Answer questions Hour 1: Review: Electric Fields Charge ......Review: Electric Fields Charge Dipoles...

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Transcript of Answer questions Hour 1: Review: Electric Fields Charge ......Review: Electric Fields Charge Dipoles...

1P02 -

Class 02: Outline

Answer questionsHour 1:

Review: Electric FieldsChargeDipoles

Hour 2:Continuous Charge Distributions

2P02 -

Last Time: FieldsGravitational & Electric

3P02 -

Gravitational & Electric Fields

Mass M Charge q (±)

2ˆMG

r= −g r 2

ˆeqkr

=E rCREATE:

g m=F g E q=F E

This is easiest way to picture field

FEEL:

4P02 -

PRS Questions:Electric Field

5P02 -

Electric Field Lines1. Direction of field line at any point is tangent to

field at that point2. Field lines point away from positive charges

and terminate on negative charges3. Field lines never cross each other

6P02 -

In-Class Problem

d

s

q− q+

P

ij

Consider two point charges of equal magnitude but opposite signs, separated by a distance d. Point Plies along the perpendicular bisector of the line joining the charges, a distance s above that line. What is the E field at P?

7P02 -

Two PRS Questions:E Field of Finite Number of Point

Charges

8P02 -

Charging

9P02 -

How Do You Charge Objects?

• Friction• Transfer (touching)• Induction

Neutral----

++++

+q

10P02 -

Demonstrations:Instruments for

Charging

11P02 -

Electric Dipoles

A Special Charge Distribution

12P02 -

Electric DipoleTwo equal but opposite charges +q and –q,

separated by a distance 2a

q

-q

2a charge×displacementˆ ˆ×2 2q a qa

= =

p

j j

Dipole Moment

p

p points from negative to positive charge

13P02 -

Why Dipoles?

Nature Likes To Make Dipoles!

http://ocw.mit.edu/ans7870/8/8.02T/f04/visualizations/electrostatics/20-Molecules2d/20-mole2d320.html

14P02 -

Dipoles make Fields

15P02 -

Electric Field Created by DipoleThou shalt use components!

3 3x ex xE k q

r r+ −

⎛ ⎞∆ ∆= −⎜ ⎟

⎝ ⎠

3 3y ey yE k q

r r+ −

+ −

⎛ ⎞∆ ∆= −⎜ ⎟

⎝ ⎠

3/2 3/22 2 2 2( ) ( )e

x xk qx y a x y a

⎛ ⎞⎜ ⎟= −⎜ ⎟⎡ ⎤ ⎡ ⎤+ − + +⎣ ⎦ ⎣ ⎦⎝ ⎠

3/2 3/22 2 2 2( ) ( )e

y a y ak qx y a x y a

⎛ ⎞− +⎜ ⎟= −⎜ ⎟⎡ ⎤ ⎡ ⎤+ − + +⎣ ⎦ ⎣ ⎦⎝ ⎠

2 3 3 3

ˆ ˆ ˆx yr r r r

∆ ∆= = +

r r i j

16P02 -

PRS Question:Dipole Fall-Off

17P02 -

Point Dipole Approximation

Take the limit r a>>

You can show…Finite Dipole

30

3 sin cos4x

pEr

θ θπε

( )23

0

3cos 14y

pEr

θπε

→ −Point Dipole

18P02 -

Shockwave for Dipole

http://ocw.mit.edu/ans7870/8/8.02T/f04/visualizations/electrostatics/06-DipoleField3d/06-dipField320.html

19P02 -

Dipoles feel Fields

20P02 -

Demonstration:Dipole in Field

21P02 -

Dipole in Uniform FieldˆE=E i

ˆ ˆ2 (cos sin )qa= +p i jθ θ

( ) 0net q q+ −= + = + − =F F F E E

tends to align with the electric field p

Total Net Force:

Torque on Dipole: = ×τ r F( )( )2 sin( )a qE θ=

= ×p Esin( )rFτ θ+= sin( )pE θ=

23P02 -

PRS Question:Dipole in Non-Uniform Field

24P02 -

Continuous Charge Distributions

25P02 -

Continuous Charge Distributions

( ) ?P =E

Vi

iQ q

Break distribution into parts:

= ∆∑

2ˆe

qkr∆

∆ =E r

E field at P due to ∆q

Superposition:

= ∆∑E E

V

dq→ ∫

d→ ∫ E

2ˆe

dqd kr

→ =E r

26P02 -

Continuous Sources: Charge DensitydVdQ ρ=

R

L

2Volume V R Lπ= = QV

ρ =

LQ

QA

σ =

dAdQ σ=w

L

Area A wL= =

dLdQ λ=Length L=

L

31P02 -

Example: Ring of Charge

P on axis of ring of charge, x from centerRadius a, charge density λ.

Find E at P

33P02 -

Ring of Charge3) Write Equation dq a dλ ϕ=

2

ˆe

rd k dqr

=E

a) My way

3x exdE k dqr

=

b) Another way

22 xar +=

3erk dqr

=

cos( )xdE d θ= E 2 3

1e e

x xk dq k dqr r r

= ⋅ =

34P02 -

Ring of Charge4) Integrate

3x x exE dE k dqr

= =∫ ∫22 xar +=

dq a dλ ϕ=

3exk dqr

= ∫

Very special case: everything except dq is constant

2aλ π=dq∫2 2

0 0a d a d

π πλ ϕ λ ϕ= =∫ ∫

Q=

35P02 -

Ring of Charge5) Clean Up

3x exE k Qr

=

( )3/ 22 2x exE k Q

a x=

+

0a →

( )3/ 22 2ˆ

exk Q

a x=

+E i

6) Check Limit

( )3/ 2 22

ex e

k QxE k Qxx

→ =

36P02 -

r

2L

−2L

+

s

P

j

i

In-Class: Line of Charge

Point P lies on perpendicular bisector of uniformly charged line of length L, a distance s away. The charge on the line is Q. What is E at P?

37P02 -

r

θ

θ

2L

−2L

+

xd ′

x′

xddq ′= λs

22 xsr ′+=

P

j

i

Hint: http://ocw.mit.edu/ans7870/8/8.02T/f04/visualizations/electrostatics/07-LineIntegration/07-LineInt320.html

Typically give the integration variable (x’) a “primed” variable name.

38P02 -

E Field from Line of Charge

2 2 1/ 2ˆ

( / 4)eQk

s s L=

+E j

Limits:

2ˆlim e

s L

Qks>>

→E j Point charge

ˆ ˆ2 2lim e es L

Qk kLs s

λ<<

→ =E j j Infinite charged line

39P02 -

In-Class: Uniformly Charged Disk

P on axis of disk of charge, x from centerRadius R, charge density σ.

Find E at P

( 0 )x >

40P02 -

Disk: Two Important Limits

( )1/ 22 2ˆ1

2disko

x

x R

⎡ ⎤⎢ ⎥= −⎢ ⎥+⎣ ⎦

E iσε

Limits:

2

1 ˆlim 4diskx R o

Qx>>

→E iπε

*** Point charge

ˆlim 2diskx R o<<

→E iσε

Infinite charged plane

41P02 -

E for Plane is Constant????

1) Dipole: E falls off like 1/r3

2) Point charge: E falls off like 1/r2

3) Line of charge:E falls off like 1/r4) Plane of charge: E constant