Post on 06-Dec-2021
Fluid Mechanics-61341
An-Najah National UniversityCollege of Engineering
Chapter [5]
Fluid Mechanics-2nd Semester 2010- [5] Flow of An Incompressible Fluid Dr. Sameer Shadeed1
Dr. Sameer Shadeed
Chapter [5]
Flow of An Incompressible Fluid
Euler’s Equation
Dr. Sameer Shadeed2 Fluid Mechanics-2nd Semester 2010- [5] Flow of An Incompressible Fluid
Euler’s Equation
Dr. Sameer Shadeed3 Fluid Mechanics-2nd Semester 2010- [5] Flow of An Incompressible Fluid
Euler’s Equation
Dr. Sameer Shadeed4 Fluid Mechanics-2nd Semester 2010- [5] Flow of An Incompressible Fluid
Bernoulli’s Equation
Dr. Sameer Shadeed5 Fluid Mechanics-2nd Semester 2010- [5] Flow of An Incompressible Fluid
Bernoulli’s Equation
Dr. Sameer Shadeed6 Fluid Mechanics-2nd Semester 2010- [5] Flow of An Incompressible Fluid
Constanthead
Elevation
head
Velocity
head
Pressure
The Energy Line (EL) and the Hydraulic Grade Line (HGL)
Each term in the Bernoulli’s equation is a type ofhead
P/g = Pressure Head
V2/2gn = Velocity Head
Z = Elevation head
EL is the sum of these three heads
HGL is the sum of the elevation and the pressureheads
Fluid Mechanics-2nd Semester 2010- [5] Flow of An Incompressible Fluid7 Dr. Sameer Shadeed
The Energy Line (EL) and the Hydraulic Grade Line (HGL)
Dr. Sameer Shadeed8 Fluid Mechanics-2nd Semester 2010- [5] Flow of An Incompressible Fluid
V2/2gEL
V2/2g
HGL
Understanding the graphical approachof EL and HGL is key to understandingwhat forces are supplying the energy thatwater holds
Point 1: Majorityof energy stored inthe water is in thePressure Head
Point 2: Majorityof energy stored in
The Energy Line (EL) and the Hydraulic Grade Line (HGL)
Q
Z
P/ g
P/g
Z
1
2HGL
of energy stored inthe water is in theelevation head
If the tube wassymmetrical, thenthe velocity wouldbe constant, andthe HGL would belevel
Fluid Mechanics-2nd Semester 2010- [5] Flow of An Incompressible Fluid9 Dr. Sameer Shadeed
Bernoulli’s Equation (Uniform Cross Section)
For uniform cross sections streamtubes, the velocity across the entire section is uniform as a result Bernoulli’sequation becomes:
Dr. Sameer Shadeed10 Fluid Mechanics-2nd Semester 2010- [5] Flow of An Incompressible Fluid
Example 1
Fluid Mechanics-2nd Semester 2010- [5] Flow of An Incompressible Fluid11 Dr. Sameer Shadeed
Example 1 (Solution)
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Application of Bernoulli’s Equation
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Torricelli’s theorem
Torricelli’s Theorem
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An ideal fluid is one that isincompressible and has noresistance to shear stress. Idealfluids do non actually exist, butsometimes it is useful toconsider what happen to anideal fluid in a particular fluidflow problem in order to simplifythe problem
Taking the datum at the center of the nozzle andchoosing the center streamline give h = z + p/gg in thereservoir where velocities are negligible
Writing Bernoulli’s equation for a streamline between thereservoir and the tip of the nozzle shown as in Fig. 5.4
Torricelli’s Theorem
reservoir and the tip of the nozzle shown as in Fig. 5.4
hgVg
Vh
g
Vphz
p
nn
n
22
0pifresultsequations'Torricelli,2
2
2
22
11
Fluid Mechanics-2nd Semester 2010- [5] Flow of An Incompressible Fluid15 Dr. Sameer Shadeed
For freely falling body
Torricelli’s Theorem
hgV
asuV
20
22
22
hgVg
Vh
hgV
nn
n
22
202
2
Fluid Mechanics-2nd Semester 2010- [5] Flow of An Incompressible Fluid16 Dr. Sameer Shadeed
Torricelli’s Theorem (Free Jets)
The velocity of a jet of water is clearly related to thedepth of water above the hole
The greater the depth, the higher the velocity
Fluid Mechanics-2nd Semester 2010- [5] Flow of An Incompressible Fluid17 Dr. Sameer Shadeed
Example 2
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Example 2 (Solution)
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Example 2 (Solution)
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Example 2 (Solution)
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Example 2 (Solution)
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Example 3
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Example 3 (Solution)
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Example 3 (Solution)
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Application of Bernoulli’s Equation
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Application of Bernoulli’s Equation
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stagnation pointstagnation point
Stagnation Points On any body in a flowing fluid, there is a stagnationstagnation pointpoint. Somefluid flows over and some under the body. The dividing line (thestagnation streamline) terminates at the stagnation point.
The velocity decreases as the fluid approaches the stagnationpoint. The pressure at the stagnation point is the pressure obtainedwhen a flowing fluid is decelerated to zero speed
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stagnation pointstagnation point
Example 4
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Example 4 (Solution)
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Example 5
Determine the difference in pressure between points1 and 2. Hint: Point 1 is called a stagnation point,because the air particle along that streamline, when ithits the biker’s face, has a zero velocity
Fluid Mechanics-2nd Semester 2010- [5] Flow of An Incompressible Fluid31 Dr. Sameer Shadeed
Assume a coordinate system fixed to the bike (from thissystem, the bike is stationary, and the world moves past it).Therefore, the air is moving at the speed of the bike. Thus, V2
= Velocity of the Biker
Apply Bernoulli’s equation from 1 to 2
Example 5 (Solution)
Point 1 = Point 2
P1/gair + V12/2g + z1 = P2/gair + V2
2/2g + z2
Knowing the z1 = z2 and that V1= 0, we can simplify the equation
P1/gair = P2/gair + V22/2g
P1 – P2 = ( V22/2g ) gair
Fluid Mechanics-2nd Semester 2010- [5] Flow of An Incompressible Fluid32 Dr. Sameer Shadeed
Example 5 (Solution)
If the Biker is traveling at 5 m/s, what pressure does he feel
on his face if the gair = 12.01 N/m3 ?
We can assume P2 = 0, because it is only atmospheric pressurepressure
P1 = ( V22/2g )(gair)
P1 = ((5)2/(2(9.81)) x 12.01
P1 = 15.3 N/m2 (gage pressure)
If the biker’s face has a surface area of 300 cm2
He feels a force of 15.3 x 300x10-4 = 0.46 N
Fluid Mechanics-2nd Semester 2010- [5] Flow of An Incompressible Fluid33 Dr. Sameer Shadeed
Application of Bernoulli’s Equation
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Application of Bernoulli’s Equation
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Example 6
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Example 6 (Solution)
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Example 6 (Solution)
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Example 6 (Solution)
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Application of Bernoulli’s Equation
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Application of Bernoulli’s Equation
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Example 7
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Example 7 (Solution)
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Example 7 (Solution)
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Example 7 (Solution)
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Example 7 (Solution)
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Example 8
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Example 8 (Solution)
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Example 8 (Solution)
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The Work Energy Equation
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The Work Energy Equation
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The Work Energy Equation
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Example 9
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Example 9 (Solution)
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Example 9 (Solution)
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Example 10
Calculate the power output of this turbine
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Example 10 (Solution)
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Example 10 (Solution)
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Example 11
Water is pumped from a large lake into an irrigationcanal of rectangular cross section 3 m wide, producing theflow situation shown in the figure. Calculate the requiredpump power assuming ideal flow.
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Example 11 (Solution)
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Example 11 (Solution)
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