CEE 320 Spring 2008 Geometric Design CEE 320 Anne Goodchild.

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Transcript of CEE 320 Spring 2008 Geometric Design CEE 320 Anne Goodchild.

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Geometric Design

CEE 320Anne Goodchild

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Outline

1. Concepts2. Vertical Alignment

a. Fundamentalsb. Crest Vertical Curvesc. Sag Vertical Curvesd. Examples

3. Horizontal Alignmenta. Fundamentalsb. Superelevation

4. Other Non-Testable Stuff

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Concepts

• Alignment is a 3D problem broken down into two 2D problems– Horizontal Alignment (plan view)– Vertical Alignment (profile view)

• Stationing– Along horizontal alignment– 12+00 = 1,200 ft.

Piilani Highway on Maui

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Stationing

Horizontal Alignment

Vertical Alignment

From Perteet Engineering

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Vertical Alignment

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Vertical Alignment

• Objective: – Determine elevation to ensure

• Proper drainage• Acceptable level of safety

• Primary challenge– Transition between two grades– Vertical curves

G1 G2G1

G2

Crest Vertical Curve

Sag Vertical Curve

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Vertical Curve Fundamentals

• Parabolic function– Constant rate of change of slope– Implies equal curve tangents

• y is the roadway elevation x stations (or feet) from the beginning of the curve

cbxaxy 2

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Vertical Curve Fundamentals

G1

G2

PVI

PVT

PVC

L

L/2

δ

cbxaxy 2

x

Choose Either:• G1, G2 in decimal form, L in feet• G1, G2 in percent, L in stations

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RelationshipsChoose Either:• G1, G2 in decimal form, L in feet• G1, G2 in percent, L in stations

G1

G2

PVI

PVT

PVC

L

L/2

δ

x

1 and 0 :PVC At the Gbdx

dYx

cYx and 0 :PVC At the

L

GGa

L

GGa

dx

Yd

22 :Anywhere 1212

2

2

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Example

A 400 ft. equal tangent crest vertical curve has a PVC station of 100+00 at 59 ft. elevation. The initial grade is 2.0 percent and the final grade is -4.5 percent. Determine the elevation and stationing of PVI, PVT, and the high point of the curve.

G1=2.0%

G2= - 4.5%

PVI

PVT

PVC: STA 100+00EL 59 ft.

G1=2.0%

G2= -4.5%

PVI

PVT

PVC: STA 100+00EL 59 ft.

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Other Properties

G1

G2

PVI

PVTPVC

x

Ym

Yf

Y

2

200x

L

AY

800

ALYm

200

ALY f

21 GGA

•G1, G2 in percent•L in feet

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Other Properties

• K-Value (defines vertical curvature)– The number of horizontal feet needed for a 1%

change in slope

A

LK

1./ GKxptlowhigh

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Crest Vertical Curves

G1G2

PVI

PVTPVC

h2h1

L

SSD

221

2

22100 hh

SSDAL

A

hhSSDL

2

212002

For SSD < L For SSD > L

Line of Sight

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Crest Vertical Curves

• Assumptions for design– h1 = driver’s eye height = 3.5 ft.

– h2 = tail light height = 2.0 ft.

• Simplified Equations

2158

2SSDAL

ASSDL

21582

For SSD < L For SSD > L

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Crest Vertical Curves

• Assuming L > SSD…

2158

2SSDK

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Design Controls for Crest Vertical Curves

from AASHTO’s A Policy on Geometric Design of Highways and Streets 2004

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Design Controls for Crest Vertical Curves

fro

m A

AS

HT

O’s

A P

olic

y o

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eo

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De

sig

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f H

igh

wa

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nd

Str

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4

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Sag Vertical Curves

G1 G2

PVI

PVTPVC

h2=0h1

L

Light Beam Distance (SSD)

tan200 1

2

Sh

SSDAL

A

SSDhSSDL

tan2002 1

For SSD < L For SSD > L

headlight beam (diverging from LOS by β degrees)

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Sag Vertical Curves

• Assumptions for design– h1 = headlight height = 2.0 ft.

– β = 1 degree

• Simplified Equations

SSD

SSDAL

5.3400

2

A

SSDSSDL

5.34002

For SSD < L For SSD > L

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Sag Vertical Curves

• Assuming L > SSD…

SSD

SSDK

5.3400

2

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Design Controls for Sag Vertical Curves

from AASHTO’s A Policy on Geometric Design of Highways and Streets 2004

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Design Controls for Sag Vertical Curves

fro

m A

AS

HT

O’s

A P

olic

y o

n G

eo

me

tric

De

sig

n o

f H

igh

wa

ys a

nd

Str

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ts 2

00

4

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Example 1

A car is traveling at 30 mph in the country at night on a wet road through a 150 ft. long sag vertical curve. The entering grade is -2.4 percent and the exiting grade is 4.0 percent. A tree has fallen across the road at approximately the PVT. Assuming the driver cannot see the tree until it is lit by her headlights, is it reasonable to expect the driver to be able to stop before hitting the tree?

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Sag Vertical Curve

• Assume S<L, try both, but this is most often the case

• Equation specific to sag curve which accommodates headlight beam

• L and S in horizontal plane and comparable (150 and 146 ft)

• Required SSD = 196.53 ft assumes 0 grade

• Text problem versus design problem.

SSD

SSDAL

5.3400

2

rtV

Gga

g

VSSD 1

21

2

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Sag Vertical Curves

G1 G2

PVI

PVTPVC

h2=0h1

L

Light Beam Distance (S)

diverging from horizontal plane of vehicle by β degrees

Daytime sight distance unrestricted

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Example 2

Similar to Example 1 but for a crest curve.

A car is traveling at 30 mph in the country at night on a wet road through a 150 ft. long crest vertical curve. The entering grade is 3.0 percent and the exiting grade is -3.4 percent. A tree has fallen across the road at approximately the PVT. Is it reasonable to expect the driver to be able to stop before hitting the tree?

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Crest Vertical Curve

• Assume S<L, try both, but this is most often the case

• Equation specific to crest curve which accommodates sight over hill

• L and S in horizontal plane and comparable (150 and 243 ft)

• Required SSD = 196.53 ft assumes 0 grade

• Text problem versus design problem.

2158

2SSDAL

A

SSDL2158

2

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Crest Vertical Curves

G1G2

PVI

PVTPVC

h2h1

L

SSD

Line of Sight

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Example 3

A roadway is being designed using a 45 mph design speed. One section of the roadway must go up and over a small hill with an entering grade of 3.2 percent and an exiting grade of -2.0 percent. How long must the vertical curve be?

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Horizontal Alignment

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Horizontal Alignment

• Objective: – Geometry of directional transition to ensure:

• Safety• Comfort

• Primary challenge– Transition between two directions– Horizontal curves

• Fundamentals– Circular curves– Superelevation

Δ

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Horizontal Curve Fundamentals

R

T

PC PT

PI

M

E

R

Δ

Δ/2Δ/2

Δ/2

RRD

000,18

180100

2tan

RT

DRL

100

180

L

D = degree of curvature (angle subtended by a 100’ arc)

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Horizontal Curve Fundamentals

1

2cos

1RE

2

cos1RM

R

T

PC PT

PI

M

E

R

Δ

Δ/2Δ/2

Δ/2L

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Example 4

A horizontal curve is designed with a 1500 ft. radius. The tangent length is 400 ft. and the PT station is 20+00. What are the PI and PT stations?

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Superelevation cpfp FFW

cossincossin22

vvs gR

WV

gR

WVWfW

α

α

Fcp

Fcn

Wp

Wn F f

F f

α

Fc

W 1 fte

≈Rv

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Superelevation

cossincossin22

vvs gR

WV

gR

WVWfW

tan1tan2

sv

s fgR

Vf

efgR

Vfe s

vs 1

2

efg

VR

sv

2This is the minimum radius that provides for safe vehicle operation

Rv because it is to the vehicle’s path

e = number of vertical feet of rise per 100 ft of horizontal distance = 100tan

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Selection of e and fs

• Practical limits on superelevation (e)– Climate– Constructability– Adjacent land use

• Side friction factor (fs) variations– Vehicle speed– Pavement texture– Tire condition

Design values of fs are chosen somewhat below this maximum value so there is a margin of safety

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Minimum Radius Tables

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WSDOT Design Side Friction Factors

from

the

200

5 W

SD

OT

Des

ign

Man

ual,

M 2

2-01

For Open Highways and Ramps

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WSDOT Design Side Friction Factors

from

the

200

5 W

SD

OT

Des

ign

Man

ual,

M 2

2-01

For Low-Speed Urban Managed Access Highways

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Design Superelevation Rates - AASHTO

from AASHTO’s A Policy on Geometric Design of Highways and Streets 2004

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Design Superelevation Rates - WSDOT

from the 2005 WSDOT Design Manual, M 22-01

emax = 8%

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Example 5

A section of SR 522 is being designed as a high-speed divided highway. The design speed is 70 mph. Using WSDOT standards, what is the minimum curve radius (as measured to the traveled vehicle path) for safe vehicle operation?

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Example 5

A section of SR 522 is being designed as a high-speed divided highway. The design speed is 70 mph. Using WSDOT standards, what is the minimum curve radius (as measured to the traveled vehicle path) for safe vehicle operation?

For the minimum curve radius we want the maximum superelevation.WSDOT max e = 0.10

For 70 mph, WSDOT f = 0.10

efg

VR

sv

2

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Stopping Sight Distance

Rv

Δs

Obstruction

Ms

DRSSD s

sv

100

180

SSD (not L)•Looking around a curve•Measured along horizontal curve from the center of the traveled lane•Need to clear back to Ms (the middle of a line that has same arc length as SSD)

Assumes curve exceeds required SSD

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Stopping Sight Distance

Rv

Δs

Obstruction

Ms v

s R

SSD

180

SSD (not L)

vvs R

SSDRM

90

cos1

v

svv

R

MRRSSD 1cos

90

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Example 6

vvs R

SSDRM

90

cos1

A horizontal curve with a radius to the vehicle’s path of 2000 ft and a 60 mph design speed. Determine the distance that must be cleared from the inside edge of the inside lane to provide sufficient stopping sight distance.

rtV

Gga

g

VSSD 1

21

2

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Superelevation Transition

from the 2001 Caltrans Highway Design Manual

FYI – NOT TESTABLE

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Spiral Curves

No Spiral

Spiral

from AASHTO’s A Policy on Geometric Design of Highways and Streets 2004

FYI – NOT TESTABLE

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No Spiral

FYI – NOT TESTABLE

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Spiral Curves

• WSDOT no longer uses spiral curves• Involve complex geometry• Require more surveying• Are somewhat empirical• If used, superelevation transition should

occur entirely within spiral

FYI – NOT TESTABLE

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Operating vs. Design Speed

85th Percentile Speed vs. Inferred Design Speed for 138 Rural Two-Lane Highway Horizontal Curves

85th Percentile Speed vs. Inferred Design Speed for

Rural Two-Lane Highway Limited Sight Distance Crest

Vertical Curves

FYI – NOT TESTABLE