The Gas Laws

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The Gas Laws. Pressure Volume & Temperature. States of Matter. In liquids and solids, the primary particles (atoms or molecules) are always in contact with each other. In gases, particles move independently. - PowerPoint PPT Presentation

Transcript of The Gas Laws

Pressure Volume & Temperatu

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In liquids and solids, the primary particles

(atoms or molecules) are always

in contact with each other.

In gases, particles move independently.

Because the atoms of gases are far apart

they are very compressible.

When pressure is applied, the volume

occupied by a gas can be decreased.

Gases fill all of the space available to them.

In a contained sample (e.g. balloon) gases expand to fill the total volume of the balloon.

If not contained:

Gases expand indefinitely.

If the cubic meter were divided into 1000 equal smaller parts, each part would be equal

to 1 Liter (slightly larger than a quart)

1 qt = 1.057 L

If each liter were divided into 1000 equal

smaller parts, each part would be equal to

1 milliliter (mL) or 1 cubic centimeter (cc)   1 mL = 1 cc 

Space occupied in 3 dimensions.

Units: liters

One liter is similar in volume to a quart

1 qt = 1.057 L

One liter is equal to 1,000 cubic centimeters

Force per unit of area.

Force / area  =  lbs / sq.in  

Pounds per square inch =  psi 14.7 psi = 1 atm

1 mm Hg = 1 torr 1 atm = 760 mm Hg

Increase the pressure

Volume decreases proportionally  

Pressure x Volume = constant

Product of pressure and volume is fixed.

P x V = constant 

P1 x V1 = P2 x V2

Compressed gas cylinder

Pressure = 135 atm

Volume = 15.0 liters

What volume the gas will occupy at 1.00 atm ?

P1 = 135 atm

V1 = 15.0 L

P2 = 1.00 atm

Determine V2

P1 x V1 = P2 x V2

V2 = ( P1 x V1 ) / P2

V2 = ( 135 atm ) ( 15.0 L ) / 1.00 atm

= 2,030 liters

Increase the temperature

Volume will increase proportionally.

The volume of a sample divided by the

temperature is equal to a constant.

V / T

= constant

V1 / T1 = V2 / T2

Determine the final volume of a

0.35 liter balloon which is heated from

room temperature to 100 degrees C.

V1 / T1 = V2 / T2

Convert all temperatures to Kelvins.

T1 = 25 °C + 273 = 298 K

T2 = 100 °C + 273 = 373 K

V1 / T1 = V2 / T2

V2 = ( V1 x T2 ) / T1

= V1 x ( T2 / T1 )

= ( 0.35 L ) ( 373 K / 298 K)

= ( 0.35 ) ( 1.25)

= 0.44 liters

Pressure is proportional to the temperature

The ratio of the absolute temperature

to the pressure is always constant.

P1 / T1 = P2 / T2  

The pressure inside a compressed gas cylinder is 134 atm @ 25 °C. Calculate the new pressure inside the cylinder if it is heated to 48 °C.

P1 = 134 atm

T1 = 25 + 273 = 298 K

  T2 = 48 + 273 = 321 K

 

Determine P2

P1 / T1 = P2 / T2

 

P2 = ( P1 x T2 ) / T1

P2 = ( 134 atm ) ( 321 K ) / 298 K

= 144 atm

The pressure of CO2 inside a bottle of carbonated soda pop is approximately 1.35 atm @ 25 °C (298 K).

Determine the pressure inside the bottle if it is chilled to 0 °C (273 K) .

 

P1 / T1 = P2 / T2

 

P2 = ( P1 x T2 ) / T1

 P2 = (

1.34 atm ) ( 273 K ) / 298 K

= 1.23 atm

We can combine all of these laws

to get a combined gas law:

P V / T = constant

P1 x V1 / T1 = P2 x V2 / T2

This law holds for a fixed amount of gas (or a fixed number

of moles, n ).

Start with 2.37 liters of gas

@ 25.0 °C ( 298 K ) and 1 atmosphere

Heat it to 297 °C ( 570 K ).

Increase the pressure to 10 atmospheres.

What is the final volume?

*Note: Upon heating, volume will increase.

But on compression, volume will decrease.

Opposing forces

P1 x V1 / T1 = P2 x V2 / T2

Solve for V2 (isolate the variable):  V2

= [ P1 x V1 / T1 ] x ( T2 / P2 )

Express as a product of ratios: V2

= V1 x [ P1 / P2 ] x [ T2 / T1 ]

P1 / P2 = 1 / 10 

T2 / T1 = 570 / 298 

V2 = ( 2.37 ) ( 1 / 10 ) ( 570 / 298)

V2 = ( 2.37 ) ( 0.19 ) = 0.453 L

*Note: Ratio of pressures = 0.10 < 1

Ratio of temps = 1.91 > 1

They offset each other.

P V = n R T

n = # of moles of gas

R = 0.0821 liter * atm / mol * K

PV / nT = constant

( P1 x V1 ) / ( n1 x T1 )

= ( P2 x V2 ) / ( n2 x T2 )

Calculate the volume of 1 mole of Ideal gas

@ Room temp (298 K) and pressure (1 atm).

P V = n R T

V = n R T / PV

= ( 1.0 ) ( 0.0821 ) ( 273 ) / 1.0

= 22.4 L

11.2 L tank of gas is found in the coldest

part of the refrigerator (0 °C = 273 K).  

It contains 4

moles of gas: (1 mole of oxygen and

3 moles of neon).

 What is the pressure in the tank?

P = nRT / V =

= ( 4.0 )( 0.0812 ) ( 273 ) / 11.2

= 7.91 atm