Post on 25-Dec-2015
Formulas…• They help us find the area.• They did not fall out of the sky!• In Exploration 10.7, you will develop the
formulas for the area of a triangle, rectangle, and parallelogram.
• Now, let’s develop the formula for the area of a trapezoid.
Area of Trapezoids• First method: draw a diagonal, and find
the area of 2 triangles.
Base 1
Base 2
Height
Area of Trapezoids• Method 2: make a 180˚ rotated image;
find the area, and cut it in half.
Base 1
Base 2
Height
Base 1
Base 2
Height
Area of a circle• If you like, read Exploration 10.8. It
explains in more detail why the area of a circle is πr2.
• Take any circle.
• Subdivide it into many congruentsectors--in this case,we made 16.
• Cut out each sector. Rearrange them.
• What shape does this remind you of?– What is the formula for finding the area of this shape? Find it!
Pythagorean Theorem • The most proved theorem ever--over
300 proofs! One was done by James Garfield, before he was president of the United States.
• If you have a right triangle with hypotenuse of length “c”, then
a2 + b2 = c2.
It looks like this!• a2 + b2 = c2.
But we use it like this.• Find the perimeter and area of this
triangle.
5 feet
x feet
13 feet
Other ways to make our life easy.
• Compare the circumference and area.
r
2r
Try this--find perimeter and area
13 “13 “
10 “
10 “
20 “
• P = tri + rect + sem13 + 13 + 10 + 20 + 10 + sem (.5 • 2π• 5)
• A = tri + rect + sem52 + x2 = 132
x = 12.5•10•12 + 20•10 + .5•π•52
13 “13 “
10 “
10 “
20 “
Try to find the shaded area• Assume the
trapezoidisisosceles.
24 cm
24 cm
38 cm--whole base7 cm
4 cm
• Area of trapezoid - area of parallelogram• Trap: .5 • 24 (24 + 38)• Para: 7 • 4• Did not need
PythagoreanTheorem!
24 cm
24 cm
38 cm--whole base7 cm
4 cm
Find the perimeter and area…
• If it looks right or congruent, it is.
• (1) (2)
9 in.9 in.
18 in.
18 in.
10 m
14 m4 m2
2.8 m
2 m
One• Perimeter
– Sides of largetriangle: 92 + 92 = x2
x = 12.712.7 + 12.7 + 12.7 + 12.7
+ 9 + 9 = 68.6 in.
• Area: Note that the largetriangle can be moved to make a rectangular figure.– 9 • 18 = 162 in.2
9 in.9 in.
18 in.
18 in.
Two• Perimeter:
– 10 + 10 + 2.8 + 2.8+ 2.8 + 2.8 + 2 + 2 =35.2 m
• Area:– Two trapezoids and a rectangle– (.5)(2)(10 + 14) + (.5)(2)(10 + 14) + 2 • 14– 84 m2
10 m
14 m4 m2
2.8 m
2 m