© Boardworks Ltd 2010 1 of 8 The Factor Theorem. © Boardworks Ltd 2010 2 of 8 The Factor Theorem...
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Transcript of © Boardworks Ltd 2010 1 of 8 The Factor Theorem. © Boardworks Ltd 2010 2 of 8 The Factor Theorem...
© Boardworks Ltd 20101 of 8
The Factor TheoremThe Factor Theorem
© Boardworks Ltd 2010 2 of 8
The Factor Theorem
If (x – a) is a factor of a polynomial then substituting a in x will give an answer of zero.If (x – a) is a factor of a polynomial then substituting a in x will give an answer of zero.
The converse is also true:
If substituting a in for x gives an answer of zero then (x – a) is a factor of a polynomial.If substituting a in for x gives an answer of zero then (x – a) is a factor of a polynomial.
Suppose that a polynomial is divided by an expression of the form (x – a) the remainder is 0.
What can you conclude about (x – a)?
If the remainder is 0 then (x – a) is a factor of the polynomial.
This is the Factor Theorem:
© Boardworks Ltd 2010 3 of 8
The Factor Theorem
(x - 3) is a factor of 2x2 - 7x + 3 if we substitute 3 in for x and get zero.
2x2 - 7x + 3 = 2(3)2 - 7(3) + 3= 18 – 21 + 3
= 0 as required.
Use the Factor Theorem to show that (x - 3) is a factor of 2x2 - 7x + 3.
And so 2x2 - 7x + 3 = (x - 3)(2x – 1)
© Boardworks Ltd 2010 4 of 8
The Factor Theorem
(x + 2) is a factor of 3x2 + 5x – 2 if we substitute –2 in for x and get zero.
3x2 + 5x – 2 = 3(–2)2 + 5(–2) – 2= 12 – 10 – 2
= 0 as required.
Use the Factor Theorem to show that (x + 2) is a factor of 3x2 + 5x – 2.
And so 3x2 + 5x – 2 = (x + 2)(3x – 1)
© Boardworks Ltd 2010 5 of 8
Factoring polynomials
The Factor Theorem can be used to factor polynomials by systematically looking for values of x that will make the polynomial equal to 0. For example:
Factor the cubic polynomial x3 – 3x2 – 6x + 8.
Let x3 – 3x2 – 6x + 8.
Start by testing 1, then -1, then 2, etc.
x3 – 3x2 – 6x + 8 = 1 – 3 – 6 + 8 = 0
(x – 1) is a factor of x3 – 3x2 – 6x + 8.
Now long divide
© Boardworks Ltd 2010 6 of 8
Long Divide
8631 23 xxxx
2x
23 1xx 23 1xx 22x x6
x2
xx 22 2 xx 22 2 x8 8
8
88 x 88 x
0
© Boardworks Ltd 2010 7 of 8
Factor Fully
)2)(4)(1(
)82)(1(
8632
23
xxx
xxx
xxx
© Boardworks Ltd 2010 8 of 8
Your turn
40183)
1)23
3
xxxb
xa