Solving Equations A Stand-ALONE INSTRUCTIONAL RESOURCE

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Solving Equations A Stand-ALONE INSTRUCTIONAL RESOURCE. Click the ‘NEXT’ button to continue. NEXT. introduction. - PowerPoint PPT Presentation

Transcript of Solving Equations A Stand-ALONE INSTRUCTIONAL RESOURCE

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Click the ‘NEXT’ button to continue

Today, in Ms. Stechschulte’s 7th grade class, we will be learning how to solve one-step equations. To navigate through this presentation, click on the arrows and buttons at the bottom of the screen. The arrow labeled ‘NEXT’, will take you to the next slide. The arrow labeled ‘BACK’, will take you back to the previous slide. When you get to the Main Menu, click on the first link to begin the lesson. If you need to go back to the previous lessons to clarify concepts, please do so.

Click the arrow below to continue.NEXT

Your goal is to learn the concept of solving equations so you are successful answering the quiz questions. You must know the concepts well enough to solve two-step equations for tomorrow’s class. When you are finished with the first 2 Lessons, go to Lesson 3 and play the online math games for the remainder of the class period.

Good luck and have fun NEXTBACK

“An equation is a written statement indicating the equality of two expressions”

It consists of a sequence of symbols that are split into left and right sides joined by an equal sign.

For example, 2 + 4 = 6 is an equation.

http://dictionary.reference.com/browse/equation

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Left side Right side

BACK

* Remember *

2x + 3 = 5

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Coefficient: the number that is in front of the x. This means that 2 and x are multiplied.

Variable: the letter you are solving for; it needs to be isolated on one side of the equation. A variable can be any letter.

Left side Right side

BACK

Lesson 1: Using adding & subtracting

Lesson 2: Using multiplication & division

Lesson 3: Online Math Games

Click on the link for Lesson 1 to begin.When finished with Lesson 1, continue with Lesson 2

then 3.

Hoop Shoot

Equation Buster

Easy Algebra Equations

Say the ‘2 – steps’: Rags to Riches

BACK

1x

=

111

x + 1 = 3To solve an equation you must get x

by itself on one side of the equal sign, while keeping the scale balanced

NEXTBACK

=

x

1

111

NEXT

To get x by itself you have to take away (subtract) 1. However, this will cause the scale to become

unbalanced, so you also have to take away 1 from the other side of the equal sign.

BACK

1

x

=

11

1

x + 1 = 3 -1 -1 x = 2

NEXT

After you subtract 1 from both sides of the equal sign, you are left with x = 2

BACK

NEXT

“Two operations are said to be inverse to each other if one operation undoes the effect of the other operation.”

Addition and Subtraction are inverse operations

Multiplication and Division are inverse operations

http://www.icoachmath.com/Sitemap/InverseOperation.html BACK

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Inverse operations must be used when solving equations.

In the previous example we SUBTRACTED to undo the ADDITION to get x by itself.

To solve x – 5 = 3,

what operation must you use to get x by itself?

BACK

MORE EXAMPLES

If you said ADDITION you are correct! To undo SUBTRACTION you must ADD.

To solve

x – 5 = 3 +5 +5 x = 8

Add 5 to both sides to keep the equation balanced.

Begin Quiz

1BACK

1x

=

111

x + 2 = 4To solve an equation get rid of whatever is with the

variable (x). What you do to one side, you must also do to the other side.

NEXT

11

1

x

=

11

1

x + 2 = 4Subtract 2 from both sides to keep the scale

balanced

1 1

x = 2

To Quiz 1

NEXTBACK

Since 2 is SUBTRACTED from x, you must ADD 2 to both sides to solve

x – 2 = 3 +2 +2 x = 5

Add 2 to both sides to keep the equation balanced.

To Quiz 1 NEXTBACK

-1 = 7 + x is the same as saying 7 + x = -1 Since 7 is ADDED to x, you must SUBTRACT 7 from both sides to solve

-1 = 7 + x -7 -7

-8 = xx = -8

Subtract 7 from both sides to keep the equation balanced.

To Quiz 1BACK

Question 1:

Solve x + 4 = 9

A. x = 13B. x = 5C. x = 9

Click on a letter to continue.

Question 2:

Solve x – 5 = 2

A. x = -3B. x = 2C. x = 7

Click on a letter to continue.

Question 3:

Solve – 5 = 4 + x

A. x = -9B. x = -1C. x = 9

Click on a letter to continue.

Correct!!

Nice Work! NEXT

Correct!!

Great Job! NEXT

Correct!!

Fabulous! NEXT

IncorrectTry Again

Let’s look at another example NEXT

1x

=

111

x + 2 = 4To solve an equation get rid of whatever is with the

variable (x). What you do to one side, you must also do to the other side.

NEXT

11

1

x

=

11

1

x + 2 = 4Subtract 2 from both sides to keep the scale

balanced

1 1

x = 2

To Quiz 1

BACK

IncorrectTry Again

Let’s look at another example NEXT

Since 2 is SUBTRACTED from x, you must ADD 2 to both sides to solve

x – 2 = 3 +2 +2 x = 5

Add 2 to both sides to keep the equation balanced.

To Quiz 1

IncorrectTry Again

Let’s look at another example NEXT

-1 = 7 + x is the same as saying 7 + x = -1 Since 7 is ADDED to x, you must SUBTRACT 7 from both sides to solve

-1 = 7 + x -7 -7

-8 = xx = -8

Subtract 7 from both sides to keep the equation balanced.

To Quiz 1

What is the inverse operation of

MULTIPLICATION?

NEXTBACK

The answer is…

DIVISION

NEXTBACK

What is the inverse operation of DIVISION?

NEXTBACK

The answer is…

MULTIPLICATION

NEXTBACK

When you have an equation with

multiplication or division, you will do the

inverse operation to solve!

NEXTBACK

Since 6 and x are multiplied, to solve, we divide by 6.

6x = 48 6x = 48

6 6x = 8

Divide by 6 on both sides to keep the equation balanced.

BACK NEXTReminder: When a number is divided by itself, it equals 1.

Since x is divided by 4, to solve, we multiply by 4.

x = 5 4

(4)x = 5(4) 4

x = 20

Multiply by 4 on both sides to keep the equation balanced.

To Quiz 2BACK

MORE EXAMPLES

The inverse operation of MULTIPLICATION is DIVISION, so we

divide by 10.

10x = 30 10x = 30

10 10x = 3

Divide by 10 on both sides to keep the equation balanced.

NEXTTo

Quiz 2BACK

The inverse operation of DIVISION is MULTIPLICATION, so we multiply by -5.

x = 3 -5

(-5)x = 3(-5) -5

x = -15

Multiply by -5 on both sides to keep the equation balanced.

NEXT

To Quiz 2

** Remember: Negative times a positive = negative

BACK

The inverse operation of MULTIPLICATION is DIVISION, so we

divide by -2.

-2x = -10 -2x = -10

-2 -2x = 5

Divide by -2 on both sides to keep the equation balanced.

To Quiz 2

** Remember: Negative times a negative = positive

BACK

Question 1:

Solve 5x = 35

A. x = 175B. x = 30C. x = 7

Click on a letter to continue.

IncorrectTry Again

Let’s look at another example NEXT

Correct!!

Super! NEXT

Question 2:

Solve x = 4

-2A. x = -8B. x = 6C. x = -2

Click on a letter to continue.

IncorrectTry Again

Let’s look at another example NEXT

Correct!!

Fantastic! NEXT

Question 3:

Solve -3x = 6

A. x = 2B. x = -2C. x = -18

Click on a letter to continue.

IncorrectTry Again

Let’s look at another example NEXT

Correct!!

Great Job! NEXT

The inverse operation of MULTIPLICATION is DIVISION, so we

divide by 10.

10x = 30 10x = 30

10 10x = 3

Divide by 10 on both sides to keep the equation balanced.

To Quiz 2

The inverse operation of DIVISION is MULTIPLICATION, so we multiply by -5.

x = 3 -5

(-5)x = 3(-5) -5

x = -15

Multiply by -5 on both sides to keep the equation balanced.

To Quiz 2

** Remember: Negative times a positive = negative

The inverse operation of MULTIPLICATION is DIVISION, so we

divide by -2.

-2x = -10 -2x = -10

-2 -2x = 5

Divide by -2 on both sides to keep the equation balanced.

To Quiz 2

** Remember: Negative times a negative = positive