL
17
Part 3: the approach proposed by Frank
In the following slides I will show the method and the results I obtained by treating the difference between GE
and SC analysis as a systematic error
18Treating the differences as syst errors
± =SC
2±
∣ S−C∣2
N · t±N ·t =N · t GEN · t SC
2±
∣N · t GE−N · t SC∣2
2= 2= 2⋅ 2
2 N · t 2
N · t 2 X syst2 =
− 2
2
P = · N · t⋅e− · N · t · X stat2 = −logP − −logP = · N · t ·
1
2= 1
stat2
1
syst2
Use the approach discussed in Adam's internal note
1
2
3
efficiency
(0.56+/-0.08)%
(2.06+/-0.13)%
(1.34+/-0.15)%
scenario
Statistics: N·t = (9.23 +/- 0.27) x 1025 y
19Result (combined)
Posterior pdf for
< 6.39 x 10-25 y-1 90%CL
> 1.09 x 1024 y 90%CL
20Summary
GE: T1/2
> 1.0 x 1024 y @90%CL
SC: T1/2
> 1.2 x 1024 y @90%CL
GE+SC: T1/2
> 1.1 x 1024 y @90%CL
21Method comparison
Consider the limit case of an experiment with two crystals where one has 100% dead time and the other has 0 dead time.Since no coincidences can be recorded in these conditions, the number of signal and background counts will be zero.
The SC approach would give a finite value for both the efficiency and the accumulated statistics, thus resulting in a non trivial limit for the half life of the process.
The GE approach would give a finite value for the statistics and a null value for the efficiency, therefore nothing can be said about the half life of the process.
22Treating the differences as syst errors
TOT= SC
2±
∣ S−C∣2
STAT TOT=STAT SSTAT C
2±
∣STAT S−STAT C∣2
= counts⋅STAT
2= 2= 2⋅ 2
2 STAT
2
STAT 2 X syst2 =
− 2
2 = 1
2
2 STAT
2
STAT 2
P counts = e−counts P = ⋅STAT⋅e−⋅STAT⋅
X stat2 = −log P − −logP = ⋅STAT⋅
1
2 = 1
stat2 1
syst2 = 1
⋅STAT⋅ 2
2 STAT
2
STAT 2
P syst =e
− ⋅STAT⋅
1⋅STAT⋅⋅1
syst2