Complex Numbers. Aim: Identify parts of complex numbers. Imaginary NumbersReal Numbers.
§ 7.7 Complex Numbers. Blitzer, Intermediate Algebra, 4e – Slide #94 Complex Numbers The...
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Transcript of § 7.7 Complex Numbers. Blitzer, Intermediate Algebra, 4e – Slide #94 Complex Numbers The...
§ 7.7
Complex Numbers
Blitzer, Intermediate Algebra, 4e – Slide #94
Complex Numbers
The Imaginary Unit iThe imaginary unit i is defined as
The Square Root of a Negative NumberIf b is a positive real number, then
.1 where,1 2 ii
.or 1)1( ibbibbb
Blitzer, Intermediate Algebra, 4e – Slide #95
Complex Numbers
EXAMPLEEXAMPLE
Write as a multiple of i: .520(b)300(a)
SOLUTIONSOLUTION
i3101310013001300300(a)
i52015201520520(b)
Blitzer, Intermediate Algebra, 4e – Slide #96
Complex Numbers
Complex Numbers & Imaginary NumbersThe set of all numbers in the form
with real numbers a and b, and i, the imaginary unit, is called the set of complex numbers. The real number a is called the real part, and the real number b is called the imaginary part of the complex number If , then the complex number is called an imaginary number.
bia
.bia 0b
Blitzer, Intermediate Algebra, 4e – Slide #97
Complex Numbers
Adding & Subtracting Complex Numbers1)
In words, this says that you add complex numbers by adding their real parts, adding their imaginary parts, and expressing the sum as a complex number.
2)
In words, this says that you subtract complex numbers by subtracting their real parts, subtracting their imaginary parts, and expressing the difference as a complex number.
idbcadicbia
idbcadicbia
Blitzer, Intermediate Algebra, 4e – Slide #98
Complex Numbers
EXAMPLEEXAMPLE
Perform the indicated operations, writing the result in the form a + bi: (a) (-9 + 2i) – (-17 – 6i) (b) (-2 + 6i) + (4 - i).
SOLUTIONSOLUTION
(a) (-9 + 2i) – (-17 – 6i)
= -9 + 2i + 17 + 6i
= -9 + 17 + 2i + 6i
= (-9 + 17) + (2 + 6)i
= 8 + 8i
Remove the parentheses. Change signs of the real and imaginary parts being subtracted.
Group real and imaginary terms.
Add real parts and imaginary parts.
Simplify.
Blitzer, Intermediate Algebra, 4e – Slide #99
Complex Numbers
(b) (-2 + 6i) + (4 - i)
= -2 + 6i + 4 - i
= -2 + 4 + 6i - i
= (-2 + 4) + (6 - 1)i
= 2 + 5i
Remove the parentheses.
Group real and imaginary terms.
Add real parts and imaginary parts.
Simplify.
CONTINUECONTINUEDD
Blitzer, Intermediate Algebra, 4e – Slide #100
Complex Numbers
EXAMPLEEXAMPLE
Find the products: (a) -6i(3 – 5i) (b) (-4 + 2i)(-4 - 2i).
SOLUTIONSOLUTION
(a) -6i(3 – 5i)Distribute -6i through the parentheses.
Multiply.
iii 5636
23018 ii Replace with -1. 13018 i 2i
Simplify and write in a + bi form.i1830
(b) (-4 + 2i)(-4 – 2i)248816 iii Use the FOIL method.
Blitzer, Intermediate Algebra, 4e – Slide #101
Complex Numbers
CONTINUECONTINUEDD
148816 ii 12 i
ii 88416 Group real and imaginary terms.
20 Combine real and imaginary terms.
Blitzer, Intermediate Algebra, 4e – Slide #102
Complex Numbers
Multiplying Complex NumbersBecause the product rule for radicals only applies to real numbers, multiplying radicands is incorrect. When performing operations with square roots of negative numbers, begin by expressing all square roots in terms of i. Then perform the indicated operation.
Blitzer, Intermediate Algebra, 4e – Slide #103
Complex Numbers
EXAMPLEEXAMPLE
Multiply:
SOLUTIONSOLUTION
Express square roots in terms of i.
.416
The square root of 64 is 8.
14116416
ii 416 264i
164
8
. and 64416 2iii
12 i
Blitzer, Intermediate Algebra, 4e – Slide #104
Complex Numbers
EXAMPLEEXAMPLE
Divide and simplify to the form a + bi:
SOLUTIONSOLUTION
Multiply by 1.
.24
36
i
i
i
i
i
i
i
i
24
24
24
36
24
36
The conjugate of the denominator is 4 – 2i. Multiplication of both the numerator and the denominator by 4 – 2i will eliminate i from the denominator.
Use FOIL in the numerator and 22 BABABA in thedenominator.
22
2
24
6121224
i
iii
Blitzer, Intermediate Algebra, 4e – Slide #105
Complex Numbers
Simplify.2
2
416
62424
i
ii
CONTINUECONTINUEDD
1416
162424
i 12 i
Perform the multiplications involving -1.416
62424
i
Combine like terms in the numerator and denominator.20
2418 i
Express answer in the form a + bi.i20
24
20
18
Simplify.i5
6
10
9
Blitzer, Intermediate Algebra, 4e – Slide #106
Complex Numbers
EXAMPLEEXAMPLE
Divide and simplify to the form a + bi:
SOLUTIONSOLUTION
Multiply by 1.
.4
5
i
i
The conjugate of the denominator, 0 - 4i, is 0 + 4i. Multiplication of both the numerator and the denominator by 4i will eliminate i from the denominator.
Multiply. Use the distributive property in the numerator.2
2
16
420
i
ii
i
i
i
i
i
i
4
4
4
5
4
5
Blitzer, Intermediate Algebra, 4e – Slide #107
Complex Numbers
Perform the multiplications involving -1.
116
1420
i
CONTINUECONTINUEDD
12 i
16
420
i
i16
20
16
4
Express the division in the
form a + bi.
i4
5
4
1 Simplify real and imaginary
parts.
Blitzer, Intermediate Algebra, 4e – Slide #108
Complex Numbers
Simplifying Powers of i1) Express the given power of i in terms of
2) Replace with -1 and simplify. Use the fact that -1 to an even power is 1 and -1 to an odd power is -1.
.2i2i
Blitzer, Intermediate Algebra, 4e – Slide #109
Complex Numbers
EXAMPLEEXAMPLE
Simplify:
SOLUTIONSOLUTION
.cba 1340046 iii
11a 2323246 ii
11b 2002002400 ii
iiiiiiii 11c 6621213