Post on 26-Dec-2015
Triatomics and Beyond
1) Complex, so we deal with simple symmetrical molecules
2) Same principles apply to orbital combinations as with Diatomics:
i) Compatible symmetry ii) Compatible energy (within 1 Rydberg, 1
Ry)
3) The number of valence AO’s must equal the number of Mo’s
4) MO’s must conform to the symmetry of the molecule.
5) Orbitals of the same energy and the same number of nodes mix.
BeH2
BeH2 is the simplest triatomic molecule.
Linear the gas phase.
The relative energies for the AO’sof Be and H are:
1s (Be) = -9.38 Ry 1s (H) = -0.99 Ry2s (Be) = -0.61 Ry2p (Be) = +0.14 Ry
Which atomic orbitals will combine to make σ MOs?
Which will combine to make p MOs?
Which will not combine remaining σ or p nonbonding MOs?
2pz
2pxy
Be H
2s
1s
1s
Along bond axis
BeH2 MO Diagram
Lewis Structure?Electron Configuration?BO?HOMO?LUMO?Lewis Acid?
2pxy
2pz
Be H * 2
Along bond axis
CO2
Lewis Structure?Shape Family?Valence atomic orbitals on C and O: 2s and 3 x 2p
Consider s and p MO’s formed separately.6 s and 6 p MO’s will be formed (12 possile for each)
Order of energies:
C O * 2
2pz
2px
y
2pxy
2pz
Along bond axis Along bond axis
2s (O) + 2s(C) small2s (O) + 2pz(C) smallest2pz(O) + 2s(C) large2pz(O) + 2pz(C) largest
Valence MO Diagram for CO2
Free atomFree atom
2s (O) + 2s(C) small1s, 2s, 3 *, s 2s
2s (O) + 2pz(C) smallest3 , s 2s, 3 , s 4 *s
2pz(O) + 2s(C) large4s, 5 *s , 4s, 3 s
2pz(O) + 2pz(C) largest6s*, 5s, 4s, 5s,
2px(O) + 2px(C) largest1p , 2p, 3 *, p 2p
2py(O) + 2py(C) largest1p , 2p, 3 *, p 2p 1s
2s
3 *s4s
5 *s
6 *s
BH3
What orbital combinations are possible now?
2pz
2pxy
B H * 3Lewis structure?
Shape Family?
Along Bonding Plane
BH3 MO Diagram
CH4 - The third dimension…
B H * 3
2pz
2pxy
Along Bonding Plane
Frontier MO Theory
BH3H-
BH3 + H- —> BH4-
Reactions take place during collisions.
Bonds are formed and/or broken.
That must mean that there is some kind of orbital interaction.
Which orbitals are most likely interact in forming the new bond?
In general, reactions take place via the interaction of the HOMO of one component with the LUMO of the other because these are the closest in energy.
These orbitals are known as the “frontier orbitals”.
Free atom
Free atom
Electron delocalization (Resonance)In resonance structures, the only electrons that move are:
Delocalized electrons are always found in orbitals.
As orbitals are usually found at higher energy than the orbitals, the
HOMO and LUMO of molecules with multiple bonds are usually orbitals.
As a result of this, we often look only at the orbitals and construct
MO diagrams.
Ethylene
1s
2s
3s4s5s1p
2 *p
*s ’s
C: 2*(2s + 3*(2p)) => 8 AO’s
H: 4*(1s ) => 4 AO’s
=> 12 AO’s
=> 12 MO’s
-MO diagram of Ethylene
Nodes…Pi-bond order…Sigma bond order
When Ethylene reacts…
Ethyne?
Ozone
Nodes…Sigma & Pi-bond order…Total bond orderLewis BOFormal Charge:
Total bond order = bond order + bond order
-7.3eV
-11
1.2
-9.5
0.2
2
-12
Ethylene Butadiene
Nodes…
The importance of the HOMO/LUMO gap. Note: this is not two isolated double bonds but a single -system spread out over four carbons.
HOMO
LUMO
HOMO
LUMO12.2 ev
9.7ev
Benzene
The polygon method for determining -MOs of monocyclic unsaturated molecules:
Works for any monocyclic molecule with contiguous atomic p orbitals.
Benzene can’t be considered to have “three double bonds and three single bonds”. It has three p bonds with bond order _____.
Accordingly, all six C-C bonds in benzene are 140 pm
(whereas pure C-C bonds are 154 pm and pure C=C bonds are 134 pm).
The -MOs of Benzene
How many pi-electrons?
Nodes…(Cuts?)
Aromatic Stabilization(1,3,5-hexatriene)
0
1
2
3