© 2003 Anita Lee-Post Inventory management Part 3 By Anita Lee-Post.
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Transcript of © 2003 Anita Lee-Post Inventory management Part 3 By Anita Lee-Post.
![Page 1: © 2003 Anita Lee-Post Inventory management Part 3 By Anita Lee-Post.](https://reader036.fdocuments.us/reader036/viewer/2022082610/56649d765503460f94a57846/html5/thumbnails/1.jpg)
© 2003 Anita Lee-Post
Inventory managementPart 3
By
Anita Lee-Post
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© 2003 Anita Lee-Post
EPQ assumptions• Same as the EOQ except: inventory arrives in
increments & is drawn down as it arrives
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© 2003 Anita Lee-Post
EPQ: Total cost equation
p
dH
QS
Q
DTC
p
dQI
HI
SQ
DTC
SQ
D
HI
Q
Q
12
rate production daily :p and rate, demand daily :d where
1)p
Qd( - Q used Total - produced Total
year per unit per cost Holding :H
order per cost etupOrdering/S :S
Demand Annual :D where
2 Q, at cost Total
cost etupordering/s Annaul
,2
cost holding Annual
max
max
max
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© 2003 Anita Lee-Post
EPQ: Total cost equation continued
rate production Daily :p
demand Daily :d
year per unit per cost Holding :H
run production per cost Setup :S
demand Annual :D where
daysEPQ
run Production
p
d-1H
2DS EPQ where
EPQ at costs setup annual holding annual 2 or
p
d-1
2 EPQ, at cost Minimal
p
SEPQ
DTC
HEPQ
SEPQ
DTC
EPQ
EPQ
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© 2003 Anita Lee-Post
EPQ exampleGiven:• Annual demand = 15,000• Setup cost = $500 per production run• Holding cost = $50 per item per year• Number of working days per year = 240• Annual production rate = 25,000(a) What is the EPQ?(b) What is the total cost at EPQ?(c) What is the maximum inventory level?(d) What is the total number of production run in a year?(e) What is the length of production run?(f) What is the time between production?(g) What is the length of time with no production?
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© 2003 Anita Lee-Post
EPQ example continued
days 6 8-14 run production no with time of Length (g)
days 41 18
240 run production between Time (f)
days 824025000
866
p
EPQ t run, production of Length (e)
18 866
15000
EPQ
demand Annual year a in runs production of number Total (d)
34625000
1500018661I inventory,Maximum (c)
$17320 500866
150002
2 EPQ at cost Total (b)
866
25000
15000150
500150002
d-1H
2DS EPQ (a)
p
max
p
dEPQ
SEPQ
D
p
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© 2003 Anita Lee-Post
DQ assumptions
• Same as the EOQ, except:– Unit price depends upon the quantity ordered
• Adjusted total cost equation:
price unit :P
year peritem per cost Holding :H
order per cost etupOrdering/S :S
demand Annual :D where
2PDH
QS
Q
DTCQD
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© 2003 Anita Lee-Post
QD procedure
1. Calculate the EOQ at the lowest price
2. Determine whether the EOQ is feasible at that price (will the vendor sell that quantity at that price?)
3. If yes, stop – if no, continue
4. Check the feasibility of EOQ at the next higher price
5. Continue until you identify a feasible EOQ
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© 2003 Anita Lee-Post
QD procedure continued
6. Calculate the total costs (including purchase price) for the feasible EOQ model
7. Calculate the total costs of buying at the minimum quantity allowed for each of the cheaper unit prices
8. Compare the total cost of each option & choose the lowest cost alternative
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© 2003 Anita Lee-Post
QD example #1
Given: • annual demand = 100 units• Ordering cost = $45 per order• Holding cost per year = 20% of item cost• Quantity discounts:
Order quantity Cost per item
50 or less $18
51 to 59 $16
60 or more $12
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© 2003 Anita Lee-Post
QD example #1 continuedThe lowest cost per item is $12 if ordered 60 units or more
Order at 62 units at a time is the recommended policy
1347$12005.735.73
10012$12$2.02
6245$
62
100
2
feasible found is EOQ The
item per $12 of price discounted
lowest the for qualifies time a units 62 Ordering
units 62122.0
4510022
PDHEOQ
SEOQ
DTC
H
DSEOQ
EOQ
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© 2003 Anita Lee-Post
QD example #2
Given: • annual demand = 100 units• Ordering cost = $45 per order• Holding cost per year = 20% of item cost• Quantity discounts:
Order quantity Cost per item
50 or less $18
51 to 99 $16
100 or more $12
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© 2003 Anita Lee-Post
QD example #2 continued
• The lowest cost per item is $12 if ordered 100 units or more
infeasible found is EOQ The
item per $12 of price discounted the for
qualify not does time a units 62 Ordering
units 62122.0
4510022
H
DSEOQ
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© 2003 Anita Lee-Post
QD example #2 continued
• The next lowest cost per item is $16 if ordered between 51 to 99 units
feasible found is EOQ The
item per $16 of price discounted the for
qualifies time a units 54 Ordering
units 54162.0
4510022
H
DSEOQ
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© 2003 Anita Lee-Post
QD example #2 continuedCost comparisons:
Order at 100 units at a time is the recommended policy
cost total lower a yields
365,1$120012045
10012$12$2.02
10045$
100
100
2
770,1$16008585
10016$16$2.02
5445$
54
100
2
100
100
54
Q
Q
EOQ
TC
PDHQ
SQ
DTC
PDHEOQ
SEOQ
DTC
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© 2003 Anita Lee-Post
QD example #3
Given: • annual demand = 100 units• Ordering cost = $45 per order• Holding cost per year = 20% of item cost• Quantity discounts:
Order quantity Cost per item
55 or less $18
56 to 99 $16
100 or more $12
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© 2003 Anita Lee-Post
QD example #3 continued
• The lowest cost per item is $12 if ordered 100 units or more
infeasible found is EOQ The
item per $12 of price discounted the for
qualify not does time a units 62 Ordering
units 62122.0
4510022
H
DSEOQ
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© 2003 Anita Lee-Post
QD example #3 continued
• The next lowest cost per item is $16 if ordered between 56 to 99 units
infeasible found is EOQ The
item per $16 of price discounted the for
qualify not does time a units 54 Ordering
units 54162.0
4510022
H
DSEOQ
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© 2003 Anita Lee-Post
QD example #3 continued
• The remaining cost per item is $18 if ordered less than 56 units
feasible found is EOQ The
item per $18 at time a units 50 Ordering
units 50182.0
4510022
H
DSEOQ
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© 2003 Anita Lee-Post
QD example #3 continuedCost comparisons:
Order at 100 units at a time is the recommended policy
cost total lowest the yields
365,1$120012045
10012$12$2.02
10045$
100
100
2
771,1$16008190
10016$16$2.02
5645$
56
100
980,1$18009090
10018$18$2.02
5045$
50
100
100
100
56
50
Q
Q
Q
EOQ
TC
PDHQ
SQ
DTC
TC
TC