Solving Systems of Equation using Substitution

By: Starr Jones

Y = 5x + 11y = 10x – 4

Y = 5x + 11y = 10x – 4

5x + 11 = 10x -4

5x + 11 = 10x – 4

-5x -5x11 = 5x – 4 +4 +415 = 5x/5 /53 = X

5x + 11 = 10x – 4Y = 5x + 11 y= 5(3)+11y = 10x – 4 y= 10(3) – 4

5x + 11 = 10x – 4

-5x -5x11 = 5x – 4 +4 +415 = 5x/5 /53 = X

5x + 11 = 10x – 4Y = 5x + 11 y= 5(3)+11y = 10x – 4 y= 10(3) – 4

5x + 11 = 10x – 4

-5x -5x11 = 5x – 4 +4 +415 = 5x/5 /5 Solution: (3, 26)3 = X