Geometry Basketball

Reviewing Circles

Find the arc or angle.

Solution

55 +65 = 120

180-120=60

Find the arc or angle.

Solution

55º

Vertical Angles

are congruent!

Find the arc or angle.

Solution

Semicircle + Arc NB

180 +55 =235

Find the arc or angle.

Solution

Inscribed Angle is ½ of its intercepted arc

<ABC = ½(84)

=42

Find the arc or angle.

Solution

Inscribed Angle is ½ its intercepted arc

<ABC= ½ (arc AC)

65 = ½ (arc AC)

130 = arc AC

Find the arc or angle.

Solution

When the lines intersect ON THE CIRCLE, the angle is

½ of the arc.

135= ½ (MLK)

270 = MLK

Find the arc or angle.

Solution

When the lines intersect ON THE CIRCLE, the angle is

½ of the arc.

m<1= ½ (260)

m<1 = 130

Find the arc or angle.

Solution

When the lines intersect IN THE CIRCLE, the angle is the sum of the arcs divided by 2.

Wrong arcs 125+105=230

360-230=130 Sum of correct arcs

m<1=130/2

m<1 = 65

Find the arc or angle.

Solution

When the lines intersect OUTSIDE THE CIRCLE, the angle is the

bigger arc –smaller arc divided by 2.

m<1= (122-64)/2

m<1 = 58/2

m<1 = 29

Find the arc or angle.

Solution

When the lines intersect OUTSIDE THE CIRCLE, the angle is the

bigger arc –smaller arc divided by 2.

m<1= (135-55)/2

m<1 = 80/2

m<1 = 40

Find the arc or angle.

Solution

When the lines intersect OUTSIDE THE CIRCLE,

Outside segmet (whole segment) = Outside segment (whole segment)

8(x+8) = 9 (9)

8(x+8) = 9²

8x+64=81

8x=17

X=17/8

Find the arc or angle.

Solution

When the lines intersect OUTSIDE THE CIRCLE,

Outside segmet (whole segment) = Outside segment (whole segment)

5(3x+5) = 10 (10)

5(3x+5) = 10²

15x+25=100

15x=75

X=5

Find the center and radius of the circle.

Solution

Center : (-3,4)

Radius: 6

Find the arc or angle.

Solution

m<KMX = 75

Vertical Angles are Congruent!

Find the arc or angle.

Solution

Semicircle = 180

90 +75 = 165

180 – 165 = 15

Find the arc or angle.

Solution

Semicircle + Arc LY

180 + 75

255

Find the arc or angle.

Solution

Inscribed Angle is ½ its intercepted arc

m<TUV= ½ (arc TV)

m<TUV = ½ (240)

m<TUV = 120

Find the arc or angle.

Solution

When the lines intersect ON THE CIRCLE, the angle is ½ of the arc.

53= ½ (arcAB)

106 = arc AB

Find the arc or angle.

Solution

When the lines intersect IN THE CIRCLE, the angle is the sum of the

arcs divided by 2.

Use Semicircle 180 – 147 = 33

m<1= (67+33)/2

m<1=100/2

m<1=50

Find the arc or angle.

Solution

When the lines intersect ON THE CIRCLE, the angle is ½ of the arc.

Use full circle 360-150=210

m<1= ½ (210)

m<1=105

Find the arc or angle.

Solution

When the lines intersect OUTSIDE THE CIRCLE, the angle is the

bigger arc –smaller arc divided by 2.

Use full Circle 360-234 =126m<1= (234-126)/2

m<1 = 108/2m<1 = 54

Find x.

Solution

When the lines intersect IN THE CIRCLE, (part)(part) = (part)(part)

(2x)(2x) = (5)(20)4x²=100

x²=25x= 5 or -5

(the lengths can’t be negative, so…)x=5

Find x.

Solution

When the lines intersect OUTSIDE THE CIRCLE,

(part)(part) = (part)(part)(2x)(2x) = (5)(20)

4x²=100x²=25

x= 5 or -5 (the lengths can’t be negative, so…)

x=5

Find x.

Find x.

Find the angle.

Find the angle.

Find the angle.