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Chapter 12

Chemical BondingChapter 12: Chemical Bonding

Homework: All questions on the “Multiple-Choice” and the odd-numbered questions on“Exercises” sections at the end of the chapter.

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Chemical Bonding

• This chapter focuses on chemical bondingand its role in compound formation

• Virtually everything in nature depends onchemical bonds– Proteins, carbohydrates, and fats that make up

living matter are complex molecules held bychemical bonds

• Rock/minerals on earth – compounds heldtogether by chemical bonds

• Chemical bonding results fromelectromagnetic forces between the electronsand nuclei

Intro

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Law of Conservation of Mass

• No detectable change in the total massoccurs during a chemical reaction

• If the total mass involved in a chemicalreaction is precisely measured beforeand after the reaction, there is nodifference

• Discovered in 1774 by FrenchmanAntoine Lavoisier

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Law of Conservation of Mass

• If a candle is burned in an airtight container ofoxygen there is no detectable change in themass

Section 12.1

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Law of Conservation of Mass - Example

• The complete burning in oxygen (O) of4.09 g of carbon (C) produces 15.00 g ofcarbon dioxide (CO2). How many gramsof oxygen reacted?

• Carbon + oxygen carbon dioxide

• 4.09 g + ? 15.00 g

• Obviously the “?” = 10.91 g

• \ of the 15.00 g of CO2

• 4.09 g = C & 10.91 g = O

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Formula Mass

• Recall that the atomic mass (AM) of anelement is the average mass of all itsnaturally occurring isotopes

– Round off these values to the nearest 0.1 u

• The formula mass (FM) of a compound isthe sum of the atomic masses given in itsformula

• For example: CH4 = 12 u + (4 x 1.0 u) =16 u

Section 12.2

2

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Calculating Formula Masses

• Find the formula mass (FM) of leadchromate, PbCrO4 – used for yellow lineson streets

• Using the Periodic Table, look up theatomic masses of Pb, Cr, and O

• Pb (207.2 u), Cr (52.0 u), O (16.0 u)

• Formula Mass = 207.2 u + 52.0 u + (4 x16 u)

• FM = 323.2 u

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Law of Definite Proportions

• Different samples of a pure compoundalways contain the same elements in thesame proportion by mass.

• For Example:– 9 g H2O = 8 g Oxygen + 1 g Hydrogen

– 18 g H2O = 16 g Oxygen + 2 g Hydrogen

– 36 g H2O = 32 g Oxygen + 4 g Hydrogen

• In each case the ratio (or proportion) bymass of Oxygen to Hydrogen is 8 to 1

Section 12.2

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Calculating Percentage by Mass of anElement

Section 12.2

• % X by mass = (atoms of X in formula) x (AMx) X 100

FMcpd• H2O for example

• % 0 by mass = (1) x (16.0 u) X 100 = 88.9%

18.0

• % H by mass = 11.1%

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Calculating Percentage by Mass for CO2

• “Dry Ice” is CO2

• AM (atomic mass) of C = 12.0 u & O = 16.0 u

• FM (formula mass) of CO2 =

– 12.0 u + (2 x 16.0 u) = 44.0 u

• % mass of C = (1 x AMc/FMCO2) x 100 = ???%

• % mass of C = (1 x 12.0 u/44.0 u) x 100 = 27.3%

• Since the % mass of C = 27.3%

• \ the % mass of O = 72.7 %

Section 12.2

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Calculating Percentage by Mass for Al2O3

• Mineral corundum (ruby & sapphire) is Al2O3

• AM (atomic mass) of Al = 27.0 u & O = 16.0 u

• FM (formula mass) of Al2O3 =

– (2 x 27.0 u) + (3 x 16.0 u) = 102.0 u

• % mass of O = (3 x AMO/FMAl2O3) x 100 = ???%

• % mass of O = (3 x 16.0 u/102.0 u) x 100 =47.1%

• Since the % mass of O = 47.1%

• \ the % mass of Al = 52.9 %

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Definite Proportions

• When a compound is broken down, itselements are found in a definiteproportion by mass

• Also, when the same compound isformed, the elements will combine inthat same proportion by mass

Section 12.2

3

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Limiting & Excess Reactants

• If constituent elements are not mixed inthe correct proportions then

• One of the elements will be usedcompletely up and is called the limitingreactant

• And one of the elements will onlypartially be used up and is called theexcess reactant

• Let’s look at an example …

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Law of Definite ProportionsNote that the Law of Conservation of Mass is also satisfied!

Correct %’s

Excess SLimited Cu

Excess CuLimited S

Section 12.2

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Dalton’s Atomic Theory

• In 1803, John Dalton proposed threehypotheses to explain the following twolaws

– Law of Conservation of Mass

– Law of Definite Proportions

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Dalton’s Atomic Theory – 1803Hypothesis #1

1) Each element is composed of smallindivisible particles called atoms

– Atoms are identical for that element, butdifferent from other atoms

Section 12.3

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Dalton’s Atomic Theory – 1803Hypothesis #2

2) Chemical combination is simply thebonding of a definite number of atomsto make one molecule of thecompound

– A given compound always has the samerelative numbers and types of atoms

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Dalton’s Atomic Theory – 1803Hypothesis #3

3) No atoms are gained/lost/changed inidentity during a chemical reaction,they are just rearranged to producenew substances

Section 12.3

4

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Dalton’s Atomic Theory - 1803

• Over the years more and moresupporting evidence for Dalton’sconcept of the atom has accumulated

• Although there have been manymodifications to his basic ideas, theyhave worked so well and for so long thatwe now call it the atomic theory

• Dalton’s atomic theory is thecornerstone of modern chemistry

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A Little Review

• In Chapter 11 we learned that elements in thesame group have the same # of valenceelectrons.– Similar compounds –> LiCl, NaCl, KCl, RbCl, CsCl

• Because of this behavior, we know that thevalence electrons are the ones involved incompound formation.

• Group 8A are the “noble gases” and generallydo not bond with other atoms.

• Chemists have concluded that having eightelectrons in the outer shell is very stable.

Section 12.4

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Electron Shell Distribution

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Octet Rule

1) Valence electrons are the ones involved incompound formation.

2) Eight electrons in the outer shell is verystable.

• The vast majority of compounds can beexplained by combining these twoconclusions.

• In forming compounds, atoms tend to gain,lose, or share valence electrons to achieveelectron configurations with eight electron inthe outer shell. (H is an exception w/ only 2in outer shell.)

Section 12.4

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Bonding

• Individual atoms can achieve this “noblegas” electron configuration (8 in outershell) in two ways:

– By transferring (gaining or losing) electrons

– By sharing electrons

• Bonding by transfer of electrons iscalled ionic bonding and will bediscussed in this section.

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Ionic Bonding

• In the transfer of electrons:– One or more atoms lose their valence

electrons

– Another one or more atoms gain thesesame electrons

– In order to achieve noble gas electronconfigurations

• Compounds formed by this electrontransfer process are called ioniccompounds.

Section 12.4

5

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Ions

• An ion is formed due to the loss or gain ofelectrons that destroy the electrical neutralityof the atom and produces a net positive ornegative electric charge.

• The net electric charge on an ion is thenumber of protons minus the number ofelectrons. (p – e = net charge)

• Metals (left side of Periodic Table) tend tolose one or two electrons.

• Nonmetals (right side of Periodic Table) tendto gain electrons.

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Pattern of Ionic Charges

Tend to lose valence electrons Gain electrons invalence shell

Noble Gases

Section 12.4

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Electron Shell DistributionResults in Ionic Charge Pattern

+1 +2 +3 -3 -2 -1

Metals Nonmetals

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Sodium Ion (Na+) (loses the electron from theouter shell)

Chloride Ion (Cl-) (gains an electron to fill theouter shell)

Section 12.4

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The Formation of Sodium Chloride

NaCl - formula unit of sodium chloride, the smallest combinationof ions that gives the compound formula

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Sodium Chloride (NaCl) – schematicdiagram of a crystal showing a formula unit

• Note that it is actuallyimpossible to associateany one Na+ with onespecific Cl-

• Thus it is somewhatinappropriate to refer to a“molecule” of any ioniccompound.

Section 12.4

6

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Lewis Symbol

• Lewis Symbol – the nucleus and innerelectrons of an atom/ion represented bythe element’s symbol, and the valenceelectrons shown by dots

Section 12.4

: ::• .Cl: or :Cl:—

• Na. or Na+

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Lewis SymbolsFor the First Three Periods of the Representative Elements

Section 12.4

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Ions

• Cations – positive ions, generally metals

– Elements that tend to lose electrons

– The positive charge will be equal to the number ofvalence electrons in the atom (its group number.)

• Anions – negative ions, generally nonmetals

– Elements that tend to gain electrons

– The negative charge on the nonmetal’s ion will bethe number of valence electrons in the atom (itsgroup number) minus 8.

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Electron Shell Distribution

+1 +2 +3 -3 -2 -1

Metals Nonmetals

Section 12.4

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Pattern of Charges??

• Valence electrons are lost by metals andgained by nonmetals generally to theextent necessary to acquire eightelectrons into the most outer shell, thatis, to acquire an electron configurationisoelectronic with a noble gas. (sameelectron configuration)

• For example: Al3+ is isoelectric with Ne

• or S2- is isoelectronic with Ar.

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Electron Shell Distribution

+1 +2 +3 -3 -2 -1

Metals Nonmetals

Section 12.4

7

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Ionic Bonds and Compounds

• Ionic bond – electrical forces that hold the ionstogether in the crystal lattice of an ioniccompound

• In every ionic compound, the total charge in theformula adds up to zero and the compoundexhibits electrical neutrality.

• In NaCl the ratio of Na+ to Cl- is always 1 to 1.

• In CaCl2 the ratio of Ca2+ to Cl- is always 1 to 2.

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Formulas for Ionic Compounds

• The numbers of atoms of the variouselements in a compound aredetermined by:

1) The total electrical charge for thecompound is zero

2) All the individual atoms have noble gasconfigurations in their outer shell

Section 12.4

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Writing formulas for Ionic Compounds –an Example

• Write the formula for calcium phosphate, themajor component of bones.

• Ca is in Group 2A 2+ ionic charge

• Phosphate is the polyatomic ion (section 11.5)PO4 3- ionic charge

• Therefore when combining these two ionsneutrality can be attained with three Ca2+ andtwo PO4

3-.

• Ca3(PO4)2

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Confidence Exercise

• Write in the formulas for the ionic compounds formedby combining each metal ion (M) with each nonmetalion (X.)

MX

MX2

MX3

M2X

MX

M2X3

M3X

M3X2

MX

Section 12.4

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Ionic Compounds

• Due to the very strong forces of attractionbetween oppositely charged ions

– Ionic compounds are always crystalline solids andalso have high melting and boiling points

• Ionic compounds also have a specificproperty when an electric current is passedthrough them.

– Solid ionic compounds DO NOT conduct electricity(because ions cannot move.)

– Melted ionic compounds will CONDUCTelectricity.

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Melted Salt (NaCl) Conducts Electricity

Aqueous solutions in which ionic compounds have been dissolvedalso conduct electricity.

Section 12.4

8

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Stock System –For metals that form two ions

• Stock System – place in parentheses directly afterthe metal’s name a Roman numeral giving the valueof the metal’s ionic charge– CrCl2 chromium(II) chloride (usually blue)– CrCl3 chromium(III) chloride (usually green)

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Stock System: Example

• A certain compound of gold and sulfur has theformula Au2S. What is the Stock systemname?

• Au = either 2+ or 1+ & S = 2-

• Therefore the Stock system name = gold(I)sulfide

• Cu = either 2+ or 1+ & F = 1-

• CuF = copper(I) fluoride

• CuF2 = copper(II) fluoride

• (The old names for these compounds werecuprous fluoride and cupric flouride.)

Section 12.4

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Covalent Bonding

• When a pair of electrons is shared by twoatoms, a covalent bond exists between theseatoms

– The two electrons no longer orbit an individualnucleus, but are shared equally by both nuclei

• If the covalent bond is between atoms of thesame element, the molecule formed is that ofan element -- H2 (hydrogen gas)

• Covalent bonds between atoms of differentelements form molecules of compounds – HCl

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Covalent Bonding in the H2 molecule

0.074 nm is the distance at which the two H atomsare the most stable

Section 12.5

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Lewis Symbol Use

• Hydrogen gas (H2)

• H. .H H : H or H—H (shows twohydrogen atoms each sharing both valenceelectrons – a covalent bond)

• Hydrogen chloride (hydrochloric acid) (HCl)

Section 12.5

..

.. ..

..

..

..• H. .Cl: H : Cl : or H-Cl : (shows the H

and Cl atoms sharing two electrons – a covalentbond)

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Stable Covalent Molecules

• Stable Covalent Molecules form whenthe atoms share electrons in such a wayas to give all atoms a share in a noblegas configuration

• Recall the Octet Rule – in formingcompounds, atoms tend to gain, lose, orshare electrons to achieve electronconfigurations of the noble gases

Section 12.5

9

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Recall the Lewis Symbols for the FirstThree Periods of Representative Elements

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Covalent Bonds & Groups

• Noble Gases (8A) tend to form 0 bonds

• Hydrogen and Group 7A tend to form 1bond

• Group 6A tend to form 2 bonds

• Group 5A tend to form 3 bonds

• Group 4A tend to form 4 bonds

Section 12.5

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Number of Covalent Bonds expected byCommon Nonmetals

Exceptions are uncommon in Periods 1 & 2, but occur with more frequencystarting with Period 3

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Double/Triple Bonding

• When an element has 2, 3, or 4unpaired valence electrons, its atomswill sometimes share more than one ofthem with another atom

• Double and Triple bonds between twoatoms are possible

Section 12.5

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Double Bond Example – CO2

Section 12.5

..

... .

..• :O. . C . .O:

.. ..• :O : : C : : O :• or

.. ..• : O==O :

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Triple Bond Example – N2

Section 12.5

• :N:::N:

• or

. .

. .• :N. .N:

____________________________

______________• :N N:

10

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Drawing Lewis Structures for SimpleCovalent Compounds – use board

• Chloroform CHCl3• C (four bonds); H (one bond); Cl (one

bond) each

• \ only C can be the central atom

• Hydrogen peroxide H2O2

• H (one bond); O(two bonds)

• \ only O can connect two atoms

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Covalent Bonding –Misc. Info.

• Unlike ionic compounds, covalentcompounds are composed of individualmolecules with a specific molecularformula

• Carbon tetrachloride (CCl4) consists ofmany individual CCl4 molecules

• Within a molecule the covalent bonds arestrong, but the individual molecules onlyweakly attract each other

Section 12.5

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Ionic & Covalent??

• Some compounds contain both ionicand covalent bonds – sodium hydroxide(NaOH)

• OH- is a polyatomic ion that has acovalent bond between the O & H

• But there is an ionic bond between theNa+ and the OH-, holding the wholemolecule together

Section 12.5

..

..• Na+[:O:H]-

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Rules to Predict Ionic or Covalent??

• Compounds formed of only nonmetals arecovalent (except ammonium compounds)

• Compounds of metals and nonmetals aregenerally ionic

• Compounds of metals with polyatomic ionsare ionic

• Compounds that are gases, liquids, or low-melting-point solids are covalent

• Compounds that conduct electricity whenmelted are ionic

Section 12.5

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Comparison of Properties of Ionic andCovalent Compounds

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Predicting Bonding Type – examples

• KF ionic, a metal and nonmetal

• SiH4 covalent, all nonmetals

• Ca(NO3)2 ionic, metal and polyatomicion

• X (a gas at room temp) covalent, agas

• Y (melts at 900oC, then conductselectricity) ionic

Section 12.5

11

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Polar Covalent Bonding

• Remember that in covalent bonding,electrons are shared, but …

– These bonds are not always shared equally

• Unless the atoms are the same element, thebonding electrons spend more time aroundthe more nonmetallic element

– The sharing is unequal

• The is called a polar covalent bond, indicatinga slightly positive end and a slightly negativeend

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Electronegativity

• Electronegativity (EN) – a measure ofthe ability of an atom in a molecule todraw bonding electrons to itself

• Electronegativity also displays definitetrends on the Periodic Table

– Increases across a period

– Decreases down a group

Section 12.5

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Electronegativity – an Example

• Consider HCl H (EN=2.1) & Cl (EN=3.0)

– Note that the Cl is more electronegative

• The two bonding electrons tend to spendmore time at the Cl- end \ resulting in a polarcovalent bond

• Polarity can be represented –

• The head of arrow points to the moreelectronegative atom and the other sidemakes a “plus”

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Electronegativity Values

Section 12.5

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Summaryof Ionic

andCovalentBonding

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Showing the Polarity of Bonds - example

• Use arrows to show the polarity of thecovalent bonds of H2O

• O (EN=3.5) & H (EN=2.1)

• Cl (EN=3.0) & C (EN=2.5)

Section 12.5

12

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Showing the Polarity of Bonds - example

• Use arrows to show the polarity of thecovalent bonds of CCl4

• O (EN=3.5) & H (EN=2.1)

• Cl (EN=3.0) & C (EN=2.5)

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Polar Bonds and Polar Molecules

• The molecule as a whole, as well asbonds, can have polarity

• A molecule is polar if electrons are moreattracted to one end of the molecule

• Such a molecule has a slightly (-) endand a slightly (+) end

• This type of molecule is said to have adipole or is called a polar molecule

Section 12.5

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Polar Bonds & Polar Molecules

H (EN=2.1) Be (EN=1.5)

Nonpolar Molecule

Section 12.5

H (EN=2.1) Cl (EN=3.0)

Polar Molecule

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Water Molecule – it is polar!

• BUT• The water molecule is

actually angular (105o)and \ has a positive andnegative end (dipole)

Section 12.5

• If water was a linearmolecule it would benonpolar

• Therefore, in order to determine if a molecule ispolar (dipole), one must know the molecule’sshape

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--Summary--Polar Bonds and Polar Molecules

• If the bonds in a molecule are nonpolar,the molecule can only be nonpolar

• A molecule with only one polar bondhas to be polar

• A molecule with more than one polarbond will be nonpolar if the shape of themolecule causes the polarities of thebonds to cancel, otherwise it will bepolar

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Polar and Nonpolar Liquids

A stream ofpolar watermolecules(left) isdeflected by acharge. Astream ofnonpolar CCl4

molecules isnot deflected

Section 12.5

13

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Types of Molecules with Polar Bonds butNo Resulting Dipole

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Dissolving

• Why does water dissolve table salt butdoes not dissolve oil?

• The polar nature of the water moleculecauses them to interact with an ionicsubstance such as salt

– The positive ends of the water moleculesattract negative ions

– The negative ends of the water moleculesattract positive ions

Section 12.6

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Polar Water Molecules Dissolve

• If the attraction of the polar watermolecules overcomes the attractionbetween the ions in the crystal, the saltdissolves

• This type of attraction is called an ion-dipole interaction

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Sodium Chloride Dissolving in Water

• The (-) ends of the polar water molecules attract/surround the (+) Na

• The (+) ends of the polar water molecules attract/surround the (-) Cl

Section 12.6

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Polar and Nonpolar Substances

• Two polar substances tend to dissolve ineach other

– They are said to have a dipole-dipole interaction

• Two nonpolar substances also tend to mixwell, but not for the same reason

– Nonpolar molecules of two types simply have noaffinity for each other and \ evenly disperse

– Gas and Oil are nonpolar molecules that mix well

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Polar and Nonpolar Substances

• In general like dissolves like

– Polar substances tend to mix well in other polarsubstances

– Nonpolar substance tend to mix well in othernonpolar substances

• Unlike substances do not tend to mix well

– The polar molecules tend to gather together andexclude the nonpolar molecules

– For example oil (nonpolar) does not mix well withwater (polar)

Section 12.6

14

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Hydrogen Bonding

• Hydrogen bond – a special kind ofdipole-dipole interaction

• Hydrogen bonding occurs wheneverhydrogen atoms are covalently bondedto small, highly electronegative atoms

• In general, O, F, and N meet thesecriteria

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Hydrogen Bonding

• When hydrogen is covalently bonded toone of these three atoms …

• The bond is very polar and thehydrogen atom is comparatively small

• Thus the partial positive charge on thehydrogen is highly concentrated

• Resulting in the hydrogen atom havingan electrical attraction for nearby O, F,or N atoms in neighboring molecules

Section 12.6

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Hydrogen Bonding in Water

The forces ofattraction (reddots) existbetween thehydrogen (+)atom of onemolecule andthe oxygen (-)atom of anothermolecule

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Hydrogen Bonds

• Hydrogen bonds are strong enough tohave a significant effect on theproperties of the substance

– Hydrogen bonds are about 5-10% thestrength of covalent bonds

Section 12.6

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Hydrogen Bonding Affects theProperties of a Substance

• One of the most pronounced effects thatresults from hydrogen bonding is thepredicted change in a substance’s boilingpoint

• Note on the following graph - the threesubstances with hydrogen bonding havesignificantly higher boiling points

– Hydrogen bonding does not occur in CH4, itsboiling point shows a normal pattern relative to theother hydrogen compounds of Group 4A

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Hydrogen Bonding at Work

In general, the boilingpoints of similarcompounds increasewith increasing formulamass. Due tohydrogen bonding theboiling points of H2O,HF, and NH3 are allanomalously high.

Section 12.6

15

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Hydrogen Bonding and Density

• Hydrogen bonding and the shape of the water molecule result inice having a more open structure. In most other substances thesolid phase is more dense than the liquid phase

Water (H2O) Benzene (C6H6)

Section 12.6