Building Estimation Methods

Prepared by:-Er. Simarpreet SinghA.P, Civil Engg.ACET, Amritsar

TABLE OF CONTENTS One Room Building

Concrete work in foundation (Center line and separate wall method)

Brickwork in footing (Center line and separate wall method)

Brickwork in walls (Center line and separate wall method) Two Rooms Building

Concrete work in foundation (Center line and separate wall method)

One Room Building

5m

4m

0.3m0.3m

0.5m0.6m0.9m

0.4m0.6m

3.5m

Section at A-A’ and B-B’ Thickness of footing and foundation is 30 cm each

A

A’

B B’

Plan

0.9 m

5.3m

4.3 m

Total Center line = 5.3+5.3+4.3+4.3=19.2 m

Width = 0.9 m Total Qty of concrete in foundation= (19.2×0.9×0.3) cum

Center Line Method

0.9 m

5.3m6.2m

4.3 m

3.4 m

Separate Wall Method

Width = 0.9 m Total Qty of concrete in fdn= (2×6.2×0.9×0.3) + (2×3.4×0.9×0.3)cum

Long Wall = 5.3+0.9=6.2 m Short Wall = 4.3-0.9=3.4 m

0.6 m

5.3m

4.3 m

Total Center line = 5.3+5.3+4.3+4.3=19.2 m

Width = 0.6 m Total Qty of brickwork in Ist footing= (19.2×0.6×0.3) cum

Center Line Method

0.6 m

5.3m

5.9 m

4.3 m

3.7 m

Width = 0.6 m

Separate Wall MethodLong Wall = 5.3+0.6=5.9 m Short Wall = 4.3-0.6=3.7 m

Total Qty of brickwork in Ist footing= (2×5.9×0.6×0.3) + (2×3.7×0.6×0.3)cum

5.3m

4.3 m

0.3 m

Total Center line = 5.3+5.3+4.3+4.3=19.2 m

Width = 0.3 m Total Qty of brickwork in walls= (19.2×0.3×3.5) cum

Center Line Method

5.6 m

5.3m

4.3 m

4 m

0.3 m

Width = 0.3 m

Separate Wall MethodLong Wall = 5.3+0.3=5.6 m Short Wall = 4.3-0.3=4.0 m

Total Qty of brickwork in walls= (2×5.6×0.3×3.5) + (2×4.0×0.3×3.5)cum

Two Rooms Building

5m

4m0.3m

0.3m

0.5m0.6m0.9m

0.4m0.6m

3.5m

Section at A-A’ and B-B’ Thickness of footing and foundation is 30 cm each

A

A’

B B’

Plan

Center Line MethodTotal Center line = 5.3+5.3+5.3+5.3+4.3+4.3+4.3=34.1 m

Width = 0.9 m Total Qty of concrete in fdn= (34.1×0.9×0.3)

5.3m 5.3m

4.3 m

0.9 m

Intermediate wall

– (2×0.9×(0.9/2) ×0.3)cum

Separate Wall MethodLong Wall = 5.3+5.3+0.9=11.5 m Short Wall = 4.3-0.9=3.4 m

Width = 0.9 m Total Qty of concrete in fdn= (2×11.5×0.9×0.3)

5.3m 5.3m

4.3 m

0.9 m

11.5 m

3.4m

Intermediate wall

+ (3×3.4×0.9×0.3)cum

THANK YOU

Any Questions?