FiberReinforcedBeamCompetitionObjectiveTheobjectiveistouseyourknowledgeofconcretematerialstodesignthestrongestfiberreinforcedbeamforflexuralstrength.Teamswillattempttousethemostefficientcross-sectionaldesignanduseoffiberreinforcementintheirbeamtogetthehigheststrengththatisclosesttotheirpredictedstrength.EligibilityOne(1)teamperschoolwillbeallowedtoparticipate.Teamsmayconsistofbetweentwo(2)andfour(4)memberswithamaximumofone(1)graduatestudent.Materials

• PortlandcementmustmeetASTMC150,butmaybeanysubtype(TypeI,II,III,etc.).

• Othercementitiousmaterialscanbemadeupofanyofthefollowing:FlyAsh(ASTMC618),SlagCement(ASTMC989),orSilicaFume(ASTMC1240).

• FiberReinforcementmustmeetASTMC1116.• ChemicaladmixturesmustmeetASTMC494and/orASTMC260• CoarseaggregatesmustmeettheNo.67orNo.57gradationsspecifiedin

ASTMC33• FineAggregatesmustmeetspecificationsinASTMC33

BeamDimensions

• Length=24inches• Crosssectionof6inchesby6incheswithatoleranceof±0.1inches• Doesnothavetobesquarecrosssection(i.e.I-beam)

LogisticsEachteam’sbeamwillbetestedusingthethird-pointloadingoutlinedinASTMC78.Eachbeamwillbejudgedinthreecategories:fiberuseefficiency,strength,andstrengthprediction.TeamsmustfilloutthemixdesignsheetinAppendixAandprovideittothejudgeswhenpresentingthebeamfortesting.Teamsmustincludetheirstrengthpredictiononthemixdesignsheet.

FiberEfficiencyFactorAteam’sscorecanbeincreasedordecreasedbasedontheamountoffiberinthemixdesign.Afiberefficiencyfactorwillbecalculatedasfollowsandmultipliedbythemaximumload.Aminimumof0.5%fiberbyvolumeisrequired.Failuretomeetminimumfiberrequirementswillresultindisqualification.

𝐹𝐸𝐹 =1

(% 𝐹𝑖𝑏𝑒𝑟 𝑏𝑦 𝑉𝑜𝑙𝑢𝑚𝑒)

Example:2%fiberbyvolume.FEF=½=0.5BeamStrengthFlexuralfailurewillbedeterminedinaccordancewithASTMC78.Allbeamswillbeloadedtofailure.Loadswillberecordedtothenearest0.1pounds.Themaximumloadheldbythebeamwillbetakenasstrength.Eachteamwillberesponsiblefororientingitsbeamforloading.Atleastone(1)personfromtheteammustbepresentatthetimeofloading.Ifnorepresentativeispresentattheloading,theteamwillbemovedtotheendofthetestingorder.Ifnorepresentativeisthereattheendofthetestingorder,thatteamwillbeawardedzero(0)points.Thebeamstrengthscorewillbedeterminedbymultiplyingthemaximumloadbythefiberefficiencyfactor.Thosestrengthswillberankedagainsttheotherteams.Theteamwiththehigheststrengthwillreceive60points,andtheotherswillbeawardedpointslinearlybasedontheirrankings,asshownbelow.

𝑃! = 60 ∗𝑆 − 𝑅 + 1

𝑆

𝑃! = 𝑆𝑡𝑟𝑒𝑛𝑔𝑡ℎ 𝑃𝑜𝑖𝑛𝑡𝑠𝑆 = 𝑇𝑜𝑡𝑎𝑙 𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑆𝑐ℎ𝑜𝑜𝑙𝑠 𝑇ℎ𝑎𝑡 𝑃𝑎𝑟𝑡𝑖𝑐𝑖𝑝𝑎𝑡𝑒𝑑 𝑖𝑛 𝑡ℎ𝑒 𝐶𝑜𝑚𝑝𝑒𝑡𝑖𝑡𝑖𝑜𝑛

𝑅 = 𝑅𝑎𝑛𝑘𝑖𝑛𝑔 𝑓𝑜𝑟 𝑆𝑡𝑟𝑒𝑛𝑔𝑡ℎ

StrengthPredictionEachteammustpredictatwhichloaditsbeamwillfail,andpointswillbeawardedbasedonhowclosetothepredictedloadthebeambreaks.Theteamwiththeclosestpredictionwillbeawarded40points,andtheremainingteamswillbeawardedpointslinearlybasedontheirranking,asshownbelow.

𝑃! = 40 ∗𝑆 − 𝑅 + 1

𝑆

𝑃! = 𝑃𝑟𝑒𝑑𝑖𝑐𝑡𝑖𝑜𝑛 𝑃𝑜𝑖𝑛𝑡𝑠𝑆 = 𝑇𝑜𝑡𝑎𝑙 𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑆𝑐ℎ𝑜𝑜𝑙𝑠 𝑇ℎ𝑎𝑡 𝑃𝑎𝑟𝑡𝑖𝑐𝑖𝑝𝑎𝑡𝑒𝑑 𝑖𝑛 𝑡ℎ𝑒 𝐶𝑜𝑚𝑝𝑒𝑡𝑖𝑡𝑖𝑜𝑛

𝑅 = 𝑅𝑎𝑛𝑘𝑖𝑛𝑔 𝑓𝑜𝑟 𝑃𝑟𝑒𝑑𝑖𝑐𝑡𝑖𝑜𝑛

Rankingswillbebasedonthesmallestabsolutevalueofthetestedloadandpredictedload.Tieswillgototheteamwiththehighesttestedstrength.TotalScore

TotalScore=BeamStrengthScore+PredictionScore

ScoringSummarySheetAuthor’sName:_________________________________________________Date:_________________ASCEStudentOrganization:_______________________________________

BeamScoringCriteria Score

1.EfficiencyFactor

2.FlexuralStrength

3.BeamStrengthScore /604.PredictionScore /40

BeamTotalScore /100

AppendixA:MixDesignSchoolName PrintedName SignatureFacultyAdvisor TeamMember StrengthPrediction

Component TypeandSize UnitWeight(𝒍𝒃/𝒇𝒕𝟑)Cement

CementitiousMaterials

CoarseAggregates

FineAggregates

ChemicalAdmixtures

Reinforcement

Water Total