Post on 16-Nov-2014
description
A. A
B. B
C. C
D. D
A. 7
B. 9
C. 13
D. 22
Find the solution of 5b – 11 = 34 using the replacement set {7, 9, 13, 16, 22}.
(over Lesson 1-3)
1. A
2. B
3. C
4. D
A. {16, 26, 36, 46}
B. {26, 36, 46}
C. {16, 26, 46}
D. {16, 26, 36}
(over Lesson 1-3)
Find the solution set of using the
replacement set {16, 26, 36, 46}.
A. A
B. B
C. C
D. D
Use the table to write aninequality to show the cost ofpurchasing 2 azalea bushes aand 3 boxwood bushes b whilekeeping cost under $40.00
(over Lesson 1-3)
A. 2a + 3b < 40
B. 3a + 2b < 40
C. 2a + 3b < 40
D. 2a + 3b = 40
• additive identity
• multiplicative identity• multiplicative inverses• reciprocal
• Recognize the properties of identity and equality.
• Use the properties of identity and equality.
Standard 1.0 Students identify and use the arithmetic properties of subsets of integers and rational, irrational, and real numbers, including closure properties for the four basic arithmetic operations where applicable.
Standard 1.1 Students use properties of numbers to demonstrate whether assertions are true or false.
Standard 25.1 Students use properties to construct simple, valid arguments (direct and indirect) for, or formulate counterexamples to claimed assertions.
Identify Properties
A. Name the property used in n ● 12 = 0. Then find the value of n.
Answer: n = 0, since 0 ● 12 = 0. This is the Multiplicative Property of Zero.
Identify Properties
B. Name the property used in n ● = 1. Then find the value of n.
Answer: This is the
Multiplicative Inverse Property.
A. A
B. B
C. C
D. D
A. Name the property used in . Then find the value of n.
A. Multiplicative Inverse Property; n = 3
B. Multiplicative Property of zero; n = 0
C.
D.
A. A
B. B
C. C
D. D
B. Name the property used in n + 0 = 11. Then find the value of n.
A. Additive Identity Property; n = 0
B. Multiplicative Identity Property; n = 11
C. Additive Identity Property; n = 11
D. Multiplicative Identity Property; n = 0
Evaluate Using Properties
Name the property used in each step.
Substitution; 12 – 8 = 4
Substitution; 15 ÷ 5 = 3
Substitution; 3 – 2 = 1
Evaluate Using Properties
Multiplicative Identity; 3 ● 1 = 3
= 4 Substitution; 1 + 3 = 4
Multiplicative Inverse; ● 4 = 1
Answer: 4