Post on 06-Jan-2016
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Chapter 7DC Biasing Circuits
Pictures are redrawn (with some modifications) from Introductory Electronic Devices and Circuits
ByRobert T. Paynter
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Objectives
• State the purpose of dc biasing circuits.
• Plot the dc load line given the value of VCC and the total collector-emitter circuit resistance.
• Describe the Q-point of an amplifier.• Describe and analyze the operations of various
bias circuits:– base-bias circuits– voltage-divider bias circuits– emitter-bias circuits– collector-feedback bias circuits– emitter-feedback bias circuits
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Fig 7.1 Typical amplifier operation.
RB
RC
Q1
VCCVB(ac)
IB(ac)
VCE(ac)
IC(ac)
4
Fig 7.2 A generic dc load line.
IC
VCE
(sat)CC
CC
VI
R
(off )CE CCV V
CC CEC
C
V VI
R
5
Fig 7.3 Example 7.1.
RB
RC2 k
Q1
+12 V
VCE2 4 6 8 10 12
2
4
6
8
IC
IC(sat)
VCE(off)
Plot the dc load line for the circuit shown in Fig. 7.3a.
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Fig 7.4 Example 7.2.Plot the dc load line for the circuit shown in Fig. 7.4. Then, find the values of VCE for IC =
1, 2, 5 mA respectively.
RB
RC1 k
Q1
+10 V
VCE2 4 6 8 10
2
4
6
8
IC
10 IC (mA) VCE (V)
1 9
2 8
5 5
CE CC C CV V I R
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Fig 7.6-8 Optimum Q-point with amplifier operation.
βC BI I
CE CC C CV V I R
VCE
IB = 0 A
IB = 10 A
IB = 20 A
IB = 30 A
IB = 40 A
IB = 50 A
IC
Q-Point
VCCVCC/2
IC(sat)
IC(sat)/2
IB
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Fig 7.9 Base bias (fixed bias).
CC BEB
B
V VI
R
βC BI I
CE CC C CV V I R
RC
RB
+0.7 V
IC
IB
IE
Input
Output
VBE
VCC
Q1
= dc current gain = hFE
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Fig 7.10 Example 7.3.
RC2 k
RB360 k
+0.7 V
IC
IB
IEVBE
+8 V
hFE = 100
0.7V 8V 0.7V
360kΩ
20.28μA
CCB
B
VI
R
100 20.28μA
2.028mAC FE BI h I
8V 2.028mA 2kΩ
3.94V
CE CC C CV V I R
The circuit is midpoint biased.
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Fig 7.11 Example 7.4.
Construct the dc load line for the circuit shown in Fig. 7.10, and plot the Q-point from the values obtained in Example 7.3. Determine whether the circuit is midpoint biased.
VCE (V)2 4 6 8 10
1
2
3
4
IC (mA)
Q
(sat )
8V4mA
2kΩCC
CC
VI
R
off 8VCCCEV V
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Fig 7.12 Example 7.6. (Q-point shift.)
The transistor in Fig. 7.12 has values of hFE = 100 when T =
25 °C and hFE = 150 when T = 100 °C. Determine the Q-point values of IC and VCE at both of these temperatures.
RC2 k
RB360 k
+0.7 V
IC
IB
IEVBE
+8 V
hFE = 100 (T = 25C)hFE = 150 (T = 100C)
Temp(°C) IB (A) IC (mA) VCE (V)
25 20.28 2.028 3.94
100 20.28 3.04 1.92
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Fig 7.13 Base bias characteristics. (1)
RC
RB
+0.7 V
IC
IB
IE
Input
Output
VBE
VCC
Q1 Advantage: Circuit simplicity.
Disadvantage: Q-point shift with temp.
Applications: Switching circuits only.
Circuit recognition: A single resistor (RB) between the base terminal and VCC. No emitter resistor.
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Fig 7.13 Base bias characteristics. (2)
RC
RB
+0.7 V
IC
IB
IE
Input
Output
VBE
VCC
Q1
(sat )
(off )
CCC
C
CE CC
VI
R
V V
Load line equations:
Q-point equations:
CC BEB
B
C FE B
CE CC C C
V VI
R
I h I
V V I R
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Fig 7.14 Voltage divider bias. (1)
R1
R2 RE
RC
+VCC
Input
Output
I1
I2 IE
IB
IC
Assume that I2 > 10IB.
2
1 2B CC
RV V
R R
0.7VE BV V
EE
E
VI
R
Assume that ICQ IE (or hFE >> 1). Then
CEQ CC CQ C EV V I R R
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Fig 7.15 Example 7.7. (1)Determine the values of ICQ and VCEQ for the circuit shown in Fig. 7.15.
R118 k
R24.7 k
RE1.1 k
RC3 k
+10 V
I1
I2IE
IB
IC
hFE = 50
2
1 2
4.7kΩ10V 2.07V
22.7kΩ
B CC
RV V
R R
0.7V
2.07V 0.7V 1.37VE BV V
Because ICQ IE (or hFE >> 1),
1.37V1.25mA
1.1kΩE
CQE
VI
R
10V 1.25mA 4.1kΩ 4.87V
CEQ CC CQ C EV V I R R
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Fig 7.15 Example 7.7. (2)Verify that I2 > 10 IB.
R118 k
R24.7 k
RE1.1 k
RC3 k
+10 V
I1
I2IE
IB
IC
hFE = 50
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2.07V440.4μA
4.7kΩBVIR
1.25mA
1 50+1
24.51μA
EB
FE
II
h
2 10 BI I
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Which value of hFE do I use?
Transistor specification sheet may list any combination of the following hFE: max. hFE,
min. hFE, or typ. hFE. Use typical value if there is one. Otherwise, use
(ave) (min) (max)FE FE FEh h h
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Example 7.9A voltage-divider bias circuit has the following values: R1 = 1.5 k, R2 = 680 , RC = 260 , RE = 240 and VCC = 10 V. Assuming the transistor is a 2N3904,
determine the value of IB for the circuit.
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1 2
680Ω10V 3.12V
2180ΩB CC
RV V
R R
0.7V 3.12V 0.7V 2.42VE BV V
2.42V10mA
240ΩE
CQ EE
VI I
R
( ) (min) (max) 100 300 173FE ave FE FEh h h
(ave)
10mA57.5μA
1 174E
BFE
II
h
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Stability of Voltage DividerBias Circuit
The Q-point of voltage divider bias circuit is less dependent on hFE than that of the base bias (fixed
bias).
For example, if IE is exactly 10 mA, the range of hFE is 100 to 300. Then
10mAAt 100, 100μA and 9.90mA
1 101E
FE B CQ E BFE
Ih I I I I
h
10mAAt 300, 33μA and 9.97mA
1 301E
FE B CQ E BFE
Ih I I I I
h
ICQ hardly changes over the entire range of hFE.
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Fig 7.18 Load line for voltage divider bias circuit.
2 4 6 8 10 12
5
10
15
20
25
IC (mA)
VCE (V)
(sat )
10V20mA
260Ω+240ΩCC
CC E
VI
R R
(off ) 10VCE CCV V
Circuit values are from Example 7.9.
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Fig 7.19-20 Base input resistance. (1)
R1
R2 RE
RC
VCC
I1
I2IE
IB
IC
RIN(base)
R1
R2
I1
I2
VCC
0.7 V
IB RIN(base)
( 1)E E E B FE EV I R I h R
(base) ( 1)EIN FE E
B
FE E
VR h R
I
h R
May be ignored.
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Fig 7.19-20 Base input resistance. (2)
IB
R1
R2
I1
I2
VCC
IB RIN(base)
VB
2 (base)
1 2 (base)
2
1 2
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//
//
//
//
//
INB CC
IN
FE ECC
FE E
EQCC
EQ FE EEQ
R RV V
R R R
R h RV
R R h R
RV
R R h RR R
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Fig 7.21 Example 7.11.
2 //
10kΩ// 50 1.1kΩ 8.46kΩ
EQ FE ER R h R
1
8.46kΩ20V 2.21V
68kΩ 8.46kΩ
EQB CC
EQ
RV V
R R
0.7V
2.21V 0.7V1.37mA
1.1kΩ
E BCQ E
E E
V VI I
R R
20V 1.37mA 7.3kΩ 9.99V
CEQ CC CQ C EV V I R R
R168k
R210k
RE1.1k
RC6.2k
VCC=20V
I1
I2
IE
IC
hFE = 50
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Fig 7.24 Voltage-divider bias characteristics. (1)
R1
R2 RE
RC
+VCC
Input
Output
I1
I2 IE
IB
IC
Circuit recognition: The voltage divider in the base circuit.
Advantages: The circuit Q-point values are stable against changes in hFE.
Disadvantages: Requires more components than most other biasing circuits.
Applications: Used primarily to bias linear amplifier.
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Fig 7.24 Voltage-divider bias characteristics. (2)
R1
R2 RE
RC
+VCC
Input
Output
I1
I2 IE
IB
IC
Load line equations: (sat )
(off )
CCC
C E
CE CC
VI
R R
V V
Q-point equations (assume that hFERE > 10R2):
2
1 2
0.7V
B CC
E B
ECQ E
E
CEQ CC CQ C E
RV V
R R
V V
VI I
R
V V I R R
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Other Transistor Biasing Circuits
• Emitter-bias circuits• Feedback-bias circuits
– Collector-feedback bias– Emitter-feedback bias
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Fig 7.25-6 Emitter bias.Assume that the transistor operation is in active region.
RC
RE
RB
IC
IE
IBQ1
Input
Output
+VCC
-VEE
0.7V
1EE
BB FE E
VI
R h R
C FE BI h I
1E FE BI h I
CE CC C C E E EEV V I R I R V
Assume that hFE >> 1.
CE CC C C E EEV V I R R V
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Fig 7.27 Example 7.12.
RC750
RE1.5k
RB100
IC
IE
IB Q1
Input
Output
+12 V
-12 V
hFE = 200
Determine the values of ICQ and VCEQ for the amplifier shown in Fig.7.27.
12V 0.7V
( 1)
11.3V37.47μA
100Ω+201 1.5kΩ
BB FE E
IR h R
200 37.47μA
7.49mA
CQ FE BI h I
( )
24V 7.49mA 750Ω 1.5kΩ
7.14V
CEQ CC C C E EEV V I R R V
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Load Line forEmitter-Bias Circuit
(sat )
( )CC EE CC EEC
C E C E
V V V VI
R R R R
( )CE off CC EE CC EEV V V V V
VCE
IC
IC(sat)
VCE(off)
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Fig 7.28 Emitter-bias characteristics. (1)
RC
RE
RB
IC
IE
IBQ1
Input
Output
+VCC
-VEE
Circuit recognition: A split (dual-polairty) power supply and the base resistor is connected to ground.
Advantage: The circuit Q-point values are stable against changes in hFE.
Disadvantage: Requires the use of dual-polarity power supply.
Applications: Used primarily to bias linear amplifiers.
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Fig 7.28 Emitter-bias characteristics. (2)
RC
RE
RB
IC
IE
IBQ1
Input
Output
+VCC
-VEE
Load line equations:
(sat )
(off )
CC EEC
C E
CE CC EE
V VI
R R
V V V
Q-point equations:
1BE EE
CQ FEB FE E
CEQ CC CQ C E EE
V VI h
R h R
V V I R R V
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Fig 7.29 Collector-feedback bias.
RB
RC
+VCC
IC
IE
IB
CC C B C B B BEV I I R I R V
( 1)CC BE
BFE C B
V VI
h R R
CQ FE BI h I
1CEQ CC FE B C
CC CQ C
V V h I R
V I R
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Fig 7.30 Example 7.14.
Determine the values of ICQ and VCEQ for the amplifier shown in Fig. 7.30.
RB
RC1.5 k
+10 V
180 k
hFE = 100
1
10V 0.7V28.05μA
180kΩ 101 1.5kΩ
CC BEB
B FE C
V VI
R h R
100 28.05μA
2.805mA
CQ FE BI h I
( 1)
10V 101 28.05μA 1.5kΩ
5.75V
CEQ CC FE B CV V h I R
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Circuit Stability ofCollector-Feedback Bias
RB
RC
+VCC
IC
IE
IB
hFE increases
IC increases (if IB is the same)
VCE decreases
IB decreases
IC does not increase that much.
Good Stability. Less dependent on hFE and temperature.
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Collector-FeedbackCharacteristics (1)
RB
RC
+VCC
IC
IE
IB
Circuit recognition: The base resistor is connected between the base and the collector terminals of the transistor.
Advantage: A simple circuit with relatively stable Q-point.
Disadvantage: Relatively poor ac characteristics.
Applications: Used primarily to bias linear amplifiers.
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Collector-FeedbackCharacteristics (2)
RB
RC
+VCC
IC
IE
IB
Q-point relationships:
( 1)CC BE
BFE C B
V VI
h R R
CQ FE BI h I
CEQ CC CQ CV V I R
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Fig 7.31 Emitter-feedback bias.
RB RC
+VCC
RE
IB
IE
IC
1CC BE
BB FE E
V VI
R h R
CQ FE BI h I
CEQ CC C C E E
CC CQ C E
V V I R I R
V I R R
1E FE BI h I
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Fig 7.32 Example 7.15.
RB680k
RC6.2k
+VCC
RE1.6k
hFE = 50
16V 0.7V
1 680kΩ 51 1.6kΩ
20.09μA
CC BEB
B FE E
V VI
R h R
50 20.09μA 1mACQ FE BI h I
16V 1mA 7.8kΩ 8.2V
CEQ CC CQ C EV V I R R
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Circuit Stability ofEmitter-Feedback Bias
hFE increases
IC increases (if IB is the same)
VE increases
IB decreases
IC does not increase that much.
IC is less dependent on hFE and temperature.
RB RC
+VCC
RE
IB
IE
IC
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Emitter-FeedbackCharacteristics (1)
Circuit recognition: Similar to voltage divider bias with R2 missing (or base bias with RE added).
Advantage: A simple circuit with relatively stable Q-point.
Disadvantage: Requires more components than collector-feedback bias.
Applications: Used primarily to bias linear amplifiers.
RB RC
+VCC
RE
IB
IE
IC
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Emitter-FeedbackCharacteristics (2)
RB RC
+VCC
RE
IB
IE
IC
Q-point relationships:
( 1)CC BE
BB FE E
V VI
R h R
CQ FE BI h I
CEQ CC CQ C EV V I R R
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Summary
• DC Biasing and the dc load line• Base bias circuits• Voltage-divider bias circuits• Emitter-bias circuits• Feedback-bias circuits
– Collector-feedback bias circuits– Emitter-feedback bias circuits